How to make a public method that is not inherited by subclasses? - actionscript-3

Question

As the question states, I want to know how I can make a function in a class that other classes can access, but subclasses cannot. I have a class that has some public getters and setters that I want my document class to have access to call, but I don't want the subclass to have these functions because they'd be useless on the subclass.
For example
public class SomeClass
{
public function SomeClass() {}
public function notInherited():void { trace("Not inherited"; }
}
public class OtherClass extends SomeClass
{
public function OtherClass()
{
notInherited(); //Want this to return an error
}
}
public class HasAccess
{
public function HasAccess()
{
notInherited(); //Not inherited
}
}
I know this probably has something to do with custom namespaces, but after searching up about them I still don't really have much understanding of how they work. That's about it; thanks for reading.

Answer 1

You can't do this quite in the general terms you've asked, but you can do this if you put your document class and your other class in the same package and use internal instead of public, and you put your sub-class in a different package. The internal keyword limits access to classes in the same package.
Example (notice the package statements):
package main {
public class Main extends MovieClip {
public function Main() {
var stuff:Stuff = new Stuff();
stuff.doStuff();
}
}
}
package main {
public class Stuff {
internal function doStuff():void { }
}
}
package other {
public class OtherStuff extends Stuff {
public function OtherStuff() {
// no access to this.doStuff()
}
}
}
As for using a namespace, this can be a good option to make the intent of your code more clear, but it doesn't actually limit access in any new way, it just requires access to be more deliberate: while the namespace does hide visibility of the API to anyone who doesn't use the namespace, anyone can use the namespace and have access to the API without any additional limits (ie public, internal and protected).
Still, this may be all you are after. Here's an example which uses a public namespace and no packages:
// my_stuff.as
package {
public namespace my_stuff;
}
// Stuff.as
package {
public class Stuff {
my_stuff function doStuff():void { }
}
}
// Main.as
package {
import flash.display.MovieClip;
public class Main extends MovieClip {
public function Main() {
use namespace my_stuff; // you can put this above the class to give the entire class access to the namespace
var stuff:Stuff = new Stuff();
stuff.doStuff();
}
}
}
// OtherStuff.as
package {
public class OtherStuff extends Stuff {
public function OtherStuff() {
this.doStuff(); // not allowed
this.my_stuff::doStuff(); // allowed
// also allowed
use namespace my_stuff;
this.doStuff();
}
}
}
(Note that if your namespace is in a package, ex package stuff { public namespace my_stuff }, you must import the namespace just like a class, for example: import stuff.my_stuff)