Removing an item from the result if it has a particular parameter somewhere in the table - mysql

Question

I've been looking all around stack overflow and can't seem to find a question like this but its probably super simple and has been asked a million times. So I am sorry if my insolence offends you guys.
I want to remove an attribute from the result if it appears anywhere in the table.
Here is an example: I want display every team that does not have a pitcher. This means I don't want to display 'Phillies' with the rest of the results.
Example of table:
Here is the example of the code I have currently have where Players is the table.
SELECT DISTINCT team
FROM Players
WHERE position ='Pitcher' Not IN
(SELECT DISTINCT position
FROM Players)
Thanks for any help you guys can provide!

Answer 1

You can use NOT EXISTS() :
SELECT DISTINCT s.team
FROM Players s
WHERE NOT EXISTS(SELECT 1 FROM Players t
where t.team = s.team
and position = 'Pitcher')
Or with NOT IN:
SELECT DISTINCT t.team
FROM Players t
WHERE t.team NOT IN(SELECT s.team FROM Players s
WHERE s.position = 'Pitcher')
And a solution with a left join:
SELECT distinct t.team
FROM Players t
LEFT OUTER JOIN Players s
ON(t.team = s.team and s.position = 'pitcher')
WHERE s.team is null

Answer 2

Use NOT EXISTS
Query
select distinct team
from players p
where not exists(
select * from players q
where p.team = q.team
and q.position = 'Pitcher'
);

Answer 3

Probably the easiest way to approach this problem is to aggregate players over team:
select team
from players
group by team
having sum(case when position = 'Pitcher' then 1 else 0 end) = 0;
The big advantage is that you'd read the table only once.
Another advantage is that you can easily adjust the HAVING clause to have more elaborate queries, e.g. get all teams that have at least one catcher, two outfielders, and no pitcher.