selecting distinct values where based on multiple arguments - sql-server-2008

Question

I hope i word this out in a way that makes sense;
I'm trying to do a basic select statement for a list of companyIDs. The arguments in questions are options regarding invoices. We have multiple invoice types and they can either be set to be sent by E-mail or be printed. They can be mixed as in some e-mail, some printed, some have nothing selected. There's a total of 9 unique invoice types that i need to check for each company ID.
I'm trying to select distinct company IDs(cmp_id) where the print AND e-mail options are all N or NULL for every single invoicetype. Both options have to be off for both print and e-mail for all invoice types ( In the table i'm selecting from, there's 9 records for the same companyID for each invoicetype)
Some examples ( I'm only using 3 invoice types for the example):
Cmp_id invoiceType print e-mail
company1 credit Y N
company1 supplemental Y N
company1 misc Y Y
company2 supplemental N N
company2 misc N N
The results should be a single column for cmp_id; In the example it would only be company2.

Answer 1

Just perfrom a coditional COUNT to check how many 'Y' you have.
Im assuming print and e-mail only have 3 states, Y, N or NULL
SELECT Cmp_id
FROM YourTable
GROUP BY Cmp_id
HAVING COUNT(CASE WHEN print = 'Y' or e-mail = 'Y' THEN 1 END) = 0
So if count is 0 mean all values are NULL or N
Working DEMO

Answer 2

SELECT DISTINCT Cmp_ID
FROM dbo.table
WHERE
COALESCE([Print], 'N') = 'N'
AND
COALESCE([E-Mail], 'N') = 'N'
Use coalesce to catch the NULLs and Ns.

Answer 3

Would this work:
SELECT DISTINCT Cmp_ID from dbo.table where (Print = 'N') AND (E-Mail = 'N') OR
(Print IS NULL) AND (E-Mail IS NULL)

Answer 4

SELECT T1.Cmp_id, COUNT(*)
FROM dbo.table T1
WHERE
COALESCE([Print], 'N') = 'N'
AND
COALESCE([E-Mail], 'N') = 'N'
GROUP BY T1.Cmp_id
HAVING COUNT(T1.Cmp_id) = (SELECT COUNT(1) FROM dbo.table WHERE Cmp_id = T1.Comp_Id)
Count where both options are either NULL or N and that count = the count of Cmp_Ids in the table.

Answer 5

Assumption:
each [Cmp_ID] has n rows in the table where n is the number of [invoiceTypes]
Sample Data:
CREATE TABLE #temp ([Cmp_id] VARCHAR(20), [invoiceType] VARCHAR(20), [print] VARCHAR(20), [e-mail] VARCHAR(20), )
INSERT INTO #temp
VALUES
('company1','credit','Y','N'),
('company1','supplemental','Y','N'),
('company1','misc','Y','Y'),
('company2','credit','N','N'),
('company2','supplemental','N','N'),
('company2','misc','N','N')
Query using Common table Expression, GROUP BY and HAVING:
We assign the value 1 for every row that has [Print], and [e-mail] as NULL or 'N'. Then we only retrieve the [Cmp_id] of the company that has all its invoiceType with [Print], and [e-mail] as NULL or 'N'.
;WITH CTE AS ( SELECT [Cmp_id],
[NoneSelected] = CASE WHEN ISNULL([print],'N') = 'N' AND ISNULL([e-mail],'N') ='N' THEN 1 ELSE 0 END
FROM #temp )
SELECT Cmp_id
FROM CTE
GROUP BY Cmp_id
HAVING SUM(NoneSelected) = 3 --<-- change this to 9 for 9 invoice types
Results:
Try using Temp tables in response to the comment "We're on compatibility 80, i've tried using CTEs before but they didn't work :S Thanks forthe input though.":
IF OBJECT_ID('tempdb..#temp2') IS NOT NULL
DROP TABLE #temp2;
SELECT [Cmp_id],
[NoneSelected] = CASE WHEN ISNULL([print],'N') = 'N' AND ISNULL([e-mail],'N') ='N' THEN 1 ELSE 0 END INTO #temp2
FROM #temp
SELECT Cmp_id
FROM #temp2
GROUP BY Cmp_id
HAVING SUM(NoneSelected) = 3 --<-- change this to 9 for 9 invoice types