i'm building multi lingual site with English and Arabic
url for English
url for Arabic
I want to switch language from any page exactly to the same page of the other language
so i made code like below.
$route = Yii::$app->controller->route;
$params = $_GET;
array_unshift($params, '/'.$route);
<?php if(Yii::$app->language == 'ar'){ ?>
<?= Html::a('English', [Yii::$app->urlManager->createUrl($params), 'language'=>'en']); ?>
<?php }else{?>
<?= Html::a('Arabic', [Yii::$app->urlManager->createUrl($params), 'language'=>'ar']); } ?>
and my url generating like below
/multi/backend/web/en/multi/backend/web/ar/site/index?val=hii&net=good
English
don't know what is wrong?
I'm using this for language management.
please check my main.php under backend/config
<?php
$params = array_merge(
require(__DIR__ . '/../../common/config/params.php'),
require(__DIR__ . '/../../common/config/params-local.php'),
require(__DIR__ . '/params.php'),
require(__DIR__ . '/params-local.php')
);
return [
'id' => 'app-backend',
'basePath' => dirname(__DIR__),
'controllerNamespace' => 'backend\controllers',
'language' => 'en',
'sourceLanguage' => 'en_UK',
'bootstrap' => ['log'],
'modules' => [],
'components' => [
'user' => [
'identityClass' => 'common\models\User',
'enableAutoLogin' => true,
],
'log' => [
'traceLevel' => YII_DEBUG ? 3 : 0,
'targets' => [
[
'class' => 'yii\log\FileTarget',
'levels' => ['error', 'warning'],
],
],
],
'errorHandler' => [
'errorAction' => 'site/error',
],
'i18n' => [
'translations' => [
'app' => [
'class' => 'yii\i18n\DbMessageSource',
'sourceLanguage' => 'en_UK',
],
],
],
'urlManager' => [
'class' => 'codemix\localeurls\UrlManager',
'languages' => ['en', 'ar'],
'enableDefaultLanguageUrlCode' => false,
'enablePrettyUrl' => true,
'showScriptName' => false,
'rules' => [
],
],
],
'params' => $params,
];
If you are doing it as in your example, you have to think about it on every link you create. This can be automated easily.
URL-Rule
You can solve this with an url-rule in your config file like so:
'<language:[\w]{2,2}>/<controller:\w+>/<action:\w+>'=>'<controller>/<action>',
This will assert the proper routing to your controller and provide you the desired language in the language-variable.
Custom UrlManager
You can extend the UrlManager-class and make sure the current language is always appended to the params:
class MyUrlManager extends \yii\web\UrlManager
{
// ...
/**
* #inheritdoc
*/
public function createUrl($params)
{
if (!isset($params['language'])) {
$params['language'] = Yii::$app->language;
}
return parent::createUrl($params);
}
// ...
}
This will automate the process of adding the language to the links you create.
Custom Application
Now you should also override the Application-class and always set the language to the one provided or choose a default (in this case en):
class MyApplication extends \yii\web\Application
{
// ...
/**
* #inheritdoc
*/
public function init()
{
parent::init();
$lang = Yii::$app->request->get('language', 'en');
Yii::$app->language = $lang;
}
// ...
}
Now your language will always be set to the default value or the one provided viathe query param as specified above.
Final thoughts
This should give you the basic idea on how to solve your problem. Adjust as necessary...especially the last part with the Application-class and how you retrieve the value of the language-var. I hope it helped!
Possible problems with your code and the extension provided
If you read the docs of the extension the urls are generated differently. It tells you to create the urls as follows:
Url::to(['demo/action', 'language'=>'ar'])
You are createing a simple link-tag and overwrite the $params. Try this instead:
echo Html::a('Arabic', Url::to(['site/index', 'language'=>'ar']));
For redirection to the current page just replace the first part with the current route.
after lots of trying ..i found a solution.. now its worked for me.
$route = Yii::$app->controller->route;
if(Yii::$app->language == 'ar'){
$_GET['language'] = 'en';
}else{
$_GET['language'] = 'ar';
}
$params = $_GET;
array_unshift($params, '/'.$route);
<?php if(Yii::$app->language == 'ar'){ ?>
<?= Html::a('English', Yii::$app->urlManager->createUrl($params)); ?>
<?php }else{?>
<?= Html::a('Arabic', Yii::$app->urlManager->createUrl($params)); } ?>
its working for the url like
http://localhost/multi/backend/web/site/index?page=2&per-page=6
and
http://localhost/multi/backend/web/site/index
Related
I have an application built using Yii2 framework, and the app has a form using kartik\form\ActiveForm, this is some line in my _form.php. In that form, user should upload a file, and submit it. After that form successfully saved, the user trying to update the data, but the form didn't show the saved uploaded file. Like this
I need to show the saved file name in that upload field. How do I can do it?
This is my code in _form.php
<?=
$form->field($model, 'buktiNpwp')->widget(FileInput::classname(), [
'options' => [
'multiple' => false,
'accept' => 'img/*', 'doc/*', 'file/*',
'class' => 'optionvalue-img',
'placeholder' => 'maximum size is 2 MB',
],
'pluginOptions' => [
'allowedFileExtensions' => ['jpg', 'gif', 'png', 'jpeg'],
'maxFileSize' => 2048, //membatasi size file upload
'layoutTemplates' => ['footer' => 'Maximum size is 2 MB'],
'browseLabel' => 'Browse (2MB)',
'showPreview' => false,
'showCaption' => true,
'showRemove' => true,
'showUpload' => false,
]
]);
?>
To save images do this in your controller. Hope that will work
$model = new YourModel();
$files = UploadedFile::getInstances($model, 'name');
foreach($files as $file){
$path = 'somepath';
$file->saveAs($path);
}
on update controller you can do
$images_old = \common\models\YourModel::find()->where(['=', 'some_id', $model->id])->all();
if ($images_old) {
foreach ($images_old as $image) {
$baseurl = \Yii::$app->request->BaseUrl;
$image_url = $baseurl . '/uploads/' . $image->thumbnail;
$all_images[] = Html::img("$image_url", ['class' => 'file-preview-image']);
$obj = (object) array('caption' => '', 'url' => $baseurl . '/some-path/delete-image', 'key' => $image->id);
$all_images_preview[] = $obj;
}
}
Now send the $all_images_preview and $all_images to your view file and show it like
$form->field($images, 'name[]')->widget(FileInput::classname(), [
'options' => ['accept' => 'image/*', 'multiple' => true],
'pluginOptions' => [
'previewFileType' => 'image',
'allowedFileExtensions' => ['jpg', 'gif', 'png', 'bmp','jpeg'],
'showUpload' => true,
'initialPreview' => $all_images,
'initialPreviewConfig'=>$all_images_preview,
'overwriteInitial' => false,
'showRemove' => true,
'showPreview' => true,
'uploadUrl' => Url::to(['cases/upload']),
//'onRemove'=>''
],
]);
In your controller class and just actionUpload define upload file directory path, because UploadedFile model save a file in absolute physical path. If you need, can necessary verify post variable use $_FILES. The method saveAs need complete absolute file path and file name. Use slash or backslash according to its SO to best results.
I have used capcha in one of my forms. It always give verification code incorrect error.
Below is my code:
SchoolsController.php
public function actions() {
return [
'captcha' => [
'class' => 'yii\captcha\CaptchaAction',
'fontFile' => '#yii/captcha/SpicyRice.ttf',
'padding' => '0',
]
];
}
Model:
['verifyCode', 'captcha', 'captchaAction' => 'schools/captcha'],
View:
echo $form->field($modelSchoolRequestEarlyAccess, 'verifyCode')->widget(Captcha::className(), [
'options' => [
'placeholder' => 'Enter characters in the image',
'autocomplete' => 'off',
'maxlength' => 20
],
'captchaAction' => 'schools/captcha',
'template' => "<div class='field'><span><strong>*</strong>".Yii::t('frontend/quicksignup','VerifyCodeLabel').":</span></span>\n<div>{image}{input}<i class='refresh-code-icn' id='get-new-code'></i></div></div>"
])->label(false);
I have specified the captcha action as schools/captcha in model as well as view. But it always show verification incorrect.
What am I doing wrong??
You wrote SchoolController.php and your route is to schools. So you probably need to adjust your route to school/captcha
Did you add the rules?
public function rules()
{
$rules = parent::rules();
$rules[] = ['captcha', 'required'];
$rules[] = ['captcha', 'captcha'];
return $rules;
}
Using karktik export menu only. Why do the following exports an excel file with no results found.. I am sure that there are records inside the TblDv model. But in the excel it says no records found.
-in the controller
public function actionExport(){
$provider = new ActiveDataProvider([
'query' => TblDv::find(),
'pagination' => [
'pageSize' => 20,
],
]);
return $this->render('export', [
'dataProvider' => $provider,
]);
}
-the view
<?php
use kartik\export\ExportMenu;
use kartik\grid\GridView;
use kartik\helpers\Html;
$gridColumns = [
'id',
];
echo ExportMenu::widget([
'dataProvider' => $dataProvider,
'columns' => $gridColumns,
'fontAwesome' => true,
]);
?>
I dont know why but it worked when I changed the gridcolumns to this..
$gridColumns=[
['class' => 'yii\grid\SerialColumn'],
'id',
];
I am using kartik yii2 editable extension to edit inline in gridview.
The extension is working fine.
Please refer this screen-shot link [http://awesomescreenshot.com/00753dvb73][1]
In this screen-shot the source field is a dropdown and I want the value of source instead id its id
My View
use kartik\editable\Editable;
[
'attribute'=>'source',
'format'=>'raw',
'value'=> function($data){
//$s = $data->getBacklog_source();//var_dump($s);exit;
return Editable::widget([
'name'=>'source',
'model'=>$data,
'value'=>$data->source,
'header' => 'Source',
'type'=>'primary',
'size'=> 'sm',
'format' => Editable::FORMAT_BUTTON,
'inputType' => Editable::INPUT_DROPDOWN_LIST,
'data'=>$data->getSource(), // any list of values
'options' => ['class'=>'form-control', 'prompt'=>'Select Source'],
'editableValueOptions'=>['class'=>'text-danger'],
'afterInput' => Html::hiddenInput('id',$data->id),
]);
}
],
The relation I made is:
public function getSource()
{
$source = BacklogSource::find()->all();
return ArrayHelper::map($source, 'id', 'Source');
}
public function getBacklog_complexity()
{
return $this->hasOne(BacklogComplexity::className(), [
'id' => 'complexity'
]);
}
Thanks for help in advance
I got the solution something like this:
[
'attribute'=>'status',
'format'=>'raw',
'value'=> function($data){
$s = BacklogStatus::findOne($data->status);
return Editable::widget([
'name'=>'status',
'model'=>$data,
'value'=>$s->Status,
'header' => 'Status',
'type'=>'primary',
'size'=> 'sm',
'format' => Editable::FORMAT_BUTTON,
'inputType' => Editable::INPUT_DROPDOWN_LIST,
'data'=>$data->getStatus(), // any list of values
'options' => ['class'=>'form-control', 'prompt'=>'Select Source'],
'editableValueOptions'=>['class'=>'text-danger'],
'afterInput' => Html::hiddenInput('id',$data->id),
]);
}
],
I have used the gii tool to create crud application. I have 3 tables the tbl_targetcities, lib_cities, and lib_provinces. I was able to connect lib_cities to tbl_targetciteis but not the lib_provinces. And also the sorting of city / Municipality does not work. It seems that it sorts according ti the ID.
tbl_target_cities
lib_cities
lib_provinces
sample View
So far here is my relation in the model.
public function getCityName()
{
return $this->hasOne(LibCities::className(),['city_code'=>'city_code']);
}
in my view file...
<?= GridView::widget([
'dataProvider' => $dataProvider,
'filterModel' => $searchModel,
'columns' => [
['class' => 'yii\grid\SerialColumn'],
[
'attribute'=>'city_code',
'value'=>'cityName.city_name'
],
[
'attribute'=>'prov code',
'value'=>'cityName.city_name'
],
'kc_classification',
'cluster',
'grouping',
'priority',
'launch_year',
['class' => 'yii\grid\ActionColumn'],
],
]); ?>
How to display the prov_name from lib_provinces???
EDIT to answer user2839376 question in the comment box
IN THE SEARCH MODEL CLASS
$query = TblSpBub::find();
$query->joinWith('brgyCode')->joinWith(['cityCode'])->joinWith(['cityCode.provCode']);
$covered= LibAreas::find()->where(['user_id'=>yii::$app->user->identity->id])->all();
$query->all();
$dataProvider = new ActiveDataProvider([
'query' => $query,
'sort'=> ['defaultOrder' => ['id'=>SORT_DESC]],
]);
$dataProvider->sort->attributes['city'] = [
'asc' => ['lib_Cities.city_name' => SORT_ASC],
'desc' => ['lib_Cities.city_name' => SORT_DESC],
];
$dataProvider->sort->attributes['province'] = [
'asc' => ['lib_provinces.prov_name' => SORT_ASC],
'desc' => ['lib_provinces.prov_name' => SORT_DESC],
];
In LibCities model add new relation:
public function getProvince()
{
return $this->hasOne(LibProvince::className(),['prov_code'=>'prov_code']);
}
And change getCityName relation. You should add with() for relation:
public function getCityName()
{
return $this->hasOne(LibCities::className(),['city_code'=>'city_code'])->with(['province']);
}
And in view correct your columnto this:
[
'attribute'=>'prov code',
'value'=>'cityName.province.prov_name'
],
You have to use the function relations() in models.
In tbl_target_cities model:
public function relations()
{
return array(
'city' => array(self::HAS_ONE, 'LibCities', 'city_code'),
);
}
In LibCities model :
public function relations()
{
return array(
'province' => array(self::HAS_ONE, 'LibProvinces', 'prov_code'),
'targets' => array(self::HAS_MANY, 'TargetCity', 'city_code',
);
}
This will allowed you to jump throw the LibCities model,
now you can simply acces to prov name like this :
$model->city->province->prov name;
Note : You need to have the 3 models defined.
EDIT
array(
'name' => 'province name',
'value' => $data->city->province->prov_name;
),
Done it, Heres how.
in addition to the above code (original post)
// in Model I added an additional function
public function getTaskowner()
{
return $this->hasOne(Tasks::className(), ['id' => 'task_id'])
->with(
['location','taskowner']
);
}
and in view i did this
....
'columns' => [
....
[
'class' => 'kartik\grid\DataColumn',
'value'=> 'tasks.location.taskowner.name',
.....
],
.....
and it worked
key points. used an array with the 'with->(..)' to include both then in the view added 'tasks.location.taskowner.name', to join them all