MySQL AVG TIME Duration Calculation and Related Functions? - mysql

Question

table with login data of the website users with two datetime columns. One is logged in time and other one is logged out time.
table has following columns
user_id (user id of the
datetime (start login time DATETIME )
datetime_end (end logout time DATETIME)
From this data I need to generate a report or calculate the following
Daily AVG Login Duration for Users (i.e 01 March 2015 its 21 mins , 03 November 2016 its 25 mins ..etc )
second report is
Current Day (Last 24 hours) based on Hour AVG Login Duration (i.e same as above but only per hour AVG)
is there a way i can achieve this via MySQL query ? (or SQL query)
table is create is
CREATE TABLE IF NOT EXISTS `users_login` (
`login_id` int(11) unsigned NOT NULL,
`user_id` int(11) unsigned NOT NULL DEFAULT '0',
`last_ip` varchar(45) NOT NULL DEFAULT '0.0.0.0',
`server_ip` varchar(225) DEFAULT '0.0.0.0',
`country` varchar(2) NOT NULL DEFAULT '00',
`continent` tinytext,
`datetime` datetime NOT NULL DEFAULT '0000-00-00 00:00:00',
`datetime_end` datetime NOT NULL DEFAULT '0000-00-00 00:00:00'
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

Answer 1

Something like this for the first one
SELECT DATE(datetime),AVG(TIMESTAMPDIFF(MINUTE,datetime,datetime_end)) as DailyAvg
FROM users_login
GROUP BY DATE(datetime)
And for hourly :
SELECT DATE(datetime),extract(hour from datetime) as HourCol,
AVG(TIMESTAMPDIFF(MINUTE,datetime,datetime_end)) as HourlyAvg
FROM users_login
WHERE DATE(datetime) = date(now())
GROUP BY DATE(datetime),extract(hour from datetime)
Of course this queries have a few exceptions.. You didn't explain you entire logic so I assumed you want to group by the hour of the login and the date of the login..