I have table localbanya ,I wanted to do pivoting of its column, Here is my table structure
Billingid prod_id qty
1 11 2
1 22 5
2 11 1
2 22 3
2 33 4
3 11 2
3 22 1
I'm expecting something like this
Billinid 11 22 33 Total
1 2 5 0 2+5+0
2 1 3 4 1+3+4
3 2 1 0 2+1+0
I have tried this but unable to get the desired result
SELECT billingid,GROUP_CONCAT(qty)
FROM localbanya
GROUP BY billingid;
please help, Thanks in advance
Related
Basically I am trying to calculate shots received in golf for various four balls, here is my data:-
DatePlayed PlayerID HCap Groups Hole01 Hole02 Hole03 Shots
----------------------------------------------------------------------
2018-11-10 001 15 2 7 3 6
2018-11-10 004 20 1 7 4 6
2018-11-10 025 20 2 7 4 5
2018-11-10 047 17 1 8 3 6
2018-11-10 048 20 2 8 4 6
2018-11-10 056 17 1 6 3 5
2018-11-10 087 18 1 7 3 5
I want to retrieve the above lines with an additional column which is to be calculated depending on the value in the group column, which is the players (Handicap - (the lowest handicap in the group)) x .75
I can achieve it in a group by but need to aggregate everything, is there a way I can return the value as above?, here is query that returns the value:
SELECT
PlayerID,
MIN(Handicap),
MIN(Hole01) AS Hole01,
MIN(Hole02) AS Hole02,
MIN(Hole03) AS Hole03,
MIN(CourseID) AS CourseID,
Groups,
ROUND(
MIN((Handicap -
(SELECT MIN(Handicap) FROM Results AS t
WHERE DatePlayed='2018-11-10 00:00:00' AND t.Groups=Results.Groups)) *.75))
AS Shots
FROM
Results
WHERE
Results.DatePlayed='2018=11=10 00:00:00'
GROUP BY
DatePlayed, Groups, PlayerID
.
PlayerID MIN(Handicap)Hole01 Hole02 Hole03 CourseID Groups Shots
-----------------------------------------------------------------
4 20 7 4 6 1 1 2
47 17 8 3 6 1 1 0
56 17 6 3 5 1 1 0
87 18 7 3 5 1 1 1
1 15 7 3 6 1 2 0
25 20 7 4 5 1 2 4
48 20 8 4 6 1 2 4
Sorry about any formatting really couldn't see how to get my table in here, any help will be much appreciated, I am using the latest mysql from ubuntu 18.04
Not an answer; too long for a comment...
First off, I happily know nothing about golf, so what follows might not be optimal, but it must, at least, be a step in the right direction...
A normalized schema might look something like this...
rounds
round_id DatePlayed PlayerID HCap Groups
1 2018-11-10 1 15 2
2 2018-11-10 4 20 1
round_detail
round_id hole shots
1 1 7
1 2 3
1 3 6
2 1 7
2 2 4
2 3 6
Hi Guys I have found the solution, basically I need to drop the MIN immediately after the ROUND of the equation and therefore it does not need a Group By.
SELECT
PlayerID,
Handicap,
Hole01,
Hole02,
Hole03,
CourseID,
Groups,
ROUND((Handicap -
(SELECT MIN(Handicap) FROM Results AS t
WHERE DatePlayed='2018-11-10 00:00:00'
AND t.Groups=Results.Groups))
*.75) AS Shots
FROM
Results
WHERE
Results.DatePlayed='2018=11=10 00:00:00'
Colummn1 Column2
----------------------------
5 24
5 20
5 13
----------------------------
2 3
----------------------------
3 25
----------------------------
1 4
----------------------------
2 6
2 42
----------------------------
5 23
5 10
----------------------------
Output should be
5 57
2 3
3 25
1 4
2 48
5 33
I have two columns. I want to sum the elements of second column when the values of column 1 are same and consecutive. ie I dont want the grouped sum to contain sum of both segments of 5.
I know how to use Group by clause bit that would aggregate the two segments. Please help me write SQL query for this .
Dear developers and programmers,
I have a tabel with SHOP_ID, PROD_ID, ipadres and some more tables, but these are where its all about...
Looks like this:
id ip number timestamp shop_id prod_id
--------------------------------------------------
42 81.69.205.25 1319488326 2 3
43 81.205.141.48 1319492649 2 3
44 193.58.10.10 1319520579 14 17
45 84.28.22.226 1319529529 11 19
46 88.15.81.188 1319543745 2 1
47 178.17.241.191 1319563031 14 7
48 87.28.107.171 1319563038 2 6
49 80.156.47.144 1319572818 14 7
50 82.76.241.175 1319577506 11 1
51 82.76.241.175 1319577584 13 1
52 82.76.241.175 1319577785 14 1
53 82.76.241.175 1319577860 4 1
54 62.94.133.153 1319579221 14 1
55 62.94.133.153 1319579281 2 3
56 77.70.175.221 1319617238 11 1
57 77.70.175.221 1319621845 13 1
58 77.70.175.221 1319621848 2 1
59 77.70.175.221 1319621850 11 1
.... more
--------------------------------------------------------
Is there a way to see for each prod_id how many ip numbers there excist for each shop id?
output example
1 2 3 4 5
---------------------------------------------
1 18 5 51 8 4
2 58 5 45 3 4
3 7 6 31 9 2
where horizontal is the prod_id and vertical is the shop_id
I've don this already:
select
shop_id,
count(distinct(ipadres)) amount
from table
GROUP BY shop_id
order by amount desc
but this wil give me only the result of all prod_id's combined.
I would like to have the prod_id's seperate in columns.
I hope there is a solution!
Kind Regards
Try this
select `prod_id`,shop_id,
count(distinct(ipadres)) amount
from table
GROUP BY shop_id,prod_id
order by amount desc
tables i am using
product_parameter
id productid parameterid value
1 1 1 10
2 2 2 11
3 1 2 34
4 2 4 44
5 3 2 55
6 3 3 43
7 4 1 33
8 1 3 33
9 1 4 24
and so on i want to display in form
parameterid 1 2 3 4. . .
productid
1 43 34 33 24
2 null 11 null 44
3
4
.
.
and so on rows and columns are not fixed
tables i am using
product_parameter
Sorry wanted to correct the output format i needed after query
id productid parameterid value
1 1 1 10
2 2 2 11
3 1 2 34
4 2 4 44
5 3 2 55
6 3 3 43
7 4 1 33
8 1 3 33
9 1 4 24
and so on i want to display in form
parameterid 1 2 3 4. . .
productid
1 43 34 33 24
2 null 11 null 44
3
4
.
.
and so on... rows and columns values are not fixed
It would be much easier to create 2D array in application code.
In SQL you have to add a join for each column.
I have the following data:
id1，id2
1 3
1 8
1 10
1 11
2 3
2 10
2 11
3 2
3 18
3 20
4 3
4 8
5 3
5 10
5 11
5 40
5 45
5 50
6 1
6 59
6 70
I won't get all id1 with id2 ＝ 3，10，11.
For example, id1=4 only with id2=3, should not return.
The results should be
id1
1
2
5
SELECT distinct(ID1) FROM TBTEST WHERE ID2 IN(3,10,11)
SQL code
SELECT ID1,COUNT(ID2) FROM TBTEST
WHERE ID2 IN(3,10,11)
GROUP BY ID1
HAVING COUNT(ID2)=3
Is this what you need?