Sequel to get select EVERY input - mysql

Question

I have created three tables
CREATE TABLE guest(
name varchar(100),
ranking int,
PRIMARY KEY (name)
);
CREATE TABLE room(
roomname varchar(100),
wallcolor varchar(100),
rating int,
PRIMARY KEY(roomnane)
);
CREATE TABLE reservation(
name varchar(100),
roomname varchar(100),
day varchar(100),
moveinday int,
moveoutday int,
PRIMARY KEY(roomname, day, start, finish),
FOREIGN KEY(roomname) REFERENCES room(roomname),
FOREIGN KEY(name) REFERENCES guest(name)
);
I am trying to write a query to find the guests who reserved EVERY "LakeView" room
I tried the following
SELECT g.name
FROM guest g, reservation r, room rr
WHERE rr.name = g.name
AND rr.roomname = "LakeView"
GROUP BY g.name
This does not seem to list out every room. How could I gix this?
Input:
insert into guest values ('Andrew', 1);
insert into guest values ('Jack', 4);
insert into guest values ('Jake', 4);
insert into room values ('LakeView', 'white', 10);
insert into room values ('BayView', 'blue', 4);
insert into reservation values ('Andrew', 'LakeView', 'Friday', 10,15);
insert into reservation values ('Jake', 'LakeView', 'Monday', 10,16);
insert into reservation values ('Jack', ' BayView', 'Tuesday', 11,15);
Desired output is
Andrew
Jake

Answer 1

try this:
Solution 1:
SELECT
guest.name
FROM guest INNER JOIN
reservation ON reservation.name = guest.name
INNER JOIN room ON reservation.roomname = room.roomname
WHERE reservation.roomname = "LakeView"
GROUP BY guest.name
Here I've highlighted your mistakes:
You tried to match rr.name with g.name. That means you are
matching roomname with guest name which you didn't want (so far I
guess).
Another mistake is you are only checking "LakeView" only in room
table entries. So other guests who haven't reserved LakeView room
might appear in the final result set. You also need to filter those
records from reservation table which have LakeView roomname.
Here's your query modified based on the above observations:
Solution 2:
SELECT g.name
FROM guest g, reservation r, room rr
WHERE r.name = g.name
AND rr.roomname = "LakeView"
AND r.roomname = "LakeView"
GROUP BY g.name;
N:B: Solution 1 is encouraged to use. Try to avoid implicit joins which are stated in solution 2.
I personally think the INNER JOIN is better, because it is more
readable. It shows better the relations between the table. You got
those relations in the join, and you do the filtering in the WHERE
clause. This separation makes the query more readable.
Have a look at this post.

Answer 2

if you using php-mysql then it will be help
$qry=mysql_query("select name from reservation where roomname='LakeView'");
while($result=mysql_fetch_array($qry)
{
echo $result['name'];
}

Answer 3

I'm assuming that the 'name' column in the reservation table is the name of the guest or guests. If this is true it sounds like you only need the reservation table for the purposes of this query, but if you wanted to combine them all anyway:
select
rv.name as Guest
from room as r
left join reservation as rv on rv.roomname = r.roomname
left join guest as g on g.name = rv.name
where
rv.roomname = 'LakeView'