According to this, there are only two MySQL version
Community
Enterprise
However the version that I installed from my CentOS repo, It is "Source Distribution"
mysql> show variables like '%version%';
+-------------------------+---------------------+
| Variable_name | Value |
+-------------------------+---------------------+
| protocol_version | 10 |
| version | 5.1.73 |
| version_comment | Source distribution |
| version_compile_machine | x86_64 |
| version_compile_os | redhat-linux-gnu |
+-------------------------+---------------------+
5 rows in set (0.01 sec)
I get that as I installed it via repo, it is stating "Source Distribution", but where does it fall in legal terms ?
Sorry for trouble guys. I found my answer.
After googling, found out it is just like community version, the only difference is, it is compiled and maintained by repo.
Related
1) I originally installed the latest version of mysql (5.7.11) using homebrew.
2) I then also installed mysql56 using homebrew
3) I then uninstalled the original mysql homebrew install
brew search mysql currently returns a check only next to 56=>
automysqlbackup
homebrew/versions/mysql55
mysql
mysql-cluster
homebrew/versions/mysql51
homebrew/versions/mysql56 ✔
4) If I start a mysql console I get the following:
Welcome to the MySQL monitor. Commands end with ; or \g.
Your MySQL connection id is 33
Server version: 5.7.11 Homebrew
5) Running mysql> SHOW VARIABLES LIKE "%version%"; returns
+-------------------------+-----------------------+
| Variable_name | Value |
+-------------------------+-----------------------+
| innodb_version | 5.7.11 |
| protocol_version | 10 |
| slave_type_conversions | |
| tls_version | TLSv1,TLSv1.1,TLSv1.2 |
| version | 5.7.11 |
| version_comment | Homebrew |
| version_compile_machine | x86_64 |
| version_compile_os | osx10.11 |
+-------------------------+-----------------------+
8 rows in set (0.15 sec)
6) mysql> SELECT VERSION();
+-----------+
| VERSION() |
+-----------+
| 5.7.11 |
+-----------+
7) However, mysql --version returns
mysql Ver 14.14 Distrib 5.6.29, for osx10.11 (x86_64) using EditLine wrapper
I believe I am having some mysql compatibility issues and need to be running 5.6.29, is there a way to verify that I am running 5.6?
Running ps auxww | grep mysql should give you the full path to the mysql you're actually running. Then you can do ls -l /usr/local/path/to/mysql which should show you the link into the directory with the version you're running. Should look something like ../Cellar/mysql/version/myversion.
Edit: This answer might be helpful too.
I've stuck on this problem for a while.
I need to schedule a job for my query daily so I have to set global event_scheduler = ON
and I got this message ..
1577 - Cannot proceed because system tables used by Event Scheduler were found damaged at server start
some guys told me i have to restart db and do it again but it's not work.
I was going to my.cnf and type event_scheduler = ON in [mysqld] section and restart again
and it's still DISABLED.
someone told me it's a bug of version 5.5 but i'm using 5.6 .....
MariaDB [(none)]> SHOW VARIABLES LIKE "%version%";
+-------------------------+---------------------+
| Variable_name | Value |
+-------------------------+---------------------+
| innodb_version | 5.6.22-72.0 |
| protocol_version | 10 |
| slave_type_conversions | |
| version | 10.0.17-MariaDB |
| version_comment | Source distribution |
| version_compile_machine | i386 |
| version_compile_os | osx10.6 |
| version_malloc_library | system |
+-------------------------+---------------------+
so I have no any idea what should i do with this thing :(
I also can't access the EVENT table in information_schema db with the same error.
if anyone can solve my problem. i'll owe you guys my entire life.
** i sincerely apologise if it's a stupid question **
Ps. I use XAMPP.
It is generally a good idea to research error codes and messages:
https://serverfault.com/questions/385015/mysql-damaged-system-tables
https://serverfault.com/questions/562282/mysqldump-error-1557-corrupt-event-table
https://serverfault.com/questions/100685/cannot-proceed-because-system-tables-used-by-event-scheduler-were-found-damaged
https://bugs.mysql.com/bug.php?id=70975
I have run this sql in windows & Linux version of mysql, and get the different result:
select (((((237803.3300+1659482.4400)/2.00)/1182208.5700)*30.00*6)+
(0.50*`(((((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+
((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6))
-(((((360.00*((1527268.4000-1182208.5700)-((2587.0000-((5354427.3100*0.0400*6)/12.00))
+99354.4800+10550.5600)))/((((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+
((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6))*0.5))-(0.50*((2587.0000-
((5354427.3100*0.0400*6)/12.00))+99354.4800+10550.5600)))*
(((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+
((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6)))/1182208.5700))-
((((237803.3300+1659482.4400)/2.00)/1182208.5700)*30.00*6)))) AS YF`
Windows version of mysql result: 105.93639914104807268662689486
Linux version of mysql result: 144.43789669025999363208811782
And I've been check this expression in some of other platform like java, excel, get the approximately value about: 105.93....., so I thought about that the calculation on linux mysql is incorrect or some of mysql variable set incorrect? Can anybody tell me why?
my linux version of mysql (At cloud server):
mysql>SHOW VARIABLES LIKE "%version%"
+-------------------------+---------------------------------+
| Variable_name | Value |
+-------------------------+---------------------------------+
| innodb_version | 1.1.8-20.1 |
| protocol_version | 10 |
| slave_type_conversions | |
| version | 5.5.18.1-Alibaba-rds-201406-log |
| version_comment | Source distribution |
| version_compile_machine | x86_64 |
| version_compile_os | Linux |
+-------------------------+---------------------------------+
I did not look closely, but you are not selecting FROM anywhere
try this:
select (((((237803.3300+1659482.4400)/2.00)/1182208.5700)*30.00*6)+(0.50*(((((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6))-(((((360.00*((1527268.4000-1182208.5700)-((2587.0000-((5354427.3100*0.0400*6)/12.00))+99354.4800+10550.5600)))/((((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6))*0.5))-(0.50*((2587.0000-((5354427.3100*0.0400*6)/12.00))+99354.4800+10550.5600)))*(((((1159248.2000+687984.6000)/2.00)/1527268.4000)*30.00*6)+((((457300.0000+1707654.0300)/2.00)/1182208.5700)*30.00*6)))/1182208.5700))-((((237803.3300+1659482.4400)/2.00)/1182208.5700)*30.00*6)))) AS YF
FROM DUAL
Answer: 105.936399141048
Fiddle: http://sqlfiddle.com/#!2/a2581/32503/0
I am trying to run a query like this:
SELECT lower (A.label) FROM addresses A;
and what I get in return is
ERROR 1305 (42000): FUNCTION db.lower does not exist
I am using
+-------------------------+-------------------------------+
| Variable_name | Value |
+-------------------------+-------------------------------+
| protocol_version | 10 |
| version | 5.0.92-community |
| version_comment | MySQL Community Edition (GPL) |
| version_compile_machine | x86_64 |
| version_compile_os | unknown-linux-gnu |
+-------------------------+-------------------------------+
Never had this issue before on any other system but this one... I was under the impression that lower is an internal function and is always there. What can be wrong?
Delete the space between lower and (
SELECT lower(A.label) FROM addresses A;
lower (A.label)
should be
lower(A.label)
MySQL doesn't like spaces between function name and argument: you are implying a column alias
(A.label) for a column lower otherwise
lower `(A.label)`
lower AS `(A.label)`
Is there any way to make MySQL tell you what version of the InnoDB plugin it's running? I know you can look at the documentation, but I'm trying to verify a potential bug if the plugin jives with the mysql version installed.
mysql> show variables like '%version%';
+-------------------------+------------------------------+
| Variable_name | Value |
+-------------------------+------------------------------+
| protocol_version | 10 |
| version | 5.1.50-community-log |
| version_comment | MySQL Community Server (GPL) |
| version_compile_machine | x86_64 |
| version_compile_os | unknown-linux-gnu |
+-------------------------+------------------------------+
I found the answer, so I'll pass this along.
1.You must be running the InnoDB plugin instead of the built-in mysql innodb. To do this, you must make these config changes to your my.cnf:
ignore_builtin_innodb
plugin-load = innodb=ha_innodb_plugin.so;innodb_trx=ha_innodb_plugin.so;innodb_locks=ha_innodb_plugin.so;innodb_lock_waits=ha_innodb_plugin.so;innodb_cmp=ha_innodb_plugin.so;innodb_cmp_reset=ha_innodb_plugin.so;innodb_cmpmem=ha_innodb_plugin.so;innodb_cmpmem_reset=ha_innodb_plugin.so
innodb_fast_shutdown = 0
Note: Load individual plugins, but make sure no spaces between the ";". Also innodb_fast_shutdown is optional, but recommended.
2.You must restart mysqld to take the new config changes.
3.Using your SQL interface, execute: "SELECT ##innodb_version;"
mysql> SELECT ##innodb_version;
+------------------+
| ##innodb_version |
+------------------+
| 1.0.11 |
+------------------+
1 row in set (0.00 sec)
Reference URLs:
Getting the version:
http://dev.mysql.com/doc/refman/5.1/en/innodb-parameters.html#sysvar_innodb_version
Using the plugin engine
http://dev.mysql.com/doc/refman/5.1/en/replacing-builtin-innodb.html
When you have installed InnoDB Plugin you can check out the version by performing the following commands
SELECT * FROM information_schema.plugins;
SELECT ##innodb_version;