I need to find in a row of my table all the values that are repetitive, e.g. 123text123text (there might be a line break between the repetitive sub-strings.
So I need an SQL query that tells PhpMyAdmin to return all instances were sub-string first half of value == sub-string second half of value.
--UPDATE I don't think i need regex for my query it just needs to select values from the row were sub-string from begin until half of string equals sub-string from half of string until end
Thanks!
ok it was as simple as
SELECT * FROM table_name WHERE substring(column, (length(column)/2)+1) like substring(column, 1, (length(column)/2)-1)
Related
I suck at REGEX, but I need to pull all the records from a table column that stats with AST, and the rest only contains numbers after. I am assuming this can be done with just REGEX and not LIKE but I'm not sure.
For instance AST000001
and not AST99XXH011
SELECT * FROM table WHERE column LIKE 'AST%' AND column REGEXP '[0-9]$'
You can use REGEXP/RLIKE on the whole column value (using start-of-string (^) and end-of-string ($) anchors to ensure you match the entire column):
SELECT *
FROM `table`
WHERE `column` REGEXP '^AST[0-9]+$'
Demo on dbfiddle
I'm looking for a way to get a row from a tabla which have a column data type of string. This column could have values as follows:
1. "1,2,3,4,5"
2. "X,3,4,5,8"
3. "X,X,3,4,5"
4. "1,2,3,4,X"
5. "1,3,4,X,X"
and so on, ...
I want to accomplish a search for a String like
"1,2,3,4,5"
I tried with a
SELECT *
FROM *table_name*
WHERE *column* LIKE '%1,2,3,4,5%';
hoping this query could retrieve at least three results (in the example, first, third and forth strings) but it returns only the first string, because of course it's the only string that matches with the specified criteria. Anyone knows a way for me to accomplish this achievement?
I assume the X listed is literally the X character - if so, try
SELECT * FROM table WHERE '1,2,3,4,5' REGEXP REPLACE(column, 'X', '.')
I have a quite big table in mysql and I need to change all the records related to this column.
records are like this :
/name/nm0000209/?ref_=ttfc_fc_cl_t1,
/name/nm0000151/?ref_=ttfc_fc_cl_t2,
...,
/name/nm0104594/?ref_=ttfc_fc_cl_t10
what I want is to keep only the string in the middle which is nm0000209, nm0000151,.... I know how to delete specific characters from the right or left of the words by REPLACE or Trim , .., but my problem is that in this case the number of characters in the third part of string are not equal (as you see when it reaches to 10, I have to delete 21 characters from the end instead of 20 characters and since this table contains lots of records I dont know how to do it.
I reaaly appreciate if someone could helop me,
thanks
I want is to keep only the string in the middle which is nm0000209, nm0000151...
You can use 'SUBSTRING_INDEX' on the column to crop part of the column value.
Following example assumes that the said column will have 'name/' as starting pattern.
Example:
update table_name
set column_name = substring_index(
substring_index( column_name, 'name/', -1 )
, '/', 1 );
The same can be used for updating with the same value.
Demo # MySQL Fiddle
One approach would be to use MYSQL's SUBSTRING_INDEX function. It would let you get whatever's after the last slash. Or after the second to last.
For your particular case
select
SUBSTRING_INDEX(SUBSTRING_INDEX(thefield,'/',-2 ),'/', 1)
from supertext
would yield the desired result
EDIT: for update purposes
UPDATE thetable
SET thefield=SUBSTRING_INDEX(SUBSTRING_INDEX(thefield,'/',-2 ),'/', 1)
I want to truncate the first letter of a string which have size more than 11 character.
I know I can use substring function like
SELECT SUBSTRING(name, 1, 10) from table1;
which will truncate and return me the first 10 letter. what should I do if I want to remove the character from the beginning if the string is greater than 10 character.
abcdefghijklmn ==> efghijklmn
How about RIGHT():
SELECT RIGHT(name, 10)
FROM table1;
Demo: SQL Fiddle
RIGHT() returns a specified number of characters from the right side of a string.
If you want to apply any function only in certain situations, a CASE statement can be used.
create table table1(name char(25));
insert into table1 values('abcdefghijklmn');
select right(name,10) from table1;
RIGHT() is the function you need to use.
Part of my SQL query includes
"select * from table where Name between 'a' and 'variable'";
I pass the variable to the query and it's a single letter a-z. If I pass it 'k', my query doesn't return names which start with 'k'. This makes sense, because 'kane' comes after 'k'. How do I get around this? I tried 'between 'a' and 'variable%' but that didn't work.
You should concat the letter 'z' to your variable as many times as necessary to reach the length of the column Name.
select * from table where Name between 'a' and RPAD('variable',len,'z');
len should be the maximun length of the column Name.