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Can I apply multiple background colors with CSS3?
(6 answers)
Closed 7 years ago.
How can I give a single div multiple background colors or images in CSS? For example, I want the top part to be red, then the middle to be blue and the bottom to be green.
A single linear-gradient as a background is enough
background: linear-gradient(to bottom,
red 0, red 33.33%,
blue 0, blue 66.66%,
green 0, green 100%
);
Example | Browser support
use gradients in css3.
YourDIVID {
background: red; /* For browsers that do not support gradients */
background: -webkit-linear-gradient(red, yellow, green); /* For Safari 5.1 to 6.0 */
background: -o-linear-gradient(red, yellow, green); /* For Opera 11.1 to 12.0 */
background: -moz-linear-gradient(red, yellow, green); /* For Firefox 3.6 to 15 */
background: linear-gradient(red, yellow, green); /* Standard syntax */
}
TOP, BOTTOM, CENTER multiple color Tutorial For Sigle Line
#multiple {
width: 700px;
height: 500px;
background:linear-gradient(red, yellow, green, blue, purple, orange);
}
Use :before and :after pseudo element rules to have three different background layers (color and images) on a single element.
Note: This solution requires the contained elements to be wrapped to stay above the backgrounds. Otherwise links may not be clickable, text not selectable, etc..
Run the code snippet for a working example.
.layered-backgrounds {
background-color: #C63;
background-image: url(https://upload.wikimedia.org/wikipedia/commons/4/47/PNG_transparency_demonstration_1.png);
background-repeat: no-repeat;
background-position: center center;
background-size: cover;
position: relative;
height: 400px;
z-index: 1;
}
.layered-backgrounds:before {
position: absolute;
content: " ";
top: 0;
height: 120px;
width: 100%;
background: #39C;
z-index: 2;
opacity: 0.8;
}
.layered-backgrounds:after {
position: absolute;
content: " ";
bottom: 0;
height: 120px;
width: 100%;
background: #9C3;
z-index: 3;
opacity: 0.8;
}
.layered-backgrounds .content {
position: relative;
z-index: 4;
}
<div class="layered-backgrounds">
<div class="content">
Clickable and selectable contents.
</div>
</div>
Related
body {
height:100%;
background: linear-gradient(top, #d808a4 50%, black 50%);
background: linear-gradient(top, #d808a4 50%,black 50%);
background: linear-gradient(to bottom, #d808a4 50%,black 50%);
height: 229vh;
}
I want to horizontally split the background into two colors where one is black color. And I want the other one to be a gradient that goes from pink to purple, I have manage to split into purple and black, but i want a purple pink grandient, can someone help me?
#top-half {
position: absolute;
left: 0;
width: 100%;
height: 50%;
background-color: black;
}
#bottom-half {
position: absolute;
left: 0;
top: 50%;
width: 100%;
height: 50%;
background: linear-gradient(90deg, rgba(255,0,209,1) 0%, rgba(151,0,255,1) 100%);
}
<div id="bottom-half"></div>
<div id="top-half"></div>
2 divs for each half
position: absolute and left: 0 and top: 50% sets the position
width: 100% sets it to screen width
height: 50% sets the height for each one to half the screen width
background-color: black obviously sets the background color to black, and background: linear-gradient(90deg, rgba(255,0,209,1) 0%, rgba(151,0,255,1) 100%) sets the background to a gradient (you can generate nice CSS gradients at https://cssgradient.io/ )
You cannot have multiple background, the newer one will overwrite the old ones. What you can do is to have multiple gradients in a single background such as (try scrolling):
body {
height: 200vh;
background:
linear-gradient(to bottom, transparent 50%, black 50%),
linear-gradient(100deg, #8a07ff, #f500d7);
}
You can do this with just one background setting.
This snippet separates out each of the CSS background settings to make it clearer what is going on.
The whole element gets a black background, then a background-image which is a linear-gradient is defined. This will sit on top of the black background-color. It is given a size and a position and is made not to repeat.
Obviously change the colors and the size to what you want.
.bg {
width: 100vw;
height: 100vh;
background-color: black;
background-image: linear-gradient(to right, purple, magenta);
background-size: 80% 50%;
background-position: center top;
background-repeat: no-repeat;
}
<div class="bg"></div>
Does anyone have an idea how to fill the middle with the same color as the background image?
#first-illustration {
padding-top: 15%;
padding-bottom: 10%;
background:url("../images/bg-section-top-desktop-1.svg") top, url("../images/bg-section-bottom-desktop-1.svg") bottom;
background-repeat: no-repeat;
background-size: contain;
}
This is how it appears
You could add a background gradient with hard transitions:
background: linear-gradient(0deg, transparent 0%, transparent 15%, #f6fbff 15%, #f6fbff 90%, transparent 90%), url(..), url(..);
But that won't be responsive out of the box, involves tweaking and possibly media queries.
A better way IMHO is to move the background images to the before and after pseudo elements, and set their aspect-ratio to that of the images:
.illustration {
background: #f6fbff;
/* ... */
}
.illustration::before, .illustration::after {
display: block;
content: '';
background: no-repeat 0 0 / cover;
}
.illustration::before {
background-image: url("../images/bg-section-top-desktop-1.svg");
aspect-ratio: 10 / 1;
}
.illustration::after {
background-image: url("../images/bg-section-bottom-desktop-1.svg");
aspect-ratio: 12 / 2;
}
I would like to know if it is possible to create a background like this in CSS3.
The background should span a header div and the gradient should go from white to black independent of the screen width (always white on the left side and black on the right side).
Reason for not using the image is that it takes longer to load and that I can't get it to resize it's width when making the browser smaller than 1920px (the width of the image).
Have tried linear-gradient but I can't get it to work...
Regards,
Jens
If you also want the black bar at the top you should give dimensions to the background, stop the repeating and also position it where you want (treat it like a normal background image)
div {
background-color: black;
background-image: linear-gradient(to right, white, black);
background-repeat:no-repeat;
background-size:100% 20px; /*full width, 20px height*/
background-position:0 100%; /*gradient at bottom*/
/*just to give size to demo*/
min-height:50px;
}
<div></div>
Here's some CSS for you:
#grad {
background: gray; /* For browsers that do not support gradients */
background: -webkit-linear-gradient(left, white , black); /* For Safari 5.1 to 6.0 */
background: -o-linear-gradient(right, white, black); /* For Opera 11.1 to 12.0 */
background: -moz-linear-gradient(right, white, black); /* For Firefox 3.6 to 15 */
background: linear-gradient(to right, white , black); /* Standard syntax */
}
Source: http://www.w3schools.com/css/css3_gradients.asp
I know the OP's question was answered. But I'll comment here anyway to deliver some more information to create a really more "complex" background.
First is you really can create multiple backgrounds stack on each other:
https://developer.mozilla.org/en-US/docs/Web/CSS/CSS_Backgrounds_and_Borders/Using_multiple_backgrounds
Second is you can determine position, size, etc,... of a background-image. And here the concise syntax for it: https://www.w3schools.com/cssref/css3_pr_background.asp.
Why background-image? A basic (and important) theory of background in CSS is: A background of an element can have only 1 background-color, and multiple background-images sit on top of it (even if the background-color is declared after background-image, background-color will be still placed below the background-images), and you can resize, reposition those background-images. And an important thing is linear-gradient is count as a background-image, not background-color. The 2 links above do give all detailed information about it.
Here is a quick demo on a "more complex" background from the OP question using only 1 div HTML:
div {
background:
linear-gradient(to right, white, black) 0 100%/100% 20px no-repeat,
linear-gradient(to left, white, black) 0 0/100% 20px no-repeat,
black;
height: 100px;
}
<div></div>
I'm inspired writing this long comment because from a tutorial
https://levelup.gitconnected.com/how-to-implement-netflix-slider-with-react-and-hooks-bdb9b99d1ce4, there's a section from it there're verbose hacks in HTML and CSS to achieve what I'm able to do within just a single line of CSS background, and I think it's cool to share, isn't it?
/* simpler */
.box {
width: 100%;
height: 100px;
background: linear-gradient(to right,black 0%,black 30%,transparent 75%,transparent 100%), green;
}
/* more complex */
.content {
height: 100px;
position: relative;
}
.background {
display: flex;
height: 100%;
}
.left {
background: black;
width: 30%;
position: relative;
}
.left:before {
content: '';
position: absolute;
background-image: linear-gradient(to right,#000,transparent);
top: 0;
bottom: 0;
left: 100%;
width: 275px;
}
.right {
background: green;
width: 70%;
}
.content-container {
color: white;
position: absolute;
top: 0;
left: 0;
right: 0;
bottom: 0;
padding: 30px
}
<!-- simpler -->
<div class="box">
<div class="content-container">content here...</div>
</div>
<hr>
<!-- more complex -->
<div class="content">
<div class="background">
<div class="left">left</div>
<div class="right">right</div>
</div>
<div class="content-container">content here...</div>
</div>
I have a page on my site that has a gray background color that I am trying to add gradient to it in a different way than just a left to right. My page has an outer div that takes up 100% of the page's width. I then have an inner div that takes up 80% of the page's with, but auto aligned. I was wondering how, if I can, do a full cycle of my gradient within each side (left & right) of the outer div, the 10% part that shows before the inner div starts.
So say an A equals 10%, and everytime I put two colors together, that is the gradient taking place within that 10%. I want to do this...
#181818, #282828 AAAAAAAA #282828, #181818
How can I do this?
HTML
<div class="graypage">
<div class="homeimg">
gfdsgsg
</div>
</div>
CSS
.graypage, .whitepage { margin: 0 auto; }
/*------Page Wraps--------*/
.graypage {
width: 100%;
left: 0;
right: 0;
min-height: 100%;
background: -webkit-linear-gradient(left, #282828, #181818); /* For Safari 5.1 to 6.0 */
background: -o-linear-gradient(right, #282828, #181818); /* For Opera 11.1 to 12.0 */
background: -moz-linear-gradient(right, #282828, #181818); /* For Firefox 3.6 to 15 */
background: linear-gradient(to right, #282828, #181818); /* Standard syntax */
}
.homeimg {
background-image: url("/images/bright_lights_small.jpg");
width: 80%;
background-size: cover;
background-position: center;
height: 100%;
position: absolute;
margin-right: 10%;
margin-left: 10%;
}
As I understand it, you'd like two bars - one on the left of the outerDiv and the other on the right. Each of these bars you'd like to be 10% of the page width. You'd also like each bar to cycle through the colours #181818, #282828, #aaaaaa, #282828, #181818.
I'd just use a linear-gradient with 12 colour-stops. Something like this:
#outerDiv
{
background: linear-gradient(to right,
#181818 0%,#282828 2%,#aaaaaa 4%,#aaaaaa 6%,#282828 8%,#181818 10%,
#181818 90%,#282828 92%,#aaaaaa 94%,#aaaaaa 96%,#282828 98%,#181818 100%); /* W3C */
width: 100%;
}
Credit: http://www.colorzilla.com/gradient-editor/
Here it's applied to the outer div and a solid colour is applied to the (80% as wide) inner div.
EDIT: Here's the (now updated) html and css used.
<style>
body
{
margin: 0;
padding: 0;
}
#outerDiv
{
background: linear-gradient(to right,
#181818 0%,#282828 10%,
#282828 90%,#181818 100%); /* W3C */
width: 100%;
}
#innerDiv
{
width: 80%;
margin: auto;
background-color: #dddddd;
}
</style>
</head>
<body>
<div id='outerDiv'>
<div id='innerDiv'>
<button id='goBtn'>Change the text</button>
<div class="menu-wrapper">
<ul>
<li>WORD1</li>
<li>WORD2</li>
<li>WORD3</li>
<li>WORD4</li>
</ul>
</div>
</div>
</div>
</body>
This code produces the following result:
Bacically, you have 2 posibilities here. You can set a repeating gradient
div {
width: 500px;
height: 100px;
background: repeating-linear-gradient(to right, yellow 0%, green 10%);
}
<div></div>
And you can play with the background-size
div {
width: 500px;
height: 100px;
background: linear-gradient(to right, yellow, green);
background-size: 10% 100%;
}
<div></div>
So I've been at it for a while trying to achieve this one shape with CSS with no good solutions. I need this to be an image because this div may resize and I want it to stay intact. I've also attempted to create an SVG which did not work out very well, I've seen some people work with gradient to make shapes but I'm not able to find any good guide to point me in the right direction. Any help is appreciated :)
Using gradients with angles is not fit for your case because (as already pointed out by King King in comments) as the width the increases, the angle of the gradient (or) the color stop percentages need to be modified to maintain the shape. That is very tricky and so this method can be employed only when the shape has fixed dimensions.
However gradients can still be used with the to [side] [side] syntax because gradients defined using this syntax can adapt to variations in container sizes. In this method no pseudo-elements are used.
$(document).ready(function() {
$('#increase').on('click', function() {
$('.gradient').css('width', '300px').css('height', '500px');
})
})
div {
display: inline-block;
vertical-align: top;
height: 300px;
width: 100px;
margin: 10px;
color: beige;
transition: all 1s;
}
.gradient {
padding: 10px;
background: linear-gradient(to top right, transparent 50%, tomato 50%) no-repeat, linear-gradient(to top right, transparent 0.1%, tomato 0.1%) no-repeat;
background-size: 100% 100px, 100% 100%;
background-position: 0% 100%, 0% -100px;
}
/* Just for demo */
body {
background: -webkit-radial-gradient(50% 50%, circle, aliceblue, steelblue);
background: radial-gradient(circle at 50% 50%, aliceblue, steelblue);
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/prefixfree/1.0.7/prefixfree.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="gradient">Some content</div>
<br>
<br>
<button id="increase">Increase Width & Height</button>
Note that it is better to make sure that the text doesn't flow into the slanted section of the shape because wrapping the text around to fit within the shape is not straight-forward.
I have attempted to make that in css as per ur image. http://jsfiddle.net/3zkme/- See if this could help. Thanks.
HTML
<div style="margin:30px">
<div class="trapezoid">
</div>
</div>
CSS
.trapezoid{
top: 150px;
vertical-align: middle;
border-bottom: 120px solid red;
border-left: 200px solid transparent;
border-top-left-radius:0px;
height: 0;
width: 150px;
transform:rotate(270deg);
-ms-transform:rotate(270deg); /* IE 9 */
-webkit-transform:rotate(270deg); /* Opera, Chrome, and Safari */
}
/* ---------- */
.trapezoid {
position:relative;
}
.trapezoid:after {
content:' ';
left:-14px;
top:10px;
position:absolute;
background:red;
border-radius:0px 0 0 0;
width:164px;
height:40px;
display:block;
}
You do not use a gradient for this, you just need to use a pseudo-element like :after.
Sample code:
#bookmark {
width: 50px;
height: 100px;
position: relative;
background: red;
}
#bookmark:after {
content: "";
position: absolute;
left: 0;
bottom: 0;
width: 0;
height: 0;
border-bottom: 35px solid #FFF;
border-right: 50px solid transparent;
}
Live JSFiddle
If you want the shape to be filled in with a gradient, you can do that, too. Just add that to the CSS:
background: linear-gradient(to right, #ff0000 0%,#B00000 100%);