Complicated SQLite or SQL SUM() between several rows - mysql

Question

I need to extend this question: SQLite SUM() between several rows
Before table was
and query was :
SELECT Sum(SERVICE)
FROM (
SELECT ft.*, (
SELECT count(*)
FROM fuel_table ft2
WHERE ft2.note='Your tank was full up.' and ft2.id>=ft.id)
AS numNotesAhead
FROM fuel_table ft)
AS ft
WHERE numNotesAhead=1
but now my fuel table is split and looks like:
I've tried:
SELECT Sum(fuel_table.SERVICE)
FROM (
SELECT ft.*, (
SELECT count(*)
FROM fuel_table ft2
LEFT JOIN note_table ON fuel_table.EnterId = note_table.EnterId
WHERE ft2.note='Your tank was full up.' and ft2.id>=ft.id)
AS numNotesAhead
FROM fuel_table ft)
AS ft
WHERE numNotesAhead=1
but it doesn't works. My app just stops.
*Note there is "_" in name of fuel table.

Answer 1

So there are two issues here - one is the joining of the tables, which is different from your previous problem. The second issue is doing the appropriate summation of the right values, which is already beautifully answered here: SQLite SUM() between several rows.
So, let's look at the JOIN.
Since the fuel_table has the greater number of records, we're going to expect some 'NULL' values from the desired JOIN with the note_table. (And we're not going to lose any records from fuel_table since we're joining on enterId, so we don't need a FULL OUTER JOIN). This means (for a LEFT JOIN), we want the fuel_table to be on the left:
SELECT f.id, f.service, f.enterid, n.note
FROM fuel_table f
LEFT JOIN note_table n
ON f.enterid = n.enterid
This will give us output:
id service enterid note
----------------------------------
2 50 25 Yes
3 20 26 NULL
4 20 35 Yes
8 30 36 NULL
9 15 37 NULL
10 20 42 Yes
So far, so good.
Now - rather than thinking about it - I just looked at the answer to the previous question, and substituted this subquery from the fuel_table from this answer: SQLite SUM() between several rows
which is a very good answer, and I can take no credit for any part of it in the following bit ...
Putting them together you get the ugly but functional query:
SELECT SUM(fq.service) AS total
FROM
(SELECT fq2.*,
(SELECT COUNT(*)
FROM (SELECT f.id, f.service, f.enterid, n.note
FROM fuel_table f
LEFT JOIN note_table n
ON f.enterid = n.enterid) fq1
WHERE fq1.note = 'Yes' AND fq1.id >= fq2.id) AS numNotesAhead
FROM
(SELECT f.id, f.service, f.enterid, n.note
FROM fuel_table f
LEFT JOIN note_table n
ON f.enterid = n.enterid) fq2) fq
WHERE numNotesAhead = 1
which returns output:
total
------
65