I am trying to add 24 to 10 in 2's complement. I found 24 in 2's complement to be: 011000 and 10 in 2's complement to be 001010. When I add the two together I get: 100010. The result is a negative number. Is this an example of overflow? Is it not possible to add 24 to 10 in 2's complement?
If you only have 6 bits, then yes, it is an overflow. The reason is that 6-bit 2's complement can only store numbers -32..31 and your desired result, 34, is outside that range.
If you had, say, 8 bits instead, your result would be 00100010, which would not be a negative number, or an overflow.
Adding two positive numbers and coming up with a negative result, or two negative numbers and coming up with a non-negative result, is a definitive indicator of signed 2's complement overflow.
Related
using 4-bit numbers calculating -3 + -3 in two's complement, my calculation yields -2.
3 in binary is 0011
making both one's complement by flipping all the digits since both are negative
1100 && 1100
adding one to them, since we are using two's complement
1101 + 1101 =
11010
first one is overflow, and are tossed away in two's complement. So are left with 1010, which is minus two in decimal. Can someone explain what is done wrong in this process?
EDIT
My problem seems more specifically how to interpret the result of a two's complement calculation. I treat the result as following:
The result is 1010.
In my world, the first bit is a sign bit, indicating that the number is negative.
The following 0 means there is 0 of -4's
the following 1 means there is 1 of -2's
the following 0 means there is 0 of -1's
therefore, I interpret it like the result is -2
The result is correct, you just interpreted it wrong. When you perform arithmetic on numbers in two's complement, the result is also two's complement. So the conversion from negative to positive is done the same way as the conversion of the original numbers from positive to negative.
Given the 4-bit binary value 1010, first flip the bits for one's complement to get 0101, then add 1 for two's complement to get 0110.
0110 is 6, so 1010 is -6.
first one is overflow
If, as you imply here, you are restricting your storage to a single nybble, then with two's complement, you can represent values in the range -8 to 7.
-2 would then be 0b1110, which is not what you have. -6 is indeed 0b1010, which is the correct sum.
I want to design a hardware which will give 2's complement of input 4-bit binary number. But i stuck at very first input: 0000.Because the method i generally use to find 2's complement is to first find 1's complement of binary number and then adding 1 into it.But if I do same with 0000, then it will give me 5-bit number 10000. that is the problem.
You have to cut off the upper bits if you're working with an n-bit value. The two's complement of the four-bit 0000 is the last four bits of 10000, or 0000. Otherwise the ones' complement of 100 would be:
1111111111...ad infinitum...1111111011
rather than the correct 011.
That (the cutting off of extraneous bits) makes sense since the negation of zero is zero (though that could be arguable for ones' complement or sign-magnitude, where -0 is a distinct possibility).
If you design hardware, see hardware circuits for produce 4-bit complement number.
Using the 2's complement method of subtraction, my result is 1111 (-1 in decimal system) whereas it should be 0 in the following case
10010
-10010
where both values are provided in binary.
The answer seems quite obvious but following the method of conversion of the negative value to 2's complement and then adding it does not seem to work in this case as the result seems to be 1111.
Thanks
Subtracting a number from itself using 2's complement means you add its 2's complement (subtracting a number is adding its 2's complement):
You need to know the word size in bits to determine 2's complemet, so let's suppose the number of bits in a word is 8. Then you have 00010010 as the original number, and 11101110 as its 2's complement. The 2's complement is the 1's complement (11101101) with 1 added to it.
Then adding:
00010010 [original number, 18 decimal]
+11101110 [2's complement, -18 decimal]
---------
00000000 [note: there's a 1 overflow bit]
10010 in twos complement (assuming 5 bit two's complement) is -14 (-16 +2). 14 in twos complement is 01110 (2+4+8). So
10010
-10010
=
10010
+01110
=
00000 (actually 100000, but the 1 is overflowed)
I was wondering if someone could double check my work for me real quick. If I'm given two negative numbers: -33 and -31. If I add them together what will be the result using 2's complement.
NOTE: A word length of 6-bits MUST being used for the operation.
MY ANSWER
So after doing this I computed -31 to be 100001 in 2's. I also computed -33 to be 011111 in 2's complement. When adding them together I got 1000000, however this number is 7 digits so I chopped off the higher order bit since I'm bound to a word length of 6-bits. This yields the number 000000. Which contains a sign bit of 0, meaning it would be even. However since the sum of 2 negative's cannot be even it's obviously an overflow. So I take the 2's of 000000 which is simply 000000.
So the answer should be: 0 since a buffer overflow occurred. Does this seem right to you guys? THANKS. :)
First of all: -33 + (-31) cannot be 0.
-33 is not representable in 6bit 2's complement. 01 1111b is +31 in decimal, so the addition results in 0.
So the correct answer is something like that: There is no result because -33 is an invalid number in 6bit representation.
in 7 bit 2's complement -33 = 101 1111b
110 0001
+101 1111
=
1100 0000
which is equal to -64.
So i was told that two's complement is usually to used to find complement of a number and I used it only to complement positive numbers (i.e positve --> negative conversion) however I just got an example in book which asks me the following :
Express 23, -23, and -9 in 8-bit binary two’s Complement
form
now what does that mean? 23 means -23 in binary and -23 means 23 ?
sorta confused over there
2's complement is used to represent negative numbers, which in turn, can be used to do subtraction.
23 = 00010111b
To get -23 (2's complement of 23), flip all the bits, and add 1:
11101000b + 1
=11101001b (-23)
-9 is the 2's complement of 9. 9 is
00001001b
So -9 is
11110111b (Flipping and add +1)
See also here
The representation of positive numbers in 2's complement is same as the unsigned representation. Things start to change when negative representation comes into play. So, in general, for given w bits, the numbers that can be represented in 2's complement are -2^(w-1)-1 to 2^(w-1) with the w bit being the signed bit. So since you have 8 bits you can represent numbers from -128 to 127. The 8th bit will be the signed bit, with 0 being positive and 1 representing negative.
For any positive representation of a number in binary 2's complement N the negative counterpart -N is pretty simple to find, just invert the bits, and add one. Example:
7 in 2's complement is 0111, inverting these bits gives: 1000, adding one gives 1001, which is -7 in 2's complement! Hope this helps!