How to update mysql data in bulk ?
How to define something like this :
UPDATE `table`
WHERE `column1` = somevalues
SET `column2` = othervalues
with somevalues like :
VALUES
('160009'),
('160010'),
('160011');
and othervalues :
VALUES
('val1'),
('val2'),
('val3');
maybe it's impossible with mysql ?
a php script ?
The easiest solution in your case is to use ON DUPLICATE KEY UPDATE construction. It works really fast, and does the job in easy way.
INSERT into `table` (id, fruit)
VALUES (1, 'apple'), (2, 'orange'), (3, 'peach')
ON DUPLICATE KEY UPDATE fruit = VALUES(fruit);
or to use CASE construction
UPDATE table
SET column2 = (CASE column1 WHEN 1 THEN 'val1'
WHEN 2 THEN 'val2'
WHEN 3 THEN 'val3'
END)
WHERE column1 IN(1, 2 ,3);
If the "bulk" data you have is dynamic and is coming from PHP (you did tag it, after all), then the query would look something like this:
INSERT INTO `foo` (id, bar)
VALUES
(1, 'pineapple'),
(2, 'asian pear'),
(5, 'peach')
ON DUPLICATE KEY UPDATE bar = VALUES(bar);
and the PHP to generate this from an existing array (assuming the array is of a format like:
$array = (
somevalues_key => othervalues_value
);
) would look something like this (by no means the best (doesn't address escaping or sanitizing the values, for instance), just an quick example):
$pairs = array();
foreach ($array as $key => $value) {
$pairs[] = "($key, '$value')";
}
$query = "INSERT INTO `foo` (id, bar) VALUES " . implode(', ', $pairs) . " ON DUPLICATE KEY UPDATE bar = VALUES(bar)";
You could try an UPDATE with JOIN as below:
UPDATE table
INNER JOIN (
SELECT 1 column1, 2 column2, 10 new_v1, 20 new_v2, 30 new_v3
UNION ALL SELECT 4 column1, 5 column2, 40 new_v1, 50 new_v2, 60 new_v3
) updates
ON table.column1 = updates.column1
AND table.column2 = updates.column2
SET
table.column1 = updates.new_v1,
table.column2 = updates.new_v2,
table.column3 = updates.new_v3;
As long as you can craft the inner SELECT statements from the updates subquery you would get the benefit of running all these updates in a single statement (which should give you some performance boost on InnoDB depending on your table size).
If you are using a drag & drop tableView or collectionView to sort datas in your app, like allowing users to arrange their photos by drag and drop functionality, send a comma seperated list of ordered ids to the backend after user edits finish.
In your backend, explode ids to the an array like
$new_ranks = array();
$supplied_orders = explode(",", $_POST["supplied_new_order"]); //52,11,6,54,2 etc
$start_order = 99999;
foreach ($supplied_orders as $supplied_row_id) {
//your all validations... make sure supplied_row_id belongs to that user or not etc..
$new_ranks[intval($supplied_row_id)] = $start_order--;
}
now, you can update all new ranks like #Farside recommendation 2.
if (count($new_ranks) > 0) {
$case_sqls = array();
foreach ($new_ranks as $id => $rank) {
$case_sqls[] = "WHEN ".intval($id)." THEN ".intval($rank)."";
}
$case_sql = implode(" ", $case_sqls);
$this->db->query("
UPDATE
service_user_medias
SET
rank = (CASE id ".$case_sql." END)
WHERE
id IN(".implode(",", array_keys($new_ranks)).");
");
}
If you have data in array format then try this
and your query is like "UPDATE table WHERE column1 = ? SET column2 = ?"
then set it like below
foreach($data as $key => $value) {
$query->bind_param('ss', $key, $value);
$query->execute();
}
hope it'll work.
Reference from this.
I am trying to save multiple queries into a database on two different tables. Below is the code that I have tried to no avail. firsttable.a is the same as secondtable.id, con holds the connection info, and everything saves perfectly with one query. Is there something I am missing here?
if(empty($id)){
$uuid = uniqid();
$query = "INSERT INTO firsttable (`id`, `a`, `b`, `uuid`) VALUES (NULL, '$a', '$b', '$uuid')";
$query2 = "INSERT INTO secondtable (`id`, `c`, `d`, `uuid`) VALUES (NULL, '$c', '$d', '$uuid')";
}else{
$query = "UPDATE `firsttable` SET `id` = '$id', `a` = '$a', `b` = '$b', `uuid` = '$uuid' WHERE `id` = $id";
$query2 = "Update INTO secondtable SET `id` = '$a', `c` = '$c', `d` = '$d',
if(!mysqli_multi_query($this->_con, $query;$query2)){
throw new Exception( mysqli_error($this->_con) );
mysql_multi_query takes two arguments: the database connection, and a single string.
You need to concatenate your two queries together as a string:
mysqli_multi_query($this->con, $query1 . ';' . $query2);
or what you were probably trying to do:
mysqli_multi_query($this->con, "$query1;$query2");
From the php documentation on how to retrieve the result sets for the subsequent queries:
To retrieve the resultset from the first query you can use mysqli_use_result() or mysqli_store_result(). All subsequent query results can be processed using mysqli_more_results() and mysqli_next_result().
The first example shows how it all works.
In your example, though, the correct syntax is UPDATE tablename ..., not UPDATE INTO tablename ....
I have table - config.
Schema:
config_name | config_value
And I would like to update multiple records in one query. I try like that:
UPDATE config
SET t1.config_value = 'value'
, t2.config_value = 'value2'
WHERE t1.config_name = 'name1'
AND t2.config_name = 'name2';
but that query is wrong :(
Can you help me?
Try either multi-table update syntax
UPDATE config t1 JOIN config t2
ON t1.config_name = 'name1' AND t2.config_name = 'name2'
SET t1.config_value = 'value',
t2.config_value = 'value2';
Here is a SQLFiddle demo
or conditional update
UPDATE config
SET config_value = CASE config_name
WHEN 'name1' THEN 'value'
WHEN 'name2' THEN 'value2'
ELSE config_value
END
WHERE config_name IN('name1', 'name2');
Here is a SQLFiddle demo
You can accomplish it with INSERT as below:
INSERT INTO mytable (id, a, b, c)
VALUES (1, 'a1', 'b1', 'c1'),
(2, 'a2', 'b2', 'c2'),
(3, 'a3', 'b3', 'c3'),
(4, 'a4', 'b4', 'c4'),
(5, 'a5', 'b5', 'c5'),
(6, 'a6', 'b6', 'c6')
ON DUPLICATE KEY UPDATE id=VALUES(id),
a=VALUES(a),
b=VALUES(b),
c=VALUES(c);
This insert new values into table, but if primary key is duplicated (already inserted into table) that values you specify would be updated and same record would not be inserted second time.
in my case I have to update the records which are more than 1000, for this instead of hitting the update query each time I preferred this,
UPDATE mst_users
SET base_id = CASE user_id
WHEN 78 THEN 999
WHEN 77 THEN 88
ELSE base_id END WHERE user_id IN(78, 77)
78,77 are the user Ids and for those user id I need to update the base_id 999 and 88 respectively.This works for me.
instead of this
UPDATE staff SET salary = 1200 WHERE name = 'Bob';
UPDATE staff SET salary = 1200 WHERE name = 'Jane';
UPDATE staff SET salary = 1200 WHERE name = 'Frank';
UPDATE staff SET salary = 1200 WHERE name = 'Susan';
UPDATE staff SET salary = 1200 WHERE name = 'John';
you can use
UPDATE staff SET salary = 1200 WHERE name IN ('Bob', 'Frank', 'John');
maybe for someone it will be useful
for Postgresql 9.5 works as a charm
INSERT INTO tabelname(id, col2, col3, col4)
VALUES
(1, 1, 1, 'text for col4'),
(DEFAULT,1,4,'another text for col4')
ON CONFLICT (id) DO UPDATE SET
col2 = EXCLUDED.col2,
col3 = EXCLUDED.col3,
col4 = EXCLUDED.col4
this SQL updates existing record and inserts if new one (2 in 1)
Camille's solution worked. Turned it into a basic PHP function, which writes up the SQL statement. Hope this helps someone else.
function _bulk_sql_update_query($table, $array)
{
/*
* Example:
INSERT INTO mytable (id, a, b, c)
VALUES (1, 'a1', 'b1', 'c1'),
(2, 'a2', 'b2', 'c2'),
(3, 'a3', 'b3', 'c3'),
(4, 'a4', 'b4', 'c4'),
(5, 'a5', 'b5', 'c5'),
(6, 'a6', 'b6', 'c6')
ON DUPLICATE KEY UPDATE id=VALUES(id),
a=VALUES(a),
b=VALUES(b),
c=VALUES(c);
*/
$sql = "";
$columns = array_keys($array[0]);
$columns_as_string = implode(', ', $columns);
$sql .= "
INSERT INTO $table
(" . $columns_as_string . ")
VALUES ";
$len = count($array);
foreach ($array as $index => $values) {
$sql .= '("';
$sql .= implode('", "', $array[$index]) . "\"";
$sql .= ')';
$sql .= ($index == $len - 1) ? "" : ", \n";
}
$sql .= "\nON DUPLICATE KEY UPDATE \n";
$len = count($columns);
foreach ($columns as $index => $column) {
$sql .= "$column=VALUES($column)";
$sql .= ($index == $len - 1) ? "" : ", \n";
}
$sql .= ";";
return $sql;
}
Execute the code below to update n number of rows, where Parent ID is the id you want to get the data from and Child ids are the ids u need to be updated so it's just u need to add the parent id and child ids to update all the rows u need using a small script.
UPDATE [Table]
SET column1 = (SELECT column1 FROM Table WHERE IDColumn = [PArent ID]),
column2 = (SELECT column2 FROM Table WHERE IDColumn = [PArent ID]),
column3 = (SELECT column3 FROM Table WHERE IDColumn = [PArent ID]),
column4 = (SELECT column4 FROM Table WHERE IDColumn = [PArent ID]),
WHERE IDColumn IN ([List of child Ids])
Execute the below code if you want to update all record in all columns:
update config set column1='value',column2='value'...columnN='value';
and if you want to update all columns of a particular row then execute below code:
update config set column1='value',column2='value'...columnN='value' where column1='value'
Assuming you have the list of values to update in an Excel spreadsheet with config_value in column A1 and config_name in B1 you can easily write up the query there using an Excel formula like
=CONCAT("UPDATE config SET config_value = ","'",A1,"'", " WHERE config_name = ","'",B1,"'")
INSERT INTO tablename
(name, salary)
VALUES
('Bob', 1125),
('Jane', 1200),
('Frank', 1100),
('Susan', 1175),
('John', 1150)
ON DUPLICATE KEY UPDATE salary = VALUES(salary);
UPDATE 2021 / MySql v8.0.20 and later
The most upvoted answer advises to use the VALUES function which is now DEPRECATED for the ON DUPLICATE KEY UPDATE syntax. With v8.0.20 you get a deprecation warning with the VALUES function:
INSERT INTO chart (id, flag)
VALUES (1, 'FLAG_1'),(2, 'FLAG_2')
ON DUPLICATE KEY UPDATE id = VALUES(id), flag = VALUES(flag);
[HY000][1287] 'VALUES function' is deprecated and will be removed in a future release. Please use an alias (INSERT INTO ... VALUES (...) AS alias) and replace VALUES(col) in the ON DUPLICATE KEY UPDATE clause with alias.col instead
Use the new alias syntax instead:
official MySQL worklog
Docs
INSERT INTO chart (id, flag)
VALUES (1, 'FLAG_1'),(2, 'FLAG_2') AS aliased
ON DUPLICATE KEY UPDATE flag=aliased.flag;
just make a transaction statement, with multiple update statement and commit. In error case, you can just rollback modification handle by starting transaction.
START TRANSACTION;
/*Multiple update statement*/
COMMIT;
(This syntax is for MySQL, for PostgreSQL, replace 'START TRANSACTION' by 'BEGIN')
Try either multi-table update syntax
Try it copy and SQL query:
CREATE TABLE #temp (id int, name varchar(50))
CREATE TABLE #temp2 (id int, name varchar(50))
INSERT INTO #temp (id, name)
VALUES (1,'abc'), (2,'xyz'), (3,'mno'), (4,'abc')
INSERT INTO #temp2 (id, name)
VALUES (2,'def'), (1,'mno1')
SELECT * FROM #temp
SELECT * FROM #temp2
UPDATE t
SET name = CASE WHEN t.id = t1.id THEN t1.name ELSE t.name END
FROM #temp t
INNER JOIN #temp2 t1 on t.id = t1.id
select * from #temp
select * from #temp2
drop table #temp
drop table #temp2
UPDATE table name SET field name = 'value' WHERE table name.primary key
If you need to update several rows at a time, the alternative is prepared statement:
database complies a query pattern you provide the first time, keep the compiled result for current connection (depends on implementation).
then you updates all the rows, by sending shortened label of the prepared function with different parameters in SQL syntax, instead of sending entire UPDATE statement several times for several updates
the database parse the shortened label of the prepared function , which is linked to the pre-compiled result, then perform the updates.
next time when you perform row updates, the database may still use the pre-compiled result and quickly complete the operations (so the first step above can be omitted since it may take time to compile).
Here is PostgreSQL example of prepare statement, many of SQL databases (e.g. MariaDB,MySQL, Oracle) also support it.
I am running the following query, but getting an error. I think it is coming from the ON DUPLICATE KEY part, but I'm not 100% sure what the correct syntax is to use there.
<?php
$form_id = $form->data['form_id'];
$cfid = $form->data['cf_id'];
$datesent = $form->data['datesent'];
$query = mysql_query("
INSERT INTO `email_history` (
`cf_id` ,
`$form_id`
)
VALUES (
'$cfid', '$datesent'
)
ON DUPLICATE KEY
UPDATE INTO
`email_history` (
`$form_id`
)
VALUES (
'$datesent'
);
") or die(mysql_error());
?>
EDIT
Using the following I am getting this error :
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ')' at line 10
<?php
$form_id = $form->data['form_id'];
$cfid = $form->data['cf_id'];
$datesent = $form->data['datesent'];
$query = mysql_query("
INSERT INTO `email_history` (
`cf_id` ,
`$form_id`
)
VALUES (
'$cfid', '$datesent'
)
ON DUPLICATE KEY
UPDATE `$form_id` = `$datesent`
);
") or die(mysql_error());
?>
The correct syntax of ON DUPLICATE KEY is something a long the lines described below.
Please note that it's just an example snippet, though it should be clear why your provided snippet fails to execute.
INSERT INTO tbl (
col1, col2, ... , colN
) VALUES (
#val1, #val2, ..., #valN
) ON DUPLICATE KEY UPDATE
col3 = VALUES(col3), col4 = #val4
Documentation
MySQL 5.0 Reference Manual :: 12.2.5.3 INSERT ... ON DUPLICATE KEY UPDATE Syntax
How would that look in my code?
$form_id = $form->data['form_id'];
$cfid = $form->data['cf_id'];
$datesent = $form->data['datesent'];
$query = mysql_query (<<<EOT
INSERT INTO `email_history` (`cf_id`, `$form_id`)
VALUES ('$cfid', '$datesent')
ON DUPLICATE KEY UPDATE `$form_id` = VALUES(`$form_id`)
EOT
) or die (mysql_error ());
What does VALUES($form_id) do?
It will yield the value of what was originally passed as the value for column named $form_id.
What is the use of <<<EOT?
In the previous snippet we are using a HEREDOC to have a string span multiple lines in an easy manner. You can read more about it in the documentation for heredocs.