Join or SubQuery? - mysql

Question

I've got a MySQL table that records the addon titles used on various websites, including a version number. For example:
AddonName | Website ID | Version
ZZZ 1 3.3
ZZZ 2 3.4
ZZZ 3 3.4
ZZZ 4 3.1
YYY 1 1.1
YYY 2 1.1
YYY 3 1.1
YYY 4 1.2
I'd like to create a query that lists a distinct list of AddonName, with details of the total count, count of all sites using the latest version, and counts of all sites using out of date versions.
i.e.:
Name | Total Addons | Up to Date | Out of Date
ZZZ 4 2 2
YYY 4 1 3
I can't figure out how to get this type of data returned, even though the information is all there. I tried using JOIN queries, but didn't have any success.
If it helps make things easier, I can add a 'latest' enum field to the table, to mark rows as up-to-date or out-of-date when the are imported.

Answer 1

Assuming max value as latest version.
Try this:
select t1.AddonName,
count(*) as total_Addon,
sum(case when t1.version=t2.version then 1 else 0 end) as up_to_date,
sum(case when t1.version!=t2.version then 1 else 0 end) as out_of_date
from table1 t1
inner join(
select AddonName,max(version) as version
from table1 group by AddonName
)t2 on t1.AddonName=t2.AddonName
group by t1.AddonName

Answer 2

Try:
SELECT your_table.AddonName,
COUNT(`Website ID`),
COUNT(IF(Version = your_table_max.max_version, 1, NULL)) AS `Up to Date`,
COUNT(IF(Version <> your_table_max.max_version, 1, NULL)) AS `Out of Date`
FROM your_table
INNER JOIN (SELECT MAX(Version) as max_version, AddonName
FROM your_table group by AddonName) your_table_max
ON your_table_max.AddonName = your_table.AddonName
GROUP BY your_table.AddonName;

Answer 3

Assuming the latest version is from the last column:
select t.name, count(*) as TotalAddons,
sum(t.version = tt.maxv) as UpToDate,
sum(t.version <> tt.maxv) as OutOfDate
from t join
(select name, max(version) as maxv
from t
group by name
) tt
on t.name = tt.name
group by t.name;
This calculates the maximum version number for each name in a subquery. It then uses that information for the outer aggregation.
This assumes that version is a number. If it is a string (so 1.10 > 1.2), then a similar approach is:
select t.name, count(*) as TotalAddons,
sum(t.version = t.maxv) as UpToDate,
sum(t.version <> t.maxv) as OutOfDate
from (select t.*,
(select version
from t t2
where t2.name = t.name
order by length(version) desc, version desc
limit 1
) as maxv
from t
) t
group by t.name;
Of course, this will also work for numbers as well.

Answer 4

try this this will solve your problem.
select AddonName,count(AddonName) as countAdd,(select count(Version)from test1 as t where t.AddonName = test1.AddonName and t.Version = max(test1.Version)),(select count(Version) from test1 as t where t.AddonName = test1.AddonName and t.Version = min(test1.Version))from test1 GROUP BY AddonName;

Answer 5

Once you add that Latest table, try following (after inserting your table names)
select
AddonName as Name,
count(*) as TotalAddons,
count(case TableName.Version when Latest.LatestVersion
then 1 else null end) as UpToDate,
TotalAddons-UpToDate as OutOfDate
from TableName join Latest
on TableName.AddonName = Latest.AddonName
group by AddonName

Answer 6

WITH cte
AS
(
SELECT t.AddonName, MAX(t.Version) AS latest_version
FROM Table1 t
GROUP BY t.AddonName
)
SELECT t.AddonName, COUNT(t.WebsiteID) AS total_addons,
SUM
(
CASE WHEN t.version = cte.latest_version
THEN 1 ELSE 0 END
) AS up_to_date,
SUM
(
CASE WHEN t.version <> cte.latest_version
THEN 1 ELSE 0 END
) AS out_of_date
FROM Table1 t
JOIN cte ON t.AddonName = cte.AddonName
GROUP BY t.AddonName