I have a following query
select YEAR(t1.date) as 'year'
, MONTHNAME(t1.date) as 'month'
, COUNT(*) as total
, if (t1.Sex = 1, 'male','female') as sex
from outpatients t1
where YEAR(t1.date) = 2015
group by MONTH(t1.date), t1.Sex
order by t1.date, t1.Sex
So the output will look like this:
I would like to write a query to see female and male as the columns.
So the output will look like.
I can't find the way to group the data
You can use SUM function to sum the male and female
select YEAR(t1.date) as year, MONTHNAME(t1.date) as month, COUNT(*) as total
, SUM(CASE WHEN sex = 'male' THEN 1 ELSE 0 END) AS male
, SUM(CASE WHEN sex = 'female' THEN 1 ELSE 0 END) AS female
from outpatients t1
where YEAR(t1.date) = 2015
group by MONTH(t1.date), t1.Sex
order by t1.date, t1.Sex
Related
Dears,
I tried to create a view that sumarize transaction per category (row) and months (columns) on one year as this :
SELECT counterpart.id_category as catid, category AS Category, (
SELECT COALESCE(SUM(amount), 0)
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
WHERE YEAR(date) = YEAR(now())
AND MONTH(date) = 1
AND id_category = catid
) AS Jan, [...]
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
INNER JOIN category
ON counterpart.id_category = category.id_category
WHERE transaction.id_user = 2
AND YEAR(date) = YEAR(now())
GROUP BY category
I don't know if it's a good way or not, at least it works as single command but not as view.
On view, the WHERE id_category = catid for subquery doesn't work properly.
Thank you.
I suspect conditional aggregation would be more appropriate and quicker than a lot of sub queries.
for example
SELECT counterpart.id_category as catid, category AS Category,
sum(case when month(date) = 1 then 1 else 0 end) as Jan,
sum(case when month(date) = 2 then 1 else 0 end) as feb,
sum(case when month(date) = 3 then 1 else 0 end) as Mar
FROM transaction
INNER JOIN counterpart
ON transaction.id_counterpart = counterpart.id_counterpart
INNER JOIN category
ON counterpart.id_category = category.id_category
WHERE transaction.id_user = 2
AND YEAR(date) = YEAR(now())
GROUP BY counterpart.id_category,category
With this example iformation table:
How can i output this information?
I'm trying this query,
but it's just returning me the total number of 'PART' rows for each 'NAMES'.
SELECT
NAMES
, SUM(PART = "F001") AS SUM_F001
, SUM(PART = "F002") AS SUM_F002
, SUM(PART = "F003") AS SUM_F003
FROM
MY_TABLE
GROUP BY NAMES ASC
You are pretty close with your current query.
But you need to use the query below to correctly pivot.
SELECT
NAMES
, MAX(CASE WHEN PART = 'F001' THEN QTY ELSE 0 END) AS F001
, MAX(CASE WHEN PART = 'F002' THEN QTY ELSE 0 END) AS F002
, MAX(CASE WHEN PART = 'F003' THEN QTY ELSE 0 END) AS F003
, SUM(QTY) AS alias
FROM
FROM
MY_TABLE
GROUP BY
NAMES # Don't use ASC OR DESC on GROUP BY because it's deprecated
ORDER BY
NAMES ASC
U can use the query as follows
SELECT NAMES , SUM(CASE WHEN PART = 'F001' THEN 1 ELSE 0 END) AS F001 , SUM(CASE WHEN PART = 'F002' THEN 1 ELSE 0 END) AS F002 , SUM(CASE WHEN PART = 'F003' THEN 1 ELSE 0 END) AS F003 , SUM(QTY) AS alias FROM FROM MY_TABLE GROUP BY NAMES ORDER BY NAMES ASC
This should be easy but I have not found the answer. I have a query that is running a count and I want to group this within the query into those where State = 1 and State <>1 and have the sum for each group.
SELECT count(`id_job`) as count, `state`
FROM job_table
GROUP BY `state`;
You can query a boolean expression and group by it too:
SELECT state = 1, COUNT(*)
FROM job_table
GROUP BY state = 1
SELECT count(id_job) as count,state FROM job_table
GROUP BY case when state = 1 then 1 else 0
In MySQL, you can easily put these into columns:
select sum( state = 1 ) as state_1,
sum( state <> 1 ) as state_2
from job_table;
If state can be NULL, you want to be a bit careful. The second condition is safer as:
select sum( state = 1 ) as state_1,
sum( not state <=> 1 ) as state_2
from job_table;
Try this
SELECT SUM(CASE WHEN State=1 THEN 1 END) as count1,
SUM(CASE WHEN State<>1 THEN 1 END) as count2,
State
FROM job_table
GROUP BY state
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I am new to SQL and would like to know how to approach writing a query for this question.
Lets say we have these fields:
date_created date_unsubscribed subscriberid
How to write a SQL query that lists, by month, how many people subscribed to the list, unsubscribed from the list, and how many net subscribers there were (new subscribers minus unsubscribers).
All in a single query...
Here's one option using conditional aggregation and union all:
select month(dt),
count(case when subscribe = 1 then 1 end) subscribecount,
count(case when subscribe = -1 then 1 end) unsubscribecountt,
sum(subscribe) overallcount
from (
select date_created as dt, 1 as subscribe
from yourtable
union all
select date_unsubscribed, -1
from yourtable
where date_unsubscribed is not null
) t
group by month(dt)
The subquery creates a list of dates with a flag for subscribe or unsubscribe. Then you can use count with case to determine the appropriate number of subscribers/unsubscribers.
SQL Fiddle Demo
You could write a sum(case) (a sum with conditions) to aggregate - assuming the date_created column is never null. For instance:
ORACLE:
SELECT
TO_CHAR(DATE_CREATED,'MM-YYYY') CREATE_MONTH
,SUM(CASE WHEN date_unsubscribed is not null then 1 else 0 end) unsubscribed
,SUM(CASE WHEN date_unsubscribed is null then 1 else 0 end) subscribed
,COUNT(SUBSCRIBER_ID)
FROM
--YOURTABLENAME
--WHERE
--WHATEVER OTHER CONDITIONS YOU HAVE APPLY
GROUP BY TO_CHAR(DATE_CREATED,'MM-YYYY')
MYSQL:
SELECT
DATE_FORMAT(DATE_CREATED,'%m-%Y') CREATE_MONTH
,SUM(CASE WHEN date_unsubscribed is not null then 1 else 0 end) unsubscribed
,SUM(CASE WHEN date_unsubscribed is null then 1 else 0 end) subscribed
,COUNT(SUBSCRIBER_ID)
FROM
--YOURTABLENAME
--WHERE
--WHATEVER OTHER CONDITIONS YOU HAVE APPLY
GROUP BY DATE_FORMAT(DATE_CREATED,'%m-%Y')
Oracle solution
Here is a query using the PIVOT operator, which was created exactly for this kind of work, and ROLLUP to get the net number. This is just for illustration; I assume the year is a user or application input (bind variable :year, set to 2015 for the output), and I show the summary for January through June.
with
test_data ( date_created, date_unsubscribed, subscriber_id ) as (
select date '2015-05-10', null , 330053448 from dual union all
select date '2015-04-28', null , 330053457 from dual union all
select date '2015-05-10', null , 330053466 from dual union all
select date '2015-04-28', null , 220053475 from dual union all
select date '2015-04-28', date '2015-05-10', 330053484 from dual
),
prep ( type, val, mth ) as (
select 'Subscribed' , 1, extract(month from date_created) from test_data
where extract(year from date_created) = :year
union all
select 'Unsubscribed', -1, extract(month from date_unsubscribed) from test_data
where extract(year from date_unsubscribed) = :year
)
select nvl(type, 'Net Subscr') as description,
nvl(sum(jan), 0) as jan, nvl(sum(feb), 0) as feb, nvl(sum(mar), 0) as mar,
nvl(sum(apr), 0) as apr, nvl(sum(may), 0) as may, nvl(sum(jun), 0) as jun
from prep
pivot (
sum(val)
for mth in (1 as jan, 2 as feb, 3 as mar, 4 as apr, 5 as may, 6 as jun)
)
group by rollup(type)
order by case type when 'Subscribed' then 1 when 'Unsubscribed' then 2 else 3 end
;
DESCRIPTION JAN FEB MAR APR MAY JUN
------------ ---------- ---------- ---------- ---------- ---------- ----------
Subscribed 0 0 0 3 2 0
Unsubscribed 0 0 0 0 -1 0
Net Subscr 0 0 0 3 1 0
3 rows selected.
I have a table called list and i have to extract the following.
fields are id and date
If date<20120401 then count on id >>>> give result
If date>20120401 then count on id >>>> give result
if there are 20 items of date<20120401 and 30 items of date>20120401 of an idnumber xyz
then the result should be...
xyz 20 30
I have done like ...
select
(select count(id) from list where id='xyz' and date<20120401) as date1,
(select count(id) from list where id='xyz' and date>20120401) as date2;
the result is 20 30
but how to print the idnumber?
SELECT
id,
SUM(CASE WHEN date < 20120401 THEN 1 ELSE 0 END) AS date1,
SUM(CASE WHEN date > 20120401 THEN 1 ELSE 0 END) AS date2,
FROM list
WHERE id = 'xyz'
GROUP BY id
UPDATE:
SELECT
list.id,
idmaster.idlocation,
SUM(CASE WHEN list.date < 20120401 THEN 1 ELSE 0 END) AS date1,
SUM(CASE WHEN list.date > 20120401 THEN 1 ELSE 0 END) AS date2,
FROM list
INNER JOIN idmaster ON list.id = idmaster.idnumber
WHERE list.id = 'xyz'
GROUP BY id
Try
select id, count(id) from list where id='xyz' and date < 20120401
union
select id, count(id) from list where id='xyz' and date > 20120401
You are looking for GROUP BY clause and maybe something like this:
SELECT
l2.id,
(SELECT COUNT(id)
FROM list l1
WHERE l1.id = l2.id AND date < 20120401) AS date1,
(SELECT COUNT(id)
FROM list l1
WHERE l1.id = l2.id AND date > 20120401) AS date2
FROM
list l2
GROUP BY
l2.id
There are more cost effective methods to get desired result, but this is the easiest to understand.
Try this:
SELECT
id,
SUM(CASE WHEN date < 20120401
THEN 1 ELSE 0 END) AS date1,
SUM(CASE WHEN date > 20120401
THEN 1 ELSE 0 END) AS date2,
FROM list
WHERE id = 'xyz'
GROUP BY id