Would like to count number of rows between occurrence where total number of score is above 60, and count number of rows where this occurrence doesn't happened.
For example 5th and 6th game will end up with more then 60, so will count 5 rows with not 60 and 2 rows with 60.
I would like something like this:
type count
no-60-gap 5
yes-60-island 1
no-60-gap 3
yes-60-island 2
I have simple database of basketball games. Rough example below
id, home, score_home, away, score_away, round
1, team_1, 33, team_2, 23, 1
2, team_4, 31, team_1, 33, 1
3, team_2, 36, team_5, 53, 2
4, team_5, 35, team_1, 63, 2
5, team_7, 31, team_8, 53, 3
6, team_2, 30, team_1, 43, 3
7, team_1, 39, team_3, 13, 4
Was google-ing out this issues and I have end up trying to solve my problem with gaps and islands.
This is my solution but it not working. Idea was just to reset gap/island to 0 when it doesn't happened.
I am kind a new in this.
SET #gap :=0; SET #island :=0;
SELECT
#gap,
#island
FROM (
SELECT
CASE
WHEN (score_home + score_away) >= 60 THEN #island:=#island+1
WHEN (score_home + score_away) >= 60 THEN #gap:=0
END,
CASE
WHEN (score_home + score_away) < 60 THEN #island:=0
WHEN (score_home + score_away) < 60 THEN #gap:=#gap+1
END
FROM basket
) AS games
Appreciate any help
I suppose you're after something like this...
SELECT v,flag,COUNT(*)
FROM
( SELECT flag
, CASE WHEN #prev = flag THEN #v:=#v ELSE #v:=#v+1 END v
, #prev:=flag
FROM
( SELECT *, score_home + score_away >= 60 flag FROM my_table ) x
JOIN
( SELECT #prev:=NULL,#v:=0) vars
ORDER
BY id
) n
GROUP
BY v,flag;
Related
The table looks like this:
id, price, amount, transactionid
1, 5, 10, abc
2, 5, 10, abc
3, 20, 40, def
4, 20, 40, def
5, 15, 40, xyz
6, 20, 40, xyz
I want to compare the sum of the amounts with the amount and only select that are not equal.
Also in the example: 15 + 20 != 40
SELECT sum(price), transactionid FROM payment group by transactionid
Now I need the check with one of the amounts from a row and show only if is unequal.
Set the conditions in the HAVING clause:
SELECT transactionid,
SUM(price) total_price,
MAX(amount) amount
FROM payment
GROUP BY transactionid
HAVING total_price <> amount;
See the demo.
I have lists of users with his points and game id. I need to find the rank of the specified user based on the game order by the max(lb_point).
I have already done the query for getting the rank based on individual game as follows.
select count(*) AS user_rank
from (
select distinct user_id
from leader_board
where lb_point >= (select max( lb_point )
from leader_board
where user_id = 1
and game_id = 2 )
and game_id = 2
) t
But i need to find the rank based on the overall game. Example i have 3 different games (1,2,3). By passing the user_id, i need to find his overall rank among all three games. Can you please help me on this?
lb_id user_id game_id lb_point
------------------------------------------------
1 1 2 670
2 1 1 200
3 1 2 650
4 1 1 400
5 3 2 700
6 4 2 450
7 2 1 550
8 2 1 100
9 1 1 200
10 2 1 100
11 1 1 200
12 2 1 100
13 1 1 200
14 2 1 100
15 1 1 200
16 2 1 100
17 1 1 200
18 2 1 100
19 1 1 200
20 2 1 100
21 1 1 200
22 2 1 800
use sandbox;
/*create table t (lb_id int, user_id int, game_id int, lb_point int);
truncate table t;
insert into t values
(1 , 1, 2, 670),
(2 , 1, 1, 200),
(3 , 1, 2, 650),
(4 , 1, 1, 400),
(5 , 3, 2, 700),
(6 , 4, 2, 450),
(7 , 2, 1, 550),
(8 , 2, 1, 100),
(9 , 1, 1, 200),
(10, 2, 1, 100),
(11, 1, 1, 200),
(12, 2, 1, 100),
(13, 1, 1, 200),
(14, 2, 1, 100),
(15, 1, 1, 200),
(16, 2, 1, 100),
(17, 1, 1, 200),
(18, 2, 1, 100),
(19, 1, 1, 200),
(20, 2, 1, 100),
(21, 1, 1, 200),
(22, 2, 1, 800);
*/
select t.*
from
(
select s.*,#rn:=#rn+1 as rank
from
(
select user_id, sum(lb_point) points
from t
where lb_id = (select t1.lb_id from t t1 where t1.user_id = t.user_id and t1.game_id = t.game_id order by t1.lb_point desc limit 1)
group by user_id
order by points desc
) s
,(select #rn:=0) rn
) t
where t.user_id = 1
The innermost query grabs the highest score per game per user and sums it.
The next query assigns a rank based on the aggregated score per user.
The outermost query selects the user.
Considering a simple MySQL table with a id column and a int column, I need to count how many times I have a gap equal or greater than certain value.
Let's say that value will be 10.
Given the following sample records:
{1, 2, 3} = 1 time
{1, 2, 3, 4, 5, 6, 7, 8, 9} = 1 time;
{1, 2, 3, 14, 17} = 2 times (1, 2, 3 and 14, 17);
{1, 2, 3, 14, 20, 40, 42} = 3 times (1, 2, 3 and 14, 20 and 40, 42);
Is it possible resolve that with mysql?
Yes. For table t with columns id and num this will be seems like this:
SET #n = 10;
SELECT 1 + SUM(COALESCE(t3.f, 0))
FROM (
SELECT DISTINCT t1.num, (
SELECT CASE WHEN t2.num - t1.num > #n THEN 1 ELSE 0 END
FROM t t2
WHERE t2.num > t1.num
ORDER BY num LIMIT 1
) AS f
FROM t t1
) t3
I got mysql database and I need to get number of zeros in sequence and print them all with date from first zero, so for example I got a table like this
id, date, impuls_count
1, '12-05-15 12:00:00', 60
2, '12-05-15 12:01:00', 0
3, '12-05-15 12:02:00', 0
4, '12-05-15 12:03:00', 49
5, '12-05-15 12:04:00', 0
6, '12-05-15 12:05:00', 0
7, '12-05-15 12:06:00', 0
8, '12-05-15 12:07:00', 0
9, '12-05-15 12:08:00', 30
10, '12-05-15 12:09:00', 0
this should give the result like this:
'12-05-15 12:01:00', 2
'12-05-15 12:04:00', 4
'12-05-15 12:09:00', 1
I tried to solve it on my own but my query works very slow(I got 5000 rows in a table) and it sometimes prints same row twice
SELECT qwe.date, ile
FROM (SELECT p.date,
(SELECT COUNT(*)
FROM performance_v2
WHERE date > p.date
AND date <
(SELECT MIN(date)
FROM performance_v2
WHERE date > p.date AND impuls_count > 0)) ile
FROM performance_v2 p
WHERE p.impuls_count > 0
AND (date(p.date)
BETWEEN '2015-05-08%'
AND '2015-05-08%')
AND (time(p.date)
between '14:00:00' and '22:00:00')
ORDER BY 1) qwe
WHERE ile > 0
In MySQL, this is easiest to solve using variables. The idea is to have a counter increment each time the value of impuls_count changes. This defines groups of common values. You can then filter the values and aggregate to get what you want:
select min(date), count(*)
from (select t.*,
(#g := if(#ic = impuls_count, #g,
if(#ic := impuls_count, #g + 1, #g + 1)
)
) as grp
from table t cross join
(select #ic := 0, #g := 0)
order by id
) t
where impuls_count = 0
group by grp
We have a traffic counter that counts cars in each lane (two inbound and two outbound) in 15 minute increments.
There is a peak period which is defined as 7:00am to 9:00am. Within this peak period we want to know the PeakHourIn and PeakHourOut and PeakHourSum.
The PeakHourIn is the highest consecutive 4x15 minute total (1 hour) for lne1in + lne4in
The PeakHourOut is the highest consecutive 4x15 minute total (1 hour) for lne2out + lne3out
The PeakHourSum is the highest consecutive 4x15 minute total (1 hour) for all lanes.
Date Time lne1in lne2out lne3out lne4in
09-18-2012 5:45 AM 2 0 0 0
09-18-2012 6:00 AM 1 0 0 1
09-18-2012 6:15 AM 2 1 0 0
09-18-2012 6:30 AM 2 1 0 0
09-18-2012 6:45 AM 6 1 2 1
09-18-2012 7:00 AM 9 1 0 3
09-18-2012 7:15 AM 81 12 22 15
09-18-2012 7:30 AM 144 31 63 56
09-18-2012 7:45 AM 84 30 62 42
09-18-2012 8:00 AM 7 1 0 3
09-18-2012 8:15 AM 11 2 3 3
09-18-2012 8:30 AM 12 3 7 1
09-18-2012 8:45 AM 16 4 8 0
09-18-2012 9:00 AM 5 2 5 0
09-18-2012 9:15 AM 10 1 4 0
Results should look like:
PeakHourIn 434
PeakHourOut 221
PeakHourSum 655
Any help would be greatly appreciated.
If you used a native temporal data type to store the date/time, you could group multiple self-joins:
SELECT MAX(lne1in + lne4in ) AS PeakHourIn,
MAX(lne2out + lne3out) AS PeakHourOut,
MAX(lne1in + lne2out + lne3out + lne4in) AS PeakHourSum
FROM (
SELECT t1.lne1in + t2.lne1in + t3.lne1in + t4.lne1in AS lne1in,
t1.lne2out + t2.lne2out + t3.lne2out + t4.lne2out AS lne2out,
t1.lne3out + t2.lne3out + t3.lne3out + t4.lne3out AS lne3out,
t1.lne4in + t2.lne4in + t3.lne4in + t4.lne4in AS lne4in
FROM my_table t1
JOIN my_table t2 ON t2.DateTime = t1.DateTime + INTERVAL 15 MINUTE
JOIN my_table t3 ON t3.DateTime = t2.DateTime + INTERVAL 15 MINUTE
JOIN my_table t4 ON t4.DateTime = t3.DateTime + INTERVAL 15 MINUTE
WHERE TIME(t1.DateTime) BETWEEN '07:00:00' AND '08:00:00'
GROUP BY t1.DateTime
) t
EDIT
Here's a solution in MySQL: http://sqlfiddle.com/#!2/ff0fb/9
create table TrafficData
(
StartTime timestamp
,Lane int
,CarCount int
);
create table LaneData
(
Lane int
, Direction bit
);
insert LaneData
select 1, 0
union select 2, 1
union select 3, 1
union select 4, 0;
insert TrafficData
select dt, lane
, case lane
when 1 then l1
when 2 then l2
when 3 then l3
when 4 then l4
else null
end
from
(
select '2012-09-18 05:45' dt, 2 l1, 0 l2, 0 l3, 0 l4
union all select '2012-09-18 06:00', 1, 0, 0, 1
union all select '2012-09-18 06:15', 2, 1, 0, 0
union all select '2012-09-18 06:30', 2, 1, 0, 0
union all select '2012-09-18 06:45', 6, 1, 2, 1
union all select '2012-09-18 07:00', 9, 1, 0, 3
union all select '2012-09-18 07:15', 81, 12, 22, 15
union all select '2012-09-18 07:30', 144, 31, 63, 56
union all select '2012-09-18 07:45', 84, 30, 62, 42
union all select '2012-09-18 08:00', 7, 1, 0, 3
union all select '2012-09-18 08:15', 11, 2, 3, 3
union all select '2012-09-18 08:30', 12, 3, 7, 1
union all select '2012-09-18 08:45', 16, 4, 8, 0
union all select '2012-09-18 09:00', 5, 2, 5, 0
union all select '2012-09-18 09:15', 10, 1, 4, 0
) as originalTable
cross join LaneData;
select Lane, max(SumCarCount) as MaxSumCarCount
from
(
select a.Lane, SUM(b.CarCount) as SumCarCount
from TrafficData a
inner join TrafficData b
on b.Lane = a.Lane
and b.StartTime between a.StartTime and DATE_ADD(DATE_ADD(a.starttime, interval 1 hour), interval -1 second)
where time(a.StartTime) between '07:00' and '08:15'
group by a.Lane, a.StartTime
) x
group by Lane
order by Lane;
select Direction, max(SumCarCount) as MaxSumCarCount
from
(
select al.Direction, SUM(b.CarCount) SumCarCount
from TrafficData a
inner join LaneData al
on al.Lane = a.Lane
inner join TrafficData b
on b.StartTime between a.StartTime and DATE_ADD(DATE_ADD(a.starttime, interval 1 hour), interval -1 second)
inner join LaneData bl
on bl.Lane = b.Lane
and bl.Direction = al.Direction
where time(a.StartTime) between '07:00' and '08:15'
group by al.Direction, a.StartTime
) x
group by Direction
order by Direction;
ORIGINAL
Here's how I'd go about it in SQL Server:
--I'd change your table structure to be like this - that way you can easily add new lanes without rewriting the whole system
declare #trafficData table
(
StartTime DateTime
,Lane int
,CarCount int
)
--here's where you store additional info about the lanes (e.g. what direction they go in)
declare #laneData table
(
Lane int
, Direction bit --0 in, 1 out
)
--populate the tables with sample data
insert #laneData
select 1, 0
union select 2, 1
union select 3, 1
union select 4, 0
insert #trafficData
select dt, lane
, case lane
when 1 then l1
when 2 then l2
when 3 then l3
when 4 then l4
else null --should never happen
end
from
(
select '2012-09-18 5:45 AM' dt, 2 l1, 0 l2, 0 l3, 0 l4
union all select '2012-09-18 6:00 AM', 1, 0, 0, 1
union all select '2012-09-18 6:15 AM', 2, 1, 0, 0
union all select '2012-09-18 6:30 AM', 2, 1, 0, 0
union all select '2012-09-18 6:45 AM', 6, 1, 2, 1
union all select '2012-09-18 7:00 AM', 9, 1, 0, 3
union all select '2012-09-18 7:15 AM', 81, 12, 22, 15
union all select '2012-09-18 7:30 AM', 144, 31, 63, 56
union all select '2012-09-18 7:45 AM', 84, 30, 62, 42
union all select '2012-09-18 8:00 AM', 7, 1, 0, 3
union all select '2012-09-18 8:15 AM', 11, 2, 3, 3
union all select '2012-09-18 8:30 AM', 12, 3, 7, 1
union all select '2012-09-18 8:45 AM', 16, 4, 8, 0
union all select '2012-09-18 9:00 AM', 5, 2, 5, 0
union all select '2012-09-18 9:15 AM', 10, 1, 4, 0
) originalTable
cross join #laneData
--peak for each individual lane
select *
from
(
select a.Lane, a.StartTime, SUM(b.CarCount) SumCarCount
, ROW_NUMBER() over (partition by a.lane order by SUM(b.CarCount) desc) r
from #trafficData a
inner join #trafficData b
on b.Lane = a.Lane
and b.StartTime between a.StartTime and DATEADD(second,-1,DATEADD(hour,1,a.starttime))
group by a.Lane, a.StartTime
) x
where r = 1
order by Lane
--peak for lane direction
select *
from
(
select al.Direction, a.StartTime, SUM(b.CarCount) SumCarCount
, ROW_NUMBER() over (partition by al.Direction order by SUM(b.CarCount) desc) r
from #trafficData a
inner join #laneData al
on al.Lane = a.Lane
inner join #trafficData b
on b.StartTime between a.StartTime and DATEADD(second,-1,DATEADD(hour,1,a.starttime))
inner join #laneData bl
on bl.Lane = b.Lane
and bl.Direction = al.Direction
group by al.Direction, a.StartTime
) x
where r = 1
order by Direction