Run the followings swift codes in the 'Playground' but line2 get an error as shown below, why cannot access the optional value for the dictTest[1]! ?
var dictTest: [Int:String]? = [1:"A"]
dictTest[1]!
error:
value of optional type '[Int : String]?' not unwrapped; did you mean
to use '!' or '?'? dictTest[1]!
Modify the swift's code as shown below :
var dictTest: [Int:String]? = [1:"A"]
var dictTest2: [Int:String] = dictTest!
dictTest2[1]
I think the trick is that we have to unwrap the optional value before use it. Anyone who have the best answer, please advise!
Related
i have extracted the fix message as below from Unix server and now need to convert this message into JSON. how can we do this?
8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111
Note: I tried to make this a comment on the answer provided by #selbie, but the text was too long for a comment, so I am making it an answer.
#selbie's answer will work most of the time, but there are two edge cases in which it could fail.
First, in a tag=value field where the value is of type STRING, it is legal for value to contain the = character. To correctly cope with this possibility, the Java statement:
pair = item.split("=");
should be changed to:
pair = item.split("=", 2);
The second edge case is when there are a pair of fields, the first of which is of type LENGTH and the second is of type DATA. In this case, the value of the LENGTH fields specifies the length of the DATA field (without the delimiter), and it is legal for the value of the DATA field to contain the delimiter character (ASCII character 1, but denoted as | in both the question and Selbie's answer). Selbie's code cannot be modified in a trivial manner to deal with this edge case. Instead, you will need a more complex algorithm that consults a FIX data dictionary to determine the type of each field.
Since you didn't tag your question for any particular programming language, I'll give you a few sample solutions:
In javascript:
let s = "8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111"
let obj = {};
items = s.split("|")
items.forEach(item=>{
let pair = item.split("=");
obj[pair[0]] = pair[1];
});
let jsonString = JSON.stringify(obj);
Python:
import json
s = "8=FIXT.1.1|9=449|11=ABCD1|35=AE|34=1734|49=REPOFIXUAT|52=20140402-11:38:34|56=TR_UAT_VENDOR|1128=8|15=GBP|31=1.7666|32=50000000.00|55=GBP/USD|60=20140402-11:07:33|63=B|64=20140415|65=OR|75=20140402|150=F|167=FOR|194=1.7654|195=0.0012|460=4|571=7852455|1003=2 USD|1056=88330000.00|1057=N|552=1|54=2|37=20140402-12:36:48|11=NOREF|453=4|448=ZERO|447=D|452=3|448=MBY2|447=D|452=1|448=LMEB|447=D|452=16|448=DOR|447=D|452=11|826=0|78=1|79=default|80=50000000.00|5967=88330000.00|10=111"
obj = {}
for item in s.split("|"):
pair = item.split("=")
obj[pair[0]] = pair[1]
jsonString = json.dumps(obj)
Porting the above solutions to other languages is an exercise for yourself. There's comments below about semantic ordering and handling cases where the the = or | chars are part of the content. That's on you to explore if you need to support those scenarios.
<script type="text/javascript">
var destinationId = #(Model.DestinationId == 0?"":Model.DestinationId);
</script>
I want to output "" if Model.DestinationId is 0 else display Model.DestinationId
Because your C# code is trying to return a string when the if condition yields true and returns an int(value of DestinationId) when the condition expression returns false. The compiler is telling you that it is not valid! You need to return the same type from both the cases.
To fix the issue, return the same type from both the cases. You can use ToString() method on the int type property so that your ternary expression will always return the same type (string)
var destinationId = #(Model.DestinationId == 0 ? "" : Model.DestinationId.ToString());
Although the above will fix your compiler error, it might not be giving what you are after. The above code will render something like this when your DestinationId property value is 0.
var destinationId = ;
Which is going to give you a script error
Uncaught SyntaxError: Unexpected token ;
and when DestinationId property has a non zero value, for example, 10.
var destinationId = 10;
There are multiple ways to solve the issue. One simple approach is to replace the empty string with something JavaScript understands. Here in the below sample, I am rendering null as the value
var destinationId = #(Model.DestinationId == 0 ? "null" : Model.DestinationId.ToString());
if (destinationId===null) {
console.log('value does not exist');
}
else {
console.log('value is '+ destinationId);
}
Another option is to simply read the DestinationId property value and check for 0 in your JavaScript code as needed.
Another option is to wrap your entire C# expression in single or double quotes. But then again you number value will be represented as a string :(, which is not good.
I suggest you to use the correct type(even in JavaScript)
I don't understand why it is not working for the post hoc test. What did I do wrong?
modmisto<-lme(Cobertura~Tratamento, random=~1|Parcela, data=Cover_BraquiT3)
summary(modmisto)
tukey<-glht(modmisto, mcp(Tratamento="Tukey"))
Error in mcp2matrix(model, linfct = linfct) :
Variable(s) ‘Tratamento’ of class ‘character’ is/are not contained as a factor in ‘model’.
Any help with this will be very appreciated!
Tratatmento does not seem to be a factor variable, try put this before:
Cover_BraquiT3$Tratamento = as.factor(Cover_BraquiT3$Tratamento)
A variable in my data.frame was of type character.
The glht function did not recognize it as a factor in the model generated by the glm function.
I Tried:
variable = as.factor (variable)
I only managed using:
library (tibble)
data <-as_tibble (data)%>%
mutate (variable = factor (variable))
Hello I'm attempting delete a certain index in my array while using Angular2 and Typescript. I would like to retrieve the index from the value.
My array is declared normally...
RightList = [
'Fourth property',
'Fifth property',
'Sixth property',
]
I start out with a basic premise to set up my remove function.
removeSel(llist: ListComponent, rlist:ListComponent){
this.selectedllist = llist;
console.log(JSON.stringify(this.selectedllist)); // what is to be searched turned into a string so that it may actually be used
My console.log of my JSON.Stringify tells me that the value that I will attempt to remove is "Sixth property". However when I attempt to look for this value in my array using the following code. It returns -1 which means my value is not found in the array.
var rightDel = this.RightList.indexOf((JSON.stringify(this.selectedllist))); // -1 is not found 1 = found
console.log(rightDel);
On my output to the console it does return the item that is to be searched for but does not find the item in the array
CONSOLE OUTPUT:
"Sixth property" // Item to be searched for
-1 // not found
Is there something wrong in my implementation of my function that searches the array?
Of course indexOf will not find you item in array because
JSON.stringify(this.selectedllist) !== this.selectedllist
This is because JSON stringified string encodes quotes around literal, that original string doesn't have. It is easy to test:
var a = 'test';
console.log( JSON.stringify(a), a, JSON.stringify(a) === a )
Remove JSON.stringify and it should work. In general, to cast something to String type you should use its .toString() method, or simply wrap this something into String(something).
I am very new to the Erlang and I am getting badarg error when I try to convert binary to string as shown below.
Prefix = binary:bin_to_list(wh_json:get_ne_value(<<"prefix">>, Patterns)),
where Patterns are:
Pattern1--> {[{<<"prefix">>,<<>>},{<<"callerId">>,<<"1001">>},{<<"cid_regex">>,<<"^\\+?1001">>}]}
Pattern2--> {[{<<"prefix">>,<<"12">>},{<<"callerId">>,<<"1001">>},{<<"cid_regex">>,<<"^\\+?1001">>}]}
for Pattern2 it works fine but for Pattern1 I am getting this error because prefix does not have any value in Pattern1.
So, can any one tell me how I can handle this situation where prefix value can be null or any value, it should work for both the conditions.
Check whether wh_json:get_ne_value returns undefined before calling binary:bin_to_list:
Prefix =
case wh_json:get_ne_value(<<"prefix">>, Patterns) of
undefined ->
prefix_not_found;
BinaryPrefix when is_binary(BinaryPrefix) ->
binary:bin_to_list(BinaryPrefix)
end