I have 3 tables:
table products
table sub products
table stock.
I want to join these tables like in the result table below. In fact, I want All products that have least price and have count greater than zero and inserted as latest records!
How can I do the query?
more explain:
table product
----------------------------------
pid | title | desc | content |
----------------------------------
1 | lumia 920| ..... | ...... |
----------------------------------
2 | galaxys6 | .... | ...... |
----------------------------------
table sub_product
------------------------
subid |pid| name |
------------------------
1 | 1 | yellow |
------------------------
2 | 1 | black |
------------------------
3 | 2 | 32 GB |
table stock
-----------------------------------------------
sid |subid| price | count | inserted_date |
-----------------------------------------------
1 | 1 | 100 | 5 | 2015-01-01 |
-----------------------------------------------
2 | 1 | 150 | 9 | 2015-01-02 |
-----------------------------------------------
3 | 1 | 100 | 0 | 2015-02-02 |
-----------------------------------------------
4 | 2 | 111 | 1 | 2015-02-21 |
-----------------------------------------------
5 | 3 | 50 | 7 | 2015-02-01 |
-----------------------------------------------
6 | 3 | 10 | 4 | 2015-03-06 |
-----------------------------------------------
7 | 3 | 400 | 9 | 2015-06-06 |
-----------------------------------------------
table result
------------------------------------------------------------
pid |subid| title | name | price | count | inserted_date
------------------------------------------------------------
1 | 2 |lumia 920| black | 111 | 1 | 2015-02-21
------------------------------------------------------------
2 | 3 |galaxy s6| 32 GB | 10 | 4 | 2015-03-06
------------------------------------------------------------
as you see in product table we have two items lumia 920 and galaxy s6
and in sub_product we have 3 items that related to products.
also in stock I saved all modication of price and count of each item
so I want return latest modification of each sub_product as current state of it sub_prodct that has least price as result
but if count was zero should return another sub_product with mentioned conditions.
Select * From stock s Join sub_product sp On s.sub_productid = sp.sub_productid Join product p On p.productid = sp.productid
Where s.counte > 0 And s.date_insert in (Select MAX(date_insert) as d From stock ss
where s.sub_productid = ss.sub_productid group by sub_productid)
This query will return the all products that have least price and have count greater than 0 and latest records.
SELECT p.pid, sp.subid, p.title, sp.name, s.price, s.count, s.inserted_date
FROM product p
INNER JOIN sub_product sp ON sp.pid = p.pid
INNER JOIN stock s ON s.subid = sp.subid
WHERE s.count > 0
GROUP BY p.title
ORDER BY s.inserted_date DESC, s.price ASC
Try something like this:
SELECT prod.title, prod.desc, subProd.spid, subProd.pid, subProd.name, stk.price, stk.discount, stk.count, stk.inserted_date
FROM products AS prod
INNER JOIN sub_products AS subProd ON prod.pid = subProd.pid
INNER JOIN stock AS stk ON subProd.spid = stk.spid
AND stk.count > 0
AND stk.spid = (select spid from stock order by inserted_date desc limit 1)
Related
I have the following tables
table anag (customer registry)
id | surname | name | phone |
----------------------------------------------
1 | Brown | Jack | +3989265781 |
2 | Smith | Bill | +3954872358 |
3 | Rogers | Stan | +3912568453 |
4 | Pickford | Eric | +3948521358 |
----------------------------------------------
table levels (table that connects each customer to his salesperson. For database registration reasons, the link between customer and seller is given by the customer's telephone number)
id | client_phone | id_seller |
--------------------------------------
1 | +3989265781 | 4 |
2 | +3954872358 | 7 |
3 | +3912568453 | 7 |
4 | +3948521358 | 8 |
--------------------------------------
table orders (contains all purchases made by customers, of course)
id | id_client | id_item | id_seller | price | status |
--------------------------------------------------------------------
1 | 1 | 2 | 4 | 12.50 | 2 |
2 | 2 | 2 | 7 | 12.50 | 2 |
3 | 2 | 3 | 7 | 10.00 | 3 |
4 | 2 | 3 | 7 | 10.00 | 3 |
5 | 2 | 4 | 7 | 20.50 | 1 |
6 | 3 | 2 | 7 | 12.50 | 1 |
7 | 3 | 5 | 7 | 19.00 | 3 |
8 | 3 | 7 | 7 | 31.00 | 2 |
9 | 4 | 1 | 8 | 5.00 | 1 |
--------------------------------------------------------------------
What I'm trying to do is get from the JOIN of these tables a complete list by seller of his customers sorted in descending order by the amount spent on orders as long as the order status is 2 or 3
Something like this (example seller id 7):
id | surname | name | amaount |
----------------------------------------
3 | Rogers | Stan | 50.00 |
2 | Smith | Bill | 32.50 |
----------------------------------------
I have tried with this query which seems correct to me, but unfortunately it returns me error in fetch_assoc()
SELECT a.id, a.surname, a.name, o.amount FROM levels AS l
JOIN anag AS a ON a.phone = l.client_phone
JOIN {
SELECT id_client, SUM(price) AS amount FROM orders
WHERE id_seller = '7' AND (status = '2' OR status = '3') GROUP BY id_client
} AS o ON o.id_client = a.id
WHERE l.id_seller = '7'
ORDER BY o.amount DESC
If I separate the subquery from the main query, both return the data I expect and it seems strange to me the JOIN between the two does not work properly
I think the only real error is using curly braces instead of parentheses:
SELECT a.id, a.surname, a.name, o.amount
FROM levels l JOIN
anag a
ON a.phone = l.client_phone JOIN
(SELECT id_client, SUM(price) AS amount
FROM orders
WHERE id_seller = '7' AND status IN ('2', '3'))
GROUP BY id_client
) o
ON o.id_client = a.id
WHERE l.id_seller = '7'
ORDER BY o.amount DESC;
In addition:
You can use IN to shorten an equality comparison to multiple values.
Although I left them in, status and id_seller look like numbers. If so, drop the single quotes. Don't mix data types.
Your question is ambiguous on what to do if the seller in orders differs from the seller in anag for a customer. This keeps your logic (the sellers need to match).
SELECT a.id, a.surname, a.name, sum(o.price) 'amount'
FROM anag a
LEFT JOIN levels l ON l.id =a.id
LEFT JOIN orders of ON o.id_seller = l.id_seller AND o.id_client = l.id
GROUP BY o.id_seller
ORDER BY amount DESC
I want to know what is the top fruit on 2021-08-15 (completed with highest total price), table below:
product
------------------
id | name
------------------
1 | banana
2 | orange
3 | apple
4 | watermelon
5 | pineapple
sales
--------------------------------------------------------------------------------
s_id | sn.id | sn.product_id | sn.status | sn.total_price | created_at
--------------------------------------------------------------------------------
1 | 1 | 2 | BOOKED | 300 | 2021-08-15 12:20:32
| 2 | 5 | COMPLETED | 800 |
| 3 | 5 | COMPLETED | 200 |
2 | 4 | 2 | COMPLETED | 500 | 2021-08-16 09:00:59
| 5 | 1 | CANCELLED | 1000 |
How to write a query on a table with nested records?
Does MySQL even have nested record data type?
select *
from
(select p.id,p.name,sum(s.total_price) as sumOfSales
from product p join sales s on p.id = s.product_id
where s.status = "COMPLETED"
group by p.id,p.name) T
order by sumOfSales desc
I have the following tables:
Customer
| c_id | name |
| -------- | -------------- |
| 1 | Adam |
| 2 | Bradley |
| 3 | Chandler |
| 4 | Damian |
| 5 | Eric |
| 6 | Frank |
orders
| order_id | c_id | amount
| -------- | -------------- | -------------- |
| 1 | 1 | 50
| 2 | 1 | 2
| 3 | 2 | 15
| 4 | 2 | 22
| 5 | 2 | 10
| 6 | 2 | 7
| 7 | 3 | 7
| 8 | 3 | 2
| 9 | 5 | 18
| 10 | 5 | 24
| 11 | 6 | 60
| 12 | 6 | 1
I want to create a list of users who have order amounts over 50.
This list should include c_id, name and the sum of all their orders including those under 50.
so it should look like this:
| c_id | name | amount
| -------- | -------------- | -------------- |
| 1 |Adam | 52
| 6 | Frank | 61
You can use group by and having:
select c.c_id, c.name, sum(o.amount)
from orders o join
customers c
on o.c_id = c.c_id
group by c.c_id, c.name
having max(o.amount) > 50;
SELECT
c_id
, name
, SUM(amount) AS total_amount
FROM
orders a
INNER JOIN customer b
ON b.c_id = a.user_id
WHERE
c_id IN (
SELECT
user_id
FROM
orders
WHERE
amount >= 50)
GROUP BY c_id, name
Best to break this down into chunks:
Customers who have a total amount over 50:
SELECT user_id FROM orders GROUP BY user_id HAVING sum(amount) >= 50;
Sum of the amounts for each order for customers that meet the criteria above:
SELECT user_id, sum(amount) as order_total
FROM orders
WHERE user_id IN (SELECT user_id FROM orders HAVING sum(amount) >= 50 GROUP BY user_id)
GROUP BY user_id;
You can just join over to your customer table to grab the name. Didn't include since that is the more straightforward ask here.
I have a table for product, sales_item and a stock with following structure
Product table:
+----+-----+-------------+
| id |name |description |
+----+-----+-------------+
| 1 |Pr1 |prod1 |
+----+-----+-------------+
| 2 |Pr2 |prod2 |
+----+-----+-------------+
| .. |... |..... |
+----+-----+-------------+
sales_item_details table
+-----+----------+------------+-----+
| id | sales_id | product_id | qty |
+-----+----------+------------+-----+
| 517 | 211 | 1 | 200 |
+-----+----------+------------+-----+
| 518 | 211 | 1 | 120 |
+-----+----------+------------+-----+
and production
+----+------------+-------+
| id | product_id | qty |
+----+------------+-------+
| 1 | 1 | 20 |
| 2 | 2 | 200 |
| 3 | 1 | 20 |
| 4 | 3 | 30 |
| 5 | 9 | 30 |
| 6 | 65 | 10 |
| 7 | 65 | 50 |
| 8 | 71 | 10 |
| 9 | 71 | 10 |
| 10 | 71 | 10 |
+----+------------+-------+
And now I am creating multiple database with same table defination and need to maintain stock
production table and product table will be maintained from single database
only sales_item_details table will be different but product id will same
So how will be the query to get SUM(qty) of sales item details and view the inventory in stock
I have tried this:
SELECT
`pr`.`id`,
`pr`.`name`,
sl.size,
IFNULL(SUM(s.qty), 0) AS sales,
IFNULL((SELECT SUM(qty) FROM production st WHERE st.product_id = `pr`.`product-id`), 0) AS stock_added
FROM products pr
LEFT JOIN (
SELECT qty, product_id FROM db1.sales_item_details
UNION ALL
SELECT qty, product_id FROM db2.sales_item_details
) s ON pr.`id` = s.product_id
LEFT JOIN size_list sl ON sl.id = `pr`.`product-size`
GROUP BY s.product_id
ORDER BY sales DESC
but getting the product which is sold
Any help will be appriciated
1st I created a view holding all sales items grouped by product id in the main database:
CREATE OR REPLACE VIEW unit_sold_all AS
SELECT
p.`product-id` AS product_id,
(
(SELECT IFNULL(SUM(s0.qty), 0) FROM db_1.sales_item_details s0 WHERE s0.product_id = p.`product-id`) +
(SELECT IFNULL(SUM(s1.qty), 0) FROM db_2.sales_item_details s1 WHERE s1.product_id = p.`product-id`) +
(SELECT IFNULL(SUM(s2.qty), 0) FROM db_3.sales_item_details s2 WHERE s2.product_id = p.`product-id`) +
(SELECT IFNULL(SUM(s3.qty), 0) FROM db_4.sales_item_details s3 WHERE s3.product_id = p.`product-id`) +
(SELECT IFNULL(SUM(s4.qty), 0) FROM db_5.sales_item_details s4 WHERE s4.product_id = p.`product-id`)
) as total_unit_sales
FROM products p
Then in another sql, I selected the sum of the sales.
PS: I answered this question myself because this might need by another person in the future.
Is there any way to return distinct values with blank/null data from a table join. Best to explain with my example below.
Table "orders"
order_id | order_total
1 | 10
2 | 20
3 | 50
Table "order_items"
item_id | order_id | name | qty_ordered | base_price | row_total
1 | 1 | Product | 1 | 10 | 10
2 | 2 | Product | 1 | 10 | 10
3 | 2 | Product2 | 1 | 10 | 10
4 | 3 | Product | 2 | 10 | 20
5 | 3 | Product2 | 3 | 10 | 30
I'm trying to produce a result set that looks like this.
order_id | item_id | name | qty_ordered | base_price | row_total | order_total
1 | 1 | Product | 1 | 10 | 10 | 10
2 | 2 | Product | 1 | 10 | 10 | 20
null | 3 | Product2 | 1 | 10 | 10 | null
3 | 4 | Product | 2 | 10 | 20 | 50
null | 5 | Product2 | 3 | 10 | 30 | null
I only want the order_id and order_total once per order. I figure this is possible with some sort of join/distinct/sub query but alas nothing I've tried has worked so far.
Use:
SELECT x.order_id,
x.item_id,
x.name,
x.qty_ordered,
x.base_price,
x.row_total,
x.order_total
FROM (SELECT CASE
WHEN #order = o.order_id THEN NULL
ELSE o.order_id
END AS order_id,
oi.item_id,
oi.name,
oi.qty_ordered,
oi.base_price,
oi.row_total,
o.order_total,
CASE
WHEN #order = o.order_id THEN NULL
ELSE o.order_total
END AS order_total,
#order := o.order_id
FROM ORDER_ITEMS oi
JOIN ORDERS o ON o.order_id = oi.order_id
JOIN (SELECT #order := -1) r
ORDER BY o.order_id, oi.item_id) x
SELECT * FROM order_items
LEFT JOIN orders
ON (
order_items.order_id=orders.order_id
AND
order_items.item_id=(
SELECT MIN(item_id)
FROM order_items a
WHERE a.order_id=order_items.order_id
)
)
This should work because the nested query always returns the same MIN(item_id) for each order, and it only joins for that item.
But this is a very, very ugly piece of sql. Don't do this.