Gulp watch, running multiple tasks issue - gulp

Question

I'm trying to setup a Gulp task that converts Sass into CSS and then minifies it.
Here's my current gulpfile.js
// include gulp
var gulp = require('gulp');
var sass = require('gulp-sass');
var minifyCss = require('gulp-minify-css');
//gulp sass
gulp.task('sass', function () {
gulp.src('./scss/main.scss')
.pipe(sass().on('error', sass.logError))
.pipe(gulp.dest('./css'));
});
gulp.task('minify-css', function() {
return gulp.src('css/*.css')
.pipe(minifyCss({compatibility: 'ie8'}))
.pipe(gulp.dest('css'));
});
gulp.task('sass:watch', function () {
gulp.watch('./scss/main.scss', ['sass','minify-css']);
});
I run gulp sass:watch and I expect it to convert main.scss into main.css which it does and then I see that it also runs minify-css, but it doesn't actually minify it.
If I run gulp minify-css, it works perfectly. Can someone please tell me how this needs to be adjusted so gulp.watch runs both tasks, one after another?
Thank you

Answer 1

Looks like I got this work, by removing the additional task and combining the css minify into the sass portion.
// include gulp
var gulp = require('gulp');
var sass = require('gulp-sass');
var minifyCss = require('gulp-minify-css');
//gulp sass
gulp.task('sass', function () {
gulp.src('./scss/main.scss')
.pipe(sass().on('error', sass.logError))
.pipe(minifyCss({compatibility: 'ie8'}))
.pipe(gulp.dest('./css'));
});
// gulp.task('minify-css', function() {
// return gulp.src('css/*.css')
// .pipe(minifyCss({compatibility: 'ie8'}))
// .pipe(gulp.dest('css'));
// });
gulp.task('sass:watch', function () {
gulp.watch('./scss/main.scss', ['sass']);
});