Put sum() function into a view - mysql

Question

I have normalize my table to separate beetwen tb_header and tb_detail.
This is the tb_repair detail.
mysql> SELECT DETAIL_ID, REPAIR_ESTIMATE_ID, REMARKS, MANHOUR FROM tb_repair_detail;
+-----------+--------------------+----------------------+---------+
| DETAIL_ID | REPAIR_ESTIMATE_ID | REMARKS | MANHOUR |
+-----------+--------------------+----------------------+---------+
| 9 | 50 | Anda | 12.00 |
| 10 | 50 | Jika | 10.00 |
| 11 | 51 | ACRYLIC | 12.00 |
| 12 | 51 | Pembersihan exterior | 10.00 |
| 13 | 51 | Repairing | 10.00 |
+-----------+--------------------+----------------------+---------+
5 rows in set (0.00 sec)
Now, for more readable to user, now I want to create a view that would be like this :
mysql> SELECT a.REPAIR_ESTIMATE_ID , a.EIR_REF ,
-> (SELECT b.NAMA FROM tb_customer_master b WHERE a.COSTUMER_ID = b.COSTUMER_ID) AS "NAMA_CUSTOMER"
-> from tb_master_repair_estimate a ;
+--------------------+---------+----------------------+
| REPAIR_ESTIMATE_ID | EIR_REF | NAMA_CUSTOMER |
+--------------------+---------+----------------------+
| 50 | 1545053 | APL |
| 51 | 1545052 | APL |
+--------------------+---------+----------------------+
2 rows in set (0.00 sec)
My question is, I want to put the manhour total based REPAIR_ESTIMATE_ID How to put this manhour total in this view ? I know the query to sum() each REPAIR ESTIMATE_ID like
mysql> SELECT SUM(MANHOUR) AS TOTAL FROM tb_repair_detail a WHERE a.REPAIR_ESTIMATE_ID = 51
mysql> SELECT SUM(MANHOUR) AS TOTAL FROM tb_repair_detail a WHERE a.REPAIR_ESTIMATE_ID = 50;
+-------+
| TOTAL |
+-------+
| 22.00 |
+-------+
+-------+
| TOTAL |
+-------+
| 32.00 |
+-------+
1 row in set (0.00 sec)
But, how I get them into those view ?

Answer 1

SELECT a.repair_estimate_id, a.eir_ref, b.nama AS nama_customer, c.total
FROM tb_master_repair_estimate a, tb_customer_master b,
(SELECT repair_estimate_id, SUM(manhour) AS total
FROM tb_repair_detail
GROUP BY repair_estimate_id) c
WHERE a.repair_estimate_id = c.repair_estimate_id
AND a.COSTUMER_ID = b.COSTUMER_ID
should, I think, give the desired result set. Make that your view's query and you ought to be set.
Note the clause GROUP BY repair_estimate_id which causes the subquery to compute SUM(manhour) for each distinct value of repair_estimate_id.