I am trying to obtain comments made on a specific profile, but as soon as more than one person with a different relation (relation_id) to the profile has commented, I get duplicate, triplicate and so forth results.
Tables involved are as follows:
Users -
user_id
user_first_name
user_last_name
user_image path
Profile comments -
comment_id
profile_id
user_id
comment_body
comment_date
Profile_user_relation -
user_id
profile_id
relation_id
Relation_types -
relation_id
relation_name
My query is as follows:
SELECT profile_comments.*,
relation_types.relation_name,
users.user_first_name,
users.user_image_path
FROM profile_comments
LEFT JOIN profile_user_relation ON profile_comments.profile_id = profile_user_relation.profile_id
LEFT JOIN relation_types ON relation_types.relation_id = profile_user_relation.relation_id
LEFT JOIN users ON profile_comments.user_id = users.user_id
WHERE profile_comments.profile_id = :profileId
Thank you!
Didn't test it out, but I think it should work, or at least to get you a little bit closer.
SELECT
C.*,
RT.relation_name,
U.user_first_name,
U.user_image_path
FROM profile_comments AS C
JOIN users AS U USING(user_id)
JOIN profile_user_relation AS UR USING(user_id, profile_id)
JOIN relation_types AS RT USING(relation_id)
WHERE C.profile_id = :profileId
Hope that will be a bit helpful.
Related
Consider the following :
**Table 1 - record**
id (int primary key),
addedby (int),
editedby (int)
**Table 2 - users**
id (int primary),
name (shorttext)
**Sample Records**
record
0 1 1
1 1 2
users
1 user1
2 user2
What I need is so do a join to to be able to show the following :
record.id, users.addedby, users.editedby
I tried, amongst others, the following :
select record.id, users.name, users.name from record left join users on record.addedby=users.id left join users on record.editedby=users.id
However, it's not even logical that that will work, so I am a bit stuck.
Any help would be much appreciated. Thank you.
Just join the same table twice. Nothing unusual. You just have to alias the tables to be able to refer to them independently.
select r.id, u1.name added, u2.name editor
from record r
inner join user u1
on r.addedby = u1.id
inner join user u2
on r.editedby = u2.id
heres a demo
Use aliasses:
select record.id, users1.name, users2.name
from record
left join users users1 on record.addedby=users1.id
left join users users2 on record.editedby=users2.id
I need to write a query for a scout database that compares the requirements of a badge with the skills a given member has already earned. The purpose being that several skills are applicable to multiple badges. My relevant tables (there are many) look like this:
Badge_Table:
Badge_ID,
Badge_Name,
Badge_Description,
Badge_Skills_Table:
Badge_Skill_ID,
Badge_ID,
Skill_ID,
Skills_Table:
Skill_ID,
Skill_Name,
Skill_Description,
Skills_Earned_Table:
Skills_Earned_ID
Skill_ID
User_ID
User_Table:
User_ID,
Name,
Age,
Address
Primary keys are shown in italics, and the foreign key relationships go from Badge_table to Badge_Skills_Table to Skills_Table to Skills_Earned_table to User_Table.
So far I have came up with the following ideas:
Selects all badges for named skill
SELECT badge_table.badge_name
FROM (badge_table
INNER JOIN badge_skills_table ON badge_ID
INNER JOIN Skills_Table ON skill_Id)
WHERE Skills_Table.Skill_Id = 1;
Selects all badges for each skill
SELECT badge_table.badge_name
FROM (badge_table
INNER JOIN badge_skills_table ON badge_ID
INNER JOIN Skills_Table ON skill_Id)
WHERE Skills_Table.Skill_Id = Skill_Badge_Table.Skill_Id
Selects all badges for named skill for named User - not quite working
SELECT badge_table.badge_name
FROM (badge_table
INNER JOIN badge_skills_table ON badge_ID
INNER JOIN Skills_Table ON skill_Id
INNER JOIN Skills_Earned_Table On skill_ID
INNER JOIN users_table ON user_ID)
WHERE Skills_Earned_Table.User_ID= 1 AND Skills_Earned_Table.SKILL_ID = Skill_Badge_Table.skill_ID
So can anyone help guide me with the following:
How to return all badges that a given skill is applicable for. (Done)
How to return all badges that a given scout has earned skills towards.
To return all badges the a given scout has earned all the skills for.
I'd appreciate any help you can offer,
You have no <conditions> in your ON clause. Try my query below:
SELECT A.badge_name
FROM badge_table A
INNER JOIN badge_skills_table B ON A.badge_ID=B.badge_ID
INNER JOIN Skills_Table C ON B.skill_Id=C.skill_ID
INNER JOIN Skills_Earned_Table D ON C.skill_ID=D.skill_ID
INNER JOIN users_table E ON user_ID ON D.user_ID=E.user_ID
WHERE D.User_ID= 1 AND D.skill_ID = B.skill_ID
want mysql query for finding mutual friend between two friend but
I am maintain the friendship of user in one way relationship for ex.
first is users table
id name
1 abc
2 xyz
3 pqr
Now second table is friend
id user_id friend_id
1 1 2
2 1 3
3 2 3
Now here i can say that abc(id=1) is friend of xyz(id=2) now similar way the xyz is friend of abc but now i want to find mutual friend between abc(id=1) and xyz(id=2) that is pqr so I want mysql query for that.
REVISED
This query will consider the "one way" relationship of a row in the friend table to be a "two way" relationship. That is, it will consider a friend relationship: ('abc','xyz') to be equivalent to the inverse relationship: ('xyz','abc'). (NOTE: we don't have any guarantee that both rows won't appear in the table, so we need to be careful about that. The UNION operator conveniently eliminates duplicates for us.)
This query should satisfy the specification:
SELECT mf.id
, mf.name
FROM (
SELECT fr.user_id AS user_id
, fr.friend_id AS friend_id
FROM friend fr
JOIN users fru
ON fru.id = fr.user_id
WHERE fru.name IN ('abc','xyz')
UNION
SELECT fl.friend_id AS user_id
, fl.user_id AS friend_id
FROM friend fl
JOIN users flf
ON flf.id = fl.friend_id
WHERE flf.user IN ('abc','xyz')
) f
JOIN users mf
ON mf.id = f.friend_id
GROUP BY mf.id, mf.name
HAVING COUNT(1) = 2
ORDER BY mf.id, mf.name
SQL Fiddle here http://sqlfiddle.com/#!2/b23a5/2
A more detailed explanation of how we arrive at this is given below. The original queries below assumed that a row in the friend table represented a "one way" relationship, in that "'abc' ff 'xyz'" did not imply "'xyz' ff 'abc'". But additional comments from the OP hinted that this was not the case.
If there is a unique constraint on friend(user_id,friend_id), then one way to get the result would be to get all of the friends of each user, and get a count of rows for that friend. If the count is 2, then we know a particular friend_id appears for both user 'abc' and for 'xyz'
SELECT mf.id
, mf.name
FROM friend f
JOIN users uu
ON uu.id = f.user_id
JOIN users mf
ON mf.id = f.friend_id
WHERE uu.name IN ('abc','xyz')
GROUP BY mf.id, mf.name
HAVING COUNT(1) = 2
ORDER BY mf.id, mf.name
(This approach can also be extended to find a mutual friend of three or more users, by including more users in the IN list, and changing the value we compare the COUNT(1) to.
This isn't the only query that will return the specified resultset; there are other ways to get it as well.
Another way to get an equivalent result:
SELECT u.id
, u.name
FROM ( SELECT f1.friend_id
FROM friend f1
JOIN users u1
ON u1.id = f1.user_id
WHERE u1.name = 'abc'
) t1
JOIN ( SELECT f2.friend_id
FROM friend f2
JOIN users u2
ON u2.id = f2.user_id
WHERE u2.name = 'xyz'
) t2
ON t2.friend_id = t1.friend_id
JOIN users u
ON u.id = t1.friend_id
ORDER BY u.id, u.name
NOTES
These queries do not check whether user 'abc' is a friend of 'xyz' (the two user names specified in the WHERE clause). It is only finding the common friend of both 'abc' and 'xyz'.
FOLLOWUP
The queries above satisfy the specified requirements, and all the examples and test cases provided in the question.
Now it sounds as if you want a row in that relationship table to be considered a "two way" relationship rather than just a "one way" relationship. It sounds like you want to want to consider the friend relationship ('abc','xyz') equivalent to ('xyz','abc').
To get that, then all that needs to be done is to have the query create the inverse rows,, and that makes it easier to query. We just need to be careful that if both those rows ('abc','xyz') and ('xyz','abc') already exist, that we don't create duplicates of them when we invert them.
To create the inverse rows, we can use a query like this. (It's simpler to look at this when we don't have the JOIN to the users table, and we use just the id value:
SELECT fr.user_id
, fr.friend_id
FROM friend fr
WHERE fr.user_id IN (1,2)
UNION
SELECT fl.friend_id AS user_id
, fl.user_id AS friend_id
FROM friend fl
WHERE fl.friend_id IN (1,2)
It's simpler if we don't include the predicates on the user_id and friend_id table, but that could be a very large (and expensive) rowset to materialize.
try this:
given that you want to get the mutual friends of friends 1 & 2
select friend_id into #tbl1 from users where user_id = 1
select friend_id into #tbl2 from users where friend_id = 2
select id, name from users where id in(select friend_id from #tbl1 f1, #tbl2 f2 where f1.friend_id=f2.friend_id)
I am having a hard time understanding joins on mySQL, and I cannot find any similar example to work with.
Suppose I have two tables: users and users_info.
in users I have id, email and password fields while, in users_info I have all their information, like name, surname, street, etc.
so, if I am getting a user like this:
SELECT * FROM users WHERE id = 43
and their information like this:
SELECT * FROM users_info WHERE id = 43
I will basically get 2 results, and 2 tables.
I understand now that I need to use join so that they are all together, but I just can't figure out out.
Any help?
It seems like both tables users and user_info are related with each others by the column id therefore you need to join them using this column like this:
SELECT
u.id,
u.email,
u.password,
i.name,
i.surname,
i.street
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id;
This will only select the fields id, email, ... etc. However, if you want to select all the columns from both the tables use SELECT *:
SELECT *
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id;
If you want to input the id and get all of these data for a specific user, add a WHERE clause at the end of the query:
SELECT *
FROM users AS u
INNER JOIN user_info AS i ON u.id = i.id
WHERE u.id = 43;
For more information about JOIN kindly see the following:
Join (SQL)From Wikipedia.
Visual Representation of SQL Joins.
Another Visual Explanation of SQL Joins.
Here's an example
SELECT * FROM users u
INNER JOIN users_info i
ON u.id=i.id
this means, you are joining users table and users_info table
for example
users
id name
---- -------
1 abc
2 xyz
users_info
id email
--- ------
1 abc#aaa.com
2 xyz#aaa.com
the query will return
id name email
--- ----- -------
1 abc abc#aaa.com
2 xyz xyz#aaa.com
Here's a nice tutorial
You can also do:
SELECT users.*, users_info.*
FROM users, users_info
WHERE users.id = users_info.id AND users.id = 43;
This means:
"Get me all the columns from the users table, all the columns from the users_info table for the lines where the id column of users and the id column of users_info correspond to each other"
I have a table - comments. Users can post if not a member of the site but want to show their details if they are.
So if a user comments who is NOT a member I show their posts but don't link to their profile, because they don't have one.
So, in the following query I want to return the rows even if there is no join:
select wc.comment, wc.comment_by_name, wc.user_id, u.url from comments wc
join users u on wc.wag_uid = u.user_id
where id = '1237' group by wc.comment order by wc.dateadded desc
I want to return:
comment comment_by_name user_id url
------- --------------- ------- ----
hello dan 12 /dan
hey jane /jane
world jack 10 /jack
But the above does not return the data for jane as she does not have a user_id
Is there a way to return all data even if the join is null?
use LEFT JOIN instead
SELECT wc.comment, wc.comment_by_name, wc.user_id, u.url
FROM comments wc
LEFT JOIN users u
on wc.wag_uid = u.user_id
WHERE id = '1237'
GROUP BY wc.comment
ORDER BY wc.dateadded DESC
basically INNER JOIN only select records which a record from one table has atleast one match on the other table while LEFT JOIN select all rows from the left hand side table (in your case, it's comments) whether it has no match on the other table.