Get week over week data - mysql

Question

I have a table as follows
CREATE TABLE messages (
id int(10) UNSIGNED AUTO_INCREMENT NOT NULL,
messagetext text NOT NULL,
created_at timestamp NOT NULL DEFAULT '0000-00-00 00:00:00',
PRIMARY KEY(id)
)
What I would like to do is to get two weeks of data, the current week and the previous week, ordered by days. For example how many messages were created on Sunday, Monday, Tuesday,Wednesday.... for this week and the last week.
I do have a query as follows
SELECT
COUNT(id) AS 'Count'
FROM
'messages'
WHERE
(WEEK(created_at) = WEEK(NOW()))
GROUP BY
WEEKDAY(created_at)
ORDER BY
week(created_at) ASC,
weekday(created_at) ASC
but I don't know how to sort it day wise. For example the query above will list me how many did i get today or yesterday but that is not what what I want. What I would like to have is to get the count day wise as well as week wise.
Here is what I would like to have
Please let me know if i clear enough with the situation that I am facing.
Update:
For more information , please see Juan's question below
If the current days are less that 14 days , in that case, the script should return the count for the days that are in the previous week , not the week before the previous week. Here is how Juan explained (imagine today is friday. if you count 14 day back you get this week monday to friday. previous week monday to sunday... and prev prev week friday to sunday. And not sure if that is the result you want)
With Regards
Gagan

Answer 1

Use conditional SUM
SELECT week(created_at) week_id,
SUM( IF(weekday(created_at) = 0, 1, 0) ) as monday,
SUM( IF(weekday(created_at) = 1, 1, 0) ) as tuesday,
SUM( IF(weekday(created_at) = 2, 1, 0) ) as wednesday,
SUM( IF(weekday(created_at) = 3, 1, 0) ) as thursday,
SUM( IF(weekday(created_at) = 4, 1, 0) ) as friday,
SUM( IF(weekday(created_at) = 5, 1, 0) ) as saturday,
SUM( IF(weekday(created_at) = 6, 1, 0) ) as sunday
FROM 'messages'
WHERE created_at >= DATE_SUB(NOW(), INTERVAL 14 DAY)
AND ( week_id = WEEK( NOW() )
OR week_id = WEEK( DATE_SUB(NOW(), INTERVAL 7 DAY)
)
GROUP BY
week_id
ORDER BY
week_id

Answer 2

Im going to send a big guess. But did you try something like this?
SELECT
week(created_at) week_id,
weekday(created_at) weekday_id,
COUNT(id) AS 'Count'
FROM
'messages'
WHERE
week_id = WEEK( NOW() )
OR week_id = WEEK( DATE_SUB(NOW(), INTERVAL 7 DAY) )
GROUP BY
week_id, weekday_id
ORDER BY
week_id, weekday_id