I have a MySQL table called event to record the whole month data, and it has one column called EventTime to record the time each of them been written into database.
Could I query the data in specific time range, regardless of their date?
For Instance, I want to query the data between 12:00 and 18:00, then it could return all data which occur between the time range in the whole month?
I believe I could do it with a for-loop in my C# code, but I'd like to know is there any SQL command I could use?
You cast the column to TIME and query it.
example:
select time(event_time) from events where time(event_time) BETWEEN '10:00' and '11:00'
the downside of this approach is that the DB won't use any index on event_time (unless you created a function based index on time(event_time))
you can use Time Function here is complete detail of Date and Time Functions
-- it will pull all records within current Month i.e December Now and given Time Range.
Select Time(EventTime) from event where MONTH(EventTime) = Month(Current_Date) and time(EventTime) BETWEEN '12:00' and '18:00'
Related
So I'm working on a schedule system for my job a basically i wanted to know if there is a way where mysql can do something like:
|Monday |tuesday|wendsday|total
|Dan |5am-7am |7am-6pm|6am-11am|
11am-2pm| |2pm-7pm |
5pm-12am|
where i can enter multiple shifts on 1 day for each person in the same cell if needed instead of the name repeating several times like:
Dan|5-4|
Dan|6-8|
and if there is a function to calculate total time in one cell with multiple shifts
There is a way (representing the data as string), but you wouldn't want to do this - you will loose all calculations, searches etc.
You should not try to represent the data in the database exactly as how it looks on paper.
I would make a table like this:
ShiftID|Person|StartTime|EndTime
Making StartTime & EndTime columns of type DATETIME, you will store not only the HH:mm of a shift's start, but also the day. This is helpful when you have a shift which starts on one day and ends in the next, like starting on Monday 2017-05-15 23:00 and ending on Tuesday 2017-05-16 02:00.
You can extract the date only from this filed using MySQL DATE() function and select only those entires which start OR end on this day.
To calculate the shift's duration you can use MySQL function TIMESTAMPDIFF()
You can even use DAYOFWEEK() to get if it is Monday, Tuesday, etc.
About duplicating the person's name - I would make another table, which will match users with their data to IDs an use ID in the column Person, but for a starter and if your data is not big and if speed is not an issue and if typo errors (like Den instead of Dan) are not a problem ... you could use the name directly in this table.
After storing the data in a table like this you could represent it as you wish in HTML (or print).
You can create a third table with the following columns:
person_id int,
start_time datetime,
end_time datetime
Where person_id would be foreign key to Person table and start_time and end_time would be datetime columns. You can then store multiple records for a person in this table and use MySQL's date functions with GROUP BY to generate the report similar to the one in question.
I am having a table as follows in MYSQL:
proj_id|hoursWorked|Date.
The date field is of type Date; I want to retrieve all the entries from a table depending on a given week number for the project in my java based web application. Please help me to achieve this.
I am unable to write a single query that will allow me to do so.
Do not use something like WHERE WEEK(column)=something - this is a performance killer: It will calculate the week number on all rows, even if they don't match. In addition to that it will make it impossible to use an index ont this column.
Instead calculate an absolute begin and end date or point in time, depending on your data type, then use BETWEEN. This will do no calculations on non-matching rows and allow the use of an index.
Rule of thumb: If you have the choice between a calculation on a constant and on a field, use the former.
use MySQL WEEK() function.
SELECT WEEK(dateColumn)
FROM...
WHERE WEEK(dateColumn) = 1
WEEK()
from MySQL Docs
This function returns the week number for date. The two-argument form
of WEEK() enables you to specify whether the week starts on Sunday or
Monday and whether the return value should be in the range from 0 to
53 or from 1 to 53.
Use WEEK
select * from your_table
where week(`Date`) = week('2012-12-01')
If you want to get only records from the current week you can do
select * from your_table
where week(`Date`) = week(curdate())
So I have a row which shows when it was created! (i.e. 12/1/2013), and I have recurring patterns with frequencies associated with it.
Frequencies are from 1 to 6 and Recurring Patterns are Daily, Weekly, Monthly, and Yearly.
So users can set up recurring like {Frequency:1, Recurrence: Monthly} or {Frequency:2, Recurrence: Monthly}
I need a query that will take the current and the created date, and see if current date falls under the frequency.
so if the Created Date: 12/1/2013, and Today: 2/1/2014, the {frequency: 2, Recurrence: Monthly} would be valid.
try this sqlFiddle it uses a function that checks to see if the given date is recurring for each row in schedule
Assuming:
Recurrence has days associated and is stored in the database as daily=1, week=7, month=31, yearly=365
That you want valid or invalid returned
That your dates are in standard mysql date format
Then the below will work:
To get the difference in days between two dates use the DATEDIFF() function
To get the absolute value of an int use the ABS() function
To get the remainder of a dividend and divisor use the MOD() function
Here is some example code:
SELECT
IF(MOD((ABS(DATEDIFF(createdDate,'2014-02-01'))/days),frequency)=0,'valid','invalid') AS result
FROM
schedule
INNER JOIN recurringtypes ON schedule.recurringtypeId=recurringtypes.id
EDITED: SQLFiddle
If I have MySQL query like this, summing word frequencies per week:
SELECT
SUM(`city`),
SUM(`officers`),
SUM(`uk`),
SUM(`wednesday`),
DATE_FORMAT(`dateTime`, '%d/%m/%Y')
FROM myTable
WHERE dateTime BETWEEN '2011-09-28 18:00:00' AND '2011-10-29 18:59:00'
GROUP BY WEEK(dateTime)
The results given by MySQL take the first value of column dateTime, in this case 28/09/2011 which happens to be a Saturday.
Is it possible to adjust the query in MySQL to show the date upon which the week commences, even if there is no data available, so that for the above, 2011-09-28 would be replaced with 2011/09/26 instead? That is, the date of the start of the week, being a Monday. Or would it be better to adjust the dates programmatically after the query has run?
The dateTime column is in format 2011/10/02 12:05:00
It is possible to do it in SQL but it would be better to do it in your program code as it would be more efficient and easier. Also, while MySQL accepts your query, it doesn't quite make sense - you have DATE_FORMAT(dateTime, '%d/%m/%Y') in select's field list while you group by WEEK(dateTime). This means that the DB engine has to select random date from current group (week) for each row. Ie consider you have records for 27.09.2011, 28.09.2011 and 29.09.2011 - they all fall onto same week, so in the final resultset only one row is generated for those three records. Now which date out of those three should be picked for the DATE_FORMAT() call? Answer would be somewhat simpler if there is ORDER BY in the query but it still doesn't quite make sense to use fields/expressions in the field list which aren't in GROUP BY or which aren't aggregates. You should really return the week number in the select list (instead of DATE_FORMAT call) and then in your code calculate the start and end dates from it.
I have the following table in MySQL that records event counts of stuff happening each day
event_date event_count
2011-05-03 21
2011-05-04 12
2011-05-05 12
I want to be able to query this efficiently by date range AND by day of week. For example - "What is the event_count on Tuesdays in May?"
Currently the event_date field is a date type. Are there any functions in MySQL that let me query this column by day of week, or should I add another column to the table to store the day of week?
The table will hold hundreds of thousands of rows, so given a choice I'll choose the most efficient solution (as opposed to most simple).
Use DAYOFWEEK in your query, something like:
SELECT * FROM mytable WHERE MONTH(event_date) = 5 AND DAYOFWEEK(event_date) = 7;
This will find all info for Saturdays in May.
To get the fastest reads store a denormalized field that is the day of the week (and whatever else you need). That way you can index columns and avoid full table scans.
Just try the above first to see if it suits your needs and if it doesn't, add some extra columns and store the data on write. Just watch out for update anomalies (make sure you update the day_of_week column if you change event_date).
Note that the denormalized fields will increase the time taken to do writes, increase calculations on write, and take up more space. Make sure you really need the benefit and can measure that it helps you.
Check DAYOFWEEK() function
If you want textual representation of day of week - use DAYNAME() function.