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I need to find all entries that contain more than one colon (:) character.
However when I do LIKE %:% it shows the entire table because of http://. How can I find more than one colon?
SELECT *
FROM `downloads`
WHERE `url` LIKE '%:%'
LIMIT 0 , 30
If you want to find a colon that occurs after the scheme of your URL, then change your LIKE clause accordingly:
SELECT *
FROM `downloads`
WHERE `url` LIKE '%:%:%'
LIMIT 0 , 30
The first colon will be in your scheme, and the second will be somewhere else in the Url after the scheme.
A word of caution, however - it is completely valid to have a colon in the Url when a port number is specified, e.g.: http://localhost:8080
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How can I add brackets to each word of a string which contains multiple words in SQL? For example, I have:
string example = 'word1,word2,word3,word4,word5'
How can I convert it to something like this:
string example = '[word1],[word2],[word3],[word4],[word5]'
We can use a combination of REPLACE() and string concatenation:
SELECT val, CONCAT('[', REPLACE(val, ',', '],[') , ']') AS output
FROM yourTable;
On MySQL 8+, we can use a regex replacement:
SELECT val, REGEXP_REPLACE(val, '([^,]+)', '[$1]') AS output
FROM yourTable;
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How can I write check constraint for one column say class_id where check condition should be: string started with CLS and followed by any 5 digit number.
for e.g: CL100987, CLS45678
try using regex
something like that
WHERE REGEXP_LIKE (COLUMN_CONDITION,'^CLS.*([0-9]{5})');
| REGEXP_LIKE -> like specific to regex | column_condition ->
explicit | '^**." -> start with and followed by any char |
([0-9]) - > only numerics | {5} -> the number of numerics in the
expression
pay attention to your dbms, some differences
hope this could help
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I have two columns in a database I want to compare. One is email addresses and the other is username.
I'm looking to return results if the first part of username matches the first component of the email address (stuff before the # sign).
Sample data:
username emailaddress
badzzycshulzey9802 badzzycshulzey#gmail.com
trogleddg1919 trogleddg#gmail.com
Tried a variety of queries but I can't seem to get this one.... thanks!
You don't really need a regexp for this, strings functions can do it:
select *
from mytable
where username like concat(substr(emailaddress, 1, locate('#', emailaddress) - 1), '%')
locate('#', emailaddress) gives you the position of the arobas in the email address, and substr(emailaddress, 1, locate(...) - 1) extracts everything before that. Then, we can check if the username starts with that part of the email address using like with a wildcard on the right side.
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I want to append any character, say $, to the name of the student field in database such that its length is increased by 40 %, and save the result in the database.
E.g.:
Name: VijayKumar
After update:
Name: VijayKumar$$$$
You would use concat() and repeat():
select concat(name, repeat('$', ceil(length(name) * 0.4))
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MySQL does not support the Negative Lookahead. How can I find the result not containing a string using REGEXP.
I am using 'NOT REGEXP' but the result is unexpected.
there is a 'Content' column in my table,i want to find the rows which the Content column contains '' label,but i still want some src to be excluded.
here is the sql:
Content REGEXP '.' AND Content NOT REGEXP '.(test.mywebsite1.com/|img.mywebsite.com/face/|test.mywebsite.com/phoneIcon.jpg).*'
but when the Content contain both and it works unexpected;
Test your REGEXP on a known set, get that working, and verify it is working.
Then add the NOT to get the boolean inverse.
Note that a MySQL boolean expression will return one of three possible values: TRUE, FALSE and NULL.
And note that NOT expr will also return one of three possible values: TRUE, FALSE and NULL.
When expr returns NULL, then NOT expr will also return NULL.
It's not really productive to attempt to provide any other assistance, absent an actual question and more details of what you are attempting to do.