How to parse JSON into data structure - json

I am trying to parse a JSON of the type
"{\"ids\":[\"a\",\"b\"]}"
Here is my code:
package main
import "fmt"
import "encoding/json"
import "strings"
type Idlist struct {
id []string `json:"ids"`
}
func main() {
var val []byte = []byte(`"{\"ids\":[\"a\",\"b\"]}"`)
jsonBody, _ := strconv.Unquote(string(val))
var holder Idlist
if err := json.NewDecoder(strings.NewReader(jsonBody)).Decode(&holder); err!= nil{
fmt.Print(err)
}
fmt.Print(holder)
fmt.Print(holder.id)
}
However, I keep getting output
{[]}[]
I cannot get the data in the structure.
Where am I going wrong? Here is the playground link: https://play.golang.org/p/82BaUlfrua

Your struct has to look like :
type Idlist struct {
Id []string `json:"ids"`
}
Golang assumes that the fields starting with capital case are public. Hence, your fields are not visible to json decoder. For more details please look into this post :
Why Golang cannot generate json from struct with front lowercase character?

This is example how you can resolve your problem: http://play.golang.org/p/id4f4r9tEr
You might need to use strconv.Unquote on your string.
And this is probably duplicate: How to unmarshal an escaped JSON string in Go?
Resolved: https://play.golang.org/p/hAShmfDUA_
type Idlist struct {
Id []string `json:"ids"`
}

Related

How to convert json to string in golang and echo framework?

I have a json that I receive by post
{"endpoint": "assistance"}
I receive this like this
json_map: = make (map[string]interface{})
Now I need to assign it to a variable as a string but I don't know how to do it.
endpoint: = c.String (json_map ["endpoint"])
A type safe way to do this would be creating a struct that represents your request object and unmarshalling it.
This gives you a panic on unexpected requests.
package main
import (
"encoding/json"
"fmt"
)
type response struct {
Endpoint string
}
func main() {
jsonBody := []byte(`{"endpoint": "assistance"}`)
data := response{}
if err := json.Unmarshal(jsonBody, &data); err != nil {
panic(err)
}
fmt.Println(data.Endpoint)
}
// assistance
This program as an example safely decodes the JSON into a struct and prints the value.
What you are trying to achieve is not to convert a JSON to a string but an empty interface interface{} to a string You can achieve this by doing a type assertion:
endpoint, ok := json_map["endpoint"].(string)
if !ok {
// handle the error if the underlying type was not a string
}
Also as #Lex mentionned, it would probably be much safer to have a Go struct defining your JSON data. This way all your fields will be typed and you will no longer need this kind of type assertion.

Golang equivalent to Python json.dumps and json.loads

This is a very weird situation but I need to convert a stringified json to something valid that I can unmarshall with:
"{\"hello\": \"hi\"}"
I want to be able to unmarshall this into a struct like this:
type mystruct struct {
Hello string `json:"hello,string"`
}
I know normally the unmarshall takes bytes but Im trying to convert what I currently get into something structified.
Any suggestions?
The issue is that the encoding/json package accepts well-formed JSON, in this case the initial JSON that you have has escaped quotes, first you have to unescape them, one way to do this is by using the strconv.Unquote function, here's a sample snippet:
package main
import (
"encoding/json"
"fmt"
"strconv"
)
type mystruct struct {
Hello string `json:"hello,omitempty"`
}
func main() {
var rawJSON []byte = []byte(`"{\"hello\": \"hi\"}"`)
s, _ := strconv.Unquote(string(rawJSON))
var val mystruct
if err := json.Unmarshal([]byte(s), &val); err != nil {
// handle error
}
fmt.Println(s)
fmt.Println(err)
fmt.Println(val.Hello)
}

How to unmarshal json in golang when left part is a number

I'd like to unmarshal a json like this in the code. But this code doesn't work. Any suggestions? Thx!
PS. playground here http://play.golang.org/p/m2f94LY_d_
package main
import "encoding/json"
import "fmt"
type Response struct {
Page int
One string "1"
}
func main() {
in := []byte(`{"page":1, "1":"this is 1"}`)
res := &Response{}
json.Unmarshal(in, &res)
fmt.Println(res)
}
You need to tell the json library what the json field names are:
type Response struct {
Page int `json:"page"`
One string `json:"1"`
}
Live: http://play.golang.org/p/CNcvQMqBGD

JSON unmarshaling with long numbers gives floating point number

I was marshaling and unmarshaling JSONs using golang and when I want to do it with number fields golang transforms it in floating point numbers instead of use long numbers, for example.
I have the following JSON:
{
"id": 12423434,
"Name": "Fernando"
}
After marshal it to a map and unmarshal again to a json string I get:
{
"id":1.2423434e+07,
"Name":"Fernando"
}
As you can see the "id" field is in floating point notation.
The code that I am using is the following:
package main
import (
"encoding/json"
"fmt"
"os"
)
func main() {
//Create the Json string
var b = []byte(`
{
"id": 12423434,
"Name": "Fernando"
}
`)
//Marshal the json to a map
var f interface{}
json.Unmarshal(b, &f)
m := f.(map[string]interface{})
//print the map
fmt.Println(m)
//unmarshal the map to json
result,_:= json.Marshal(m)
//print the json
os.Stdout.Write(result)
}
It prints:
map[id:1.2423434e+07 Name:Fernando]
{"Name":"Fernando","id":1.2423434e+07}
It appears to be that the first marshal to the map generates the FP. How can I fix it to a long?
This is the link to the program in the goland playground:
http://play.golang.org/p/RRJ6uU4Uw-
There are times when you cannot define a struct in advance but still require numbers to pass through the marshal-unmarshal process unchanged.
In that case you can use the UseNumber method on json.Decoder, which causes all numbers to unmarshal as json.Number (which is just the original string representation of the number). This can also useful for storing very big integers in JSON.
For example:
package main
import (
"strings"
"encoding/json"
"fmt"
"log"
)
var data = `{
"id": 12423434,
"Name": "Fernando"
}`
func main() {
d := json.NewDecoder(strings.NewReader(data))
d.UseNumber()
var x interface{}
if err := d.Decode(&x); err != nil {
log.Fatal(err)
}
fmt.Printf("decoded to %#v\n", x)
result, err := json.Marshal(x)
if err != nil {
log.Fatal(err)
}
fmt.Printf("encoded to %s\n", result)
}
Result:
decoded to map[string]interface {}{"id":"12423434", "Name":"Fernando"}
encoded to {"Name":"Fernando","id":12423434}
The JSON standard doesn't have longs or floats, it only has numbers. The json package will assume float64 when you haven't defined anything else (meaning, only provided Unmarshal with an interface{}).
What you should do is to create a proper struct (as Volker mentioned):
package main
import (
"encoding/json"
"fmt"
"os"
)
type Person struct {
Id int64 `json:"id"`
Name string `json:"name"`
}
func main() {
//Create the Json string
var b = []byte(`{"id": 12423434, "Name": "Fernando"}`)
//Marshal the json to a proper struct
var f Person
json.Unmarshal(b, &f)
//print the person
fmt.Println(f)
//unmarshal the struct to json
result, _ := json.Marshal(f)
//print the json
os.Stdout.Write(result)
}
Result:
{12423434 Fernando}
{"id":12423434,"name":"Fernando"}
Playground: http://play.golang.org/p/2R76DYVgMK
Edit:
In case you have a dynamic json structure and wish to use the benefits of a struct, you can solve it using json.RawMessage. A variable of type json.RawMessage will store the raw JSON string so that you later on, when you know what kind of object it contains, can unmarshal it into the proper struct. No matter what solution you use, you will in any case need some if or switch statement where you determine what type of structure it is.
It is also useful when parts of the JSON data will only be copied to the another JSON object such as with the id-value of a JSON RPC request.
Example of container struct using json.RawMessage and the corresponding JSON data:
type Container struct {
Type string `json:"type"`
Data json.RawMessage `json:"data"`
}
var b = []byte(`{"type": "person", "data":{"id": 12423434, "Name": "Fernando"}}`)
A modified version of your example on Playground: http://play.golang.org/p/85s130Sthu
Edit2:
If the structure of your JSON value is based on the name of a name/value pair, you can do the same with a:
type Container map[string]json.RawMessage

Marshall and UnMarshall JSON Content in GoLang

I have a sample json file which is structured like this
{
"method":"brute_force",
"bc":"select * from blah;",
"gc":[
"select sum(year) from blah;",
"select count(*) from table;"
]
}
I am trying to write a go program which can read this file and operate of json content.
package main
import (
"fmt"
"encoding/json"
"io/ioutil"
)
type Response2 struct {
method string
bc string
gc []string
}
func main() {
file,_ := ioutil.ReadFile("config.json")
fmt.Printf("%s",string(file))
res := &Response2{}
json.Unmarshal([]byte(string(file)), &res)
fmt.Println(res)
fmt.Println(res.method)
fmt.Println(res.gc)
}
res.method and res.gc dont print anything. I have no idea on whats going wrong.
type Response2 struct {
method string
bc string
gc []string
}
The name of the fields Must be Uppercase otherwise the Json module can't access them (they are private to your module).
You can use the json tag to specify a match between Field and name
type Response2 struct {
Method string `json:"method"`
Bc string `json:"bc"`
Gc []string `json:"gc"`
}