I'm updating an existing table by adding data into an existing column.
I have already have an output of the data to be inserted, but due to the amount of records, i'm looking for the best way to insert this into my table without having to manually write to each line of sql.
Here's my sql (partial) i want to insert into
INSERT INTO `tbl_user_variables_dobRE` (`user_id`, `value`) VALUES
(150, '1959-11-02'),
(151, '1948-04-20'),
(152, '1961-06-18'),
And this is the table i want to insert it into
id | 7
username | guestinvite
password | BLANK
forname | forname
surname | surname
email | guestinvite#test.com
address_id | 286
type_id | 4
dob | 0000-00-00
plusGuest | 0
update | 2016-02-16 11:54:36
created | 2016-04-04 17:03:12
So i want to insert the second item into the 'dob' column where first item = id
Is there anyway to do this programmatically or do i have to write WHERE & OR statements for every line?
You tagged both MySql AND sql-server in your post. The following is assuming you're using SQL Server, but the idea would remain the same in MySQL (just different syntax)...
If I'm understanding correctly, it sounds like you want to do an UPDATE, not an INSERT, being that you're modifying existing rows.
You said that you have an output of the data to be inserted - Insert this into a TEMP table and JOIN it to the table you'd like to update where the id's match.
BEGIN TRANSACTION [Transaction1] -- Do large updates as transactions to avoid data loss
CREATE TABLE #temp ( -- Create temp table
[user_id] int,
[dob] nvarchar(20)
)
INSERT INTO #temp
-- YOUR SELECT GOES HERE
SELECT my_id as [user_id], my_dob as [dob]
UPDATE my_table
SET my_table.dob = t.dob
FROM tbl_user_variables_dobRE my_table
INNER JOIN #temp t ON t.user_id = my_table.id
DROP TABLE #temp
If your data looks good, commit the transaction: (Don't dwell too long, transactions lock table data!)
COMMIT TRANSACTION [Transaction1]
Otherwise:
ROLLBACK TRANSACTION [Transaction1]
The quickest way I can think of doing this is creating a temporary table with the new data that you want to add (you could possibly bulk import it all from say, a CSV file).
The temporary table will just need a couple of columns - one with user_id and the other one dob - you'll be getting rid of it after anyway.
You could then do something like this:
UPDATE tbl_user_variables_dobRE a
JOIN tmp_table b
ON ( a.user_id = b.user_id )
SET a.dob = b.dob
Once you've done that you can DROP your temporary table and be good to go - good luck!
Important
Be super-careful when updating data - it's so easy to mess up your data by forgetting to add a clause. If possible, do this with some test data before trying it with the real production data.
To the very basic query
SELECT id, column1, column2
FROM table1
WHERE id IN ("id1", "id2", "id3")
in which the the arguments in the where statement are passed as a variable, I need to return values also for rows where the id doesn't exist. In general, this is a very similar problem as outlined here: SQL: How to return an non-existing row? However, multiple parameters are in the WHERE statement
The result right now when id2 doesn't exist:
-------------------------------
| id | column1 | column2 |
-------------------------------
| id1 | some text | some text |
| id3 | some text | some text |
-------------------------------
Desired outcome when id2 doesn't exist
-----------------------------------
| id | column1 | column2 |
-----------------------------------
| id1 | some text | some text |
| id2 | placeholder | placeholder |
| id3 | some text | some text |
-----------------------------------
My first thought was to create a temporary table and join it against the query. Unfortunately, I don't have the rights to create any kind of temporary table so that I am limited to a SELECT statement.
Is there way to do that in with a SQL SELECT query?
Edit:
Indeed, the above mentioned is a hypothetical situation. In the WHERE clause can be hundreds of ids where the amount of missing in unknown.
You can do a derived table to create something like a temp table, but it can only be used for this one query:
SELECT t.id, COALESCE(t.column1, _dflt.column1) AS column1
FROM (
SELECT 'id1' AS id, 'placeholder text 1' as column1
UNION ALL
SELECT 'id2', 'placeholder text 3'
UNION ALL
SELECT 'id3', 'placeholder text 3'
) AS _dflt
LEFT OUTER JOIN table1 t USING (id);
Re comments:
I just tested the method above on MySQL 5.6.15 to see how many distinct SELECTs I can get with a series of UNION ALLs, one row per SELECT.
I got the derived table to return 5332 rows, but I think I could go higher if I had more RAM.
If I try one more UNION ALL, I get: ERROR 1064 (42000): memory exhausted near '' at line 10665. I only have 2.0GB of RAM configured on this VM.
It doesn't matter how many ids are unknown for this solution to work. Just put them all in the derived table. By using LEFT OUTER JOIN, it automatically finds those that exist in your table1, and for the ones that are missing, the entry from the derived table will be matched up with NULLs.
The COALESCE() function returns its first non-null argument, so it'll use columns from the matched rows if those are present. Where none is found, it'll default to the columns in the derived table.
Create a stored procedure that would take as input id1, id2 and so on...
DELIMITER //
CREATE PROCEDURE P1(IN p_in varchar(5))
BEGIN
DECLARE count integer;
SELECT count(id) INTO count FROM TABLE1
WHERE id = p_in;
IF count = 1 THEN
SELECT * from table1 where id = p_in;
ELSE
select p_id, 'some text', 'some text';
END IF;
END//
DELIMITER ;
The call the procedure to get desired output..
CALL P1('id1');
CALL P2('id2');
.. and so on from your program..
Project a derived table containing all the candidate ids you want, then left join to it:
select ids.id, coalesce(table1.column1,'placeholder')
From
(Select 'id1' as id
Union
Select 'id2'
Union
Select 'id3') ids
left join table1
on ids.id1 = table1.id1
and table1.id in (...);
If you are producing the list of candidate ids from an external source (e.g. an application), you could insert the ids into a temporary table and then join to it (MySql doesn't support table variables yet).
I have 2 mysql databases
DB1
DB2
I want to select all contact values from contact_mst table under DB1, and then insert all those values inside contact_mst table under DB2. I do not want to copy the contact_id field for some reason and want to keep them incremental, but also do not want them to be AUTO_INCREMENT as I have used 2 primary keys Company_id which is 1 and Contact_id which is auto generated using php code for some specific purpose.
So I made a SQL query for transfering data like this :
INSERT INTO DB2.contactsmaster (Company_id, Contact_id, Contact_person)
SELECT 1, (SELECT COALESCE(MAX(Contact_id),0)+1 FROM DB2.contactsmaster), Contact_person FROM DB1.contact_mst;
Which I think I have done something wrong, as this will not generate new IDS each time and in place will return Contact_id as 1 every time.
Any suggestion?
P.S. I just want to achieve this using SQL Query only. I know I can do this with PHP code but actually I want to supply .sql file to my client.
Below is the sample code for inserting records to table tab2 where value of column a is a sequence of integer and value of column b is same as value of column b of tab1
create table tab1
(
a int,
b int
);
create table tab2
(
a int,
b int
);
insert into tab1
values
(10,20),(30,40);
tab1 contents:
| a | b |
---------
|10 |20 |
|30 |40 |
insert into tab2
select #row := #row + 1, b FROM tab1 , (SELECT #row := 0) r
tab2 contents:
| a | b |
---------
|1 |20 |
|2 |40 |
Check the working of the query at sqlfiddle:
http://www.sqlfiddle.com/#!2/5f9a39/1
Let me know if it solved your problem or not.
try this
INSERT INTO DB2.contactsmaster (Company_id, Contact_id, Contact_person)
VALUES(
1,
(SELECT COALESCE(MAX(Contact_id),0)+1 FROM DB2.contactsmaster),
(SELECT Contact_person FROM DB1.contact_mst LIMIT 1)
)
To insert record with seprate key generate you need to use trigger for insert key
create bellow trigger in db2
CREATE TRIGGER `trg_before_insert` BEFORE INSERT ON `contactsmaster `
FOR EACH ROW
set new.Contact_id =(SELECT COALESCE(MAX(Contact_id),0)+1 FROM contactsmaster)
DELIMITER ;
after trigger created execute bellow sql
INSERT INTO DB2.contactsmaster (Company_id, Contact_person)
SELECT 1, Contact_person FROM DB1.contact_mst;
I need to DELETE duplicated rows for specified sid on a MySQL table.
How can I do this with an SQL query?
DELETE (DUPLICATED TITLES) FROM table WHERE SID = "1"
Something like this, but I don't know how to do it.
This removes duplicates in place, without making a new table.
ALTER IGNORE TABLE `table_name` ADD UNIQUE (title, SID)
Note: This only works well if index fits in memory.
Suppose you have a table employee, with the following columns:
employee (first_name, last_name, start_date)
In order to delete the rows with a duplicate first_name column:
delete
from employee using employee,
employee e1
where employee.id > e1.id
and employee.first_name = e1.first_name
Deleting duplicate rows in MySQL in-place, (Assuming you have a timestamp col to sort by) walkthrough:
Create the table and insert some rows:
create table penguins(foo int, bar varchar(15), baz datetime);
insert into penguins values(1, 'skipper', now());
insert into penguins values(1, 'skipper', now());
insert into penguins values(3, 'kowalski', now());
insert into penguins values(3, 'kowalski', now());
insert into penguins values(3, 'kowalski', now());
insert into penguins values(4, 'rico', now());
select * from penguins;
+------+----------+---------------------+
| foo | bar | baz |
+------+----------+---------------------+
| 1 | skipper | 2014-08-25 14:21:54 |
| 1 | skipper | 2014-08-25 14:21:59 |
| 3 | kowalski | 2014-08-25 14:22:09 |
| 3 | kowalski | 2014-08-25 14:22:13 |
| 3 | kowalski | 2014-08-25 14:22:15 |
| 4 | rico | 2014-08-25 14:22:22 |
+------+----------+---------------------+
6 rows in set (0.00 sec)
Remove the duplicates in place:
delete a
from penguins a
left join(
select max(baz) maxtimestamp, foo, bar
from penguins
group by foo, bar) b
on a.baz = maxtimestamp and
a.foo = b.foo and
a.bar = b.bar
where b.maxtimestamp IS NULL;
Query OK, 3 rows affected (0.01 sec)
select * from penguins;
+------+----------+---------------------+
| foo | bar | baz |
+------+----------+---------------------+
| 1 | skipper | 2014-08-25 14:21:59 |
| 3 | kowalski | 2014-08-25 14:22:15 |
| 4 | rico | 2014-08-25 14:22:22 |
+------+----------+---------------------+
3 rows in set (0.00 sec)
You're done, duplicate rows are removed, last one by timestamp is kept.
For those of you without a timestamp or unique column.
You don't have a timestamp or a unique index column to sort by? You're living in a state of degeneracy. You'll have to do additional steps to delete duplicate rows.
create the penguins table and add some rows
create table penguins(foo int, bar varchar(15));
insert into penguins values(1, 'skipper');
insert into penguins values(1, 'skipper');
insert into penguins values(3, 'kowalski');
insert into penguins values(3, 'kowalski');
insert into penguins values(3, 'kowalski');
insert into penguins values(4, 'rico');
select * from penguins;
# +------+----------+
# | foo | bar |
# +------+----------+
# | 1 | skipper |
# | 1 | skipper |
# | 3 | kowalski |
# | 3 | kowalski |
# | 3 | kowalski |
# | 4 | rico |
# +------+----------+
make a clone of the first table and copy into it.
drop table if exists penguins_copy;
create table penguins_copy as ( SELECT foo, bar FROM penguins );
#add an autoincrementing primary key:
ALTER TABLE penguins_copy ADD moo int AUTO_INCREMENT PRIMARY KEY first;
select * from penguins_copy;
# +-----+------+----------+
# | moo | foo | bar |
# +-----+------+----------+
# | 1 | 1 | skipper |
# | 2 | 1 | skipper |
# | 3 | 3 | kowalski |
# | 4 | 3 | kowalski |
# | 5 | 3 | kowalski |
# | 6 | 4 | rico |
# +-----+------+----------+
The max aggregate operates upon the new moo index:
delete a from penguins_copy a left join(
select max(moo) myindex, foo, bar
from penguins_copy
group by foo, bar) b
on a.moo = b.myindex and
a.foo = b.foo and
a.bar = b.bar
where b.myindex IS NULL;
#drop the extra column on the copied table
alter table penguins_copy drop moo;
select * from penguins_copy;
#drop the first table and put the copy table back:
drop table penguins;
create table penguins select * from penguins_copy;
observe and cleanup
drop table penguins_copy;
select * from penguins;
+------+----------+
| foo | bar |
+------+----------+
| 1 | skipper |
| 3 | kowalski |
| 4 | rico |
+------+----------+
Elapsed: 1458.359 milliseconds
What's that big SQL delete statement doing?
Table penguins with alias 'a' is left joined on a subset of table penguins called alias 'b'. The right hand table 'b' which is a subset finds the max timestamp [ or max moo ] grouped by columns foo and bar. This is matched to left hand table 'a'. (foo,bar,baz) on left has every row in the table. The right hand subset 'b' has a (maxtimestamp,foo,bar) which is matched to left only on the one that IS the max.
Every row that is not that max has value maxtimestamp of NULL. Filter down on those NULL rows and you have a set of all rows grouped by foo and bar that isn't the latest timestamp baz. Delete those ones.
Make a backup of the table before you run this.
Prevent this problem from ever happening again on this table:
If you got this to work, and it put out your "duplicate row" fire. Great. Now define a new composite unique key on your table (on those two columns) to prevent more duplicates from being added in the first place.
Like a good immune system, the bad rows shouldn't even be allowed in to the table at the time of insert. Later on all those programs adding duplicates will broadcast their protest, and when you fix them, this issue never comes up again.
Following remove duplicates for all SID-s, not only single one.
With temp table
CREATE TABLE table_temp AS
SELECT * FROM table GROUP BY title, SID;
DROP TABLE table;
RENAME TABLE table_temp TO table;
Since temp_table is freshly created it has no indexes. You'll need to recreate them after removing duplicates. You can check what indexes you have in the table with SHOW INDEXES IN table
Without temp table:
DELETE FROM `table` WHERE id IN (
SELECT all_duplicates.id FROM (
SELECT id FROM `table` WHERE (`title`, `SID`) IN (
SELECT `title`, `SID` FROM `table` GROUP BY `title`, `SID` having count(*) > 1
)
) AS all_duplicates
LEFT JOIN (
SELECT id FROM `table` GROUP BY `title`, `SID` having count(*) > 1
) AS grouped_duplicates
ON all_duplicates.id = grouped_duplicates.id
WHERE grouped_duplicates.id IS NULL
)
After running into this issue myself, on a huge database, I wasn't completely impressed with the performance of any of the other answers. I want to keep only the latest duplicate row, and delete the rest.
In a one-query statement, without a temp table, this worked best for me,
DELETE e.*
FROM employee e
WHERE id IN
(SELECT id
FROM (SELECT MIN(id) as id
FROM employee e2
GROUP BY first_name, last_name
HAVING COUNT(*) > 1) x);
The only caveat is that I have to run the query multiple times, but even with that, I found it worked better for me than the other options.
This always seems to work for me:
CREATE TABLE NoDupeTable LIKE DupeTable;
INSERT NoDupeTable SELECT * FROM DupeTable group by CommonField1,CommonFieldN;
Which keeps the lowest ID on each of the dupes and the rest of the non-dupe records.
I've also taken to doing the following so that the dupe issue no longer occurs after the removal:
CREATE TABLE NoDupeTable LIKE DupeTable;
Alter table NoDupeTable Add Unique `Unique` (CommonField1,CommonField2);
INSERT IGNORE NoDupeTable SELECT * FROM DupeTable;
In other words, I create a duplicate of the first table, add a unique index on the fields I don't want duplicates of, and then do an Insert IGNORE which has the advantage of not failing as a normal Insert would the first time it tried to add a duplicate record based on the two fields and rather ignores any such records.
Moving fwd it becomes impossible to create any duplicate records based on those two fields.
The following works for all tables
CREATE TABLE `noDup` LIKE `Dup` ;
INSERT `noDup` SELECT DISTINCT * FROM `Dup` ;
DROP TABLE `Dup` ;
ALTER TABLE `noDup` RENAME `Dup` ;
Here is a simple answer:
delete a from target_table a left JOIN (select max(id_field) as id, field_being_repeated
from target_table GROUP BY field_being_repeated) b
on a.field_being_repeated = b.field_being_repeated
and a.id_field = b.id_field
where b.id_field is null;
This work for me to remove old records:
delete from table where id in
(select min(e.id)
from (select * from table) e
group by column1, column2
having count(*) > 1
);
You can replace min(e.id) to max(e.id) to remove newest records.
delete p from
product p
inner join (
select max(id) as id, url from product
group by url
having count(*) > 1
) unik on unik.url = p.url and unik.id != p.id;
I find Werner's solution above to be the most convenient because it works regardless of the presence of a primary key, doesn't mess with tables, uses future-proof plain sql, is very understandable.
As I stated in my comment, that solution hasn't been properly explained though.
So this is mine, based on it.
1) add a new boolean column
alter table mytable add tokeep boolean;
2) add a constraint on the duplicated columns AND the new column
alter table mytable add constraint preventdupe unique (mycol1, mycol2, tokeep);
3) set the boolean column to true. This will succeed only on one of the duplicated rows because of the new constraint
update ignore mytable set tokeep = true;
4) delete rows that have not been marked as tokeep
delete from mytable where tokeep is null;
5) drop the added column
alter table mytable drop tokeep;
I suggest that you keep the constraint you added, so that new duplicates are prevented in the future.
This procedure will remove all duplicates (incl multiples) in a table, keeping the last duplicate. This is an extension of Retrieving last record in each group
Hope this is useful to someone.
DROP TABLE IF EXISTS UniqueIDs;
CREATE Temporary table UniqueIDs (id Int(11));
INSERT INTO UniqueIDs
(SELECT T1.ID FROM Table T1 LEFT JOIN Table T2 ON
(T1.Field1 = T2.Field1 AND T1.Field2 = T2.Field2 #Comparison Fields
AND T1.ID < T2.ID)
WHERE T2.ID IS NULL);
DELETE FROM Table WHERE id NOT IN (SELECT ID FROM UniqueIDs);
Another easy way... using UPDATE IGNORE:
U have to use an index on one or more columns (type index).
Create a new temporary reference column (not part of the index). In this column, you mark the uniques in by updating it with ignore clause. Step by step:
Add a temporary reference column to mark the uniques:
ALTER TABLE `yourtable` ADD `unique` VARCHAR(3) NOT NULL AFTER `lastcolname`;
=> this will add a column to your table.
Update the table, try to mark everything as unique, but ignore possible errors due to to duplicate key issue (records will be skipped):
UPDATE IGNORE `yourtable` SET `unique` = 'Yes' WHERE 1;
=> you will find your duplicate records will not be marked as unique = 'Yes', in other words only one of each set of duplicate records will be marked as unique.
Delete everything that's not unique:
DELETE * FROM `yourtable` WHERE `unique` <> 'Yes';
=> This will remove all duplicate records.
Drop the column...
ALTER TABLE `yourtable` DROP `unique`;
If you want to keep the row with the lowest id value:
DELETE n1 FROM 'yourTableName' n1, 'yourTableName' n2 WHERE n1.id > n2.id AND n1.email = n2.email
If you want to keep the row with the highest id value:
DELETE n1 FROM 'yourTableName' n1, 'yourTableName' n2 WHERE n1.id < n2.id AND n1.email = n2.email
Deleting duplicates on MySQL tables is a common issue, that usually comes with specific needs. In case anyone is interested, here (Remove duplicate rows in MySQL) I explain how to use a temporary table to delete MySQL duplicates in a reliable and fast way, also valid to handle big data sources (with examples for different use cases).
Ali, in your case, you can run something like this:
-- create a new temporary table
CREATE TABLE tmp_table1 LIKE table1;
-- add a unique constraint
ALTER TABLE tmp_table1 ADD UNIQUE(sid, title);
-- scan over the table to insert entries
INSERT IGNORE INTO tmp_table1 SELECT * FROM table1 ORDER BY sid;
-- rename tables
RENAME TABLE table1 TO backup_table1, tmp_table1 TO table1;
delete from `table` where `table`.`SID` in
(
select t.SID from table t join table t1 on t.title = t1.title where t.SID > t1.SID
)
Love #eric's answer but it doesn't seem to work if you have a really big table (I'm getting The SELECT would examine more than MAX_JOIN_SIZE rows; check your WHERE and use SET SQL_BIG_SELECTS=1 or SET MAX_JOIN_SIZE=# if the SELECT is okay when I try to run it). So I limited the join query to only consider the duplicate rows and I ended up with:
DELETE a FROM penguins a
LEFT JOIN (SELECT COUNT(baz) AS num, MIN(baz) AS keepBaz, foo
FROM penguins
GROUP BY deviceId HAVING num > 1) b
ON a.baz != b.keepBaz
AND a.foo = b.foo
WHERE b.foo IS NOT NULL
The WHERE clause in this case allows MySQL to ignore any row that doesn't have a duplicate and will also ignore if this is the first instance of the duplicate so only subsequent duplicates will be ignored. Change MIN(baz) to MAX(baz) to keep the last instance instead of the first.
This works for large tables:
CREATE Temporary table duplicates AS select max(id) as id, url from links group by url having count(*) > 1;
DELETE l from links l inner join duplicates ld on ld.id = l.id WHERE ld.id IS NOT NULL;
To delete oldest change max(id) to min(id)
This here will make the column column_name into a primary key, and in the meantime ignore all errors. So it will delete the rows with a duplicate value for column_name.
ALTER IGNORE TABLE `table_name` ADD PRIMARY KEY (`column_name`);
I think this will work by basically copying the table and emptying it then putting only the distinct values back into it but please double check it before doing it on large amounts of data.
Creates a carbon copy of your table
create table temp_table like oldtablename;
insert temp_table select * from oldtablename;
Empties your original table
DELETE * from oldtablename;
Copies all distinct values from the copied table back to your original table
INSERT oldtablename SELECT * from temp_table group by firstname,lastname,dob
Deletes your temp table.
Drop Table temp_table
You need to group by aLL fields that you want to keep distinct.
DELETE T2
FROM table_name T1
JOIN same_table_name T2 ON (T1.title = T2.title AND T1.ID <> T2.ID)
here is how I usually eliminate duplicates
add a temporary column, name it whatever you want(i'll refer as active)
group by the fields that you think shouldn't be duplicate and set their active to 1, grouping by will select only one of duplicate values(will not select duplicates)for that columns
delete the ones with active zero
drop column active
optionally(if fits to your purposes), add unique index for those columns to not have duplicates again
You could just use a DISTINCT clause to select the "cleaned up" list (and here is a very easy example on how to do that).
Could it work if you count them, and then add a limit to your delete query leaving just one?
For example, if you have two or more, write your query like this:
DELETE FROM table WHERE SID = 1 LIMIT 1;
There are just a few basic steps when removing duplicate data from your table:
Back up your table!
Find the duplicate rows
Remove the duplicate rows
Here is the full tutorial: https://blog.teamsql.io/deleting-duplicate-data-3541485b3473
I've got a table A with a column full of sentences.
I've got another table B with two columns: words and abbreviations.
I want to look through table A's column sentences and if a word from table B's word column matches then replace it with abbreviation.
Hope that is clear.
Case doesn't matter, I can deal with that. Assume everything is lower or upper or whatever.
You can't do this with SQL alone, you'd need to pull the data from the database, manipulate it and then push it back.
There's a bunch of ways to do it, some are simpler that others and some are more efficient.
For example a simple but slow method would be (in pseudocode)...
sentence_list = db.execute("SELECT id, sentence FROM A")
for sentence in sentence_list do
words = tokenize(sentence.text)
for word in words do
abbrev = db.execute("SELECT abbrev FROM B WHERE word=word")
if abbrev
word = abbrev
sentence.text = concat(words)
db.execute("UPDATE A SET sentence=" + sentence.text + " WHERE id = " + sentence.id + ")")
That's doing a query for every word in every sentence and not recommended for performance critical situations but it does the job.
I know it's an old question but since there is no answer, I'll give a try with this :
SQL Fiddle
MySQL 5.5.32 Schema Setup:
CREATE TABLE Table1
(`Id` int, `Sentence` varchar(80))
;
INSERT INTO Table1
(`Id`, `Sentence`)
VALUES
(1, 'Mister John is going to Los Angeles')
;
CREATE TABLE Table2
(`Id` int, `Word` varchar(60), `Abbrev` varchar(10))
;
INSERT INTO Table2
(`Id`, `Word`, `Abbrev`)
VALUES
(1, 'Mister', 'Mr.'),
(2, 'Los Angeles', 'L.A.')
;
DROP PROCEDURE IF EXISTS updateSentences //
CREATE PROCEDURE updateSentences()
BEGIN
DECLARE count INT;
SELECT COUNT(*) INTO count
FROM Table1
INNER JOIN Table2 ON CONCAT(' ',Sentence,' ') LIKE CONCAT('%',Word,'%');
WHILE count > 0 DO
UPDATE Table1
INNER JOIN (SELECT t1.id, Word,Abbrev
FROM Table1 t1
INNER JOIN Table2 ON CONCAT(' ',Sentence,' ') LIKE CONCAT('%',Word,'%')
LIMIT 1) Table2 ON Table1.Id = Table2.Id
SET Sentence = REPLACE(Sentence,Word,Abbrev);
SELECT COUNT(*) INTO count
FROM Table1
INNER JOIN Table2 ON CONCAT(' ',Sentence,' ') LIKE CONCAT('%',Word,'%');
END WHILE;
END//
Query:
SELECT *
FROM Table1
[Results]:
| ID | SENTENCE |
|----|-------------------------------------|
| 1 | Mister John is going to Los Angeles |
Query:
CALL updateSentences()
SELECT *
FROM Table1
Results:
| ID | SENTENCE |
|----|---------------------------|
| 1 | Mr. John is going to L.A. |
You could get crazy and add a mysql odbc connection in excel. Query the sentences in one query table, Query the lookup words in another table, and write a little macro that refreshes the tables then does a find and replace, then re-import it back into your table. I know in Ms sql, you can do all this automatically in DTS/SSIS.