I'm having the following file structure:
/ src
-- app.less
/ gulp
-- index.js
-- gulpfile.js
This file structure is mounted in a vagrant box in /vagrant which means the path to app.less becomes /vagrant/src/app.less. Yes, I've checked this.
gulpfile.js
require('./gulp');
index.js
var paths = {
less: '/vagrant/src/app.less'
};
gulp.task('less', function () {
console.log('less function running');
return gulp.src(paths.less)
.pipe(less());
});
gulp.task('watch:styles', function () {
console.log('watch function running');
gulp.watch(paths.less, gulp.series('less'));
});
gulp.task('watch', gulp.parallel('watch:styles'));
gulp -v returns:
[10:02:05] CLI version 0.4.0
[10:02:05] Local version 4.0.0-alpha.1
gulp watch returns:
[09:45:20] Using gulpfile /vagrant/gulpfile.js
[09:45:20] Starting 'watch'...
[09:45:20] Starting 'watch:styles'...
watch function running
I've been using Gulp 4 for over 2 months without problems with the watcher. Since last week the watcher is not responding to files that are being changed. I've tried several editors, I've tried multiple paths like '/vagrant/**/*.less' and '../src/*.less' and even the absolute path to app.less '/vagrant/src/app.less', none of them worked.
After some research I found several issues on the github repo of Gulp 4 about the watcher. Yet, I can't figure out what the problem is. Maybe I'm overlooking an error in my code or something new in the docs, but I'm trying to solve this since yesterday morning without any luck.
It appears you're using Vagrant. If you have Gulp running on your Vagrant machine instead of on the host it won't detect any changes to files that you make on the host. This is because the events that notify the OS about filesystem changes don't propagate into the VM.
If this is the case, the solution is to simply run Gulp wherever you actually make changes to the files (i.e. if you make the changes on the VM, run it on the VM, if you make changes on the host, run Gulp on the host).
Also maybe make the path relative, instead of tying your implementation to your Vagrant box. i.e. less: './src/app.less'.
Related
Short Question Version
Changes to files happen below a target directory. I have browsersync setup like this:
var bs = require("browser-sync").create();
// Start the browsersync server
bs.init({
server: './target'
});
bs.reload("*.html");
However this is not detecting changes that occur in target subdirectories and refreshing the browser. Seems that the above lines are not enough?
Long Question Version
I have built a CLI. It watches for CSS changes in src/main/css and compiles the CSS (Using PostCSS) to target/main/css. The same is enabled for html templates in src/main/html.
Gaze watches for file changes and runs the functions that performs the compiling and this part works fine.
The full source code can be seen here.
I was hoping BrowserSync would pickup on the file changes in the target directory and refresh the browser when edits are performed, however I'm not seeing any refreshes. I have BrowserSync setup like this within the serve command:
var bs = require("browser-sync").create();
// Start the browsersync server
bs.init({
server: './target'
});
bs.reload("*.html");
The CLI can be tested by doing:
git clone https://github.com/superflycss/cli
cd cli
npm i -g
Or just install from NPM:
npm i -g #superflycss/cli
Then run:
sfc new project
cd project
sfc serve
The target folder will open up in the browser. Change the URL to http://localhost:3000/test/html/. Edit the html in src/test/html/index.html. The changes compile to target/test/html/index.html and BrowserSync should pickup on the changes IIUC...but it's not...
Thoughts?
It's pretty obvious, but bs.reload("*.html"); has to be called from within the on event of the watcher. So in other words whenever there is a file change call bs.reload("*.html");.
Since I'm using gaze to watch for file changes, I ended up doing this:
gaze(PLI.SRC_MAIN_CSS, (err, watcher) => {
if (err) {
log('error', 'Error buliding src/main/css/ content.');
throw new Error(err);
}
/**
* Triggered both when new files are added and when files are changed.
*/
watcher.on('changed', function (filepath) {
buildMainCSS();
bs.reload("*.html");
});
});
Problem: I'm learning ES6 through playing around with the code. I found that it's quite annoying to rebuild and restart the server every time I made any changes.
Goal: I want the changes that I saved to be reflected on the browser, without having to manually rebuild, and restart the server. What's the simplest way to do that?
Background:
The current script configuration in the package.json file is as below.
"scripts": {
"babel": "babel --presets es2015 js/main.js -o build/main.bundle.js",
"start": "http-server -p 9000"
},
I hope this is clear. Thank you!
I believe you must be using gulp tasks to run your project. If so, browser-sync + gulp.watch() is the best option for this. Below is what working for me, add something like below to your gulp task .js file. Whenever you change and save your es6 source code, it will automatically build and refresh the browser.
var gulp = require('gulp');
var browser = require('browser-sync').create();
// your default task goes here that should add "watch-changes" as dependency
// watch changes in js and html files
gulp.task('watch-changes', function() {
browser.init({
// initiate your browser here, refer browser-sync website
});
gulp.watch(
['build/main.bundle.js', 'webapp/**/*.html'],
browser.reload);
});
Check here neat example.
Refer browser-sync website and npm gulp-watch task
I currently have a file structure like this
SASS
gulpfile.js
node_modules
sites
example-site
scss
css
example-site-two
scss
css
example-site-three
scss
css
I have gulp installed in the main parent SASS folder with a task 'sass-all' that can go through every single sites scss folder and compile it into css.
I'm trying to write a new task called 'sass-single' which can be run from any of the example-site folders. So let's say I'm in the folder "example-site-two", I want to be able to cmd and do 'gulp sass-single' and ONLY have it compile the SASS in this site. Same thing for a watch-single task I'd like to setup.
Problem is whenever I run this task from a site folder, it changes my working directory up to the parent SASS folder. I don't want to have 100 different tasks for every different site, I'd prefer to just have one 'sass-single' task thats smart enough to only compile the files from the folder I was in when I ran the script.
current Gulp task attempt
gulp.task('sass-single', function () {
process.chdir('./');
// Where are the SCSS files?
var input = './scss/*.scss';
// Where do you want to save the compiles CSS file?
var output = './css';
return gulp
.src(input)
.pipe(sourcemaps.init())
.pipe(sass(sassOptions).on('error', sass.logError))
.pipe(postcss(processors))
.pipe(sourcemaps.write('./maps'))
.pipe(gulp.dest(output));
});
However this goes back to the main SASS folder and then just does nothing.
How would I go about modifying this to be able to run from any site folder and have it only do it for that site?
If you want to change the current working directory (CWD) back to the directory where you invoked gulp then this won't work:
process.chdir('./');
That's a relative path. Relative paths are relative to the CWD. But by the time you execute process.chdir('./') Gulp has already changed the CWD to the directory where your Gulpfile.js is located. So you're just changing the CWD to ... the CWD.
You could explicitly pass a CWD to gulp on the command line:
SASS/sites/example-site> gulp --cwd .
But that would get annoying pretty quickly.
Luckily for you Gulp stores the original CWD in process.env.INIT_CWD before changing it. So you can use the following in your task to change the CWD back to the original:
process.chdir(process.env.INIT_CWD);
I have an isolated npm module with assets. I want to add gulp to this. Inside the project aside from my assets i have a bash script that downloads and updates my assets. I have been trying to find a way to create a gulp task that can run this script but i have not yet been able to get it to work. I tried the following and although it ran it did not run the script.
gulp.task('update-json', function(){
gulp.src('assets/update_json.sh');
});
I have the following set up within the assets/sass folder:
app.scss
- partials
_settings.scss
_main.scss
Now the issue is that when i run gulp watch, it runs all ok as a normal gulp, but then it just repeats the sass process, even when I have not touched anything, have anything in the files etc
It constantly runs the following over and over, sometime constantly or after a few seconds: The below is the loop thats is spat out within the terminal.
[20:49:30] Starting 'sass'...
[20:49:30] Running Sass: resources/assets/sass/app.scss
[20:49:30] gulp-notify: [Laravel Elixir] Sass Compiled!
[20:49:30] Finished 'sass' after 23 ms
Now doing several tests to see whats causing this, if i have DONT have any files with in the partials directory and just have code within the app.scssthen the gulp watchruns and simply waits for changes.
But as soon as I add a file within the sass folder or in the partials folder the gulp watch runs as I would expect, BUT this then never stops running the script...
I am using a simple elixir set up, for now:
elixir(function(mix) {
mix.sass('app.scss', 'public/js/main.css');
});
Any ideas why this is.
Running on a Homestead VM latest
Using latest elixir version
Laravel v.5.1.13
EDIT: Update
I was doing this outside the VM so thought to try to run this through the VM and it seems to be OK and run as expected...
I am running this outside the VM and so when run within the VM its runs as expected. But i do get the Error in plugin 'gulp-notify' not found: notify-senderror, but i can turn this off via adding process.env.DISABLE_NOTIFIER = true; to the top of the gulp file.