I have created a table where there are 3 entity id(type varchar), name(type varchar) and menu(type longtext). In the menu I have put some longtxt values, e.g
Now I want to get the id's or the names where the name=any one of the long text vales. I have tried, but simply it didn't succeed.
I think you are looking for FIND_IN_SET:
SELECT * FROM table WHERE FIND_IN_SET(`name`, `menu`);
Related
I have two use cases.
For all the columns in my table I am allowing user to search for contains. My query will be
Select * from table where column like "%value%";
When it comes to boolean columns and if they are searching for t/tr/tru/true I should be showing the results with
Select * from table where column is true;
Currently I am checking the entered string with a regular expression and hard coding the query. Is there a better way to achieve this ?
When the user query for equals to and the string contains special characters
Select * from table where column = "string with backslash escaped";
This query does not work but if I use like instead of = it works.
But like doesn't work for boolean columns.
You can use something like this to match against a boolean expression:
SELECT *
FROM my_table
WHERE IF(boolean_column, 'true', 'false') LIKE '%tr%';
The Like clause can be used only on text type of data (i.e VARCHAR, CHAR etc). Your logic should be more of finding out column name being searched and based on that define which operators to use.
If you have option to use a view in place of this table, you can create a view on this table and convert Boolean column to text based column which would allow you to search that column like all others.
I'm trying to select all rows that contain only specific alphanumeric characters in MySQL using:
SELECT * FROM table WHERE column LIKE '%abc%' OR column LIKE '%abd%'
OR column LIKE '%ab%'
For instance:
abc1234 is ok
abd1234 is ok
abe1234 is not ok
abg4567 is not ok
ab1234 is ok
ac1234 is not ok
The problem is, it select all the "abe","abg". How to select abc1234, abd1234 and ab1234?
With this
OR column LIKE '%ab%'
As part of the WHERE clause, it's no surprise that abe and abg are selected.
Please permit me to also mention that queries LIKE '%something%' cannot make use of any indexes and are likely to be very slow on large tables. The fact that you have three of them in one query is only going to make it worse.
Use the below Query which will also use indexes on column column
SELECT * FROM table WHERE column LIKE 'ab%' AND column not LIKE 'abe%'
AND column not LIKE 'abg%'
The Reason the indexes will be used in this case is the query is not using wildcard in the beginning of the string literal
Remove the last part of your query, it is telling it to select abg and abe.
You have told it to select all items beginning with anything and ending with anything providing ab is in the middle.
Because column LIKE '%ab%' will get "abe" or "abg"
If you want number after "ab", this is your query:
SELECT * FROM table WHERE column LIKE '%abc%' OR column LIKE '%abd%'
OR column LIKE '%ab0%' OR column LIKE '%ab1%' OR column LIKE '%ab2%' OR column LIKE '%ab3%' OR column LIKE '%ab4%' OR column LIKE '%ab5%' OR column LIKE '%ab6%' OR column LIKE '%ab7%' OR column LIKE '%ab8%' OR column LIKE '%ab9%'
Are you going to select column contain "abc" or "abd" or "ab" but not "abe"or "abg". For this case i don't think you can use LIKE. Try to use REGEXP. i think "ab[^g^e]?" should do the job for you.
SELECT name FROM table WHERE column REGEXP 'ab[^g^e]?';
I am trying to write a Query to find if a string contains part of the value in Column (Not to confuse with the query to find if a column contains part of a string).
Say for example I have a column in a table with values
ABC,XYZ
If I give search string
ABCDEFG
then I want the row with ABC to be displayed.
If my search string is XYZDSDS then the row with value XYZ should be displayed
The answer would be "use LIKE".
See the documentation: https://dev.mysql.com/doc/refman/5.0/en/string-comparison-functions.html
You can do WHERE 'string' LIKE CONCAT(column , '%')
Thus the query becomes:
select * from t1 where 'ABCDEFG' LIKE CONCAT(column1,'%');
If you need to match anywhere in the string:
select * from t1 where 'ABCDEFG' LIKE CONCAT('%',column1,'%');
Here you can see it working in a fiddle:
http://sqlfiddle.com/#!9/d1596/4
Select * from table where #param like '%' + col + '%'
First, you appear to be storing lists of things in a column. This is the wrong approach to storing values in the database. You should have a junction table, with one row per entity and value -- that is, a separate row for ABC and XYZ in your example. SQL has a great data structure for storing lists. It is called a "table", not a "string".
If you are stuck with such a format and using MySQL, there is a function that can help:
where find_in_set('ABC', col)
MySQL treats a comma delimited string as a "set" and offers this function. However, this function cannot use indexes, so it is not particularly efficient. Did I mention that you should use a junction table instead?
I am trying to INNER JOIN two tables on a text field, but I can't get it to work.
I've backtracked to see if I can identify where my query is falling down.
I've simplified my query to use only one table, to see if I can select data from it based on a text string.
I can't make it work.
I feel like an idiot.
This is so basic, why isn't it doing it?
select * from `my-table`
where myKey = "some-text-data-that-i-copied-from-the-data-in-the-table";
Returns no rows.
"some-text-data-that-i-copied-from-the-data-in-the-table" is in field myKey. I can see it. It's in the table!!!
[if it makes any difference I am most familiar with using an Access front-end and I am porting my "skills" to MySQL because MySQL is just better really.. this seems like the most run of the mill SELECT statement ever and yet it doesn't do anything!]
EDIT:
IMSoP does this help any...
select * from mymathssowlink
where MyMathsResourceKey = 'KS2-Number-Counting and Place Value-NC3-Negative Numbers 1';
EDIT 2:
Diego Marinelli - thanks - this returns data
select * from mymathssowlink
where MyMathsResourceKey like '%KS2%';
EDIT 3:
This works...
select * from mymathssowlink
where MyMathsResourceKey like '%KS2-Number-Counting and Place Value-NC3-Negative Numbers 1%';
EDIT 4:
But this still doesn't...
select * from mymathssowlink
where MyMathsResourceKey = 'KS2-Number-Counting and Place Value-NC3-Negative Numbers 1';
puzzled
Table:
CREATE TABLE `mymathssowlink` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`ObjectiveID` varchar(13),
`MyMathsResourceKey` varchar(100),
PRIMARY KEY (`ID`),
UNIQUE KEY `idnew_table_UNIQUE` (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
HOW IT GOT FIXED:
okay very weird but I have fixed the simplified problem now! I remember from my Access days that trailing spaces are the bane of matches and it seems the MySQL is a bit fiddly in this regard to. There was no problem with the data as such but the field MyMathsResourceKey was the last bit of data on each line and so not terminated with a comma. Some lines didn't have any data in that column and so were terminated with a comma rather than the MyMathsResourceKey data. I fixed it by adding a third column to my csv into which i uniformly stuck the string "PLACEHOLDER". I matched this to a column called placeholder in the table receiving the data. Now that the active (2nd column) is always terminated with a comma all the data seems to work. I can't help thinking that this is a bit odd and that MySQL data imports really don't want to be behaving like this... now to try an make my JOIN work, which how this all started!
Thanks to all, especially Rahul for the help.
... and the JOIN Works now...
Going by all the edits in your post and comments; what I feel is, there is extra space present in your column value and so you are not getting the data (since it's not matching the exact string).
So either try like
select * from mymathssowlink
where MyMathsResourceKey
like '%KS2-Number-Counting and Place Value-NC3-Negative Numbers 1%';
(OR)
Use a REPLACE() function to remove all spaces in the field value
select * from mymathssowlink
where REPLACE(MyMathsResourceKey, ' ', '')
= 'KS2-Number-Counting and Place Value-NC3-Negative Numbers 1';
You can as well use TRIM() function if you can guarantee that the spaces are present only in left/right extreme of the string.
select * from mymathssowlink
where TRIM(MyMathsResourceKey)
= 'KS2-Number-Counting and Place Value-NC3-Negative Numbers 1';
You can try Select * from table; and if that works then try select * from table where key like '%some_text%'
It could not be a problem with the sintax but with the query itself.
I am using mysql database ...
I have a table with col name food_type
in this field all the food types are in comma separated.
Now my problem is that i want to get the search result from them.
For Example:
Data in food_type col is like BBQ,Fast Food,Desi,Seafood,Vegetarian,
And I want to search BBQ,Seafood. But it can't give me the accurate result .
i try to use like in my sql query but same result :-(
How can I achieve this .
You could even use find_in_set() function
select * from table
where find_in_set('bbq',field_name) and find_in_set('Seafood',field_name)
but, as already written, your table needs to be normalized.
You can try 2 LIKE queries:
select * from table where field like "bbq" and field like "seafood"