I have a MySQL table which records values in a database when a user has paid by voucher. It records the voucher value. I need to get a total sum of all voucher values broken down by the voucher amount. The query I currently have is below. However the butchery_class_voucher_155 and butchery_class_voucher_135 are always returned as 0.
Please help to solve this problem.
select
case
when voucher_value = '155.00'
then round(sum(voucher_value/1.2), 2)
else 0.00 end
as butchery_class_voucher_155,
case
when voucher_value = '10.00'
then round(sum(voucher_value/1.2), 2)
else 0.00 end
as shop_voucher,
case when voucher_value = '135.00'
then round(sum(voucher_value/1.2), 2)
else 0.00 end
as butchery_class_voucher_135,
ifnull(round(sum(final_price/1.2), 2),0.00) as paidbycard,
ifnull(round(sum(transfer_fee/1.2), 2),0.00) as transfer_fee
from `bookings`
where `location_id` = 6
The problem is that you have the sum() call within a case, even though the cases (or ifs) should be inside the sum(). With your current code, if the 1st record has a voucher_value of 10, then only the shop_voucher expression will give you any result other than zero.
select
round(sum(if(voucher_value=155,voucher_value/1.2,0)), 2) as butchery_class_voucher_155,
...
from `bookings`
where `location_id` = 6
You need to consider one more thing: where exactly you put your rounding function. You can sum the results first and then round that (this is what is used in my code above), or you can apply the rounding at each and every division.
The reason this is failing is due to the way you have set up your case statement. You've written a query to give you the sum if the voucher_value equals a certain value, or to give you zero. On the last row the query analyzes, it will only compare that voucher value, and the others will return as 0.
To fix this, you need to adjust your SUM() function to add the voucher value in the case that the value matches, otherwise to add 0:
SELECT ROUND(SUM(CASE WHEN voucher_value = 155 THEN (voucher_value / 1.2) ELSE 0 END), 2) AS butchery_class_voucher_155...
And so on.
Related
I have a "CONTRACTS" table in which the user can select whether a Contract is "ANUAL" or "MONTHLY" (working on MariaDB/phpmyadmin)
The data is stored in the following manner:
CONTRACT
PERIOD
CICLE
SALE PRICE
CATEGORY
001
1
YEARLY
12000
CAT1
002
1
MONTHLY
1000
CAT2
I want to make a report that tells me the SUM of monthly contracts by CATEGORY
RIGHT NOW, THIS QUERY BELOW WORKS but its useless, since its doing SUM of "yearly" contracts along with monthly contracts
SELECT SUM(contracts.salesprice), `categories`.*
FROM `contracts`
LEFT JOIN `categories` ON `contratos`.`cat_id` = `categories`.`id_cat`
GROUP BY categorias.descripcion_cat;1
I'm a newbie and so far I was fine with INSERT, SELECT, UPDATE, DELETE;
I tried reading all documentation about CASE or IF, but I cant figure how to tell mysql to SUM based AND calculate on conditions
when CICLE = YEARLY then SALEPRICE /12 (to get the monthly value)
You were on the correct track with CASE.
The following code snippet will convert your yearly sales prices into monthly:
SUM(
CASE
WHEN contracts.cicle = 'YEARLY' THEN (contracts.salesprice / 12)
WHEN contracts.cicle = 'MONTHLY' THEN contracts.salesprice
ELSE 0
END
)
To use it in your query, simply replace your SUM(...) with that one.
To explain what it is doing, the CASE statement has several WHEN conditions. It uses the value of the first one that is true, if none are true, it will use the ELSE value (which you can change if you don't like 0). All of those resulting values are then summed up with SUM.
The benefit of CASE over IF is that CASE can be expanded as needed if you need more calculations for bi-annual, quarter, etc.
I want to check that lastdate to today is equal to 75 days or not. If it is equal then return 1 else return 0.
I tried below query which gives error-
Select (DATE_ADD(Last_date,CURDATE())=75 DAY) from assessment;
Please give me correct query to get the result-
You need to use CASE expression with DATEDIFF:
Select
CASE WHEN DATEDIFF(Last_date,CURDATE()) = 75 then 1 else 0 END AS col
from assessment
Note that: If last_date might be before or after the CUR_DATE, in this case you will get a negative results. Because:
DATEDIFF() returns expr1 − expr2 expressed as a value in days
So, you might need to get the absolute value of the difference using ABS:
Select
CASE WHEN ABS(DATEDIFF(Last_date,CURDATE()) = 75 then 1 else 0 END) AS col
from assessment
You need to use the MySQL DATEDIFF function
https://www.w3schools.com/sql/func_mysql_datediff.asp
I have written this query to get my data, and all the data is fine.
I have one column which has either Pass Or Fail. I want to calculate the % of number of bookings that failed, and output it in a single value.
I will have to write another query to show that one number.
For example : The below data, I have 4 bookings , out which 2 failed. So 50% is the failure rate. I am omitting some columns , in the display, but can be seen in the query.
That's an aggregation over all records and simple math:
select count(case when decision = 'Fail' then 1 end) / count(*) * 100
from (<your query here>) results;
Explanation: COUNT(something) counts non null values. case when decision = 'Fail' then 1 end is 1 (i.e. not null) for failures and null otherwise (as null is the default for no match in CASE/WHEN ‐ you could as well write else null end explicitly).
Modify your original condition to the following. Notice that there is no need to wrap your query in a subquery.
CONCAT(FORMAT((100 * SUM(CASE WHEN trip_rating.rating <= 3 AND
(TIMESTAMPDIFF(MINUTE,booking.pick_up_time,booking_activity.activity_time) -
ROUND(booking_tracking_detail.google_adjusted_duration_driver_coming/60)) /
TIMESTAMPDIFF(MINUTE,booking.pick_up_time,booking_activity.activity_time)*100 >= 15
THEN 1
ELSE 0
END) / COUNT(*)), 2), '%') AS failureRate
This will also format your failure rate in the format 50.0%, with a percentage sign.
I have searched SO for this question and found slightly similar posts but was unable to adapt to my needs.
I have a database with server requests since forever, each one with a timestamp and i'm trying to come up with a query that allows me to create a heatmatrix chart (CCC HeatGrid).
The sql query result must represent the server load grouped by each hour of each weekday.
Like this: Example table
I just need the SQL query, i know how to create the chart.
Thank you,
Those looks like "counts" of rows.
One of the issues is "sparse" data, we can address that later.
To get the day of the week ('Sunday','Monday',etc.) returned, you can use the DATE_FORMAT function. To get those ordered, we need to include an integer value 0 through 6, or 1 through 7. We can use an ORDER BY clause on that expression to get the rows returned in the order we want.
To get the "hour" across the top, we can use expressions in the SELECT list that conditionally increments the count.
Assuming your timestamp column is named ts, and assuming you want to pull all rows from the year 2014, we start with something like this:
SELECT DAYOFWEEK(t.ts)
, DATE_FORMAT(t.ts,'%W')
FROM mytable t
WHERE t.ts >= '2014-01-01'
AND t.ts < '2015-01-01'
GROUP BY DAYOFWEEK(t.ts)
ORDER BY DAYOFWEEK(t.ts)
(I need to check the MySQL documentation, WEEKDAY and DAYOFWEEK are real similar, but we want the one that returns lowest value for Sunday, and highest value for Saturday... i think we want DAYOFWEEK, easy enough to fix later)
The "trick" now is the columns across the top.
We can extract the "hour" from timestamp using the DATE_FORMAT() function, the HOUR() function, or an EXTRACT() function... take your pick.
The expressions we want are going to return a 1 if the timestamp is in the specified hour, and a zero otherwise. Then, we can use a SUM() aggregate to count up the 1. A boolean expression returns a value of 1 for TRUE and 0 for FALSE.
, SUM( HOUR(t.ts)=0 ) AS `h0`
, SUM( HOUR(t.ts)=1 ) AS `h1`
, SUM( HOUR(t.ts)=2 ) AS `h2`
, '...'
, SUM( HOUR(t.ts)=22 ) AS `h22`
, SUM( HOUR(t.ts)=23 ) AS `h23`
A boolean expression can also evaluate to NULL, but since we have a predicate (i.e. condition in the WHERE clause) that ensures us that ts can't be NULL, that won't be an issue.
The other issue we can encounter (as I mentioned earlier) is "sparse" data. To illustrate that, consider what happens (with our query) if there are no rows that have a ts value for a Monday. What happens is that we don't get a row in the resultset for Monday. If it does happen that a row is "missing" for Monday (or any day of the week), we do know that all of the hourly counts across the "missing" Monday row would all be zero.
I Need to retrieve values from database to plot them in graph. For that I need to get values on criteria basis. Data matching different criteria has to be returned as different rows/ column to my query
(i.e)
I have a table called TABLEA which has a column TIME. I need to get the value based on time critreia as a result, count of rows which are matching TIME>1 and TIME<10 as a result, TIME>11 and TIME <20 as a result and so on. Is it possible to get the values in a single query. I use Mysql with JDBC.
I should plot all the counts in a graph
Thanks in advance.
select sum(case when `time` between 2 and 9 then 1 else 0 end) as count_1,
sum(case when `time` between 12 and 19 then 1 else 0 end) as count_2
from your_table
This can be done with CASE statements, but they can get kind of verbose. You may just want to rely on Boolean (true/false) logic:
SELECT
SUM(TIME BETWEEN 1 AND 10) as `1 to 10`,
SUM(TIME BETWEEN 11 and 20) as `11 to 20`,
SUM(TIME BETWEEN 21 and 30) as `21 to 30`
FROM
TABLEA
The phrase TIME BETWEEN 1 AND 10) will either returnTRUEorFALSEfor each record.TRUEbeing equivalent to1andFALSEbeing equivalent to0`, we then only need sum the results and give our new field a name.
I also made the assumption that you wanted records where 1 <= TIME <= 10 instead of 1 < TIME < 10 which you stated since, as stated, it would drop values where the TIME was 1,10,20, etc. If that was your intended result, then you can just adjust the TIME BETWEEN 1 AND 10 to be TIME BETWEEN 2 AND 9 instead.