I need to generate date between 2015-1-1 and 2015-12-12
my recent code is here
set #startdate = '2015-1-10';
set #enddate = '2015-12-12';
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) - (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a where a.Date between #startdate and #enddate
from this code i have result truncated date start from 2015-7-29,
but if the code set date between 2016-01-01 and 2016-12-31 the result is generate full date (perfect)
Thanks for your help
I suspect the problem is that the values are converted to strings for the comparison.
I would just change the formats to be bona fide YYYY-MM-DD:
set #startdate = '2015-01-10';
-----------------------^
set #enddate = '2015-12-12';
However, the date function might also work:
where a.Date between date(#startdate) and date(#enddate)
EDIT:
I think you have two problems. First, your arithmetic is off, you are mixing + and -. Second, you are doing everything relative to the current date. You should use the start date. So:
select a.Date
from (select date_add(date(startdate), INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY) as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a
where a.Date between #startdate and #enddate;
Related
I want to get the Mondays between two dates with a select statement, but I only have searched in sql server.
I have tried this, but it doesn´t work:
SELECT DATE_ADD('2017-01-01', INTERVAL ROW DAY) AS Date
FROM (
SELECT #row := #row + 1 AS row
FROM (
SELECT 0 UNION ALL
SELECT 1 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6
) t1,
(
SELECT 0 UNION ALL
SELECT 1 UNION ALL
SELECT 3 UNION ALL
SELECT 4 UNION ALL
SELECT 5 UNION ALL
SELECT 6
) t2,
(
SELECT #row:=-1
) t3 LIMIT 31
) b
WHERE DATE_ADD('2017-01-01', INTERVAL ROW DAY) BETWEEN '2017-01-01' AND '2017-12-31'
AND DAYOFWEEK(DATE_ADD('2017-01-01', INTERVAL ROW DAY)) = 2
This query only gives me the Monday´s date for one month.
I hope that you can help me
Regards!
If you really want to solve this SQL only, you have to delve a bit deeper and generate a sequence of days, this is by far the most difficult side task to solve this. Besides this, as you have already guessed, you can use DAYOFWEEK or WEEKDAY to get your desired days.
SELECT *
FROM (
SELECT DATE_ADD('2013-01-01',
INTERVAL n4.num*1000+n3.num*100+n2.num*10+n1.num DAY ) AS DATE
FROM (
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n1,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n2,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n3,
(
SELECT 0 AS num
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
) AS n4
) AS a
WHERE DATE >= '2017-01-01' AND DATE < NOW()
AND WEEKDAY(DATE) = 0
ORDER BY DATE
Some other RDBMS have inbuild functions for that.
If would be way easier if you have a calendar table where all dates are already present.
I think that this solution will work with better performance than previous
SET #date_start = date('2019-07-06');
SET #date_end = date('2019-09-18');
SELECT CASE WHEN MOD(DAYOFWEEK(#date_start), 7) <= 2 AND
MOD(DAYOFWEEK(#date_start), 7) + DATEDIFF(v.selected_date, #date_start) - 7 * FLOOR(DATEDIFF(v.selected_date, #date_start) / 7) >= 2 OR
MOD(DAYOFWEEK(#date_start), 7) > 2 AND
MOD(DAYOFWEEK(#date_start), 7) + DATEDIFF(v.selected_date, #date_start) - 7 * FLOOR(DATEDIFF(v.selected_date, #date_start) / 7) >= 9 THEN 1 ELSE 0 END
+ FLOOR(DATEDIFF(v.selected_date, #date_start) / 7) num_of_mo
, #date_start start_date,v.selected_date end_date
FROM (select adddate(#date_start,t4*10000 + t3*1000 + t2*100 + t1*10 + t0) selected_date from
(select 0 t0 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
(select 0 t1 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
(select 0 t2 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
(select 0 t3 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
(select 0 t4 union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
WHERE v.selected_date <= #date_end;
I need to generate the days between two dates in sql like this:
generate days from date range
Im using this query:
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a
Works well but this generates always 1000 days. How can i generate any other number of days like 365?
You could add a limit clause (and an order by)
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all
select 3 union all select 4 union all select 5 union all
select 6 union all select 7 union all select 8 union all
select 9) as c
) a
order by 1 desc
limit 365
Or, if you are allowed to create temporary tables, in a more readable fashion - and extendable to 10,000 integers or more quite easily:
CREATE TEMPORARY TABLE units(idx)
ENGINE=MEMORY
AS (
SELECT 0
UNION ALL SELECT 1
UNION ALL SELECT 2
UNION ALL SELECT 3
UNION ALL SELECT 4
UNION ALL SELECT 5
UNION ALL SELECT 6
UNION ALL SELECT 7
UNION ALL SELECT 8
UNION ALL SELECT 9
);
SELECT a.the_date
FROM (
SELECT curdate() - INTERVAL (hundreds + tens + units) DAY AS the_date
FROM (SELECT idx AS units FROM units) units
CROSS JOIN (SELECT idx* 10 AS tens FROM units) tens
CROSS JOIN (SELECT idx* 100 AS hundreds FROM units) hundreds
WHERE hundreds + tens + units < 365
) AS a
ORDER BY 1
;
I need to convert this query from MySQL format to SQLite. I'm trying myself but I've found some difficulty.
In SQLite, the curdate() and the interval functions do not exist.
select a.Date
from (
select curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a
where a.Date between '2010-01-20' and '2010-01-24'
What this query actually does is just generating lots of consecutive dates (up to one thousand previous days).
In SQLite 3.8.3 or later, this can be done more easily with a recursive common table expression:
WITH RECURSIVE dates(d)
AS (VALUES('2010-01-20')
UNION ALL
SELECT date(d, '+1 day')
FROM dates
WHERE d < '2010-01-24')
SELECT d AS date FROM dates;
Here is the basic syntax:
select a.Date
from (select date('now', '-'||(a.a + (10 * b.a) + (100 * c.a))|| ' days') as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9
) a cross join
(select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9
) b cross join
(select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9
) c
) a;
I left out the where clause because those dates are more than 1000 days in the past, so they won't select anything anyway.
How can i create a list of all the month names e.g January, February etc.. between two dates. e.g 2012-02-01 to 2013-03-29 with MySQL .. whereas February will be generated twice, one for the year 2012 and the other 2013
I guess this is what you're looking for:
select MonthName(aDate) from (
select #maxDate - interval (a.a + (10 * b.a) + (100 * c.a)) month as aDate from
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) a,
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) b,
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) c,
(select #minDate := '2012-02-01', #maxDate := '2013-03-29') d
) e
where aDate between #minDate and #maxDate
Just in case someone finds this post and finds it a bit harder to understand it I'm a adding a short explanation:
This is a dynamically (and a bit ugly) solution to creating a date range that does not require creating a table and is based on the following query which generates enough records for most applications (10000 records):
select aDate from (
select #maxDate - interval (a.a+(10*b.a)+(100*c.a)+(1000*d.a)) day aDate from
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) a, /*10 day range*/
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) b, /*100 day range*/
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) c, /*1000 day range*/
(select 0 as a union all select 1 union all select 2 union all select 3
union all select 4 union all select 5 union all select 6 union all
select 7 union all select 8 union all select 9) d, /*10000 day range*/
(select #minDate := '2001-01-01', #maxDate := '2002-02-02') e
) f
where aDate between #minDate and #maxDate
Depending on the length of the date range you can reduce the amount of dynamically generated results (10000 days means over 27 years of records each representing one day) by removing tables (d, c, b and a in that order) and also removing them from the upper formula. Setting the #minDate and #maxDate variables will allow you to specify the dates between you want to filter the results.
I'm looking to make a date lookup table that will allow me to match some pivots together in excel and I was wondering how to go about taking the first of every week and adding it to a new mysql table?
This query selects all sundays of 2011. Expand it for the years you need and insert this select into a table of your choice.
select a.Date
from (
select DATE('2011-12-31') - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) DAY as Date
from (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as a
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as b
cross join (select 0 as a union all select 1 union all select 2 union all select 3 union all select 4 union all select 5 union all select 6 union all select 7 union all select 8 union all select 9) as c
) a
where DAYOFWEEK(a.Date)=1 and a.Date between '2011-01-01' and '2011-12-31'
Reference