I have a table listing people along with their date of birth (currently a nvarchar(25))
How can I convert that to a date, and then calculate their age in years?
My data looks as follows
ID Name DOB
1 John 1992-01-09 00:00:00
2 Sally 1959-05-20 00:00:00
I would like to see:
ID Name AGE DOB
1 John 17 1992-01-09 00:00:00
2 Sally 50 1959-05-20 00:00:00
There are issues with leap year/days and the following method, see the update below:
try this:
DECLARE #dob datetime
SET #dob='1992-01-09 00:00:00'
SELECT DATEDIFF(hour,#dob,GETDATE())/8766.0 AS AgeYearsDecimal
,CONVERT(int,ROUND(DATEDIFF(hour,#dob,GETDATE())/8766.0,0)) AS AgeYearsIntRound
,DATEDIFF(hour,#dob,GETDATE())/8766 AS AgeYearsIntTrunc
OUTPUT:
AgeYearsDecimal AgeYearsIntRound AgeYearsIntTrunc
--------------------------------------- ---------------- ----------------
17.767054 18 17
(1 row(s) affected)
UPDATE here are some more accurate methods:
BEST METHOD FOR YEARS IN INT
DECLARE #Now datetime, #Dob datetime
SELECT #Now='1990-05-05', #Dob='1980-05-05' --results in 10
--SELECT #Now='1990-05-04', #Dob='1980-05-05' --results in 9
--SELECT #Now='1989-05-06', #Dob='1980-05-05' --results in 9
--SELECT #Now='1990-05-06', #Dob='1980-05-05' --results in 10
--SELECT #Now='1990-12-06', #Dob='1980-05-05' --results in 10
--SELECT #Now='1991-05-04', #Dob='1980-05-05' --results in 10
SELECT
(CONVERT(int,CONVERT(char(8),#Now,112))-CONVERT(char(8),#Dob,112))/10000 AS AgeIntYears
you can change the above 10000 to 10000.0 and get decimals, but it will not be as accurate as the method below.
BEST METHOD FOR YEARS IN DECIMAL
DECLARE #Now datetime, #Dob datetime
SELECT #Now='1990-05-05', #Dob='1980-05-05' --results in 10.000000000000
--SELECT #Now='1990-05-04', #Dob='1980-05-05' --results in 9.997260273973
--SELECT #Now='1989-05-06', #Dob='1980-05-05' --results in 9.002739726027
--SELECT #Now='1990-05-06', #Dob='1980-05-05' --results in 10.002739726027
--SELECT #Now='1990-12-06', #Dob='1980-05-05' --results in 10.589041095890
--SELECT #Now='1991-05-04', #Dob='1980-05-05' --results in 10.997260273973
SELECT 1.0* DateDiff(yy,#Dob,#Now)
+CASE
WHEN #Now >= DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)) THEN --birthday has happened for the #now year, so add some portion onto the year difference
( 1.0 --force automatic conversions from int to decimal
* DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)),#Now) --number of days difference between the #Now year birthday and the #Now day
/ DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),1,1),DATEFROMPARTS(DATEPART(yyyy,#Now)+1,1,1)) --number of days in the #Now year
)
ELSE --birthday has not been reached for the last year, so remove some portion of the year difference
-1 --remove this fractional difference onto the age
* ( -1.0 --force automatic conversions from int to decimal
* DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),DATEPART(m,#Dob),DATEPART(d,#Dob)),#Now) --number of days difference between the #Now year birthday and the #Now day
/ DATEDIFF(day,DATEFROMPARTS(DATEPART(yyyy,#Now),1,1),DATEFROMPARTS(DATEPART(yyyy,#Now)+1,1,1)) --number of days in the #Now year
)
END AS AgeYearsDecimal
Gotta throw this one out there. If you convert the date using the 112 style (yyyymmdd) to a number you can use a calculation like this...
(yyyyMMdd - yyyyMMdd) / 10000 = difference in full years
declare #as_of datetime, #bday datetime;
select #as_of = '2009/10/15', #bday = '1980/4/20'
select
Convert(Char(8),#as_of,112),
Convert(Char(8),#bday,112),
0 + Convert(Char(8),#as_of,112) - Convert(Char(8),#bday,112),
(0 + Convert(Char(8),#as_of,112) - Convert(Char(8),#bday,112)) / 10000
output
20091015 19800420 290595 29
I have used this query in our production code for nearly 10 years:
SELECT FLOOR((CAST (GetDate() AS INTEGER) - CAST(Date_of_birth AS INTEGER)) / 365.25) AS Age
You need to consider the way the datediff command rounds.
SELECT CASE WHEN dateadd(year, datediff (year, DOB, getdate()), DOB) > getdate()
THEN datediff(year, DOB, getdate()) - 1
ELSE datediff(year, DOB, getdate())
END as Age
FROM <table>
Which I adapted from here.
Note that it will consider 28th February as the birthday of a leapling for non-leap years e.g. a person born on 29 Feb 2020 will be considered 1 year old on 28 Feb 2021 instead of 01 Mar 2021.
So many of the above solutions are wrong DateDiff(yy,#Dob, #PassedDate) will not consider the month and day of both dates. Also taking the dart parts and comparing only works if they're properly ordered.
THE FOLLOWING CODE WORKS AND IS VERY SIMPLE:
create function [dbo].[AgeAtDate](
#DOB datetime,
#PassedDate datetime
)
returns int
with SCHEMABINDING
as
begin
declare #iMonthDayDob int
declare #iMonthDayPassedDate int
select #iMonthDayDob = CAST(datepart (mm,#DOB) * 100 + datepart (dd,#DOB) AS int)
select #iMonthDayPassedDate = CAST(datepart (mm,#PassedDate) * 100 + datepart (dd,#PassedDate) AS int)
return DateDiff(yy,#DOB, #PassedDate)
- CASE WHEN #iMonthDayDob <= #iMonthDayPassedDate
THEN 0
ELSE 1
END
End
EDIT: THIS ANSWER IS INCORRECT. I leave it in here as a warning to anyone tempted to use dayofyear, with a further edit at the end.
If, like me, you do not want to divide by fractional days or risk rounding/leap year errors, I applaud #Bacon Bits comment in a post above https://stackoverflow.com/a/1572257/489865 where he says:
If we're talking about human ages, you should calculate it the way
humans calculate age. It has nothing to do with how fast the earth
moves and everything to do with the calendar. Every time the same
month and day elapses as the date of birth, you increment age by 1.
This means the following is the most accurate because it mirrors what
humans mean when they say "age".
He then offers:
DATEDIFF(yy, #date, GETDATE()) -
CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE()))
THEN 1 ELSE 0 END
There are several suggestions here involving comparing the month & day (and some get it wrong, failing to allow for the OR as correctly here!). But nobody has offered dayofyear, which seems so simple and much shorter. I offer:
DATEDIFF(year, #date, GETDATE()) -
CASE WHEN DATEPART(dayofyear, #date) > DATEPART(dayofyear, GETDATE()) THEN 1 ELSE 0 END
[Note: Nowhere in SQL BOL/MSDN is what DATEPART(dayofyear, ...) returns actually documented! I understand it to be a number in the range 1--366; most importantly, it does not change by locale as per DATEPART(weekday, ...) & SET DATEFIRST.]
EDIT: Why dayofyear goes wrong: As user #AeroX has commented, if the birth/start date is after February in a non leap year, the age is incremented one day early when the current/end date is a leap year, e.g. '2015-05-26', '2016-05-25' gives an age of 1 when it should still be 0. Comparing the dayofyear in different years is clearly dangerous. So using MONTH() and DAY() is necessary after all.
I believe this is similar to other ones posted here.... but this solution worked for the leap year examples 02/29/1976 to 03/01/2011 and also worked for the case for the first year.. like 07/04/2011 to 07/03/2012 which the last one posted about leap year solution did not work for that first year use case.
SELECT FLOOR(DATEDIFF(DAY, #date1 , #date2) / 365.25)
Found here.
Since there isn't one simple answer that always gives the correct age, here's what I came up with.
SELECT DATEDIFF(YY, DateOfBirth, GETDATE()) -
CASE WHEN RIGHT(CONVERT(VARCHAR(6), GETDATE(), 12), 4) >=
RIGHT(CONVERT(VARCHAR(6), DateOfBirth, 12), 4)
THEN 0 ELSE 1 END AS AGE
This gets the year difference between the birth date and the current date. Then it subtracts a year if the birthdate hasn't passed yet.
Accurate all the time - regardless of leap years or how close to the birthdate.
Best of all - no function.
I've done a lot of thinking and searching about this and I have 3 solutions that
calculate age correctly
are short (mostly)
are (mostly) very understandable.
Here are testing values:
DECLARE #NOW DATETIME = '2013-07-04 23:59:59'
DECLARE #DOB DATETIME = '1986-07-05'
Solution 1: I found this approach in one js library. It's my favourite.
DATEDIFF(YY, #DOB, #NOW) -
CASE WHEN DATEADD(YY, DATEDIFF(YY, #DOB, #NOW), #DOB) > #NOW THEN 1 ELSE 0 END
It's actually adding difference in years to DOB and if it is bigger than current date then subtracts one year. Simple right? The only thing is that difference in years is duplicated here.
But if you don't need to use it inline you can write it like this:
DECLARE #AGE INT = DATEDIFF(YY, #DOB, #NOW)
IF DATEADD(YY, #AGE, #DOB) > #NOW
SET #AGE = #AGE - 1
Solution 2: This one I originally copied from #bacon-bits. It's the easiest to understand but a bit long.
DATEDIFF(YY, #DOB, #NOW) -
CASE WHEN MONTH(#DOB) > MONTH(#NOW)
OR MONTH(#DOB) = MONTH(#NOW) AND DAY(#DOB) > DAY(#NOW)
THEN 1 ELSE 0 END
It's basically calculating age as we humans do.
Solution 3: My friend refactored it into this:
DATEDIFF(YY, #DOB, #NOW) -
CEILING(0.5 * SIGN((MONTH(#DOB) - MONTH(#NOW)) * 50 + DAY(#DOB) - DAY(#NOW)))
This one is the shortest but it's most difficult to understand. 50 is just a weight so the day difference is only important when months are the same. SIGN function is for transforming whatever value it gets to -1, 0 or 1. CEILING(0.5 * is the same as Math.max(0, value) but there is no such thing in SQL.
What about:
DECLARE #DOB datetime
SET #DOB='19851125'
SELECT Datepart(yy,convert(date,GETDATE())-#DOB)-1900
Wouldn't that avoid all those rounding, truncating and ofsetting issues?
Just check whether the below answer is feasible.
DECLARE #BirthDate DATE = '09/06/1979'
SELECT
(
YEAR(GETDATE()) - YEAR(#BirthDate) -
CASE WHEN (MONTH(GETDATE()) * 100) + DATEPART(dd, GETDATE()) >
(MONTH(#BirthDate) * 100) + DATEPART(dd, #BirthDate)
THEN 1
ELSE 0
END
)
select floor((datediff(day,0,#today) - datediff(day,0,#birthdate)) / 365.2425) as age
There are a lot of 365.25 answers here. Remember how leap years are defined:
Every four years
except every 100 years
except every 400 years
There are many answers to this question, but I think this one is close to the truth.
The datediff(year,…,…) function, as we all know, only counts the boundaries crossed by the date part, in this case the year. As a result it ignores the rest of the year.
This will only give the age in completed years if the year were to start on the birthday. It probably doesn’t, but we can fake it by adjusting the asking date back by the same amount.
In pseudopseudo code, it’s something like this:
adjusted_today = today - month(dob) + 1 - day(dob) + 1
age = year(adjusted_today - dob)
The + 1 is to allow for the fact that the month and day numbers start from 1 and not 0.
The reason we subtract the month and the day separately rather than the day of the year is because February has the annoying tendency to change its length.
The calculation in SQL is:
datediff(year,dob,dateadd(month,-month(dob)+1,dateadd(day,-day(dob)+1,today)))
where dob and today are presumed to be the date of birth and the asking date.
You can test this as follows:
WITH dates AS (
SELECT
cast('2022-03-01' as date) AS today,
cast('1943-02-25' as date) AS dob
)
select
datediff(year,dob,dateadd(month,-month(dob)+1,dateadd(day,-day(dob)+1,today))) AS age
from dates;
which gives you George Harrison’s age in completed years.
This is much cleaner than fiddling about with quarter days which will generally give you misleading values on the edges.
If you have the luxury of creating a scalar function, you can use something like this:
DROP FUNCTION IF EXISTS age;
GO
CREATE FUNCTION age(#dob date, #today date) RETURNS INT AS
BEGIN
SET #today = dateadd(month,-month(#dob)+1,#today);
SET #today = dateadd(day,-day(#dob)+1,#today);
RETURN datediff(year,#dob,#today);
END;
GO
Remember, you need to call dbo.age() because, well, Microsoft.
DECLARE #DOB datetime
set #DOB ='11/25/1985'
select floor(
( cast(convert(varchar(8),getdate(),112) as int)-
cast(convert(varchar(8),#DOB,112) as int) ) / 10000
)
source: http://beginsql.wordpress.com/2012/04/26/how-to-calculate-age-in-sql-server/
Try This
DECLARE #date datetime, #tmpdate datetime, #years int, #months int, #days int
SELECT #date = '08/16/84'
SELECT #tmpdate = #date
SELECT #years = DATEDIFF(yy, #tmpdate, GETDATE()) - CASE WHEN (MONTH(#date) > MONTH(GETDATE())) OR (MONTH(#date) = MONTH(GETDATE()) AND DAY(#date) > DAY(GETDATE())) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(yy, #years, #tmpdate)
SELECT #months = DATEDIFF(m, #tmpdate, GETDATE()) - CASE WHEN DAY(#date) > DAY(GETDATE()) THEN 1 ELSE 0 END
SELECT #tmpdate = DATEADD(m, #months, #tmpdate)
SELECT #days = DATEDIFF(d, #tmpdate, GETDATE())
SELECT Convert(Varchar(Max),#years)+' Years '+ Convert(Varchar(max),#months) + ' Months '+Convert(Varchar(Max), #days)+'days'
After trying MANY methods, this works 100% of the time using the modern MS SQL FORMAT function instead of convert to style 112. Either would work but this is the least code.
Can anyone find a date combination which does not work? I don't think there is one :)
--Set parameters, or choose from table.column instead:
DECLARE #DOB DATE = '2000/02/29' -- If #DOB is a leap day...
,#ToDate DATE = '2018/03/01' --...there birthday in this calculation will be
--0+ part tells SQL to calc the char(8) as numbers:
SELECT [Age] = (0+ FORMAT(#ToDate,'yyyyMMdd') - FORMAT(#DOB,'yyyyMMdd') ) /10000
CASE WHEN datepart(MM, getdate()) < datepart(MM, BIRTHDATE) THEN ((datepart(YYYY, getdate()) - datepart(YYYY, BIRTH_DATE)) -1 )
ELSE
CASE WHEN datepart(MM, getdate()) = datepart(MM, BIRTHDATE)
THEN
CASE WHEN datepart(DD, getdate()) < datepart(DD, BIRTHDATE) THEN ((datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE)) -1 )
ELSE (datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE))
END
ELSE (datepart(YYYY, getdate()) - datepart(YYYY, BIRTHDATE)) END
END
SELECT ID,
Name,
DATEDIFF(yy,CONVERT(DATETIME, DOB),GETDATE()) AS AGE,
DOB
FROM MyTable
How about this:
SET #Age = CAST(DATEDIFF(Year, #DOB, #Stamp) as int)
IF (CAST(DATEDIFF(DAY, DATEADD(Year, #Age, #DOB), #Stamp) as int) < 0)
SET #Age = #Age - 1
Try this solution:
declare #BirthDate datetime
declare #ToDate datetime
set #BirthDate = '1/3/1990'
set #ToDate = '1/2/2008'
select #BirthDate [Date of Birth], #ToDate [ToDate],(case when (DatePart(mm,#ToDate) < Datepart(mm,#BirthDate))
OR (DatePart(m,#ToDate) = Datepart(m,#BirthDate) AND DatePart(dd,#ToDate) < Datepart(dd,#BirthDate))
then (Datepart(yy, #ToDate) - Datepart(yy, #BirthDate) - 1)
else (Datepart(yy, #ToDate) - Datepart(yy, #BirthDate))end) Age
This will correctly handle the issues with the birthday and rounding:
DECLARE #dob datetime
SET #dob='1992-01-09 00:00:00'
SELECT DATEDIFF(YEAR, '0:0', getdate()-#dob)
Ed Harper's solution is the simplest I have found which never returns the wrong answer when the month and day of the two dates are 1 or less days apart. I made a slight modification to handle negative ages.
DECLARE #D1 AS DATETIME, #D2 AS DATETIME
SET #D2 = '2012-03-01 10:00:02'
SET #D1 = '2013-03-01 10:00:01'
SELECT
DATEDIFF(YEAR, #D1,#D2)
+
CASE
WHEN #D1<#D2 AND DATEADD(YEAR, DATEDIFF(YEAR,#D1, #D2), #D1) > #D2
THEN - 1
WHEN #D1>#D2 AND DATEADD(YEAR, DATEDIFF(YEAR,#D1, #D2), #D1) < #D2
THEN 1
ELSE 0
END AS AGE
The answer marked as correct is nearer to accuracy but, it fails in following scenario - where Year of birth is Leap year and day are after February month
declare #ReportStartDate datetime = CONVERT(datetime, '1/1/2014'),
#DateofBirth datetime = CONVERT(datetime, '2/29/1948')
FLOOR(DATEDIFF(HOUR,#DateofBirth,#ReportStartDate )/8766)
OR
FLOOR(DATEDIFF(HOUR,#DateofBirth,#ReportStartDate )/8765.82) -- Divisor is more accurate than 8766
-- Following solution is giving me more accurate results.
FLOOR(DATEDIFF(YEAR,#DateofBirth,#ReportStartDate) - (CASE WHEN DATEADD(YY,DATEDIFF(YEAR,#DateofBirth,#ReportStartDate),#DateofBirth) > #ReportStartDate THEN 1 ELSE 0 END ))
It worked in almost all scenarios, considering leap year, date as 29 feb, etc.
Please correct me if this formula have any loophole.
Declare #dob datetime
Declare #today datetime
Set #dob = '05/20/2000'
set #today = getdate()
select CASE
WHEN dateadd(year, datediff (year, #dob, #today), #dob) > #today
THEN datediff (year, #dob, #today) - 1
ELSE datediff (year, #dob, #today)
END as Age
Here is how i calculate age given a birth date and current date.
select case
when cast(getdate() as date) = cast(dateadd(year, (datediff(year, '1996-09-09', getdate())), '1996-09-09') as date)
then dateDiff(yyyy,'1996-09-09',dateadd(year, 0, getdate()))
else dateDiff(yyyy,'1996-09-09',dateadd(year, -1, getdate()))
end as MemberAge
go
CREATE function dbo.AgeAtDate(
#DOB datetime,
#CompareDate datetime
)
returns INT
as
begin
return CASE WHEN #DOB is null
THEN
null
ELSE
DateDiff(yy,#DOB, #CompareDate)
- CASE WHEN datepart(mm,#CompareDate) > datepart(mm,#DOB) OR (datepart(mm,#CompareDate) = datepart(mm,#DOB) AND datepart(dd,#CompareDate) >= datepart(dd,#DOB))
THEN 0
ELSE 1
END
END
End
GO
DECLARE #FromDate DATETIME = '1992-01-2623:59:59.000',
#ToDate DATETIME = '2016-08-10 00:00:00.000',
#Years INT, #Months INT, #Days INT, #tmpFromDate DATETIME
SET #Years = DATEDIFF(YEAR, #FromDate, #ToDate)
- (CASE WHEN DATEADD(YEAR, DATEDIFF(YEAR, #FromDate, #ToDate),
#FromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(YEAR, #Years , #FromDate)
SET #Months = DATEDIFF(MONTH, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(MONTH,DATEDIFF(MONTH, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SET #tmpFromDate = DATEADD(MONTH, #Months , #tmpFromDate)
SET #Days = DATEDIFF(DAY, #tmpFromDate, #ToDate)
- (CASE WHEN DATEADD(DAY, DATEDIFF(DAY, #tmpFromDate, #ToDate),
#tmpFromDate) > #ToDate THEN 1 ELSE 0 END)
SELECT #FromDate FromDate, #ToDate ToDate,
#Years Years, #Months Months, #Days Days
What about a solution with only date functions, not math, not worries about leap year
CREATE FUNCTION dbo.getAge(#dt datetime)
RETURNS int
AS
BEGIN
RETURN
DATEDIFF(yy, #dt, getdate())
- CASE
WHEN
MONTH(#dt) > MONTH(GETDATE()) OR
(MONTH(#dt) = MONTH(GETDATE()) AND DAY(#dt) > DAY(GETDATE()))
THEN 1
ELSE 0
END
END
declare #birthday as datetime
set #birthday = '2000-01-01'
declare #today as datetime
set #today = GetDate()
select
case when ( substring(convert(varchar, #today, 112), 5,4) >= substring(convert(varchar, #birthday, 112), 5,4) ) then
(datepart(year,#today) - datepart(year,#birthday))
else
(datepart(year,#today) - datepart(year,#birthday)) - 1
end
The following script checks the difference in years between now and the given date of birth; the second part checks whether the birthday is already past in the current year; if not, it subtracts it:
SELECT year(NOW()) - year(date_of_birth) - (CONCAT(year(NOW()), '-', month(date_of_birth), '-', day(date_of_birth)) > NOW()) AS Age
FROM tableName;
Related
Just wondering if anyone can help me setting a date variable for a report to run between certain dates every year without needing to be updated manually.
For example, I have the dates hard-coded below, but I was wondering if I could set a date format for when it goes into 2017 that the dates will change for the 2017 year. I presume there is a way to set a yearly date format I am just not sure how.
This is my hard-coded variables I set.
Put in the wrong Date Ranges changed as below.
set #start_date = '2016-01-02';
set #end_date = '2017-01-01';
Below is what I have in my where clause also.
and create_date between #start_date and #end_date
Your range covers all days in the year, except January 1. So you can simply check the day and month:
WHERE NOT (DAY(create_date) = 1 AND MONTH(create_date) = 1)
set #start_date = CAST(CAST(YEAR(getdate()) AS nvarchar(4)) + '0102' AS DATETIME);
to get end of current year
SET #end_date = DATEADD(day, -1 , DATEADD(month,13 - MONTH(getdate()), DATEADD(day,1 - DAY(getdate()),getdate())));
I assume you want the FULL "current year" based on "today"
MySQL
select *
from whatever
where ( create_date >= CONCAT(YEAR(CURDATE()),'-01-01')
and create_date < CONCAT(YEAR(CURDATE())+1,'-01-01')
)
Test it with:
SELECT
CONCAT(YEAR(CURDATE()),'-01-01') This_year_start
, CONCAT(YEAR(CURDATE())+1,'-01-01') Next_year_start
SQL Server (tsql)
select *
from whatever
where ( create_date >= DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()), 0)
and create_date < DATEADD(YEAR, DATEDIFF(YEAR, -1, GETDATE()), 0)
)
Test it with:
select
DATEADD(YEAR, DATEDIFF(YEAR, 0, GETDATE()) , 0) This_year_start
, DATEADD(YEAR, DATEDIFF(YEAR, -1, GETDATE()), 0) Next_year_start
This_year_start Next_year_start
01.01.2016 00:00:00 01.01.2017 00:00:00
DATEDIFF(YEAR, 0, GETDATE()) calculates the number of years from the
base year
add that number of years to the base date (1900-01-01)
DATEDIFF(YEAR, -1, GETDATE()) calculates the number of years from
year before the base year (is a bigger number, by 1, than above)
add that number of years to the base date (1900-01-01)
Please avoid using between for date ranges. It is far safer to use a combination of >= and <
e.g.
where create_date >= '2016-01-01' and create_date < '2017-01-01'
With that approach, no matter what time precsion applies to the data in [create_date] you will get the precise range of information requested.
Here you go.
declare #s datetime, #e datetime
set #s=cast(cast(year(getdate()) as char(4))+'-01-02' as date)
set #e=cast(cast(year(getdate()) as char(4))+'-12-31' as date)
select #s,#e
Any help with the syntax would be appreciated.
Datediff(day,dateOne, dateTwo) as TimeServed
How would I get the number of days between those dates excluding Saturday and Sunday?
I do not have the ability to create functions.
Please check out below code, it might help:
declare #firstdate Date
declare #seconddate Date
set #firstDate = convert(date, '2019-11-01')
set #seconddate = convert(date, '2019-11-30')
select ((datediff(dd, #firstDate, #secondDate)+1) -
( DateDiff(wk, #firstDate, #secondDate) * 2) -
case when datepart(dw, #FirstDate) = 1 then 1 else 0 end -
case when datepart(dw, #secondDate) = 7 then 1 else 0 end)
Ok,
This is a little tricky, I am trying to replace the dates in a SQL Query results with a standard date, based on the month.
For example:
Any dates that are in July get 20140701
August gets 20140801
I could use a case statement:
Case
When Datepart(mm, TxnDate) = 1 and Datepart(yy, TxnDate) = 2014 then TxnDate = 20140101
etc...
but that could get very long as the database goes back 5 years and the result sets cover different periods then.
Any quick suggestions would be greatly appreciated.
Thanks,
declare #mydate datetime
select #mydate = GETDATE()
select cast(datepart(yy,#mydate) as varchar(4)) + RIGHT('0' + RTRIM(MONTH(#mydate)), 2) + '01'
select #mydate = GETDATE() - 10
select cast(datepart(yy,#mydate) as varchar(4)) + RIGHT('0' + RTRIM(MONTH(#mydate)), 2) + '01'
should print 20140701 and 20140601
If you simply want to set every TxnDate to the first of its month, you can do this:
TxnDate = DATEADD(month, DATEDIFF(month, 0, TxnDate), 0)
If your requirement is more complicated than that, you will need to explain.
Try Something like this
SELECT REPLACE (CONVERT(VARCHAR(8), TxnDate, 112),SUBSTRING(CONVERT(VARCHAR(8), TxnDate, 112),7,8),'01') AS [YYYYMMDD]
hope this is what you are looking for
How to get the financial day of the year i.e., if i pass 2nd of april to the function, it should return 2. The financial year starts on 1st of April for every year.
Fiscal calendars are specific to the organization and, although rare, can change. The simplest solution is to create a table that outlines the Fiscal calendar. So, you can mimic this using a CTE but it is better to store it as a table.
With FiscalCalendarStarts As
(
Select 1 As FiscalPeriod
, Cast('20120401' As DateTime) As StartDate
Union All
Select FiscalPeriod + 1
, Case
When Month(StartDate) = 12 Then DateAdd(m, Month(StartDate) - 12 + 1, StartDate)
Else DateAdd(m, 1, StartDate)
End
From FiscalCalendarStarts
Where FiscalPeriod < 12
)
, FiscalCalendar As
(
Select FiscalPeriod
, StartDate
, DateAdd(d, -1, DateAdd(m, 1, StartDate)) As EndDate
From FiscalCalendarStarts
)
Select *
From FiscalCalendar
Where #SomeDate Between StartDate And EndDate
Edit
To get the day count (which I admit I did not provide in the above solution), the trick is to determine the actual fiscal year start date based on the input date. To do that, you could do something like the following, which per your request, I've put into a function
Create Function dbo.FiscalDay ( #Input datetime )
Returns int
As
Begin
Declare #StartDayMonth char(4);
Set #StartDayMonth = '0401';
Return (
Select DateDiff(d, FYStartDate, #Input) + 1
From (
Select DateAdd(yyyy
, Case
When DatePart(dy, #Input) >= DatePart(dy, StartDate) Then 0
Else -1
End
, StartDate) As FYStartDate
From (
Select Cast( Cast(Year(#Input) As char(4))
+ #StartDayMonth As datetime ) As StartDate
) As S1
) As S
)
End
I start with the stub of 0401 which represents the month and day of the start of the fiscal year. To that I prepend the passed date's year so I get something like 20120401 if a date in 2012 was passed. If #Input is later than 1-Apr, then we're in the new fiscal year for the year of the #Input. If #Input is earlier than 1-Apr, then we're in the fiscal year that start on 1-Apr of the previous year. Now that we have the fiscal start date, we can simply find the numbers of days between them and add 1 (otherwise 1-Apr will be seen as day 0 instead of day 1). Note that passing 31-Mar-2012 returns 366 instead of 365 since 2012 was a leap year.
#Olivarsham, The financial year in not common for every country. Some where it is Apr-mar, some where it is Jan-Dec. So It it is your special application requirement then you need to write for your self. I think no standard query for that.
Kindly try this function. This will return your the day number of the fiscal year.
CREATE FUNCTION [dbo].[FiscalDay] (#CurrentDATE datetime)
RETURNS int
AS
BEGIN
DECLARE #FiscalDay int;
DECLARE #YearStartDate DateTime;
Set #YearStartDate=Cast('20120401' As DateTime)
set #FiscalDay = DATEDIFF(DAY,#YearStartDate , #CurrentDATE)
RETURN(#FiscalDay);
END;
GO
I have this code which I'm writing into a stored procedure:
declare #StartTime time
declare #EndTime time
declare #Temp_StartTime time
declare #temp_StartHour int
declare #temp_EndHour int
declare #temp_StartMinute int
declare #temp_EndMinute int
SET #StartTime='22:30:00'
SET #EndTime='00:52:00'
SET #Temp_StartTime=#StartTime
SET #temp_StartHour=DATEPART(HOUR, #StartTime)
SET #temp_EndHour=DATEPART(HOUR, #EndTime)
SET #temp_StartMinute=DATEPART(MI, #StartTime)
SET #temp_EndMinute=DATEPART(MI, #EndTime)
if(#temp_EndMinute>0)
BEGIN
SET #temp_EndHour=#temp_EndHour+1
END
DECLARE #Temp_Table TABLE
(
StartHour int,
StartMinute int,
EndHour int,
EndMinute int,
StartTime time,
EndTime time
)
WHile((#temp_EndHour-#temp_StartHour>=1))
BEGIN
INSERT INTO #Temp_Table
SELECT (DATEPART(HOUR, #Temp_StartTime)) AS StartHour,(DATEPART(MINUTE, #Temp_StartTime)) AS StartMinute,
#temp_StartHour+1 AS EndHour,
0 AS EndMinute, #StartTime as StartTime, #EndTime as EndTime
SET #temp_StartHour=#temp_StartHour+1
SET #Temp_StartTime=DATEADD(HOUR,1,#Temp_StartTime)
if(DATEPART(MI, #Temp_StartTime)!=0)
BEGIN
SET #Temp_StartTime=DATEADD(MI,-#temp_StartMinute,#Temp_StartTime)
END
END
SELECT * FROM #Temp_Table
It works great if you use any time value other than the 00:52:00 example I have up there. For instance, if EndTime was 23:05, the stored procedure works great. I did some research around DATEPART but didn't find anything helpful as to how to get it to calculate midnight at military time properly.
EDIT: When the code runs properly, it calculates the time in how many hours between start and end time and the idea is to store new rows for each hour into the temp table (eventually this is going to be saved to a new table for tracking outages by hour). It works find when I run it with 21:30 to 22:15. I get two rows reflecting 21:00 to 22:00 and 22:00 to 23:00 (this is the logic I want). But throw military midnight in there, and I get no rows returned as the calc won't compute the 00.
I have found examples in my database that show start times of 22:00:0000 and end times of 00:00:00.0000000 and then visa versa. So one way WILL calculate, where start time is 00, but if start time is 21:00:0000 and end time is 00:52:0000 then no dice. I get no rows returned.
If I am not missing anything, this is what you could try instead of your loop:
DECLARE
#StartTime time,
#EndTime time;
SET #StartTime = '22:30:00';
SET #EndTime = '00:52:00';
WITH timerange AS (
SELECT
StartTime = CAST(#StartTime AS datetime),
EndTime = DATEADD(
DAY,
CASE WHEN #StartTime > #EndTime THEN 1 ELSE 0 END,
CAST(#EndTime AS datetime)
)
),
hourly AS (
SELECT
n.number,
t.StartTime,
t.EndTime,
HStart = DATEADD(HOUR, DATEDIFF(HOUR, 0, t.StartTime) + n.number , 0),
HEnd = DATEADD(HOUR, DATEDIFF(HOUR, 0, t.StartTime) + n.number + 1, 0)
FROM timerange t
INNER JOIN master..spt_values n
ON n.number BETWEEN 0 AND DATEDIFF(HOUR, t.StartTime, t.EndTime)
WHERE n.type = 'P'
),
hourly2 AS (
SELECT
number,
HStart = CASE WHEN StartTime > HStart THEN StartTime ELSE HStart END,
HEnd = CASE WHEN EndTime < HEnd THEN EndTime ELSE HEnd END
FROM hourly
)
SELECT
StartHour = DATEPART(HOUR , HStart),
StartMinute = DATEPART(MINUTE, HStart),
EndHour = DATEPART(HOUR , HEnd ),
EndMinute = DATEPART(MINUTE, HEnd ),
StartTime = CAST(HStart AS time),
EndTime = CAST(HEnd AS time)
FROM hourly2
ORDER BY number
;
The output produced is this:
StartHour StartMinute EndHour EndMinute StartTime EndTime
----------- ----------- ----------- ----------- ---------------- ----------------
22 30 23 0 22:30:00.0000000 23:00:00.0000000
23 0 0 0 23:00:00.0000000 00:00:00.0000000
0 0 0 52 00:00:00.0000000 00:52:00.0000000