I'm working on my first laravel project- a family tree website. Everything's going great with the normal models/controllers/views, but I've gotten to a special case that I'm not sure how to approach. I have about a dozen auxiliary stories that go along with specific people or families- this is extra stuff that most records don't have.
In my previous incarnation of this site, I had a stories table with a headline, source for the material, and a slug, I made an html page for each story, and then I'd link to that page using the slug value.
In Laravel this seems like a really clunky way to go about it (especially as I add more stories), because it's messy to have to make a new route/controller/view for each one.
So I've made a general StoryController and view in hopes of reusing that to display the contents of any story. I've added a 'text' column into my stories table for those contents, and I've copied the HTML (with the problematic characters escaped). But of course when I display this story text on the view, I see all the markup tags displayed themselves (instead of helping to render the actual text in paragraphs, etc).
So two questions: is there a way to treat the field as html itself (instead of a string)? And is my approach off-base and I should do this a different way?
Thanks in advance for any help!
Update: thanks to The Happy Mamba, it works if I call to another function for html_entity_decode and echo out the results, but weirdly it DOESN'T work if I 'return' the results (or do it in the same function). It didn't render the tags until I did it like so (in StoryController):
public function convert($string)
{
echo (html_entity_decode($string));
}
public function show($id)
{
$story = Story::find($id);
$content = StoryController::convert($story->text);
return view ('story/show', compact('story', 'content'));
}
The snag there is that because it's using echo, that field is displayed first no matter what.... so if I can't get around that I'll need to conversion in and out of the database as suggested (still need to get the Connection string working)- but this is a great step forward!
Have you tried pulling it out of the database and then sending the text to htmlentities?
Here's some code to test it. Examples are in postgresql but should work the same with PDO/laravel specific functions:
<?php
$conn = pg_connect('db connection string here');
$text = pg_escape_literal( $conn, htmlentities( '<html><head></head><body><em>test</em></body></html>' ) );
pg_query( $conn, 'TRUNCATE TABLE test' );
pg_query( $conn, "INSERT INTO test VALUES ( {$text} )" );
$result = pg_query( $conn, 'SELECT * FROM test' );
$row = pg_fetch_row( $result );
pg_close( $conn );
$string = $row[0];
echo html_entity_decode($string);
?>
Result:
bolded "test" in browser.
After trying a few things, the solution I like best is to make a partial for each story, and then dynamically include the correct one based on the story.slug. (This way I still need only one story route/show function/view, and I can update the content much more easily than if I'm cramming html into the database)
Related
I'm using MediaWiki at work and creating a Knowledge Base. We've got everything set up but one requirement is to have a unique identifier on each page, then it can be referenced in official documentation. I've done this by using the magic word {{PAGEID}} so it's added to the bottom right of each page.
Another requirement is to be able to find the page based on this unique number but when using the built in search function the page can't be found.
For example, the main page has the text "Page ID:1" in the bottom right corner. When doing a search for "Page ID:1" nothing can be found and the Wiki only gives me the option to create the page.
Does anyone know how you can either search on, or have the search include the Page ID?
Any help would be appreciated.
global $wgHooks;
$wgHooks['SearchGetNearMatchBefore'][] = function ( array $allSearchTerms, &$titleResult ) {
$searchTerm = $allSearchTerms[0];
if ( preg_match( '/^id:\d+$/', $searchTerm ) ) {
$pageId = (int)substr( $searchTerm, 3 );
$titleResult = Title::newFromID( $pageId );
return false;
}
};
will jump to the page with ID 123 when you enter id:123 in the search box. Seems like a silly way to use search though.
I'm curious if there's any way to display SQL query(Just the statement itself, not the result) with proper format in HTML document. I'm using it for documentation/demo purpose.
For example here you can display a SQL query like this(with gray background):
SELECT *
FROM USERS
The only thing I came close is using Wells from Bootstrap(which looks very similar to above). But I'm wondering if there's any other way of doing it. If it has functionality of syntax highlighting too, that would be great.
$query = "SELECT * FROM USERS";
<code><?php echo $query; ?></code>
<pre><?php echo $query; ?></pre>
I have a fairly complicated html table containing lots of PHP, CSS etc., and it comprises about 200 lines of code. I need to reproduce the table in three different areas on my webpage. What is the best approach to replicating the table the 2nd and 3rd time so that I don't have to copy and paste the 200 lines of code each time? Surely there must be a best-practice for doing this.
You can just use include files, then put a reference to the include file on each page where you want the table.
<?php include("table.php"); ?>
And more info from w3schools can be found here:
http://www.w3schools.com/php/php_includes.asp
Are you using jQuery? Where does the data originate? Is it hard coded or in a database? You are correct in my opinion, you should never be adding even a 200 row table to your view (in the first place) that is coded in static HTML.
Please provide some detailed context for your problem and what you are trying to accomplish and I will try and help you out.
Here is a solution using PHP if you are quering your information from a database. This will make a new row for each result that is returned from your DB. I presume that with 200 different bits of information you are using a database for that?
Hope this helps you out somehow :)
EDIT : Just re-read the question, jumped the boat a bit there Im afraid (apologies) I suggest the poster above and his includes method :)
<table>
<tr>
<?php
// create query and make them load so the most recent shows first
$query = "SELECT * FROM ourtable ORDER BY id DESC";
// execute query
$result = mysql_query($query) or die ("Error in query: $query. ".mysql_error());
while($row = mysql_fetch_row($result)) {
echo "<td>".$row[0]."</td>";
}
?>
</tr>
</table>
Put a div wrapper around the table with an id. then put empty divs in the other spots it needs to go then:
<script type="text/javascript"
function dupTable()
{
str=document.getElementById('tableWrapper').innerHTML;
document.getElementById('dest1').innerHTML=str;
document.getElementById('dest2').innerHTML=str;
}
onload=dupTable;
</script>
I have this code which gets the contents from a mysql databse.
So basically, what happens is that foreach row in the database, it creates a div with the contents in. However, I want the user to be able to delete the post, but I simply can't get my head around how to do it.
This is the code:
while($row = mysql_fetch_assoc($query))
{
$contents= $row['contents'];
}
echo '<div class = "post" style = "margin-right: 300px;">'.$contents.'<br><p>DELETE -- HOW CAN I DO THIS??</p></div>';
Basically, what this does is get the contents of the row, each time. But I want the user to be able to click on delete it, and it deletes the div which has the contents, and removes it from the database.
I have tried simply to delete the div, but that deletes ALL the divs, not just the one that I clicked delete in.
How can I do this, I don't care how.
Thanks. I am sorry if there is too much info, or I ask too much.
You need to output a [Delete] link that sends the user back to the server to actually perform the delete. The deletion from MySQL will occur as a separate request. The PHP code that handles that request will have to construct a proper DELETE FROM table WHERE id = $id type of SQL statement, and then execute that. Once that is finished, you'll have to refresh the display so that item is no longer listed - easiest way would be to simply redirect back to the page that you already have.
If you add a class say "delete" to the p-tag
<p class="delete">DELETE -- HOW CAN I DO THIS??</p>
Then you could delete the div like this, for instance:
$(".delete").click(function(){ $(this).parent().remove(); });
Note:
You would still need some extra functionality, an AJAX-call for instance, to remove the post from the DB and not just from the DOM.
I have found out what to do.
Here is what I did:
while($row = mysql_fetch_assoc($query))
{
$contents= $row['contents'];
$contentID = $row['contentID'];
}
echo '<div class = "post" style = "margin-right: 300px;">'.$contents.'<br>X</div>';
And on the delete.php I have something like this:
$id = 1;
mysql_query("DELETE FROM table_name WHERE $contentID = $id");
Is it possible to create a wiki page, where you mark a single piece of text as a placeholder which can be put anywhere else on the wiki?
Let's say I have a wiki page containing a simple list. The first item in list must be always shown in the Main Page but the editing user should not edit two pages for that, just one page.
The list page:
Pineapples
{{SaveThisText|TodaysMeal|Dumplings}}
Beans
Oranges
Main Page:
Today, we'll have {{GetSavedText|TodaysMeal}}
...Main Page will result to "Today, we'll have Dumplings"
I know that it is possible to do this using templates but I want to avoid them, I want to edit the template like it's a part of page.
You can do this without writing any custom PHP, see:
http://www.mediawiki.org/wiki/Extension:Variables
This is definitely possible if you write a MediaWiki extension for it. This means that you could place a hook on GetSavedText and SaveThisText so their behaviour can be customized.
If you have a small wiki, you could just cycle through every page on the occurance of GetSavedText an search for {{SaveThisText|TodaysMeal|. Getting every page is easy:
// get existing pages
$db = wfGetDB ( DB_MASTER );
$results = $db->resultObject ( $db->query(
"select distinct page_title from {$wgDBprefix}page " )
);
$existing_pages = array();
while ( $r = $results->next() )
$title = Title::newFromText( $r->page_title );
$article = new Article ( $title );
$content = $article->getContent();
A more efficient approach would be to place a hook on the update of a page. If SaveThisText is present, you could update a line in a database table.