I have these two tables
The first one is expenses table and the second one is expensename
Exp_Type(first table) is the Expense name(second table) as 2 is Food
I am trying to group expense according to expense type and get data between certain dates.
This is what i have tried, but it wont work.
select
(select
(select name from EXPENSENAME where id=EXP_TYPE)as ExpenseType,
sum(PRICE) as cost
from EXPENSES WHERE USERID=1 GROUP BY EXPENSES.EXP_TYPE),
[date]
from EXPENSES where [date] BETWEEN '10-09-2015' and '10-18-2015 23:59:59'
And
select
(select name from EXPENSENAME where id=EXP_TYPE)as ExpenseType,
sum(PRICE) as cost,
date
from EXPENSES WHERE USERID=1 and DATE BETWEEN '01/10/2015' and '29/10/2015' GROUP BY EXPENSES.EXP_TYPE
With out date, i am getting result by this query but i need the same data between certain dates,please help
select
(select name from EXPENSENAME where id=EXP_TYPE)as ExpenseType,
sum(PRICE) as cost
from EXPENSES WHERE USERID=1 GROUP BY EXPENSES.EXP_TYPE
you want to join the tables together
SELECT en.name as ExpenseType, SUM(e.price) as cost
FROM expenses e
JOIN expensename en ON en.id = e.exp_type
WHERE e.date BETWEEN '10-09-2015' and '10-18-2015'
GROUP BY en.name
this should give you the cost per name
the current query you have is TERRIBLE... and this is why
SELECT (SELECT ... FROM ... WHERE ... ) as ...
this is creating a correlated subquery which is executing once for every row of the parent select. meaning if you have a table with 4 rows in it (SELECT ... FROM ... WHERE ... ) will execute 4 times scanning 16 rows (assuming its from the same table) in general that is a really really bad way to get data... if you have a million rows... well do the math, its a bad idea
Related
i have two tables
Income
(id,
income,
date,
userid)
and table
Expense
(id,amount,date,userid). Now I'm trying to create a View with sum of income, sum of amount in one year. Also it must be GROUPED by year and userid.
So new table (view) must have sum of income, expenses, year. Right now i am stuck on this code.
SELECT
id,
i.Prihod,
e.Rashod,
YEAR
YEAR(COALESCE(e.god, i.godi))) AS Godina ,
users_id
FROM
(
SELECT
sum(insum) as 'Prihod',
YEAR(datum) as 'Godi',
users_id
FROM
GROUP BY users_id
) as i
FULL OUTER JOIN
(
SELECT
sum(amount) as 'Rashod',
YEAR(datum) as 'God',
users_id
FROM expense
GROUP BY users_id
) as e
This is a job for the structured part of structured query language. Start with three subqueries (virtual tables).
First: A list of the years and users. You need this because MySQL doesn't have FULL OUTER JOIN capability. If you write this query correctly, it will contain one row for each user for each year you need.
SELECT DISTINCT YEAR(datum) Godi, users_id FROM income
UNION
SELECT DISTINCT YEAR(datum) Godi, users_id FROM expense
Second, a summary of the income by year and user.
SELECT sum(insum) as Prihod,
YEAR(datum) as Godi,
users_id
FROM income
GROUP BY YEAR(datum), users_id
Third, a similar sum of expenses by year and user
SELECT sum(amount) as Rashod,
YEAR(datum) as God,
users_id
FROM expense
GROUP BY YEAR(datum), users_id
Next, test these subqueries individually, standalone, to ensure you have the results you expect.
Finally, join them together as if they were tables, like so
SELECT yr.users_id, yr.Godi, inc.Prihod, exp.Rashod
FROM (
SELECT DISTINCT YEAR(datum) Godi, users_id FROM income
UNION
SELECT DISTINCT YEAR(datum) Godi, users_id FROM expense
) yr
LEFT JOIN (
SELECT sum(insum) as Prihod,
YEAR(datum) as Godi,
users_id
FROM income
GROUP BY YEAR(datum), users_id
) inc ON yr.users_id = inc.users_id AND yr.Godi = inc.Godi
LEFT JOIN (
SELECT sum(amount) as Rashod,
YEAR(datum) as God,
users_id
FROM expense
GROUP BY YEAR(datum), users_id
) exp ON yr.users_id = exp.users_id AND yr.Godi = exp.God
The query pattern here is to develop three subqueries. The first of them determines the number of rows in your final result set, because it contains one row for each desired row. The second and third queries have one, or maybe zero, rows for each row you need in your final result set. Then you join them together.
first ,i need to get the sum of TotalPrice of sport's and music's departments from the first 3 months of 2016,second, i need to get the result of what i wrote before dividing to sum of all TotalPrice at the year of 2016 from all departments, and third- i need to get the first result dividing to sum of all Total price from all over the years.
all this at the same query!
thanks!
the table called Sales and the attributes are: S_id, date, department, totalPrice.
THIS IS MY CHRY :
Select sum(TotalPrice) as sportMusic, sportMusic/sum(TotalPrice)
From Sales
Where (Department="MUSIC" OR Department="SPORT") and
DATE BETWEEN "2016/01/01" AND "2016/03/31"
You can use your query and two more queries as subqueries (also called "derived tables") in your from clause. Cross join the three result rows and use the totals in your select clause. Something along the lines of:
select
ms_2016_q1.total as ms_2016_q1_total,
ms_2016_q1.total / all_2016.total as rate_2016,
ms_2016_q1.total / all_years.total as rate_all
from
(
select sum(totalprice) as total
from sales
where department in ('MUSIC', 'SPORT')
and date between date '2016-01-01' and date '2016-03-31'
) ms_2016_q1
cross join
(
select sum(totalprice) as total
from sales
where date between date '2016-01-01' and date '2016-12-31'
) all_2016
cross join
(
select sum(totalprice) as total
from sales
) all_years;
How to optimize the below query:
I have two tables, 'calendar_table' and 'consumption', Here I use this query to calculate monthly consumption for each year.
The calendar table has day, month and year for years 2005 - 2009 and consumption table has billed consumption data for monthly bill cycle. This query will count the number of days for each bill and use that the find the consumption for each month.
SELECT id,
date_from as bill_start_date,
theYear as Year,
MONTHNAME(STR_TO_DATE(theMonth, '%m')) as month,
sum(DaysOnBill),
TotalDaysInTheMonth,
sum(perDayConsumption * DaysOnBill) as EstimatedConsumption
FROM
(
SELECT
id,
date_from,
theYear,
theMonth, # use theMonth for displaying the month as a number
COUNT(*) AS DaysOnBill,
TotalDaysInTheMonth,
perDayConsumption
FROM
(
SELECT
c.id,
c.date_from as date_from,
ct.dt,
y AS theYear,
month AS theMonth,
DAY(LAST_DAY(ct.dt)) as TotalDaysInTheMonth,
perDayConsumption
FROM
consumption AS c
INNER JOIN
calendar_table AS ct
ON ct.dt >= c.date_from
AND ct.dt<= c.date_to
) AS allDates
GROUP BY
id,
date_from,
theYear,
theMonth ) AS estimates
GROUP BY
id,
theYear,
theMonth;
It is taking around 1000 seconds to go through around 1 million records. Can something be done to make it faster?.
The query is a bit dubious pretending to do one grouping first and then building on that with another, which actually isn't the case.
First the bill gets joined with all its days. Then we group by bill plus month and year thus getting a monthly view on the data. This could be done in one pass, but the query is joining first and then using the result as a derived table which gets aggregated. At last the results are taken again and "another" group is built, which is actually the same as before (bill plus month and year) and some pseudo aggregations are done (e.g. sum(perDayConsumption * DaysOnBill) which is the same as perDayConsumption * DaysOnBill, as SUM sums one record only here).
This can simply written as:
SELECT
c.id,
c.date_from as bill_start_date,
ct.y AS Year,
MONTHNAME(STR_TO_DATE(ct.month, '%m')) as month,
COUNT(*) AS DaysOnBill,
DAY(LAST_DAY(ct.dt)) as TotalDaysInTheMonth,
SUM(c.perDayConsumption) as EstimatedConsumption
FROM consumption AS c
INNER JOIN calendar_table AS ct ON ct.dt BETWEEN c.date_from AND c.date_to
GROUP BY
c.id,
ct.y,
ct.month;
I don't know if this will be faster or if MySQL's optimizer doesn't see through your query itself and boils it down to this anyhow.
Here my table is having filed as following:
employee_id,
expense_id,
expense_type,
expense_cost,
expense_date and etc,
And i want to display as month wise expenses as row wise for particular employee.
in my table data has stored like
2wheeler 01/03/2014 99 Santhosh 4493.00 March 500.00
Auto 03/02/2014 99 Santhosh 0.00 February 80.00
Food 01/02/2014 99 Santhosh 0.00 February 200.00
Phone Expense 01/03/2014 99 Santhosh 0.00 March 500.00
In this table i want to get out as
single user row with concat of expense type and sum of cost for every month that mean : march have single row with concat of expense type & sum of cost.
I would suggest doing a sub query that sums up all the occurances of an expenses per employee per month per expense. Then use that as a source to get the list of employees, months and the GROUP_CONCATed list of expense types and the total cost of them.
Like this:-
SELECT employee_id, expense_month, GROUP_CONCAT(CONCAT_WS('=', expense_type, monthly_exployee_expense))
FROM
(
SELECT employee_id, MONTH(expense_date) AS expense_month, expense_type, SUM(expense_cost) AS monthly_exployee_expense
FROM some_table
GROUP BY employee_id, expense_month, expense_type
) Sub1
GROUP BY employee_id, expense_month
EDIT
Reading you comment it seems that you need an expense listed even when an employee has not incurred that expense that month.
To do that I think you will need to cross join the employees (I have assumed a table name of tbl_employee) with the table of expenses types, and also all the possible months (assuming you want a row for a month for an employee when that employee has had no expenses that month). I have got the possible months by just selecting the distinct year / month from the table listing all the expenses (but there are other ways to get this - depends if there are any months where no employees had any expenses and if you want to put these out anyway).
Once those are cross joined to get every combination of employee, month and expense you can left join the actual expenses in the sub query, and then do the GROUP_CONCAT much as before.
Not tested, but something like this:-
SELECT employee_id, expense_month, GROUP_CONCAT(CONCAT_WS('=', exp_type_text, monthly_exployee_expense))
FROM
(
SELECT tbl_employee.employee_id, expense_months.expense_month, tbl_expense_type.exp_type_id, tbl_expense_type.exp_type_text, SUM(expense_cost) AS monthly_exployee_expense
FROM tbl_employee
CROSS JOIN tbl_expense_type
CROSS JOIN
(
SELECT DISTINCT DATE_FORMAT(expense_date, '%Y%m') AS expense_month
FROM some_table
) expense_months
LEFT OUTER JOIN some_table
ON tbl_employee.employee_id = some_table.employee_id
AND tbl_expense_type.exp_type_id = some_table.expense_type
AND expense_months.expense_month = DATE_FORMAT(some_table.expense_date, '%Y%m')
GROUP BY tbl_employee.employee_id, expense_months.expense_month, tbl_expense_type.exp_type_id, tbl_expense_type.exp_type_text
) Sub1
GROUP BY employee_id, expense_month
I'm trying to join 3 tables for a system to keep track of what comes in and out of my shop.
The first tables is as following. (Production)
id
Amount
Date
item id
next table is: (sales)
id
date
amount
customer id
amount
the last is: (waste)
id
date
amount
reason
I haven't really found a way to join those 3 tables without using a common value they could join on. I need to order them by date so I can see the history of my income and expenses. If the 3 different tables could come with a individual value like 3 for waste 2 for sales and 1 for production would also be great.
What you want is not a join of the tables but a union: http://dev.mysql.com/doc/refman/5.0/en/union.html
Something like
(SELECT 'production' as source, id, Amount AS amount, Date AS date FROM Production)
UNION
(SELECT 'sales' as source, id, amount, date FROM sales)
UNION
(SELECT 'waste' as source, id, amount, date FROM waste)
ORDER BY date;