I can't find a proper way to escape apostrophe sign(’) in my mysql query. Regexp I have, works fine with online tools for regexp testing.
Problematic example is the string G’Schlössl.
I want to have optional apostrophe sign in the query in front of the s character G(’?)Schlö(’?)ssl for all the different cases which could occur in other strings. I am not sure if the problem is caused by incorrect sign escaping but I have tried many options like ’?, \’?, \’{0,1} which works for the first occurrence but doesn't for the second optional one and cause query to return nothing. Other possibilities like ’’?, [’]?, [\’]?, [\’]{0,1} does not work even for the first one.
select id, name from restaurant where name regexp '.*g\’?(s|ß|ss|sz)chl(o|ö|oe)\’?s.*';
When I remove the last \’? it works:
select id, name from restaurant where name regexp '.*g\’?(s|ß|ss|sz)chl(o|ö|oe)s.*';
When I replace the last \’? with x? it works as well:
select id, name from restaurant where name regexp '.*g\’?(s|ß|ss|sz)chl(o|ö|oe)x?s.*';
Any ideas where the problem is or what else to try?
This thread explains escaping normal single quote only, which seems not to work in my case.
Instead of \’?, try (’)?. I'm thinking that the ? may apply to only the last byte of ’. By using parentheses instead, the ? applies to the entire 3 bytes (hex E28099) of the "RIGHT SINGLE QUOTATION MARK".
Related
So I'm trying to find what "special characters" have been used in my customer names. I'm going through updating this query to find them all one-by-one, but it's still showing all customers with a - despite me trying to exlude that in the query.
Here's the query I'm using:
SELECT * FROM customer WHERE name REGEXP "[^\da-zA-Z\ \.\&\-\(\)\,]+";
This customer (and many others with a dash) are still showing in the query results:
Test-able Software Ltd
What am I missing? Based on that regexp, shouldn't that one be excluded from the query results?
Testing it on https://regex101.com/r/AMOwaj/1 shows there is no match.
Edit - So I want to FIND any which have characters other than the ones in the regex character set. Not exclude any which do have these characters.
Your code checks if the string contains any character that does not belong to the character class, while you want to ensure that none does belong to it.
You can use ^ and $ to check the while string at once:
SELECT * FROM customer WHERE name REGEXP '^[^\da-zA-Z .&\-(),]+$';
This would probably be simpler expressed with NOT, and without negating the character class:
SELECT * FROM customer WHERE name NOT REGEXP '[\da-zA-Z .&\-(),]';
Note that you don't need to escape all the characters within the character class, except probably for -.
Use [0-9] or [[:digit:]] to match digits irrespective of MySQL version.
Use the hyphen where it can't make part of a range construction.
Fix the expression as
SELECT * FROM customer WHERE name REGEXP "[^0-9a-zA-Z .&(),-]+";
If the entire text should match this pattern, enclose with ^ / $:
SELECT * FROM customer WHERE name REGEXP "^[^0-9a-zA-Z .&(),-]+$";
- implies a range except if it is first. (Well, after the "not" (^).)
So use
"[^-0-9a-zA-Z .&(),]"
I removed the + at the end because you don't really care how many; this way it will stop after finding one.
I am trying to isolate an email address from a block of free field text (column name is TEXT).
There are many different variations of preceding and succeeding characters in the free text field, i.e.:
email me! john#smith.com
e:john#smith.com m:555-555-5555
john#smith.com--personal email
I've tried variations of INSTR() and SUBSTRING_INDEX() to first isolate the "#" (probably the one reliable constant in finding an email...) and extracting the characters to the left (up until a space or non-qualifying character like "-" or ":") and doing the same thing with the text following the #.
However - everything I've tried so far hasn't filtered out the noise to the level I need.
Obviously 100% accuracy isn't possible but would someone mind taking a crack at how I can structure my select statement?
There is no easy solution to do this within MySQL. However you can do this easily after you have retrieved it using regular expressions.
Here would be a an example of how to use it in your case: Regex example
If you want it to select all e-mail addresses from one string: Regex Example
You can use regex to extract the ones where it does contain an e-mail in MySQL but it still doesn't extract the group from the string. This has to be done outside MySQL
SELECT * FROM table
WHERE column RLIKE '\w*#\w*.\w*'
RLIKE is only for matching it, you can use REGEXP in the SELECT but it only returns 1 or 0 on whether it has found a match or not :s
If you do want to extract it in MySQL maybe this other stackoverflow post helps you out. But it seems like a lot of work instead of doing it outside MySQL
Now in MySQL 5 and 8 you can use REGEXP_SUBSTR to isolate just the email from a block of free text.
SELECT *, REGEXP_SUBSTR(`TEXT`, '([a-zA-Z0-9._%+\-]+)#([a-zA-Z0-9.-]+)\.([a-zA-Z]{2,4})') AS Emails FROM `mytable`;
If you want to get just the records with emails and remove duplicates ...
SELECT DISTINCT REGEXP_SUBSTR(`TEXT`, '([a-zA-Z0-9._%+\-]+)#([a-zA-Z0-9.-]+)\.([a-zA-Z]{2,4})') AS Emails FROM `mytable` WHERE `TEXT` REGEXP '([a-zA-Z0-9._%+\-]+)#([a-zA-Z0-9.-]+)\.([a-zA-Z]{2,4})';
I've been trying to get a table row with this query:
SELECT * FROM `table` WHERE `field` LIKE "%\u0435\u0442\u043e\u0442%"
Field itself:
Field
--------------------------------------------------------------------
\u0435\u0442\u043e\u0442 \u0442\u0435\u043a\u0441\u0442 \u043d\u0430
Although I can't seem to get it working properly.
I've already tried experimenting with the backslash character:
LIKE "%\\u0435\\u0442\\u043e\\u0442%"
LIKE "%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%"
But none of them seems to work, as well.
I'd appreciate if someone could give a hint as to what I'm doing wrong.
Thanks in advance!
EDIT
Problem solved.
Solution: even after correcting the syntax of the query, it didn't return any results. After making the field BINARY the query started working.
As documented under String Comparison Functions:
Note
Because MySQL uses C escape syntax in strings (for example, “\n” to represent a newline character), you must double any “\” that you use in LIKE strings. For example, to search for “\n”, specify it as “\\n”. To search for “\”, specify it as “\\\\”; this is because the backslashes are stripped once by the parser and again when the pattern match is made, leaving a single backslash to be matched against.
Therefore:
SELECT * FROM `table` WHERE `field` LIKE '%\\\\u0435\\\\u0442\\\\u043e\\\\u0442%'
See it on sqlfiddle.
it can be useful for those who use PHP, and it works for me
$where[] = 'organizer_info LIKE(CONCAT("%", :organizer, "%"))';
$bind['organizer'] = str_replace('"', '', quotemeta(json_encode($orgNameString)));
I want to remove the names which may be registered with fake names.
As the developer forgot to put validation on form registration.
Now i want to remove the fake names.
And for checking if that name is fake or not, I am checking if the name content any numbers or not ?
This is my query which i have written but its not working...
SELECT registration.regi_id, student.first_name,
student.cont_no, student.email_id,
registration.college,
registration.event_name,
registration.accomodation
FROM student, registration
WHERE student.stud_id = registration.stud_id
AND student.first_name NOT RLIKE '%[0-9]%'
How to fix this problem ?
Sorry for my language issues,
P.S.
There are many names in "first_name" field like "asdfasdf12323", i don't want that kind of names to be shown on list.
Your column may contain Alphanumeric characters also.YOu need to filter Numbers and Alphanumeric characters both
For Alphanumeric characters Try REGEXP '^[A-Za-z0-9]+$'
For numbers Try REGEXP '[0-9]'
Well as far as the regex is involved, your expression is only looking for a single number. Also, your 'NOT RLIKE' isn't using regex but is doing a basic string search for the literal '[0-9]' I believe. MySql has support for regex, and your last clause would look like so: AND student.first_name NOT REGEXP '[0-9]*'
I have table with rows of strings.
I'd like to search for those strings that consists of only
two words.
I tried few ways with [[:space:]] etc but mysql was returning
three, four word strings also
try this:
select * from yourTable WHERE field REGEXP('^[[:alnum:]]+[[:blank:]]+[[:alnum:]]+$');
more details in link :
http://dev.mysql.com/doc/refman/5.1/en/regexp.html
^\w+\s\w+$ should do well.
Note; what I experience more often in the last days is that close to nobody uses the ^$-operators.
They are absolutely needed if you want to tell if a string starts or ends with something or want to match the string exactly, word for word, as you. "Normal" strings, like you used (I assume you used something like \w[:space]\w match in the string, what means that they also match if the condition is true anywhere within the string!
Keep that in mind and Regex will serve you well :)
REGEXP ('^[a-z0-9]*[[:space:]][a-z0-9]*$')