What is wrong in the following query:
SELECT * FROM forms
LEFT JOIN form_fields ON forms.id = form_field.parent_id
LEFT JOIN form_options ON form_field.id = form_options.parent_id
WHERE forms.name = activities
MySQL says 'unknown column 'activities'' where obviously forms.name should be seen as column name
I think you're just missing the quotes, try this:
SELECT * FROM forms
LEFT JOIN form_fields ON forms.id = form_field.parent_id
LEFT JOIN form_options ON form_field.id = form_options.parent_id
WHERE forms.name = 'activities'
Related
I am having issues with getting this double left join to get the listingspecificsListPrice, but that info exists in the table, cant figure out why it would not include it. This is my sql.
SELECT mls_subject_property.*, mls_images.imagePath, mls_forms_listing_specifics.listingspecificsListPrice
FROM mls_subject_property
LEFT JOIN mls_images ON mls_subject_property.mls_listingID = mls_images.mls_listingID
LEFT JOIN mls_forms_listing_specifics ON mls_forms_listing_specifics.mls_listingID = mls_subject_property.mls_listingID AND mls_images.imgOrder = 0
WHERE userID = 413
GROUP BY mls_subject_property.mls_listingID
The result comes out like this..
All of the other fields come back, but it doesnt seem to want to bring back those two items.
This is a picture of the other table, to show that the data does in fact exist.
The mls_images.imgOrder = 0 condition should be in the join with mls_images, not mls_forms_listing_specifics.
Don't use GROUP BY if you're not using any aggregation functions. Use SELECT DISTINCT to prevent duplicates.
SELECT DISTINCT mls_subject_property.*, mls_images.imagePath, mls_forms_listing_specifics.listingspecificsListPrice
FROM mls_subject_property
LEFT JOIN mls_images ON mls_subject_property.mls_listingID = mls_images.mls_listingID AND mls_images.imgOrder = 0
LEFT JOIN mls_forms_listing_specifics ON mls_forms_listing_specifics.mls_listingID = mls_subject_property.mls_listingID
WHERE userID = 413
I'm trying to join four tables together. The code works fine when I'm only comparing the EVENT_DATA and joining the PERSONA tables as I'm able to get the "Name" column from PERSONA (which doesn't exist in the EVENT_DATA table). However, one of the problems is that this "Name" column also exists in the CUSTOMCAR table, so I can only get one or the other. Additionally, when I tried adding the last join statement, the code wouldn't run at all.
If someone could please help me, that would be great!
$sql = "SELECT * FROM EVENT_DATA
LEFT JOIN PERSONA ON EVENT_DATA.personaId = PERSONA.ID
LEFT JOIN CUSTOMCAR ON CUSTOMCAR.ownedCarId = EVENT_DATA.carId
LEFT JOIN CARCLASSES ON CARCLASSES.store_name = CUSTOMCAR.name
WHERE (EVENT_DATA.EVENTID = '299')";
You should avoid * and use explicit columns list instead:
SELECT EVENT_DATA.personaId, ...
FROM EVENT_DATA
LEFT JOIN PERSONA ON EVENT_DATA.personaId = PERSONA.ID
LEFT JOIN CUSTOMCAR ON CUSTOMCAR.ownedCarId = EVENT_DATA.carId
LEFT JOIN CARCLASSES ON CARCLASSES.store_name = CUSTOMCAR.name
WHERE (EVENT_DATA.EVENTID = '299');
If you have same column name you need to to use aliasing:
SELECT ...
CUSTOMCAR.NAME AS c_name,
PERSONA.NAME AS p_name
...
You could also use Aliasing:
$sql = "SELECT ed.*,
pa.*,
cc.*,
ccs.*
FROM EVENT_DATA AS ed
LEFT JOIN PERSONA AS pa ON ed.personaId = pa.ID
LEFT JOIN CUSTOMCAR AS cc ON cc.ownedCarId = e.carId
LEFT JOIN CARCLASSES AS ccs ON ccs.store_name = cc.name
WHERE (ed.EVENTID = '299')";
Note: Although as suggested by #Lukasz, you should really avoid using wildcard (*), and provide an explicit list of columns in the SELECT clause.
I am trying to run the following query:
SELECT `aalv_test`.`aircraft`.*, `aalv_test`.`airports`.*, `aalv_test`.`bids`.*
FROM `bids`
LEFT JOIN `aalv_test`.`pilots` ON `bids`.`pid` = `pilots`.`id`
LEFT JOIN `aalv_test`.`schedules` ON `bids`.`fid` = `schedules`.`id`
LEFT JOIN `aalv_test`.`aircraft` ON `schedules`.`aircraft` = `aircraft`.`id`
LEFT JOIN `aalv_test`.`airports` AS `arr` ON `schedules`.`arricao` = `arr`.`icao`
LEFT JOIN `aalv_test`.`airports` AS `dep` ON `schedules`.`depicao` = `dep`.`icao`
WHERE `pilots`.`id` = 419
However,
MYSQL returns error #1051 - Table airports does not exist.
I don't know what the issue is and Google hasn't helped. Any ideas? Also, if I only use one alias, I only get one airport but I need both. And the data is only in the table airports which according to this query, does not exist. Also, if I try throwing an AS section in the SELECT clause, I get error 1064: syntax error near AS.
EDIT: Database name is aalv_test, the .* at the end specifies to use all fields in the table, and the middle part is the table name, yes I am chaining fields.
Try this:
SELECT a.*, arr.*, dep.*, b.*
FROM bids AS b
LEFT JOIN aalv_test.pilots AS p ON b.pid = p.id
LEFT JOIN aalv_test.schedules AS s ON b.fid = s.id
LEFT JOIN aalv_test.aircraft AS a ON s.aircraft = a.id
LEFT JOIN aalv_test.airports AS arr ON s.arricao = arr.icao
LEFT JOIN aalv_test.airports AS dep ON s.depicao = dep.icao
WHERE p.id = 419;
I hope you can help me again, thanks already for pointing me to the right direction with creating the check digit for the new IBAN in Germany. I am now trying to update our membership database with the newly calculated BIC and IBAN but seem to have a problem with the UPDATE statement on the MariaDB MySQL database, despite the fact that I think I got the syntax right.
All I am trying to do is set the two fields "konto_bic" and "konto_iban" in the table "mitglieder" from the SELECT statement which creates a temporary table called b with the columns "id", "bic" and "iban". The "id" is the same in the two tables.
Here is my first try:
update a
set a.`konto_bic` = b.`BIC`, a.`konto_iban` = b.`IBAN`
from `mitglieder` a
INNER JOIN (SELECT m.`id`, m.`nachname`, m.`vorname`, m.`konto_bank`, m.`konto_blz`, m.`konto_nummer`, k.`bic` AS 'BIC', CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'IBAN'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k
ON m.`konto_blz` = k.`blz`
ORDER BY m.`nachname`, m.`vorname`) b
ON a.`id` = b.`id`
However, this produced an error and I tried this instead:
update `mitglieder` a
set a.`konto_bic` = b.`bic`, a.`konto_iban` = b.`iban`
FROM (SELECT m.`id` as 'id', k.`bic` as 'bic', CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'iban'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k
ON m.`konto_blz` = k.`blz`) b
WHERE a.`id` = b.`id`
That also did not get me any further (error from DB).
Can anyone see what my syntax error might be?
Thank you in advance for your help
Stephan
Try below SQL
UPDATE `mitglieder` a,
(SELECT m.`id` AS 'id',
k.`bic` AS 'bic',
CONCAT('DE',LPAD(98-MOD(CONVERT(CONCAT(m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0'),'1314','00'), decimal(24)),97),2,'0'),m.`konto_blz`,LPAD(m.`konto_nummer`,10,'0')) AS 'iban'
FROM `mitglieder` m
LEFT JOIN `konvert_bic_blz` k ON m.`konto_blz` = k.`blz`) b
SET a.`konto_bic` = b.`bic`, a.`konto_iban` = b.`iban`
WHERE a.`id` = b.`id`
UPDATE Syntax
http://dev.mysql.com/doc/refman/5.0/en/update.html
I tried this on MariaDB 10.2.6 :
SET sql_mode = 'ANSI_QUOTES'
UPDATE "test"."user" AS "a"
INNER JOIN "test"."user_profile" AS "c" ON "c".user_id = "a".id
INNER JOIN "test"."profile" AS "d" ON "d".id = "c".profile_id
SET "a".firstname = 'laurent'
WHERE "a".id = 3;
And it works :)
I have the below SQL statement. What I would like to do is include an IF statement to cover the possibility of one of the columns returning a 0 or blank result, there are no 0 ID's. In this case, I'm trying to cover the possibility of the magez_cfv_nations result possibly returning a zero or blank result.
SELECT c.clan_name, n.nation_name,
CONCAT(r.rarity_shorthand, " - ", r.rarity_name) AS rarity_text,
t.trigger_name, s.skill_name
FROM `magez_cfv_cards` AS cards
JOIN `magez_cfv_clans` c ON cards.clan_id = c.clan_id
JOIN `magez_cfv_nations` n ON cards.nation_id = n.nation_id
JOIN `magez_cfv_rarity` r ON cards.rarity_id = r.rarity_id
JOIN `magez_cfv_trigger` t ON cards.trigger_id = t.trigger_id
JOIN `magez_cfv_skills` s ON cards.skill_id = s.skill_id
You need a LEFT JOIN
The LEFT JOIN keyword returns all rows from the left table
(table_name1), even if there are no matches in the right table
Try this
SELECT c.clan_name, n.nation_name,
CONCAT(r.rarity_shorthand, " - ", r.rarity_name) AS rarity_text,
t.trigger_name, s.skill_name
FROM `magez_cfv_cards` AS cards
JOIN `magez_cfv_clans` c ON cards.clan_id = c.clan_id
LEFT JOIN `magez_cfv_nations` n ON cards.nation_id = n.nation_id
JOIN `magez_cfv_rarity` r ON cards.rarity_id = r.rarity_id
JOIN `magez_cfv_trigger` t ON cards.trigger_id = t.trigger_id
JOIN `magez_cfv_skills` s ON cards.skill_id = s.skill_id
the function you should use is IIF() and its syntax is
IIF([condition],[if true],[if false])