I am unable to map the record as my expectation.
Doc Table
-------+-------------------
doc_id | doc_title
-------+-------------------
1 | My book
-------+-------------------
2 | My sec Book
--------------------------
Doc details Table
-----------+--------------+-----------------------
fk_doc_id | doc_version | submit_date
-----------+--------------+-----------------------
1 | 1 | 2015-10-25 14:32:01
-----------+--------------+-----------------------
1 | 2 | 2015-10-26 13:00:01
-----------+--------------+-----------------------
1 | 3 | 2015-10-27 09:00:00
--------------------------+-----------------------
2 | 1 | 2015-10-25 11:15:01
-----------+--------------+-----------------------
2 | 2 | 2015-10-26 10:00:00
--------------------------+-----------------------
Question: How do I join this two tables to get each documents with the latest version doc info? even though I get the latest version but the row info which is not correct.
So far I have tried this query
SELECT *, max(doc_version) AS latest_version
FROM d_doc
JOIN d_doc_dtl ON d_doc.doc_id = d_doc_dtl.fk_doc_id
GROUP BY d_doc.doc_id;
My expected result is
--------+--------------+----------------+--------------------
doc_id | doc_title | latest_version | submit_date
--------+--------------+----------------+--------------------
1 | My book | 3 | 2015-10-27 09:00:00
--------+--------------+----------------+--------------------
2 | My sec book | 2 | 2015-10-26 10:00:00
----------------------------------------+--------------------
but my result is
--------+--------------+----------------+--------------------
doc_id | doc_title | latest_version | submit_date
--------+--------------+----------------+--------------------
1 | My book | 3 | 2015-10-25 14:32:01
--------+--------------+----------------+--------------------
2 | My sec book | 2 | 2015-10-25 11:15:01
----------------------------------------+--------------------
NOTE: the submit_date which is no correct.
SELECT d_doc.doc_id, d_doc.doc_title, max_table.latest_version
FROM d_doc JOIN (
select fk_doc_id, max(doc_version) as latest_version from d_doc_dtl group by fk_doc_id
) as max_table ON d_doc.doc_id = max_table.fk_doc_id
This query should work as you expect. It selects latest document versions in inner subquery and than joins it with documents.
SELECT d.doc_id,
d.doc_title,
dtl.doc_version latest_version,
dtl.submit_date
FROM d_doc d
INNER JOIN (SELECT dt.*
FROM d_doc_dtl dt
INNER JOIN (SELECT fk_doc_id, MAX(doc_version) doc_version
FROM d_doc_dtl
GROUP BY fk_doc_id) dm
ON dt.fk_doc_id = dm.fk_doc_id
AND dt.doc_version = dm.doc_version) dtl
ON d.doc_id = dtl.fk_doc_id
You get wrong results because you selected only max(version), but date as it is not in group by clause can contain any value. First you need to get records containing latest version as shown above.
Easy, instead of
SELECT *, max(doc_version) AS latest_version
Use this
SELECT d_doc.*, max(doc_version) AS latest_version
What you were doing by selecting * is getting all the results after the table is joined and you only wanted the original table results.
select * from doc_table , doc_version where exists( select
max(version_id)
from
doc_version vert
where
(doc_table .DOC_ID = vert.VERSION_DOC_ID) ) group by doc_id;
You can try something like this.
Related
I have a single MySQL table with the name 'checkins' and 4 columns.
id | userIDFK | checkin_datetime | shopId
------------------------------------------------
1 | 1 | 2018-01-18 09:44:00 | 3
2 | 2 | 2018-01-18 10:32:00 | 3
3 | 3 | 2018-01-18 11:19:00 | 3
4 | 1 | 2018-01-18 17:57:00 | 3
5 | 1 | 2018-01-18 16:31:00 | 1
6 | 1 | 2018-01-19 08:31:00 | 3
Basically I want to find rows where users have checked-in more than once (>=2) on the same day and the same shop. So for instance if a user checks-in as in rows with ids 1 and 4 (same user, same day, same shop), the query should return a hit with the the entire rows (id, userIDFK, checkin_datetime, shopId). Hope this makes sense.
I already tried using
SELECT id, userIDFK, checkin_datetime, shopId
FROM (
SELECT * FROM 'checkins' WHERE COUNT(userIDFK)>=2 AND COUNT(shopId)>=2
)
The same day part I have no clew how to do it, and I know this query is way off, but this is the best I could.
You can try grouping by userId checkin_date and shopID
SELECT userIDFK, checkin_datetime, shopId,COUNT(SHOPiD)
FROM checkins
GROUP BY userIDFK, DATE(checkin_datetime), shopId
HAVING COUNT(SHOPID)>1
EDIT
You can include a subquery to get all lines:
select b.id,b.userIDFK, b.checkin_datetime, b.shopId
from checkins b
where (SELECT COUNT(SHOPiD)
FROM checkins a
where a.userIDFK=b.userIDFK and date(a.checkin_datetime)=date(b.checkin_datetime) and a.shopId=b.a.shopId
GROUP BY userIDFK, DATE(checkin_datetime), shopId)>1
GROUPBY can be used to get the multiple occurrences.
SELECT id, userIDFK, checkin_datetime, shopId
FROM checkins
GROUP BY userIDFK, DATE(checkin_datetime), shopId
HAVING count(id) > 1;
Hope it helps!
EDIT:
Using inner join you can achieve it. Here is the query:
SELECT c1.* FROM checkins c1 INNER JOIN checkins c2
ON c1.userIDFK = c2.userIDFK
AND date(c1.checkin_datetime) = date(c2.checkin_datetime)
AND c1.shopId = c2.shopId
AND c1.id != c2.id
Cheers!!
I have 3 tables and I am trying to join those tables with inner join. however when I use count(distinct column_id) it mysql through error which is
SQL syntax : check
for the right syntax to use near '(DISTINCT as_ticket.vehicle_id) FROM as_vehicle INNER JOIN as_ticket
My Query
SELECT
`as_vehicle`.`make`, `as_vehicle`.`model`, `as_odometer`.`value`
COUNT (DISTINCT `as_ticket`.`vehicle_id`)
FROM `as_vehicle`
INNER JOIN `as_ticket`
ON `as_vehicle`.`vehicle_id` = `as_ticket`.`vehicle_id`
INNER JOIN `as_odometer`
ON `as_odometer`.`vehicle_id` = `as_vehicle`.`vehicle_id`
WHERE `as_ticket`.`vehicle_id` = 7
ORDER BY `as_odometer`.`value`
DESC
Tbl as_vehicle
+------------+-------------+---------+
| vehicle_id |make | model |
+------------+-------------+---------|
| 1 | HYUNDAI | SOLARIS |
| 2 | A638EA15 | ACCENT |
+-------------+------------+---------+
Tbl as_odometer;
+------------+-------+
| vehicle_id | value |
+------------+-------+
| 1 | 10500 |
| 5 | 20000 |
| 1 | 20000 |
+------------+-------+
Tbl service
+-----------+------------+
| ticket_id | vehicle_id |
+-----------+------------+
| 1 | 1 |
| 2 | 1 |
+-----------+------------+
You forgot a comma before count.
SELECT `as_vehicle`.`make`, `as_vehicle`.`model`, `as_odometer`.`value`,
count(DISTINCT `as_ticket`.`vehicle_id`) // here ---^
First, you should not have a space after the count() and you have a missing comma (as already noted). More importantly, you don't have a group by, so your query will return one row.
And, because of the where clause, the value will always be "1". You have restricted the query to just one vehicle id.
I suspect the query you want is more like:
SELECT `as_vehicle`.`make`, `as_vehicle`.`model`, `as_odometer`.`value`
COUNT(*)
FROM `as_vehicle` INNER JOIN
`as_ticket`
ON `as_vehicle`.`vehicle_id` = `as_ticket`.`vehicle_id` INNER JOIN
`as_odometer`
ON `as_odometer`.`vehicle_id` = `as_vehicle`.`vehicle_id`
WHERE `as_ticket`.`vehicle_id` = 7
GROUP BY `as_vehicle`.`make`, `as_vehicle`.`model`, `as_odometer`.`value`
ORDER BY `as_odometer`.`value` DESC;
Also, you should learn to use table aliases and all those backquotes don't help the query.
How to filter query with order by and limit when using left join
store_profile
id + store_name
1 | Accessorize.me
2 | Active IT
3 | Edushop
4 | Gift2Kids
5 | Heavyarm
6 | Bamboo
store_fee
id + store_id + date_end
1 | 1 | 27-6-2013
2 | 2 | 29-8-2013
3 | 3 | 02-6-2013
4 | 4 | 20-4-2013
5 | 4 | 01-7-2013
6 | 4 | 28-9-2013
7 | 5 | 03-9-2013
8 | 6 | 01-9-2013
my previous query
$order_by_for_sort_column = "order by $column" //sorting column
$query = "SELECT * FROM store_profile sp LEFT JOIN store_fee sf ON (sf.store_id = sp.id) $order_by_for_sort_column";
what i want is order by id desc and limit 1 for table store_fee not for for entire query. So i can grab the latest date in date_end for each store.
As you can see for store_id 4(store_fee) i have 3 different date and i just want grab the latest date.
and the result should be something like this
1 | Accessorize.me 27-6-2013
2 | Active IT 29-8-2013
3 | Edushop 02-6-2013
4 | Gift2Kids 28-9-2013
5 | Heavyarm 03-9-2013
6 | Bamboo 01-9-2013
SELECT a.id, a.store_name, MAX(b.date_End) date_end
FROM store_profile a
LEFT JOIN store_fee b
ON a.ID = b.store_ID
GROUP BY a.id, a.store_name
SQLFiddle Demo
but if the datatype date_End column is varchar, the above query won't work because it sorts the value by character and that it can mistakenly gives undesired result. 18-1-2013 is greater than 01-6-2013.
To further gain more knowledge about joins, kindly visit the link below:
Visual Representation of SQL Joins
SELECT *
FROM store_profile AS sp
LEFT JOIN (
SELECT store_id, MAX(date_end)
FROM store_fee
GROUP BY store_id
) AS sf
ON sp.id=sf.store_id;
Update #1: query gives me syntax error on Left Join line (running the query within the left join independently works perfectly though)
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance'
FROM MyTable b1
JOIN CustomerInfoTable c on c.id = b1.company_id
#Filter for Clients of particular brand, package and active status
where c.brand_id = 2 and c.status = 2 and c.package_id = 3
LEFT JOIN
(
SELECT b2.company_id, sum(b2.debit) as 'Current_Usage'
FROM MyTable b2
WHERE year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
)
b3 on b3.company_id = b1.company_id
group by b1.company_id;
Original Post:
I keep track of debits and credits in the same table. The table has the following schema:
| company_id | timestamp | credit | debit |
| 10 | MAY-25 | 100 | 000 |
| 11 | MAY-25 | 000 | 054 |
| 10 | MAY-28 | 000 | 040 |
| 12 | JUN-01 | 100 | 000 |
| 10 | JUN-25 | 150 | 000 |
| 10 | JUN-25 | 000 | 025 |
As my result, I want to to see:
| Grouped by: company_id | Balance* | Current_Usage (in June) |
| 10 | 185 | 25 |
| 12 | 100 | 0 |
| 11 | -54 | 0 |
Balance: Calculated by (sum(credit) - sum(debits))* - timestamp does not matter
Current_Usage: Calculated by sum(debits) - but only for debits in JUN.
The problem: If I filter by JUN timestamp right away, it does not calculate the balance of all time but only the balance of any transactions in June.
How can I calculate the current usage by month but the balance on all transactions in the table. I have everything working, except that it filters only the JUN results into the current usage calculation in my code:
SELECT b.company_id, ((sum(b.credit)-sum(b.debit))/1024/1024/1024/1024) as 'BW_remaining', sum(b.debit/1024/1024/1024/1024/28*30) as 'Usage_per_month'
FROM mytable b
#How to filter this only for the current_usage calculation?
WHERE month(a.timestamp) = 'JUN' and a.credit = 0
#Group by company in order to sum all entries for balance
group by b.company_id
order by b.balance desc;
what you will need here is a join with sub query which will filter based on month.
SELECT T1.company_id,
((sum(T1.credit)-sum(T1.debit))/1024/1024/1024/1024) as 'BW_remaining',
MAX(T3.DEBIT_PER_MONTH)
FROM MYTABLE T1
LEFT JOIN
(
SELECT T2.company_id, SUM(T2.debit) T3.DEBIT_PER_MONTH
FROM MYTABLE T2
WHERE month(T2.timestamp) = 'JUN'
GROUP BY T2.company_id
)
T3 ON T1.company_id-T3.company_id
GROUP BY T1.company_id
I havn't tested the query. The point here i am trying to make is how you can join your existing query to get usage per month.
alright, thanks to #Kshitij I got it working. In case somebody else is running into the same issue, this is how I solved it:
SELECT b1.company_id, ((sum(b1.credit)-sum(b1.debit)) as 'Balance',
(
SELECT sum(b2.debit)
FROM MYTABLE b2
WHERE b2.company_id = b1.company_id and year(b2.timestamp) = '2012' and month(b2.timestamp) = '06'
GROUP BY b2.company_id
) AS 'Usage_June'
FROM MYTABLE b1
#Group by company in order to add sum of all zones the company is using
group by b1.company_id
order by Usage_June desc;
I have a table say :
id| AccID | Subject | Date
1 | 103 | Open HOuse 1 | 11/24/2011 9:00:00 AM
2 | 103 | Open HOuse 2 | 11/25/2011 10:00:00 AM
3 | 72 | Open House 3 | 11/26/2011 1:10:28 AM
4 | 82 | OPen House 4 | 11/27/2011 5:00:29 PM
5 | 82 | OPen House 5 | 11/22/2011 5:00:29 PM
From the above table, i need all the unique values for the Accid. But say, if there are two or more columns with the same Accid, then i need the one which has the smaller date (among the columns which have the same Accid)
So, from the above table, the o/p should be :
1
3
5
Can any1 please help me in this ? Thanks
SELECT t1.*
FROM [MyTable] t1
INNER JOIN
(
SELECT AccID, MIN(Date) Date
FROM [MyTable]
GROUP BY AccID
) t2 ON t1.AccID = t2.AccID AND t1.Date = t2.Date
More than just the AccID but...
WITH SEL
AS
(
SELECT AccID, MIN(DATE)
FROM table
GROUP BY AccID
)
SELECT table.*
FROM table
JOIN SEL ON SEL.AccID = table.AccID