WHERE in (subquery) clause yii - mysql

Question

I have a mysql query like this
(SELECT
`notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, `event`.`title` as sourceName,concat_ws(" ",v.firstname,v.lastname) as ActorName
FROM
`notification`
INNER JOIN
`event`
ON
event.id = notification.source_id
INNER JOIN
`user` as v
ON
v.id = notification.user_id
AND
notification.activity_type = "checkin"
where
user_id in
(SELECT friend.friend_id from friend WHERE friend.user_id=1 AND friend.is_active=1))
UNION
(SELECT
`notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, concat_ws(" ",u.firstname,u.lastname) as sourceName,concat_ws(" ",v.firstname,v.lastname) as ActorName
FROM
`notification`
INNER JOIN
`user` as u
ON
u.id = notification.source_id
INNER JOIN
`user` as v ON v.id = notification.user_id
AND
notification.activity_type = "friend"
where user_id in
(SELECT friend.friend_id from friend WHERE friend.user_id=1 AND friend.is_active=1) )
And i want to write that query in yii2 and i dont know how to write subquery in where in clause.
So far i have done this
$query2 ->select(['notification.id', 'notification.user_id AS user_id', 'notification.activity_type', 'notification.source_id', 'concat_ws(" ",u.firstname,u.lastname) as sourceName','concat_ws(" ",v.firstname,v.lastname) as ActorName','user_image.imagepath as image'])
->from('notification' )
->innerJoin('user as u', 'u.id = notification.source_id')
->innerJoin('user_image','user_image.user_id = notification.user_id')
->innerJoin('user as v', 'v.id = notification.user_id AND notification.activity_type = "friend"')
->where('user_image.imagetype="profile"')
->andWhere(['user_id'=>('SELECT friend.friend_id from friend WHERE friend.user_id='.$id.' AND friend.is_active=1')]);
$query ->select(['notification.id','notification.user_id AS user_id','notification.activity_type', 'notification.source_id', 'event.title as sourceName','concat_ws(" ",v.firstname,v.lastname) as ActorName','organiser.image as image'])
->from('notification')
->innerJoin('event', 'event.id = notification.source_id')
->innerJoin('organiser','organiser.organiser_id = event.organiser_id')
->innerJoin('user as v', 'v.id = notification.user_id AND notification.activity_type = "checkin"')
->Where(['in', 'user_id', [488,489]])
->union($query2);
Which generates the command query like this
(SELECT
`notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, `event`.`title` AS `sourceName`, concat_ws(" ",v.firstname,v.lastname) as ActorName, `organiser`.`image` AS `image`
FROM
`notification`
INNER JOIN
`event`
ON
event.id = notification.source_id
INNER JOIN
`organiser`
ON
organiser.organiser_id = event.organiser_id
INNER JOIN
`user` `v`
ON
v.id = notification.user_id
AND
notification.activity_type = "checkin"
WHERE
`user_id` IN (:qp0, :qp1))
UNION
( SELECT
`notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, concat_ws(" ",u.firstname,u.lastname) as sourceName, concat_ws(" ",v.firstname,v.lastname) as ActorName, `user_image`.`imagepath` AS `image`
FROM
`notification`
INNER JOIN
`user` `u`
ON
u.id = notification.source_id
INNER JOIN
`user_image`
ON
user_image.user_id = notification.user_id
INNER JOIN
`user` `v`
ON
v.id = notification.user_id
AND
notification.activity_type = "friend"
WHERE
(user_image.imagetype="profile") AND (`user_id`=:qp2) )
But its not working,so what is the right syntax
and also feel free to give suggestion if where in could be write with inner join
that would make it very easy to write query
thank you

Answer 1

Try This
$query = (new Query())
->select('notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, `event`.`title` as sourceName,concat_ws(" ",v.firstname,v.lastname) as ActorName')
->from('notification')
->innerJoin('event' ,'event.id = notification.source_id')
->innerJoin('user v' ,'v.id = notification.user_id')
->where([
'user_id' => (new Query())
->select('friend.friend_id')
->from('friend')
->where([
'friend.user_id' => 1,
'friend.is_active' => 1
])
])->andWhere([
'notification.activity_type' => "checkin"
]);
$query2 = (new Query())
->select('`notification`.`id`, `notification`.`user_id` AS `user_id`, `notification`.`activity_type`, `notification`.`source_id`, concat_ws(" ",u.firstname,u.lastname) as sourceName,concat_ws(" ",v.firstname,v.lastname) as ActorName')
->from('notification')
->innerJoin('user v' ,'v.id = notification.user_id')
->where([
'user_id' => (new Query())
->select('friend.friend_id')
->from('friend')
->where([
'friend.user_id' => 1,
'friend.is_active' => 1
])
])->andWhere([
'notification.activity_type' => "checkin"
])->union($query)->all();

Answer 2

You can use Yii2 Query Builder, here is an example.
$subQuery = (new \yii\db\Query())->select([
'users.id as userId',
'users.first_name',
'users.username',
'users.last_name',
'users.sector_id',
])
->from(['users'])
->where(['=', 'role_id', 3])
->orWhere(['=', 'role_id', 2])
->groupBy('users.id');
$query = (new \yii\db\Query())->select(['user.*', 'user_address.*'])
->from(['user'=>$subQuery])
->leftJoin('user_address', 'user.userId = user_address.user_id')
->where(['between', 'latitude', $min_lat, $max_lat])
->andWhere(['between', 'longitude', $min_lon, $max_lon])
->groupBy('user.userId');