At first, it's a bit complicated to create an SQL fiddle with the problem because the data amount is huge. By this I try to drop an screenshot with the result I have.
The problem seems to be small, my query runs perfectly but because different images are linked to different locations in the same city (or cities in range of the distance) I get back two times or more the same image at this time. Because this query is running on 'city' niveau, I just need to get back one image as I need the first one out of the results (supposed to be the closest one to my lan/lon).
The query:
SELECT c.slug
,l.location_id
,fl.flyer_id
,f.salt
,f.NAME
,f.online
,f.cover
,fc.cat_id
,ca.NAME AS cat_name
,lan
,lon
,(6371 * acos(cos(radians(1.5000759112888)) * cos(radians(lan)) * cos(radians(lon) - radians(2.6118285879120)) + sin(radians(1.5000759112888)) * sin(radians(lan)))) AS distance
FROM cities c
INNER JOIN locations l
ON c.slug = l.city_slug
INNER JOIN flyers_locations fl
ON l.location_id = fl.location_id
INNER JOIN flyers_categories fc
ON fl.flyer_id = fc.flyer_id
INNER JOIN categories ca
ON fc.cat_id = ca.id
INNER JOIN flyers f
ON fl.flyer_id = f.id
HAVING distance < 25
AND l.location_id != ''
AND fc.cat_id = '41'
AND f.online = '1'
ORDER BY distance ASC
LIMIT 100
The result
Many thanks
If you don´t want an image to appear twice you could try using distinct in front of the column name.
But if you realy only want to fetch the first one why not just set the limit to 1? This way you would only get the first (closest) row.
Related
Is it possible to use two "select" in the same query?
I tried it but got the syntax error several times.
My query example:
SELECT
comp.id,
comp.document,
comp.dateStart,
comp.companyName,
comp.fantasyName,
comp.legalNature,
comp.mainActivity,
comp.situation,
comp.shareCapital,
comp.idCompanyStatus,
pp.userCredentialId,
uc.name,
cs.name AS 'nameStatus',
cs.color AS 'colorStatus',
cs.description,
comp.idPurchasedProduct,
comp.actived,
comp.createAt,
comp.updateAt,
comp.phone
FROM `PurchasedProduct` pp
INNER JOIN
`Company` comp on comp.idPurchasedProduct = pp.id
INNER JOIN
`UserCustomer` uc on pp.userCredentialId = uc.credentialId
INNER JOIN
`CompanyStatus` cs on cs.id = comp.idCompanyStatus
WHERE
comp.actived = 1
LIMIT 0,5;
SELECT COUNT(id) AS totalItems, CEILING(COUNT(id) / 10) AS totalPages FROM Company;
I would like the result shown to be all queries on the screen.
Basically, what I want is that the result shown when executing the query is the first and second "select" together.
I really don't know how or don't understand how to do this.
Example:
first result with seconde result
I want to show both results at once.
The documents is fake, not real. Only for demo.
You should be able to do by having the second query as its own JOIN query. Since there is no group by, it is only returning a single row. By no join condition, the value will be available for every row otherwise. So you SHOULD be able to get by doing
select
[ all your other columns ],
JustCounts.TotalItems,
JustCounts.TotalPages
from
[PurchasedProduct and all your other joins]
JOIN ( SELECT
COUNT(id) AS totalItems,
CEILING(COUNT(id) / 10) AS totalPages
FROM Company ) as JustCounts
where
[rest of your original query]
Hi dev's i'm new with "advanced" SQL I've try alone but I dont understand how to have the good result.
I'll try to take information from 4 tables in the same DB.
The first table items only have id and name.
2 others tables take the id from items to extract data.
The last tables takes one data from items_buy for print another data.
Lastly I concat 2 column from 2 DB for having a full information.
SELECT items.id, items.name, items_buy.item_cost AS item_cost, items_sales.item_price AS item_price, CONCAT(trader.name, planet.name) AS name_point
FROM ((((items
INNER JOIN items_buy ON items_buy.id = items.id)
INNER JOIN trader ON trader.id = items_buy.name_point)
INNER JOIN items_sales ON items_sales.id = items.id)
INNER JOIN planet ON planet.id = trader.planet)
WHERE items.id = 1;
I dont know how to make it work, she doesnt return an error in SQLyog or on my server.
In order:
ID / NAMEITEM / PRICE / SELLINGPRICE / NAME from concat
If you need more, some test data:
https://pastebin.com/6Bs4kbN9
I've run your test data and run your script against it. As I suggested in my commment, the problem is with the INNER JOIN you are using.
I am not sure whether you are aware, but when using an INNER JOIN, if the joined table is NULL for the current row, then nothing at all will be returned.
If you modify your query to use a LEFT JOIN, you will see the results that are available regardless of whether the joined tables are NULL or otherwise:
SELECT items.id, items.name, items_buy.item_cost AS item_cost, items_sales.item_price AS item_price, CONCAT(trader.name, planet.name) AS name_point
FROM ((((items
LEFT JOIN items_buy ON items_buy.id = items.id)
LEFT JOIN trader ON trader.id = items_buy.name_point)
LEFT JOIN items_sales ON items_sales.id = items.id)
LEFT JOIN planet ON planet.id = trader.planet)
WHERE items.id = 1;
This produces:
1 Agricium 24.45 25.6 NULL
1 Agricium 24.6 25.6 NULL
The problem in the case of your example is that the join to trader or planet has no result and therefore produces no output.
I'm trying to create a SQL query that uses one table to count the number of blade servers our company has in each chassis and groups those, while joining it with chassis information from another table.
However, one of the chassis has no blades in it, so the name does not appear in the blade inventory table. Using an INNER JOIN creates a table that doesn't contain that blade in any capacity. A LEFT JOIN achieves the same effect, but a RIGHT JOIN gives me an extra row with a null value for the chassis name.
I'm guessing this is because the non-existence of that blade name in the first table is being given precedence over the second, but not sure how to correct that. My query, as of now, looks like this:
SELECT e.EnclosureName, e.PDUName, q.Blades, r.Serial#
FROM bladeinventory.table e JOIN
(
SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q ON e.EnclosureName = q.EnclosureName
LEFT JOIN chassisinventory.table r
ON e.EnclosureName = r.EnclosureName
GROUP BY e.EnclosureName, e.PDUName, q.Blades, r.Serial#
Is it possible to edit this in such a way that the name of the chassis with 0 blades is actually generated by the query?
Just pull the name from the chassisinventory table. I'll use coalesce(), just in case you switch the order of the joins (again):
SELECT COALESCE(r.EncloseName, e.EnclosureName) as EnclosureName, e.PDUName, q.Blades, r.Serial#
FROM bladeinventory.table e JOIN
(SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q
ON e.EnclosureName = q.EnclosureName LEFT JOIN
chassisinventory.table r
ON e.EnclosureName = r.EnclosureName
GROUP BY COALESCE(r.EncloseName, e.EnclosureName), e.PDUName, q.Blades, r.Serial#;
You can also use below code where case is being used which is much simpler and effective
SELECT e.EnclosureName, r.PDUName,
case when q.Blades IS NULL then 0
else q.Blades end Blades,
e.Serial#
FROM chassisinventory.table e
LEFT OUTER JOIN bladeinventory.table r on e.EnclosureName = r.EnclosureName
LEFT OUTER JOIN (SELECT EnclosureName,COUNT(*) Blades
FROM bladeinventory.table
GROUP BY EnclosureName
) q on e.EnclosureName = q.EnclosureName
My goal is to show search results of companies both: with categories and without (not added yet). My companies table has more or less 12 000 records. Companies with categories are only more or less 200.
There are two search inputs:
$name -> name of company or category.
$id_country -> id of the country
I want to display:
1) how many results is in all database. (that's why i use: SQL_CALC_FOUND_ROWS)
2) i use LIMIT to show 10 results per page (with pagination).
My query:
SELECT SQL_CALC_FOUND_ROWS
c.*,
lc.name as langName,
lc.shortDesc,
lc.longDesc
FROM companies c
JOIN lang_companies lc USING(id_company)
LEFT JOIN categories_companies cc USING(id_company)
LEFT JOIN lang_categories lang_cat USING (id_category)
WHERE
lc.id_lang = '2' AND c.status = 1 AND c.active = 1 AND c.id_country = ".$id_country." AND
(lc.name = LCASE('".$name."') OR (lang_cat.name = LCASE('".$name."') AND lang_cat.id_lang = '2')
OR c.city = '".$name."')
GROUP BY c.id_company
ORDER BY c.id_hierarchi asc
LIMIT 0, 10
This query executes more or less 6 seconds and I want to optimize it. Could you help me?
I will be grateful for any suggestions.
Out of the FROM part of your query, you do not seem to actually use the tables which are joined with these two lines:
LEFT JOIN categories_companies cc USING(id_company)
LEFT JOIN categories cat USING (id_category)
I presume you can simply exclude them from the query, if they are not relevant through something more sublte like the join suppressing rows.
I'm having an odd problem with the following query, it works all correct,
the count part in it gets me the number of comments on a given 'hintout'
I'm trying to add a similar count that gets the number of 'votes' for each hintout, the below is the query:
SELECT h.*
, h.permalink AS hintout_permalink
, hi.hinter_name
, hi.permalink
, hf.user_id AS followed_hid
, ci.city_id, ci.city_name, co.country_id, co.country_name, ht.thank_id
, COUNT(hc.comment_id) AS commentsCount
FROM hintouts AS h
INNER JOIN hinter_follows AS hf ON h.hinter_id = hf.hinter_id
INNER JOIN hinters AS hi ON h.hinter_id = hi.hinter_id
LEFT JOIN cities AS ci ON h.city_id = ci.city_id
LEFT JOIN countries as co ON h.country_id = co.country_id
LEFT JOIN hintout_thanks AS ht ON (h.hintout_id = ht.hintout_id
AND ht.thanker_user_id = 1)
LEFT JOIN hintout_comments AS hc ON hc.hintout_id = h.hintout_id
WHERE hf.user_id = 1
GROUP BY h.hintout_id
I tried to add the following to the select part:
COUNT(ht2.thanks_id) AS thanksCount
and the following on the join:
LEFT JOIN hintout_thanks AS ht2 ON h.hintout_id = ht2.hintout_id
but the weird thing happening, to which I could not find any answers or solutions,
is that the moment I add this addtiional part, the count for comments get ruined (I get wrong and weird numbers), and I get the same number for the thanks -
I couldn't understand why or how to fix it...and I'm avoiding using nested queries
so any help or pointers would be greatly appreciated!
ps: this might have been posted twice, but I can't find the previous post
When you add
LEFT JOIN hintout_thanks AS ht2 ON h.hintout_id = ht2.hintout_id
The number of rows increases, you get duplicate rows for table hc, which get counted double in COUNT(hc.comment_id).
You can replace
COUNT(hc.comment_id) <<-- counts duplicated
/*with*/
COUNT(DISTINCT(hc.comment_id)) <<-- only counts unique ids
To only count unique appearances on an id.
On values that are not unique, like co.county_name the count(distinct will not work because it will only list the distinct countries (if all your results are in the USA, the count will be 1).
Quassnoi
Has solved the whole count problem by putting the counts in a sub-select so that the extra rows caused by all those joins do not influence those counts.
SELECT h.*, h.permalink AS hintout_permalink, hi.hinter_name,
hi.permalink, hf.user_id AS followed_hid,
ci.city_id, ci.city_name, co.country_id, co.country_name,
ht.thank_id,
COALESCE(
(
SELECT COUNT(*)
FROM hintout_comments hci
WHERE hc.hintout_id = h.hintout_id
), 0) AS commentsCount,
COALESCE(
(
SELECT COUNT(*)
FROM hintout_comments hti
WHERE hti.hintout_id = h.hintout_id
), 0) AS thanksCount
FROM hintouts AS h
JOIN hinter_follows AS hf
ON hf.hinter_id = h.hinter_id
JOIN hinters AS hi
ON hi.hinter_id = h.hinter_id
LEFT JOIN
cities AS ci
ON ci.city_id = h.city_id
LEFT JOIN
countries as co
ON co.country_id = h.country_id
LEFT JOIN
hintout_thanks AS ht
ON ht.hintout_id = h.hintout_id
AND ht.thanker_user_id=1
WHERE hf.user_id = 1