I have a query like :
SELECT COUNT(DISTINCT `ID`) FROM db1.table UNION ALL SELECT COUNT(DISTINCT `ID`) FROM db2.table
My real query is more complicate, i have LEFT JOIN and multiple condition etc...
This query return to me an array with 2 results : Count 1 and Count 2
How can i only return one result ? Count 1 + Count 2 ?
Thanks !
Try this:
SELECT (SELECT COUNT(DISTINCT `ID`) FROM db1.table) +
(SELECT COUNT(DISTINCT `ID`) FROM db2.table)
If you also want to return separate db1, db2 counts, then use this query:
SELECT countDb1, countDb2, countDb1 + countDb2 AS total
FROM (
SELECT (SELECT COUNT(DISTINCT `ID`) FROM db1.table) AS countDb1,
(SELECT COUNT(DISTINCT `ID`) FROM db2.table) AS countDb2) AS t
Related
This is the result of a UNION of two SELECT
SELECT count(*) FROM
((SELECT session_id_current_user from test.tws_analytics
WHERE (add_date BETWEEN '2022-05-15' AND '2022-05-15') AND ((pathURL='vues/login.php' AND name_current_user='') OR (pathURL='' AND searchURL='?job=forgotten' AND name_current_user=''))
AND session_id_current_user NOT IN
(SELECT session_id_current_user from test.tws_analytics
WHERE (pathURL <> 'vues/login.php' AND searchURL <> '?job=forgotten') AND add_date BETWEEN '2022-05-15' AND '2022-05-15' order by session_id_current_user)
order by session_id_current_user)
UNION
(SELECT name_current_user from test.tws_analytics where add_date BETWEEN '2022-05-15' AND '2022-05-15' AND name_current_user IS NOT NULL AND name_current_user <> ''))
AS tem
The result is 11.
What I want to do is to select this result with other columns like this :
SELECT count(session),count(name), [AND tem.count(*)] FROM ....
This is the general idea, though i didn't know how to implement it.
a simplified general answer would be
select * from (select count(*) numsessions from sessions), (select count(*) numusers from users)
this will give 2 different counts, i didn't include the logics that you provided, but that will need to be done inside the 2 subqueries.
Below is my query to get some data for dashboard screen.
SELECT COUNT(*) as occupied_rooms FROM rooms where available='N' ;
SELECT COUNT(*) as checkedIn_guests FROM booking where checkout_time='' ;
SELECT COUNT(*) as available_rooms FROM rooms where available='Y' ;
SELECT COUNT(*) as total_guest FROM booking;
SELECT COUNT(*) as total_booking FROM booking;
SELECT COUNT(*) as total_staff FROM employee;
It produce output as show in above
How ever I want the output like given above image.
Use union all
SELECT 'occupied_rooms' as which, COUNT(*) as cnt FROM rooms where available = 'N'
UNION ALL
SELECT 'checkedIn_guests', COUNT(*) FROM booking where checkout_time = ''
UNION ALL
SELECT 'available_rooms', COUNT(*) FROM rooms where available = 'Y' ;
UNION ALL
SELECT 'total_guest', COUNT(*) FROM booking;
UNION ALL
SELECT 'total_booking', COUNT(*) FROM booking;
UNION ALL
SELECT 'total_staff', COUNT(*) FROM employee;
You could make the query a bit more efficient by combining the queries that reference the same table. But the overall structure would be essentially the same.
You could use a UNION for build single table result with each result in a row
SELECT 'occupied_rooms', COUNT(*) count
FROM rooms
where available='N'
UNION
SELECT 'checkedIn_guests', COUNT(*)
FROM booking
where checkout_time=''
UNION
SELECT 'available_rooms', COUNT(*)
FROM rooms
where available='Y'
UNION
SELECT 'total_guest', COUNT(*)
FROM booking
UNION
SELECT 'total_booking', COUNT(*)
FROM booking
UNION
SELECT 'total_staff', COUNT(*)
FROM employee;
I have 3 tables. I want to select count in 1 result, like:
table1=1000 records + table2=400 records + table3=200 records = 1600
1600 is the one result I want back from the server.
MySQL inner join perhaps? Any suggestions?
Try this :
select sum(c) from (
select count(*) as c from table1
union
select count(*) as c from table2
union
select count(*) as c from table3
) tmp
That'll give you the total.
select
(
select count(columnname) from table1
) + (
select count(columnname) from table2
)+ (
select count(columnname) from table3
)
try this...,
SELECT (SELECT COUNT(*) FROM tbl1
)+
(SELECT COUNT(*) FROM tbl2
)+
( SELECT COUNT(*) FROM tbl3
) as 'AllCount'
select
((select count(*) from table1) + (select count(*) from table2) + (select count(*) from table3))
as totalCount;
Try this:
SELECT ((SELECT COUNT(*) FROM tbl1 ) + (SELECT COUNT(*) FROM tbl2 ) + (SELECT COUNT(*) FROM tbl3 )) AS TotalRecords
Thank you all for your responses I have 3 tables and i want to select a count in 1 single result
still i get results back like this
count1 count2 count3
1235 134 234
and this is not what i want a total one result
People
here is my little problem.
I have three table:
a_names_1
b_names_2
c_names_3
they are same by structure. all of them has two item: name and used
Is there any QUERY to run to get and count all the 'name' that has 'used'=1 from all those three tables together.
I've tried this one, but didn't work:
(SELECT COUNT(*) 'name' from a_names_1) UNION
(SELECT COUNT(*) 'name' from a_names_2) UNION
(SELECT COUNT(*) 'name' from a_names_3) WHERE `used`=1
I'm using PHPMyAdmin for MySQL.
Any Help would be appreciated.. thanks in advance
This query outputs count of distinct names from all tables with used=1
select count(distinct name)
from
(
select name,used from a_names_1 where used=1
union all
select name,used from a_names_2 where used=1
union all
select name,used from a_names_3 where used=1
) t
If you need to SUM all USED for each NAME from all tables and output only with SUM of used=1 then:
select count(*) from
(
select name, SUM(used)
from
(
select name,used from a_names_1
union all
select name,used from a_names_2
union all
select name,used from a_names_3
) t
GROUP BY name
HAVING SUM(used)=1
) t1
select count(*) as name
from
(
select name, used from a_names_1
union
select name, used from a_names_2
union
select name, used from a_names_3) t
where t.used = 1
Probably this is slow, because you lose the index optimizations. What I would do is do the three queries, something like
SELECT SUM('name') AS name_sum
FROM ((SELECT COUNT(*) 'name' from a_names_1 WHERE `used`=1)
UNION (SELECT COUNT(*) 'name' from a_names_2 WHERE `used`=1));
If this doesn't work, it is probably a problem with the usage of name
Maybe you wanted this way:
select count(*) as cnt
from
(
select name from a_names_1 t1 where t1.used = 1
union
select name from a_names_2 t2 where t2.used = 1
union
select name from a_names_3 t3 where t3.used = 1
) t
The straight forward solution;
SELECT SUM(used) FROM (
SELECT used FROM a_names_1 WHERE used=1
UNION ALL
SELECT used FROM a_names_2 WHERE used=1
UNION ALL
SELECT used FROM a_names_3 WHERE used=1
) a
SQLfiddle for testing
An alternative if you have an index on used (and the only values of used are 0 or 1) is to just do the counting using the index;
SELECT SUM(used) total FROM (
SELECT SUM(used) used FROM a_names_1
UNION ALL
SELECT SUM(used) FROM a_names_2
UNION ALL
SELECT SUM(used) FROM a_names_3
) a
SQLfiddle for this example.
If you look at the query plan of the latter query, you can see it uses the indexes effectively.
I have two tables that I count rows of them. For example;
Select count(*) FROM tbl_Events
Select count(*) FROM tbl_Events2
I need total count. How can I sum the result with a single statement?
select sum(cnt) from (
select count(*) as cnt from tbl_events
union all
select count(*) as cnt from tbl_events2
) as x
Try this:
SELECT (Select count(*) FROM tbl_Events) + (Select count(*) FROM tbl_Events2)
Or (tested in MSSQL), this:
SELECT COUNT(*)
FROM (SELECT * FROM tbl_Events
UNION ALL
SELECT * FROM tbl_Events2) AS AllEvents
I'd guess the first will lead to better performance because it has more obvious index options. Test to be sure, though.
Select Count(*)
From(
Select * From tbl_Events
Union All
Select * From tbl_Events2) as A