I tried searching but no success i want to upload max 5 images to database along with user form data.I have table where all user data of form posted is saved along with images uploaded[image upload is attached with user form] picture fields in database are named as pic1,pic2,pic3.. pic5 + email,password etc I am successfull in uploading image data to database but not images.
//controller
if ($this->form_validation->run()!=true) {
$data['countryDrop'] = $this->Country_states_cities->getCountries();
$this->load->view('header');
$this->load->view('register',$data); //Display page
$this->load->view('footer');
}else{
$form=array();
$form['first_name']=$this->input->post("first_name",true);
$form['last_name']=$this->input->post("last_name",true);
$form['dob']=date('Y-m-d',strtotime($this->input->post("dob",true)));
$form['email']=$this->input->post("email",true);
$form['password']=sha1($this->input->post("password",true));
$form['phone']=$this->input->post("phone",true);
$form['addline2']=$this->input->post("addressline2",true);
$form['zip']=$this->input->post("zip",true);
$result = $this->Couch_reg->insert_new_user($form); //call to model
//model
function insert_new_user($form)
{
$this->db->insert('tbl_usrs',$form);
if ($this->db->affected_rows() > 0) {
return true;
} else {
return false;
}
}
//view
<input type="file" name="uploadfile[]" accept = "image/*" multiple = "multiple" size="20" /> <br />
as we can see model part is very short i want to collect images name in array form and send it to database.
You need to save the images in the upload folder and save the image name in the database.
<html>
<body>
<form method="POST" action="<?php echo site_url('my-controller/file_upload');?>" 'enctype'=>'multipart/form-data'>
<label for="file">Filename:</label>
<input type="file" name="userfile[]" id="file" multiple>
<input type="submit" value="upload"></form>
</body>
</html>
Then create controller
make funtion inside it:
$files = $_FILES;
$cpt = count($_FILES['userfile']['name']);
for($i=0; $i<$cpt; $i++)
{
$_FILES['userfile']['name']= $files['userfile']['name'][$i];
$_FILES['userfile']['type']= $files['userfile']['type'][$i];
$_FILES['userfile']['tmp_name']= $files['userfile']['tmp_name'][$i];
$_FILES['userfile']['error']= $files['userfile']['error'][$i];
$_FILES['userfile']['size']= $files['userfile']['size'][$i];
$this->upload->initialize($this->set_upload_options());
$this->upload->do_upload();
$fileName = $_FILES['userfile']['name'];
$images[] = $fileName;
Hope this will help you.
For more you can try this: http://w3code.in/2015/09/upload-file-using-codeigniter/
Related
I want to store an Image through a modal, usually, I store images this way. But it never stores, it stores null on the database, like the file wasn't even uploaded. Everything else on the modal stores perfectly, except the image.
This is the code for the image on my controller.
if($request->hasFile('image')){
$file = $request->file('image');
$extension = $file->getClientOriginalExtension();
$filename = time() .'.'.$extension;
$file->move('uploads/event/',$filename);
$event->image = $filename;
}
In my view, this is how I upload the image.
<div class="text-center">
<img src='http://ssl.gstatic.com/accounts/ui/avatar_2x.png' width="300px" height="300px" class="avatar img-circle img-thumbnail" alt="avatar" name="image" >
</div><hr>
<div class="input-group">
<div class="custom-file">
<input type="file" class="custom-file-input" name="image" >
<label class="custom-file-label">Upload picture</label>
</div>
</div>
For the code I had, the only problem was that I didn't use the enctype="multipart/form-data". After looking for options, I found this and wrote it on the form of action and form-group div. It worked, the image stores and it also updates.
<form action="{{action('CalendarController#store')}}" method="POST" enctype="multipart/form-data">
{{csrf_field()}}
<div class="modal-body">
<div class="form-group" enctype="multipart/form-data">
Since I got this working I will start implementing other codes for better performance and start to learn about the Storage in laravel. Thanks to all of you!
Try this on your Controller:
use Image;
public function store(CreateRequest $request)
{
$file = $request->file('image');
$imagename = $file->getClientOriginalName();
$imageext = $file->getClientOriginalExtension();
$path = 'upload/image/'.time().'.'.$imageext;
$image = Image::make($file);
$image->save($path);
$input = $request->all();
$input['image'] = $path;
$user = $this->userRepository->create($input);
return redirect(route('users.index'));
}
do the same with update() function
The file will store in /public/upload/image folder
You can also try and use the 'Intervention\Image' and File class:
composer require intervention/image
<?php
...
use File;
use Intervention\Image\Facades\Image
...
if ($request->hasFile('image')) {
$image = $request->file('image');
$filename = 'image.'.$image->getClientOriginalExtension();
$save_path = storage_path().'uploads/event/';
$path = $save_path.$filename;
$public_path = 'uploads/event/'.$filename;
// Make the user a folder and set permissions
File::makeDirectory($save_path, $mode = 0755, true, true);
// Save the file to the server
Image::make($image)->resize(300, 300)->save($save_path.$filename);
// Save the public image path
$event->image = $public_path;
$event->save();
}
return response()->json(['path' => $path], 200);
} else {
return response()->json(false, 200);
}
I have a problem with refreshing upload file form. First time when I clik Upload File it uploads file on server (folder uploads/), and path name uploads in mysql base (table 'files'). When I refresh that page it duplicates same path name in mysql base, it does not duplicate file in uploads/. I found similar solutions but not my case, where I need to stay on the same page, and list all uploaded files. Here is the form code :
<?php
if(isset($_POST['upload'])){
$targetfolder = "uploads/";
$target_file = $targetfolder . basename( $_FILES['file']['name']) ;
$ok=1;
$file_name = $_FILES['file']['name'];
$file_type=$_FILES['file']['type'];
if ($file_type=="application/pdf" || $file_type=="image/gif" || $file_type=="image/jpeg" || $file_type== "application/msword" || $file_type == "application/vnd.openxmlformats-officedocument.wordprocessingml.document" ) {
if ($ok == 0) {
echo "Sorry, your file was not uploaded.";
} else {
if (move_uploaded_file($_FILES["file"]["tmp_name"], $target_file)) {
$sql = "INSERT INTO files (path, profesor, struka) VALUES ('" .$file_name. "', '". $_SESSION['username']. "','')";
if (mysqli_query($link, $sql)){
}else {echo "ERROR connecting database $sql".mysqli_error($link);
}
} else {
echo "Sorry, there was an error uploading your file.";
}
}}
else {
echo "Sorry only PDF, DOCX, JPEG, GIF.<br>";
}}
?>
<div class = "upload">
<form method="post" enctype="multipart/form-data" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
Select file for upload:</br>
<input type="file" name="file" >
<input type="submit" id = "button_upload" value="Upload File" name="upload">
</form>
</div>
first, i don't see a place in your code, where you actually show the list of uploaded files.
second - if you refresh your page, the form is submited one more time, so another insert is done with the same data. you don't see the duplicate file, because it is just overwritten.
so, after you successfully inserted and uploaded, you should do a redirect to the same page, for example with header('Location: yourscript.php'). in this case POST will not be set.
I need to save the image for an avatar.
Can anyone give me a simple code to save and retrieve image?
I need to:
Save image in folder
Save image name in DB
Finally retrieve on image tag; I have to do it by Query Builder
Form:
<form action="" method="post" role="form" multiple>
{{csrf_field()}}
<legend>Form Title</legend>
<div class="form-group">
<label for="">Your Image</label>
<input type="file" name="avatar">
</div>
<button type="submit" class="btn btn-primary">save</button>
back
</form>
<img name="youravatar" src="">
</div>
Route:
Route::get('pic','avatarController#picshow');
Route::post('pic','avatarController#pic');
Controller:
I have the avatarController, but it is empty because I don't know what to do.
Database:
Table name: avatar
Fields: name id, imgsrc, created_at, Updated_at
Other:
I found this code but I can't find out anything:
if ($request->hasFile('avatar')) {
$file = array('avatar' => Input::file('avatar'));
$destinationPath = '/'; // upload path
$extension = Input::file('avatar')->getClientOriginalExtension();
$fileName = rand(11111,99999).'.'.$extension; // renaming image
Input::file('avatar')->move($destinationPath, $fileName);
}
First, make sure you have the encrypt attribute in your form
<form action="#" method="post" enctype="multipart/form-data">
You can use something similar to this in your controller
public function save(Request $request)
{
$file = $request->file('file');
// rename your file
$name = $file->getClientOriginalName();
\Storage::disk('local')->put($name, \File::get($file));
return "file saved";
}
Yes, you should store the file route in your database as well.
Make sure you are using a consistent path for your images like
Finally you have to create a route to give public access to your image file, like so:
Route::get('images/{file}', function ($file) {
$public_path = public_path();
$url = $public_path . '/storage/' . $file;
// file exists ?
if (Storage::exists($archivo))
{
return response()->file($pathToFile);
}
//not found ?
abort(404);
});
Check the docs about Laravel Responses
I hope this gives you an Idea of what to do.
Upload Image in laravel 5.4
check if request has image
$request->hasFile('image')
OR
$request->file('image')->isValid()
Now Save Image
$request->inputname->store('folder-name') return image path 'folder name/created image name
$request->image->store('images')
Check if image exits
Storage::disk('local')->exists('image name');
Delete Image
Storage::delete('image');
This is my code
if ($request->hasFile('image') && $request->file('image')->isValid())
{
$path = $request->image->store('images');
if(!empty($path)){
$edit = Model::FindOrFail($id);
// Delete old image
$exists = Storage::disk('local')->exists($edit->image);
if($exists){
Storage::delete($edit->image);
}
$edit->image = $path;
$edit->save();
}
}
Reference
I'm trying to access the following properties from the Wikidata API: id, url, aliases, description and label but so far have been unsuccessful. I'm sure I'm making basic mistakes and so far only have the following code. Any suggestions as to the best way to access this data is much appreciated.
<html>
<body>
<form method="post">
Search: <input type="text" name="q" value="Google"/>
<input type="submit" value="Submit">
</form>
<?php
if (isset($_POST['q'])) {
$search = $_POST['q'];
$errors = libxml_use_internal_errors(true);
$doc = new DOMDocument();
$doc->loadHTMLFile("https://www.wikidata.org/w/api.php?
action=wbsearchentities&search=Google&format=json&language=en");
libxml_clear_errors();
libxml_use_internal_errors($errors);
}
?>
</body>
</html>
Edit - I have managed to get a string ($jsonArr) containing particular data that I would like. However I would like to get the first instance of the particular elements from the string specifically id, url, alias, description and label i.e. specifically: variable1 - Q95, variable2 - //www.wikidata.org/wiki/Q95, variable3 - Google.Inc, varialbe4 - American multinational Internet and technology corporation, variable5 - Google/ Please see code below:
<HTML>
<body>
<form method="post">
Search: <input type="text" name="q" value="Google"/>
<input type="submit" value="Submit">
</form>
<?php
if (isset($_POST['q'])) {
$search = $_POST['q'];
$errors = libxml_use_internal_errors(true);
$doc = new DOMDocument();
$doc->loadHTMLFile("https://www.wikidata.org/w/api.php?
action=wbsearchentities&search=$search&format=json&language=en");
libxml_clear_errors();
libxml_use_internal_errors($errors);
var_dump($doc);
echo "<p>";
$jsonArr = $doc->documentElement->nodeValue;
$jsonArr = (string)$jsonArr;
echo $jsonArr;
}
?>
</body>
</HTML>
You need to show the JSON you want to parse...
Basicly you can get values out of JSON in PHP like this...
If $doc is the JSON you want to parse
$jsonArr = json_decode($doc, true);
$myValue = $jsonArr["keyYouWant"];
Edit after understanding what you are doing there :-)
Hi, Im sorry I was completely confused of what you were doing there... So I have testet your code on my server and just get what you want...
Following the code you wanted... I took clear var names, so they are a little bit longer, but easier to understand...
$searchString = urlencode($_POST['q']); //Encode your Searchstring for url
$resultJSONString = file_get_contents("https://www.wikidata.org/w/api.php?action=wbsearchentities&search=".$searchString."&format=json&language=en"); //Get your Data from wiki
$resultArrayWithHeader = json_decode($resultJSONString, true); //Make an associative Array from respondet JSON
$resultArrayClean = $resultArrayWithHeader["search"]; //Get the search Array and ignore the header part
for ($i = 0; $i < count($resultArrayClean); $i++) { //Loop through the search results
echo("<b>Entry: ".$i."</b>");
echo("<br>");
echo($resultArrayClean[$i]["id"]); //Search results value of key 'id' at position n
echo("<br>");
echo($resultArrayClean[$i]["url"]); //Search results value of key 'url' at position n
echo("<br>");
echo($resultArrayClean[$i]["aliases"]); //Search results value of key 'aliases' at position n
echo("<br>");
echo("<br>");
echo("<br>");
}
I am trying to upload multiple images with description in codeigniter. Everything is fine, image is uploaded, image filename is sent to database however "description" is not going to database, where did i mistake ?
form code is like this
File 1: <input type="file" name="image1" /><br />
Descr: <input type="text" name="description[]" size="50" value="" /><br/><br/>
File 2: <input type="file" name="image2" /><br />
Descr: <input type="text" name="description[]" size="50" value="" /><br/><br/>
File 3:<input type="file" name="image3" /><br />
Descr: <input type="text" name="description[]" size="50" value="" /><br/><br/>
and model is this
for($i = 1; $i < 6; $i++) {
/* Handle the file upload */
$upload = $this->upload->do_upload('image'.$i);
/* File failed to upload - continue */
if($upload === FALSE) continue;
/* Get the data about the file */
$data = $this->upload->data();
$uploadedFiles[$i] = $data;
/* If the file is an image - create a thumbnail */
if($data['is_image'] == 1) {
$configThumb['source_image'] = $data['full_path'];
$this->image_lib->initialize($configThumb);
$this->image_lib->resize();
}
$image['raw'] = $data['raw_name'];
$image['ext'] = $data['file_ext'];
$image['newsid'] = $_POST['newsid'];
$image['description'] = $_POST['description'][$i];
$this->db->insert('multipics', $image);
}
Please note that the above code makes multiple rows insertion, I just need the description field to go in database
As a work around, I would get the POST variable first outside of the loop:
// (1) Get the POST description variable outside of the look
// As a precaution, dump or echo $description to make sure it looks right...
$description_ = $this->input->post('description');
for ($i = 1; $i < 6; $i++)
{
...
// Put some checks to make sure $i is an index...
$image['description'] = $description[$i];
...
}
Try this and let us know how you get on!
Change Change name="description[]" to name="description
You may also want to look at CI's insert_batch() method. This will let you insert all of the records with one query.