I have 3 tables
draws users and ratings
users contains the user_id, draws contains an id for the draw and the user_id who is the owner of that draw, in the ratings table i save the user that gives the rating, the draw_id and the score given. Now i need to list to the user his votes received, so i need to check in the ratings table which users has voted on his draws, but i don't know how because the queries i've tried lists me only 1 record and i need all records.
Something like this:
5 stars | Draw Name | User
4 stars | Draw Name | User
This is th query i have until now, i achieved to show the most voted users but not this one.
SELECT u.usuario, u.id_usuario, d.id, COUNT(v.id) AS votos
FROM valoraciones v
JOIN dibujos d ON v.id_dibujo = d.id
JOIN usuarios u ON v.id_quien = u.id_usuario GROUP BY v.fecha ORDER BY votos DESC
This is driving me crazy.
Appreciate any help
Ok, some people here thinks is funny to downvote a post, well i'm posting the solution cause i know that it can be helpfull to.
This is the Query i built:
SELECT u.usuario, u.id_usuario, d.id, v.valoracion, v.fecha
FROM icar_valoraciones v
JOIN icar_dibujos d ON v.id_dibujo = d.id
JOIN icar_usuarios u ON v.id_quien = u.id_usuario WHERE d.id_quien = '{ID OF THE USER LOGGED IN}' GROUP BY v.id ORDER BY v.fecha DESC
You can find it here => http://sqlfiddle.com/#!9/b44fe/2
Related
I am using MySQL 5.6.
I have a SQL table with a list of users:
id name
1 Alice
2 Bob
3 John
and a SQL table with the list of gifts for each user (numbered in order of preference):
id gift rank
1 balloon 2
1 shoes 1
1 seeds 3
1 video-game 1
2 computer 2
3 shoes 2
3 hat 1
And I would like a list of the preferred gift for each user (the highest rank - if two gifts have the same rank, pick only one randomly) (bonus: if the list could be randomized, that would be perfect!):
id name gift rank
2 Bob computer 2
1 Alice shoes 1
3 John hat 1
I tried to use the clause GROUP BY but without any success.
Considering rank as a part of your data; Without using window functions or complex sub queries
SELECT u.id, u.name, g.gift
FROM users u
JOIN gifts g ON g.id = u.id
LEFT JOIN gifts g2 ON g2.id = g.id AND g2.rank > g.rank
WHERE g2.id IS NULL;
Added link http://sqlfiddle.com/#!9/62f59e/15/0
You can use row_number to get one row for each User.(Mysql 8.0+)
SELECT A.ID,NAME,GIFT,`RANK` FROM USERS A
LEFT JOIN (
SELECT ID,GIFT,`RANK` FROM
(SELECT *,ROW_NUMBER() OVER(PARTITION BY ID ORDER BY `RANK` ASC) AS RN FROM X) X
WHERE RN =1
) B
ON A.ID= B.ID
I do not know DB what you use. And I'm not an expert in SQL(I can have some mistake in next). But I think it is not difficult.
So I can give you just advice that you have to think gradually. Let me write.
First All I need is the highest rank. So I have to get this.
SELECT MAX(RANK)
FROM GIFT
GROUP BY ID
And then I think that I need get gifts from this rank.
SELECT GIFT.*
FROM GIFT
INNER JOIN(
SELECT ID, MAX(RANK)
FROM GIFT
GROUP BY ID
) filter ON GIFT.ID = filter.ID AND GIFT.RANK = filter.RANK
I think this is the table what you want!
So If below code works, That's what you really want.
SELECT *
FROM USER
LEFT OUTER JOIN(
above table
) GIFT ON USER.ID = GIFT.ID
But Remember this, I said I'm not an expert in SQL. There can be better way.
Checkout the query
SELECT tbluser.id,name,gift,rank into tblrslt
FROM tbluser
LEFT JOIN tblgifts
ON tbluser.id = tblgifts.id order by id,rank;
SELECT tt.*
FROM tblrslt tt
INNER JOIN
(SELECT id, min(rank) AS rank
FROM tblrslt
GROUP BY id) groupedtt
ON tt.id = groupedtt.id
AND tt.rank = groupedtt.rank order by id
In MySQL versions older than 8 you have no ranking functions available. You'll select the minimum rank per user instead and use these ranks to select the gift rows. This means you access the gifts table twice.
I suggest this:
select *
fron users u
join gifts g
on g.id = u.id
and (g.id, g.rank) in (select id, min(rank) from gifts group by id)
order by u.id;
If you also want to show users without gifts, simply change the inner join to a left outer join.
Working example: http://sqlfiddle.com/#!9/80995/20
I have three tables, a user table, a user_group table, and a link table.
The link table contains the dates that users were added to user groups. I need a query that returns the count of users currently in each group. The most recent date determines the group that the user is currently in.
SELECT
user_groups.name,
COUNT(l.name) AS ct,
GROUP_CONCAT(l.`name` separator ", ") AS members
FROM user_groups
LEFT JOIN
(SELECT MAX(added), group_id, name FROM link LEFT JOIN users ON users.id = link.user_id GROUP BY user_id) l
ON l.group_id = user_groups.id
GROUP BY user_groups.id
My question is if the query I have written could be optimized, or written better.
Thanks!
Ben
You actual query is not giving you the answer you want; at least, as far as I understand your question. John actually joined group 2 on 2017-01-05, yet it appears on group 1 (that he joined on 2017-01-01) on your results. Note also you're missing one Group 4.
Using standard SQL, I think the next query is what you're looking for. The comments in the query should clarify what each part is doing:
SELECT
user_groups.name AS group_name,
COUNT(u.name) AS member_count,
group_concat(u.name separator ', ') AS members
FROM
user_groups
LEFT JOIN
(
SELECT * FROM
(-- For each user, find most recent date s/he got into a group
SELECT
user_id AS the_user_id, MAX(added) AS last_added
FROM
link
GROUP BY
the_user_id
) AS u_a
-- Join back to the link table, so that the `group_id` can be retrieved
JOIN link l2 ON l2.user_id = u_a.the_user_id AND l2.added = u_a.last_added
) AS most_recent_group ON most_recent_group.group_id = user_groups.id
-- And get the users...
LEFT JOIN users u ON u.id = most_recent_group.the_user_id
GROUP BY
user_groups.id, user_groups.name
ORDER BY
user_groups.name ;
This can be written in a more compact way in MySQL (abusing the fact that, in older versions of MySQL, it doesn't follow the SQL standard for the GROUP BY restrictions).
That's what you'll get:
group_name | member_count | members
:--------- | -----------: | :-------------
Group 1 | 2 | Mikie, Dominic
Group 2 | 2 | John, Paddy
Group 3 | 0 | null
Group 4 | 1 | Nellie
dbfiddle here
Note that this query can be simplified if you use a database with window functions (such as MariaDB 10.2). Then, you can use:
SELECT
user_groups.name AS group_name,
COUNT(u.name) AS member_count,
group_concat(u.name separator ', ') AS members
FROM
user_groups
LEFT JOIN
(
SELECT
user_id AS the_user_id,
last_value(group_id) OVER (PARTITION BY user_id ORDER BY added) AS group_id
FROM
link
GROUP BY
user_id
) AS most_recent_group ON most_recent_group.group_id = user_groups.id
-- And get the users...
LEFT JOIN users u ON u.id = most_recent_group.the_user_id
GROUP BY
user_groups.id, user_groups.name
ORDER BY
user_groups.name ;
dbfiddle here
I am struggling with the WHERE part of a query. The query itself contains a LEFT JOIN based on an ID that is present in both tables. However I require the where statement to only return the largest single result that is present in one of the columns. Currently I am return all the values in the join, including values that I do not want.
My Current SQL is
SELECT u.uid, t.id
GROUP_CONCAT(u.forename, ' ', u.surname) AS name,
GROUP CONCAT(DISTINCT scores.points) AS point
FROM users AS U
JOIN teamname AS t
LEFT JOIN (
SELECT team_id, id
FROM games AS g
LEFT JOIN (
SELECT points, team_id
FROM scores as s
) AS S ON t.id = S.team_id
WHERE IF (S.points > 3, S.points > 2, S.point =1)
) AS G ON t.id = G.team_id
ORDER BY surname ASC;
The result of such might be something along the lines of
NAME | TEAM | GAMES | POINTS
Joe | 1 | 1,2,3,4 | 1,3,3,2,3
In this instance the first game was a draw and was replied resulting in a higher points score, I am only wanting the higher points score based on that game.
Any help would be appreciated.
Updated with Tables
users
uid
forename
surname
Team
id
teamname
uid
games
id
team_id
points
Still not quite sure if I understood your tables correctly. It seems a users has one or more teams, each team has one or more games with one or more results per game. You want to show for each user and each team the games concatenated in one column and the highest points for each game concatenated in a second column.
If my assumptions are correct the following query should do the trick. Basically, you first group the data by user/team/game and select the max points per game, then you group the results by user/team and concatenate the games and points.
Please let me know if I misunderstood any of your requirements.
Example in an SQL Fiddle
SELECT
t.uid,
t.forename,
t.team_id,
GROUP_CONCAT(t.game_id) as games,
GROUP_CONCAT(t.max_points) as max_points
FROM (
SELECT
users.uid,
users.forename,
teams.id AS team_id,
games.id AS game_id,
max(games.points) as max_points
FROM
users
LEFT JOIN teams ON users.uid = teams.uid
LEFT JOIN games ON teams.id = games.team_id
GROUP BY
users.uid,
users.forename,
teams.id,
games.id
) t
GROUP BY
t.uid,
t.forename,
t.team_id
I have a table called reviews. I get the most current user reviews like this:
SELECT b.item, b.item_id, a.review_id, a.review, c.category, u.username, c.cat_id
FROM reviews a
INNER JOIN items b
ON a.item_id = b.item_id
INNER JOIN master_cat c
ON c.cat_id = b.cat_id
INNER JOIN users AS u
ON u.user_id = a.user_id
ORDER BY a.review_id DESC;
What I want to do is slightly alter it to be more personable for users.
I have another table of user "connections". Kind of like Twitter. When a user follows someone, it gets logged in this table called profile_follow. This has three columns. id, user_id, follow_id. Simply: If I am user #1, and I "follow" user # 3 and user #5, two rows will be added in this table:
profile_follow
------------------------
id | user_id | follow_id
| 1 | 3
| 1 | 5
Here is how I want to change the query above. I want to only show newest reviews, from people you follow.
So I will need at least one more join, for table profile_follow. And I need to pass in a user_id (it's a php function), doing something like `WHERE profile_follow.user_id = '{$user_id}'. I think I will have to add a sub query on this, not use.
Can someone show me how to finish this query? I am not sure how to handle it from here? All of my attempts have been off so far.
I think I need to do something like:
Selectfollow_idwhereuser_id= (logged in user)
And then in the main query:
Select reviews only with profile_follow.follow_id = review.user_id.
I can't figure out how to make this filter work.
Always difficult without testing, but:
SELECT b.item, b.item_id, a.review_id, a.review, c.category, u.username, c.cat_id
FROM reviews a
INNER JOIN items b
ON a.item_id = b.item_id
INNER JOIN master_cat c
ON c.cat_id = b.cat_id
INNER JOIN profile_follow pf
ON pf.follow_id = a.user_id
WHERE profile_follow.user_id = '{$user_id}'
ORDER BY a.review_id DESC;
I have a table - comments. Users can post if not a member of the site but want to show their details if they are.
So if a user comments who is NOT a member I show their posts but don't link to their profile, because they don't have one.
So, in the following query I want to return the rows even if there is no join:
select wc.comment, wc.comment_by_name, wc.user_id, u.url from comments wc
join users u on wc.wag_uid = u.user_id
where id = '1237' group by wc.comment order by wc.dateadded desc
I want to return:
comment comment_by_name user_id url
------- --------------- ------- ----
hello dan 12 /dan
hey jane /jane
world jack 10 /jack
But the above does not return the data for jane as she does not have a user_id
Is there a way to return all data even if the join is null?
use LEFT JOIN instead
SELECT wc.comment, wc.comment_by_name, wc.user_id, u.url
FROM comments wc
LEFT JOIN users u
on wc.wag_uid = u.user_id
WHERE id = '1237'
GROUP BY wc.comment
ORDER BY wc.dateadded DESC
basically INNER JOIN only select records which a record from one table has atleast one match on the other table while LEFT JOIN select all rows from the left hand side table (in your case, it's comments) whether it has no match on the other table.