Query to join 3 tables - mysql

I need to write a query to join 3 tables.
My tables are:
ucommerce_customer
ucommerce_order
ucommerce_order_line
All 3 tables have a column called order_id.
The table ucommerce_order has a column called order_status.
When the order_status is set to "open" I want to display the order details.
ResultSet myRs = myStmt.executeQuery
("SELECT * FROM ucommerce_customer
INNER JOIN ucommerce_order
INNER JOIN ucommerce_order_line
WHERE ucommerce_order.order_status = 'open'");
My query ignores the order status and displays all orders, open and closed.
Also I have several products so ucommerce_order_line has several entries for the same order_id, my query displays duplicate entries and it duplicates the entire list as well.
How can I write a query that will show only open orders without duplicating everything?

In MySQL, the on/using clause is optional. This is very sad because someone can make mistakes like you did. Your question only mentions one column, so perhaps that is all that is needed for the join:
SELECT *
FROM ucommerce_customer INNER JOIN
ucommerce_order
USING (orderId) INNER JOIN
ucommerce_order_line
USING (OrderId)
WHERE ucommerce_order.order_status = 'open';
I would be surprised if the customer table really had a column called OrderId (seems like a bad idea in most situations), so the first USING clause might want to use CustomerId.

I would recommend to use a natural join instead. Maybe that's where the errors are coming from.
The duplicates can be removed by running SELECT DISTINCT * ...

Related

comparing two table columns in mysql results in duplicate

I have two tables, I've been trying to print the result from each but they are being duplicated. These are the two MySQL tables and the result. Notice the duplication.
The sql code for the project is:
SELECT * FROM savings,savtype WHERE cust_id=".$_SESSION['user']
I'm also looking for a work around this, in the meantime, id appreciate any assistance on this.
because you are not specifying how the two tables are related. You need to add that, either via an explicit ... JOIN ... (USING|ON)
SELECT
*
FROM
savings JOIN savtype USING (savtype_id)
WHERE
cust_id = ".$_SESSION['user']
or by providing the criteria in the where clause.
SELECT
*
FROM
savings, savtype
WHERE
savings.savtype_id = savtype.savtype_id AND
cust_id = ".$_SESSION['user']
As I understand from the screenshot you added, it makes joint between those tables, and what you probably want it left join from savings and savtype tables.
SELECT *
FROM `savings`
LEFT JOIN `savtype`
ON savings.savtype_id=savtype.savtype_id
where cust_id=".$_SESSION['user'] .";
Update if this did the trick,
You can learn more about left join here: https://www.w3schools.com/sql/sql_join_left.asp

SQL query for selecting all but needing aliases

I'm trying to perform a join operation on two tables linked by item IDs. However, the problem with them is that they've got columns with the same name as follows:
items
(ID, **Quantity**, etc. /*[nothing in etc. is shared by status' columns]*/)
status
(ID, **Quantity**, etc. /*[nothing in etc. is shared by items' columns]*/)
I want to get all records from these tables and join them, but I don't know what the SQL query would look like. I know it'd be something like:
SELECT *
FROM items
LEFT OUTER JOIN status
ON items.ID = status.ID
and I know I need aliases for the two quantity columns (which I know how to do), but where does the latter part of the query fit in?
In general, I recommend avoiding SELECT * queries. Just select the specific columns you need, and if there are duplicate column names you can easily assign aliases for them.
SELECT i.col1, i.col2, i.quantity AS item_quantity, s.col3, s.col4, s.quantity AS status_quantity
FROM items AS i
JOIN status AS s ON i.ID = s.ID
But if you really need to select all columns, you can use the solution in Marc B's answer.

How to deal with bad data in mysql?

I have three tables that I want to combine.
I have the following query to run:
DROP TABLE
IF EXISTS testgiver.smart_curmonth_downs;
CREATE TABLE testgiver.smart_curmonth_downs
SELECT
ldap_karen.uid,
ldap_karen.supemail,
ldap_karen.regionname,
smart_curmonth_downs_raw.username,
smart_curmonth_downs_raw.email,
smart_curmonth_downs_raw.publisher,
smart_curmonth_downs_raw.itemtitle,
smart_items.`Owner`
FROM
smart_curmonth_downs_raw
INNER JOIN ldap_karen ON smart_curmonth_downs_raw.username = ldap_karen.uid
INNER JOIN smart_items ON smart_curmonth_downs_raw.itemtitle = smart_items.Title
I want to know how to create the joins while maintaining a one to one relationship at all times with rows in table smart_curmonth_downs_raw.
For instance if there is not a uid in ldap_karen I have issues. And then the last issue I have found is that our CMS is allowing for duplicate itemtitle. So if I run my query I am getting a lot more rows because it is creating a row for each itemtitle. For example would there be a way to only catch the last itemtitle that is in smart_items. I would just really like to maintain the same number of rows - and I have no control over the integrity issues of the other tables.
The smart_curmonth_downs_raw table is the raw download information (download stats), the karen table adds unique user information, and the smart_items table adds unique items (download) info. They are all important. If a user made a download but is knocked off the karen table I would like to see NULLs for the user info and if there is more than one item in smart_items that has the same name then I would like to see just the item with the highest ID.
It sounds like relationship between smart_curmonth_downs_raw and ldap_karen is optional, which means you want to use a LEFT JOIN which all the rows in the first table, and, if the right table does not exists, use NULL as the right table's column values.
In terms of the last item in the smart_items table, you could use this query.
SELECT title, MAX(id) AS max_id
FROM smart_items
GROUP BY title;
Combining that query with the other logic, try this query as a solution.
SELECT COALESCE(ldap_karen.uid, 'Unknown') AS uid,
COALESCE(ldap_karen.supemail, 'Unknown') AS supemail,
COALESCE(ldap_karen.regionname, 'Unknown') AS regionname,
smart_curmonth_downs_raw.username,
smart_curmonth_downs_raw.email,
smart_curmonth_downs_raw.publisher,
smart_curmonth_downs_raw.itemtitle,
smart_items.`Owner`
FROM smart_curmonth_downs_raw
INNER JOIN (SELECT title, MAX(id) AS max_id
FROM smart_items
GROUP BY title) AS most_recent
ON smart_curmonth_downs_raw.itemtitle = most_recent.Title;
INNER JOIN smart_items
ON most_recent.max_id = smart_items.id
LEFT JOIN ldap_karen
ON smart_curmonth_downs_raw.username = ldap_karen.uid;

mysql: join on with or condition displaying result twice

why this query displaying same result twice.
"SELECT * from sony.bsha
inner join sony.frndreq
on sony.frndreq.from='"+email+"' or sony.frndreq.to='"+email+"'";
And please tell to me how to stop displaying data twice.
You should join your tables on some common field, and then use WHERE clause:
SELECT *
FROM sony.bsha
INNER JOIN sony.frndreq
ON sony.bsha.someField = sony.frndreq.someField
WHERE sony.frndreq.from='"+email+"' OR sony.frndreq.to='"+email+"' "
If you're still getting double results use DISTINCT or GROUP BY. It's hard to say anything more not being given your database schema etc.
Use GROUP BY
"SELECT *
from sony.bsha
inner join sony.frndreq
on sony.frndreq.from='"+email+"' or sony.frndreq.to='"+email+"'
GROUP BY sony.frndreq.from
";
You should have to specify a condition on a common field between two tables. Then only you will get unique records.
"SELECT * FROM sony.bsha
INNER JOIN sony.frndreq ON sony.bsha.id = sony.frndreq.bid
WHERE sony.frndreq.from='"+email+"' OR sony.frndreq.to='"+email+"'";
In above SQL I assumed fields for
sony.bsha.id = sony.frndreq.bid
condition where sony.bsha.id is Primary Key in Left Table and sony.frndreq.bid is Foriegn Key in Right Table.
Be aware that even though you are using an inner join that it will still return more than one of the "same" record if redundant data exists. Perhaps if you check "email" you may find more than one occurrence of a value in which you are getting duplicates for. Run a query using a value from the duplicate records you are getting and see what you get.
In the case there are duplicate values for email (and that is not in error), do as the other user has said and use DISTINCT or GROUP BY. Remember though for those to work that all the fields you specify in the select must be the same, not just email.

simple joins between 2 mysql tables returning all results every time.. Help!

I just imported a large amount of data into two tables. Let's call them shipments and returns.
When trying to do a simple join (left or inner) based on any criteria in these two tables. query looks like it tries to do a cross join or find every combination instead of what the query should be pulling.
each table has an PK id field, but there is not FK relationship between the two other than some shared field.
I'm currently just trying to related them on shipment_id.
I feel this is a simple answer. Am I missing a reference or something obvious that is causing this? Thanks!
here's an example. This should returned under 100 rows. This instead returns hundreds of thousands.
SELECT r.*
FROM returns as r
left outer join shipments as s
on r.shipment_id = s.shipment_id
where r.date = '2011-06-20'
Here is a query that should work:
SELECT T0.*, T1.*
FROM shipments AS T0 LEFT JOIN returns AS T1 ON T0.shipment_id = T1.shipment_id
ORDER BY T0.shipment_id;
This query join assumes 1:1 on the shipment_id
It would be nice if you included the query you were using
You need to specify what you are joining on, otherwise it will do a cartesian join:
SELECT r.*
FROM returns as r
LEFT JOIN shipments as s ON s.shipment_id = r.shipment_id
where r.date = '2011-06-20'
Josh,
I would be interested in seeing what would happen if you forced a join to a specific record or set of records instead of the whole table. Assuming there is a shipment with an id of 5 in your table, you could try:
SELECT r.* FROM returns as r
left join shipments as s
ON 5 = r.shipment_id
WHERE r.date = '2011-06-20'
While just a fancy where clause, it would at least prove that the join you are attempting will eventually work correctly. The issue is that your on clause is always returning true, no matter what the value is. This could be because it's not interpreting the shipment_id as an integer, but instead as a true/false variable where any value evaluates to true.
Original Rejected Solution:
No Foreign Key relationship should be needed in order to make the joins happen. The PK id fields I'm assuming are an integer (or number, or whatever your rdms equivalent is)?
Can you past a snippet of your sql query?
Updating based on posted query:
I would add your explicit join criteria in order to rule out any funny business (my guess is since no criteria is specified, it's using 1=1, which always joins). So I would change your query to look like:
SELECT r.*
FROM returns as r
left join shipments as s ON
s.ShipId = R.ReturnId
where r.date = '2011-06-20'
The issue turned out to be very simple, just not readily apparent until going through all the columns. It turns out that the shipment ID was duplicated through every row as it hit the upper limit for the int datatype. This is why joins were returning every record.
After switching the datatype to bigint and reimporting, everything worked great. Thanks all for looking into it.