Table 1 : Anamoly
id Source
1 dls
2 aus
3 dls
4 aus
Table 2 : Logical_Mapping
Source Destination minValue
dls hst 1
aus hst 2
dls buf 1
aus buf 2
Expected Output
Anomaly-Mapping
id Source Destination minValue
1 dls hst(or)buf 1
2 aus hst(or)buf 2
3 dls hst(or)buf 1
4 aus hst(or)buf 2
The 'minValue' is dependent on the source and not the 'destination'.
The query I tried was :
select an.id,an.Source, (select l.Destination from logical_mapping as l where an.Source= l.Source limit 1) as Dest from anomaly;
The query seems to work fine. But I need 'minValue' also along with 'Destination'.
Try this:
SELECT an.id, an.source, l.destination, l.minValue
FROM anamoly an
LEFT JOIN logical_mapping l ON l.source=an.source
Related
i have a table for my sql like this :
result_podium
id_result_podium
id_race
id_rider
position
point
and
result_dnf
id_result_dnf
id_race
id_rider
So what im trying to do is to join those two table and shown it as one, and here is the result and what i have tried so far :
Attempt 1 :
$this->db->select_sum('result_podium.point');
$this->db->select('riders.name AS rider_name, teams.name AS team_name');
$this->db->from('result_podium');
$this->db->join('riders','riders.id_rider = result_podium.id_rider');
$this->db->join('result_dnf','result_dnf.id_rider = riders.id_rider', 'left');
$this->db->join('teams','teams.id_team = riders.id_team');
$this->db->where('riders.is_deleted','0');
$this->db->order_by("SUM(result_podium.point) DESC");
$this->db->group_by(array('result_podium.id_rider','result_dnf.id_rider'));
$query = $this->db->get();
return $query->result();
And the result is something like this :
No
rider
point
1
Nick
10
2
A
5
3
D
5
4
CC
4
5
B
4
it managed to get data from table result_podium but not managed to join data from table result_dnf, and here is my another attempt :
Attempt 2 :
$this->db->select_sum('result_podium.point');
$this->db->select('result_dnf.*, riders.name AS rider_name, teams.name AS team_name');
$this->db->from('result_dnf');
$this->db->join('riders','riders.id_rider = result_dnf.id_rider');
$this->db->join('teams','teams.id_team = riders.id_team');
$this->db->join('result_podium','result_podium.id_rider = riders.id_rider', 'left');
$this->db->where('riders.is_deleted','0');
$this->db->order_by("SUM(result_podium.point) DESC");
$this->db->group_by(array('result_dnf.id_rider','result_podium.id_rider'));
and here is the result :
No
rider
point
1
A
5
2
D
5
3
B
4
4
CC
4
5
Bri
6
Brum
the point data forBri and Brum, is null because they came from result_dnf, but i did not managed to get Nick data from result_podium.
And here what i was expecting for the data to shown in my view :
No
rider
point
1
Nick
10
2
A
5
3
D
5
4
CC
4
5
B
4
5
Bri
6
Brum
is there a way to join those two table?, anyhelp is really appreciated thank you!.
I have 2 tables
First tabel name is "consumer"
id_consumer
name
1
Roy
2
Dori
3
Rico
Second tabel name is "consumer_address"
id_consumer
address
status
1
Street Avenue
1
1
Park Hill
0
2
Highwalk Street
1
2
Albion Place
0
Condition
name from tabel "consumer"
address from "consumer_address" , but i want to get only 1 address when consumer_address.status = 1
When Consumer not have data in tabel "consumer_address", field is NULL
The Final Tabel Like this
id_consumer
name
address
status
1
Roy
Street Avenue
1
2
Dori
Highwalk Street
1
3
Rico
NULL
NULL
i have query, but its not work
this is my query
SELECT
id_consumer,
name,
CASE WHEN (`consumer_address`.`status` = 1) THEN `consumer_address`.`address` ELSE NULL END as "Address",
CASE WHEN (`consumer_address`.`status` = 1) THEN `consumer_address`.`status` ELSE NULL END as "Status"
FROM consumer
JOIN consumer_address ON consumer_address.id_consumer = consumer.id_consumer
Thanks
Very simple solution:
SELECT
`id_consumer`,
`name`,
`consumer_address`.`address`,
`consumer_address`.`status`
FROM consumer
LEFT JOIN consumer_address ON
`consumer_address`.`id_consumer` = `consumer`.`id_consumer` AND
`consumer_address`.`status` = 1
Instead of using CASE WHEN just include the status in the JOIN.
Additionally, to keep consumer 3, you need a LEFT JOIN.
SELECT
id_consumer,
name,
`consumer_address`.`address`,
`consumer_address`.`status`
FROM
consumer
LEFT JOIN
consumer_address
ON consumer_address.id_consumer = consumer.id_consumer
AND consumer_address.status = 1
Let's say I have the following table in my MySQL database:
id item value
1 Plump A
2 Apple B
3 Banana F
4 Peach K
5 Orange B
6 Cherry U
And I have this table on my computer:
id value
1 B
2 F
3 L
4 A
5 B
6 A
I want to import the table from computer and replace the values from value with the values from value where id = id without changing the values in item.
Means, I need this on my MySQL database at the end:
id item value
1 Plump B
2 Apple F
3 Banana L
4 Peach A
5 Orange B
6 Cherry A
How can I do that?
I ended up with doing the following in Apple Numbers:
Then copy and paste in something like Coda. Search replace tab characters.
Result is:
UPDATE my_table SET value = "B" WHERE id = 1;
UPDATE my_table SET value = "F" WHERE id = 2;
UPDATE my_table SET value = "L" WHERE id = 3;
UPDATE my_table SET value = "A" WHERE id = 4;
UPDATE my_table SET value = "B" WHERE id = 5;
UPDATE my_table SET value = "A" WHERE id = 6;
Now I just have to execute these SQL codes in my database. Done!
i got some problem obtaining value from my db,this is my first db
ID_HARGA ID_USER ID_BAG_PEMASARAN ID_ITEM HARGA ENTRY_DATE
1 9 1 3 1000000 2015-01-11 09:55:27
2 9 1 5 2000000 2015-01-13 07:19:10
5 9 1 3 3000000 2015-01-13 13:47:32
6 9 1 43 7000000 2015-01-13 13:49:49
13 9 1 50 3000000 2015-01-13 17:56:54
37 9 1 50 100 2015-01-19 09:08:20
this is the second one
ID_ITEM NAMA_ITEM SPEC_ITEM MASA_GARANSI STATUS_ITEM DIR_IMAGE
3 water heater emas bagus sekali selamanya 1
5 water heater tembaga bagus super selamanya 1
43 water hater heater seupo 3 1 water_22.jpg
50 tankkk 50 Liter 1 1 water_2.jpg
i know there is some null value just igniore it, i already did this
public function get_item()
{
//menghitung jumlah varian barang yang ada
$querycounter = $this->db->query('select * from ITEM WHERE STATUS_ITEM = 1');
$counter = $querycounter->num_rows();
$this->db->select('ITEM.ID_ITEM,NAMA_ITEM,SPEC_ITEM,HARGA,DIR_IMAGE');
$this->db->from('ITEM');
$this->db->join('HARGA', 'ITEM.ID_ITEM = HARGA.ID_ITEM','left');
// $this->db->order_by('ENTRY_DATE','DESC');
//$this->db->limit($counter);
$this->db->where('STATUS_ITEM',1);
//$query = $this->db->query('select from ITEM i join HARGA h on i.ID_ITEM = h.ID_ITEM order by h.ENTRY_DATE ASC');
$query = $this->db->get();
return $query->result_array();
//$this->db->select('nama_item','spec_item');
//$query = $this->db->get('item');
}
what i want is,just ignore dir_image
ID_ITEM NAMA_ITEM HARGA DIR_IMAGE
3 water heater emas 1000000
5 water heater tembaga 3000000
43 water hater 7000000
50 tankk 100
ID_item with biggest number not the old , so everytime i am insert into id_harga with ID_ITEM
the result always the newest HARGA
Thx before
There is a little confession that, do you want to get the maximum hagra, or newest inserted data (identifiable by HAGRA_ID if its auto increment by 1) in Hagra table. Your Code should be like
$this->db->select('ITEM.ID_ITEM,NAMA_ITEM,SPEC_ITEM,max(HARGA),DIR_IMAGE');
$this->db->from('ITEM');
$this->db->join('HARGA', 'ITEM.ID_ITEM = HARGA.ID_ITEM','left');
$this->db->where('STATUS_ITEM',1);
$this->db->group_by('item.item_id');
This will join your tables and select maximum value of Hagra. To use Max function, you need to use group_by(CodeIgniter Documentation) clause, other wise it will show only the single maximum value. Group_by will help to show maximum value of each group (each item);
If you want to get the newest inserted data, you can use the same technique using
$this->db->select('MAX(HAGRA_ID),ITEM.ID_ITEM,NAMA_ITEM,SPEC_ITEM,HARGA,DIR_IMAGE');
This is a followup question for this one: how to select/add a column to pandas dataframe based on a function of other columns?
have a data frame and I want to select the rows that match some criteria. The criteria is a function of values of other columns and some additional values.
Here is a toy example:
>> df = pd.DataFrame({'A': [1,2,3,4,5,6,7,8,9],
'B': [randint(1,9) for x in xrange(9)],
'C': [4,10,3,5,4,5,3,7,1]})
>>
A B C
0 1 6 4
1 2 8 10
2 3 8 3
3 4 4 5
4 5 2 4
5 6 1 5
6 7 1 3
7 8 2 7
8 9 8 1
I want select all rows for which some non trivial function returns true, e.g. f(a,c,L), where L is a list of lists and f returns True iff a and c are not part of the same sublist.
That is, if L = [[1,2,3],[4,2,10],[8,7,5,6,9]] I want to get:
A B C
0 1 6 4
3 4 4 5
4 5 2 4
6 7 1 3
8 9 8 1
Thanks!
Here is a VERY VERY hacky and non-elegant solution. As another disclaimer, since your question doesn't state what you want to do if a number in the column is in none of the sub lists this code doesn't handle that in any real way besides any default functionality within isin().
import pandas as pd
df = pd.DataFrame({'A': [1,2,3,4,5,6,7,8,9],
'B': [6,8,8,4,2,1,1,2,8],
'C': [4,10,3,5,4,5,3,7,1]})
L = [[1,2,3],[4,2,10],[8,7,5,6,9]]
df['passed1'] = df['A'].isin(L[0])
df['passed2'] = df['C'].isin(L[0])
df['1&2'] = (df['passed1'] ^ df['passed2'])
df['passed4'] = df['A'].isin(L[1])
df['passed5'] = df['C'].isin(L[1])
df['4&5'] = (df['passed4'] ^ df['passed5'])
df['passed7'] = df['A'].isin(L[2])
df['passed8'] = df['C'].isin(L[2])
df['7&8'] = (df['passed7'] ^ df['passed8'])
df['PASSED'] = df['1&2'] & df['4&5'] ^ df['7&8']
del df['passed1'], df['passed2'], df['1&2'], df['passed4'], df['passed5'], df['4&5'], df['passed7'], df['passed8'], df['7&8']
df = df[df['PASSED'] == True]
del df['PASSED']
With an output that looks like:
A B C
0 1 6 4
3 4 4 5
4 5 2 4
6 7 1 3
8 9 8 1
I implemented this rather quickly hence the utter and complete ugliness of this code, but I believe you can refactor it any way you would like (e.g. iterate over the original set of lists with for sub_list in L, improve variable names, come up with a better solution, etc).
Hope this helps. Oh, and did I mention this was hacky and not very good code? Because it is.