Get Gulp pipes of dependencies - gulp

Question

I have a gulpfile with some tasks. All task are combined in a default task, that has dependencies to all others tasks. I want to add a deploy task. The deploy can take a list of files. I want only deploy changed files.
Is there a way to get the pipes of all dependencies? Or any other way, without merge everything into one task?
Here a simple sample to explain:
var gulp = require('gulp');
var concat = require('gulp-concat');
var debug = require('gulp-debug');
var newer = require('gulp-newer');
gulp.task('default', ['js', 'css']);
gulp.task('js', function () {
return gulp.src('./app/**/*.js')
.pipe(newer('./dist/app.js'))
.pipe(concat('app.js'))
.pipe(gulp.dest('./dist/'));
});
gulp.task('css', function () {
gulp.src('./app/**/*.css')
.pipe(newer('./dist/style.css'))
.pipe(concat('style.css'))
.pipe(gulp.dest('./dist/'));
});
gulp.task('deploy', ['default'], function () {
gulp.src('./dist/*')
// Here I want only files changed in dist
.pipe(debug());
});
Update:
Here some more of my task:
gulp.task('default', ['js', 'css', 'images', 'templates']);
gulp.task('images', function () {
return gulp.src('./app/images/*')
.pipe(newer('./dist/app/images'))
.pipe(gulp.dest('./dist/app/images'));
gulp.task('templates', function () {
return gulp.src('./app/**/*.html')
.pipe(newer('./dist/app/templates.js'))
.pipe(minifyHTML({ empty: true }))
.pipe(templateCache({ module: 'app' }))
.pipe(uglify())
.pipe(gulp.dest('./dist/app'));

Answer 1

I added a deployed folder, where i keep track of all files that a deployed.
var gulp = require('gulp');
var concat = require('gulp-concat');
var debug = require('gulp-debug');
var newer = require('gulp-newer');
gulp.task('default', ['js', 'css']);
gulp.task('js', function () {
return gulp.src('./app/**/*.js')
.pipe(newer('./dist/app.js'))
.pipe(concat('app.js'))
.pipe(gulp.dest('./dist/'));
});
gulp.task('css', function () {
gulp.src('./app/**/*.css')
.pipe(newer('./dist/style.css'))
.pipe(concat('style.css'))
.pipe(gulp.dest('./dist/'));
});
gulp.task('deploy', ['default'], function () {
gulp.src('./dist/*')
.pipe(newer('./deployed'))
.pipe(debug())
.pipe(gulp.dest('./deployed'))
});