Hi All I have a result from mysql that looks like this:
+---------------------+------+
| timestamp | data |
+---------------------+------+
| 2015-06-01 04:25:18 | 10 |
| 2015-06-15 04:25:18 | 20 |
| 2015-06-30 04:25:18 | 30 |
| 2015-07-01 04:25:18 | 50 |
| 2015-07-15 04:25:18 | 60 |
| 2015-07-30 04:25:18 | 70 |
| 2015-08-01 04:25:18 | 80 |
| 2015-08-15 04:25:18 | 90 |
| 2015-08-30 04:25:18 | 100 |
+---------------------+------+
I can use a query to work out the delta so it is like this:
+---------------------+------+------+
| timestamp | data | delta |
+---------------------+------+------+
| 2015-06-01 04:25:18 | 10 | 0 |
| 2015-06-15 04:25:18 | 20 | 10 |
| 2015-06-30 04:25:18 | 30 | 10 |
| 2015-07-01 04:25:18 | 50 | 20 |
| 2015-07-15 04:25:18 | 60 | 10 |
| 2015-07-30 04:25:18 | 70 | 10 |
| 2015-08-01 04:25:18 | 80 | 10 |
| 2015-08-15 04:25:18 | 90 | 10 |
| 2015-08-30 04:25:18 | 100 | 10 |
+---------------------+------+------+
And what I am after is a grouping of the delta column by month:
+-------+-------------+
| month | consumption |
+-------+-------------+
| 6/15 | 20 |
| 7/15 | 40 |
| 8/15 | 30 |
+-------+-------------+
I thought I had to try GROUP BY MONTH(timestamp) but it does not aggregate the deltas.
Any thoughts?
EDIT
to clarify the delta is a calculated column here is a modified query to show you what i mean:
SELECT
node_time,
node_read - #prev AS delta,
#prev := waveflow_data.node_read
FROM
meter_data
INNER JOIN waveflow_data ON meter_data.node_address = waveflow_data.node_address
CROSS JOIN (SELECT #prev := (SELECT node_read FROM waveflow_data ORDER BY `node_time` DESC LIMIT 1)) variable_initialization_query_alias
WHERE
meter_data.node_address = '10164E998976'
ORDER BY waveflow_data.`node_time` DESC
You just need to sum(delta) like below:
select time_stamp,sum(delta) as Consumption from test
group by month(time_stamp);
Check SQL FIDDLE DEMO
If you want the final result from the initial given set of data then you can do as
select
date_format(timestamp,'%m/%y') as month,
sum(delta) as delta
from
(
select
timestamp,
data,
#diff:= if(#prev=0,0,(data - #prev)) as delta,
#prev:= data
from table_name,(select #prev:=0)x
order by timestamp
)x
group by month;
DEMO
Say if you have a query like, Select timestamp,data,delta from mytable groupby timestamp
update it to Select DATE_FORMAT(timestamp,'%m/%y') as timestamp,data,delta from mytable groupby timestamp
The timestamp would now be in your desired format and grouping would automatically be done based on that.
Related
I have a table in an old version of MySQL 5.x like this:
+---------+------------+------------+
| Task_ID | Start_Date | End_Date |
+---------+------------+------------+
| 1 | 2015-10-15 | 2015-10-16 |
| 2 | 2015-10-17 | 2015-10-18 |
| 3 | 2015-10-19 | 2015-10-20 |
| 4 | 2015-10-21 | 2015-10-22 |
| 5 | 2015-11-01 | 2015-11-02 |
| 6 | 2015-11-17 | 2015-11-18 |
| 7 | 2015-10-11 | 2015-10-12 |
| 8 | 2015-10-12 | 2015-10-13 |
| 9 | 2015-11-11 | 2015-11-12 |
| 10 | 2015-11-12 | 2015-11-13 |
| 11 | 2015-10-01 | 2015-10-02 |
| 12 | 2015-10-02 | 2015-10-03 |
| 13 | 2015-10-03 | 2015-10-04 |
| 14 | 2015-10-04 | 2015-10-05 |
| 15 | 2015-11-04 | 2015-11-05 |
| 16 | 2015-11-05 | 2015-11-06 |
| 17 | 2015-11-06 | 2015-11-07 |
| 18 | 2015-11-07 | 2015-11-08 |
| 19 | 2015-10-25 | 2015-10-26 |
| 20 | 2015-10-26 | 2015-10-27 |
| 21 | 2015-10-27 | 2015-10-28 |
| 22 | 2015-10-28 | 2015-10-29 |
| 23 | 2015-10-29 | 2015-10-30 |
| 24 | 2015-10-30 | 2015-10-31 |
+---------+------------+------------+
If the End_Date of the tasks are consecutive,
then they are part of the same project.
I am interested in finding the total number of different projects completed.
If there is more than one project that have the same number of completion days,
then order by the Start_Date of the project.
For this few sample records the expected output would be:
2015-10-15 2015-10-16
2015-10-17 2015-10-18
2015-10-19 2015-10-20
2015-10-21 2015-10-22
2015-11-01 2015-11-02
2015-11-17 2015-11-18
2015-10-11 2015-10-13
2015-11-11 2015-11-13
2015-10-01 2015-10-05
2015-11-04 2015-11-08
2015-10-25 2015-10-31
I am a bit jammed with this.
I would really appreciate any help. Thanks.
Following query should work:
select tmp.projectid, date_sub(max(tmp.ed2), interval max(tmp.projectdays) day) start_date,
max(tmp.ed2) end_date,
max(tmp.projectdays) No_Of_ProjectDays
from
(
select t1.task_id tid1, t1.start_date sd1, t1.end_date ed1,
t2.task_id tid2, t2.start_date sd2, t2.end_date ed2,
case when datediff(t2.start_date, ifnull(t1.start_date,'1000-01-01')) != 1
then (#pid := #pid + 1)
else (#pid := #pid)
end as ProjectId,
case when datediff(t2.start_date, ifnull(t1.start_date,'1000-01-01')) != 1
then (#pdays := 1)
else (#pdays := #pdays + 1)
end as ProjectDays
from tasks t1 right join tasks t2
on t2.task_id = t1.task_id + 1
cross join (select #pid :=1, #pdays := 1) vars
) tmp
group by tmp.projectid
order by max(tmp.projectdays), start_date
Please find the Demo here.
EDIT : I have made changes in the query and link according to new data sample. Please have a look.
This answers -- and answers correctly -- the original version of this question.
Hmmmm . . . I think you can use variables. The simplest way is to generate a sequential number and then subtract this value to get a constant for adjacent rows from the date:
select min(start_date), max(end_date)
from (select t.*, (#rn := #rn + 1) as rn
from (select t.* from tasks t order by end_date) t cross join
(select #rn := 0) params
) t
group by (end_date - interval rn day);
Here is a db<>fiddle.
It's a little tricky problem, but the query below works fine.
It builds two tables, one with Start_Date and other with End_Date
that NOT IN End_Date and Start_Date respectively from Projects table,
and query these tables fetching Start_Date WHERE Start_Date < End_Date grouping by Start_Date
using aggregate function MIN with End_Date to get a complete Project.
DATEDIFF(MIN(End_Date), Start_Date) to calculate project_duration and able to order by project_duration.
SELECT Start_Date, MIN(End_Date) AS End_Date, DATEDIFF(MIN(End_Date), Start_Date) AS project_duration
FROM
(SELECT Start_Date FROM Projects WHERE Start_Date NOT IN (SELECT End_Date FROM Projects)) a,
(SELECT End_Date FROM Projects WHERE End_Date NOT IN (SELECT Start_Date FROM Projects)) b
WHERE Start_Date < End_Date
GROUP BY Start_Date
ORDER BY project_duration ASC, Start_Date ASC;
expected output
+------------+------------+---------------+
| Start_Date | End_Date | project_duration |
+------------+------------+---------------+
| 2015-10-15 | 2015-10-16 | 1 |
| 2015-10-17 | 2015-10-18 | 1 |
| 2015-10-19 | 2015-10-20 | 1 |
| 2015-10-21 | 2015-10-22 | 1 |
| 2015-11-01 | 2015-11-02 | 1 |
| 2015-11-17 | 2015-11-18 | 1 |
| 2015-10-11 | 2015-10-13 | 2 |
| 2015-11-11 | 2015-11-13 | 2 |
| 2015-10-01 | 2015-10-05 | 4 |
| 2015-11-04 | 2015-11-08 | 4 |
| 2015-10-25 | 2015-10-31 | 6 |
+------------+------------+---------------+
I am trying to show invoices for every single day, so for that purpose I used group by on created date and sum on subtotal. This is how I done it :
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
Its working, but I also want to get the Invoice # from and Invoice # to for every date. Is it possible to do it with single query ?
EDIT :
Table Structure :
------------------------------------------------
| id | inoice_no | created_at | subtotal
| 1 | 34 | 2015-03-17 05:55:27 | 5
| 2 | 35 | 2015-03-17 12:35:00 | 7
| 3 | 36 | 2015-03-20 01:40:00 | 3
| 4 | 37 | 2015-03-20 07:05:13 | 6
| 5 | 38 | 2015-03-20 10:25:23 | 1
| 6 | 39 | 2015-03-24 12:00:00 | 6
------------------------------------------------
Output
---------------------------------------------------------------
| id | inoice_no | created_at | subtotal | total_sales
| 2 | 35 | 2015-03-17 12:35:00 | 7 | 12
| 5 | 38 | 2015-03-20 10:25:23 | 1 | 10
| 6 | 39 | 2015-03-24 12:00:00 | 6 | 6
-----------------------------------------------------------------
What I Expect
---------------------------------------------------------------
| id | inoice_no | created_at | subtotal | total_sales | in_from | in_to
| 2 | 35 | 2015-03-17 12:35:00 | 7 | 12 | 34 | 35
| 5 | 38 | 2015-03-20 10:25:23 | 1 | 10 | 36 | 38
| 6 | 39 | 2015-03-24 12:00:00 | 6 | 6 | 39 | 39
-----------------------------------------------------------------
If your invoice number is INTEGER then below query will give you the result what you want:
SELECT DATE_FORMAT(A.created_at, "%m-%y") AS InvoiceDate,
MIN(A.invoiveNo) AS FromInvoiceNo,
MAX(A.invoiveNo) AS ToInvoiceNo,
SUM(A.subtotal) AS total_sales
FROM sales_invoice AS A
GROUP BY InvoiceDate;
I guess salesid is primaryid in sales_invoice table.
select * from(
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
order by main_table.salesid limit 1
union all
SELECT
`main_table`.*,
SUM(subtotal) AS `total_sales`
FROM
`sales_invoice` AS `main_table`
GROUP BY
DATE_FORMAT(created_at, "%m-%y")
order by main_table.salesid desc limit 1
)a
I have a table like this:
+--------+---------+----------------------+--------------+----------+
| idadata | value_r | date_r | idparameter | idnode |
+--------+-----------+-----------------------+--------------+--------+
| 54620 | 66.6627 | 2014-10-16 12:01:09 | 46 | 9 |
| 54621 | 19.4953 |2014-10-16 12:01:09 | 40 | 9 |
| 54622 | 19.9384 |2014-10-16 12:01:09 | 47 | 9 |
| 54623 | 163.849 | 2014-10-16 12:01:09 | 43 | 9 |
| 54624 | 67.9257 | 2014-10-16 12:02:09 | 44 | 9 |
| 54625 | 315 | 2014-10-16 12:02:09 | 42 | 9 |
| 54626 | 0.699 | 2014-10-16 12:02:09 | 41 | 9 |
| 54627 | 67.9257 | 2014-10-16 12:03:09 | 46 | 9 |
| 54628 | 19.2308 | 2014-10-16 12:03:09 | 40 | 9 |
| 54629 | 11.207 | 2014-10-16 12:03:09 | 47 | 9 |
| 54630 | 118.743 | 2014-10-16 12:03:09 | 43 | 9 |
| 54631 | 292.5 | 2014-10-16 12:03:09 | 42 | 9 |
+---------+----------+----------------------+---------------+-------+
I need to get the statistical mode or the value_r that repeats the most for a given idparameter and idnode in a given datime interval each hour. I have managed to get the mode when I set the datetime difference for 1 hour manually. However, when I try to group by hour or time difference it doesn't work and I end up with mode of the whole Start-End datetime and not group by hours.
So far this is my code:
select value_r , date_r , max(counter_v) from
(SELECT iddata, value_r,date_r ,count( value_r ) counter_v
FROM wsnca.data dat
where dat.idnode=9 and dat.idparameter=42 and
( dat.date_r between ('2014-10-16 12:00:00') and ('2014-10-16 13:00:00') )
group by value_r
order by counter_v DESC) T;
Result:
+----------+----------------------+---------------+
| value_r | date_r | max(counter_v)|
+-----------+----------------------+--------------+
| 270 | 2014-10-16 12:03:09 | 7 |
+-----------+-----------------------+--------------+
However, the result I'm looking for would be like this:
+----------+----------------------+---------------+
| value_r | date_r | max(counter_v)|
+-----------+----------------------+--------------+
| 270 | 2014-10-16 12:00:00 | 7 |
+-----------+-----------------------+--------------+
| 90 | 2014-10-16 13:00:00 | 4 |
+-----------+-----------------------+--------------+
| 45 | 2014-10-16 14:00:00 | 9 |
+-----------+-----------------------+--------------+
| 180 | 2014-10-16 15:00:00 | 8 |
+-----------+-----------------------+--------------+
As I said before, I don't know how to group that by one hour time interval and reading from the query round at the hour datetime as in the desired table.
I know I could do it in the PHP doing several queries but would prefer to do it in the one query.
You can number the count for each value_r per hour starting with #1 for the highest count, #2 for the 2nd highest and so on and then only keep #1 rows, which will be the modes for each hour.
select date_hour, value_r, cnt from (
select * ,
#rowNum := IF(date_hour = #prevDateHour,#rowNum+1,1) rowNum,
#prevDateHour := date_hour
from (
select value_r, hour(date_r) date_hour, count(*) cnt
from wsnca.data dat
where dat.idnode=9 and dat.idparameter=42
group by value_r, hour(date_r)
) t1 order by date_hour, cnt desc
) t1 where rowNum = 1
change group by value_r into group by value_r, date_r I think that should make it
EDIT Better Response for what you want to achieve
select value_r , DATE_FORMAT(date_r, '%Y-%m-%d %H') as formatted_date, max(counter_v) from
(SELECT iddata, value_r,date_r ,count( value_r ) counter_v
FROM wsnca.data dat
where dat.idnode=9 and dat.idparameter=42 and
( dat.date_r between ('2014-10-16 12:00:00') and ('2014-10-16 13:00:00') )
group by value_r, formatted_date
order by counter_v DESC) T
i have a table that has the following columns : s.no,house_no,energy,time
i want to find the total energy for each house for every one hour.
table :
+-----+----------+---------------------+--------+
| sno | house_no | time | energy |
+-----+----------+---------------------+--------+
| 1 | 1 | 2014-10-20 10:00:00 | 5 |
| 2 | 1 | 2014-10-20 10:30:00 | 10 |
| 3 | 2 | 2014-10-20 10:00:00 | 7 |
| 4 | 1 | 2014-10-20 11:01:00 | 3 |
| 5 | 2 | 2014-10-20 11:00:00 | 20 |
+-----+----------+---------------------+--------+
i am trying for 10-11 am.But this query sums the energy of the rows whose time value is greater than 11 am also.
SELECT house_no, sum( energy ) AS sum, time
FROM main
GROUP BY house_no
HAVING (
TIMESTAMPDIFF(
MINUTE , time, '2014-10-20 11:00:00' ) >0)
the result is :
+----------+------+---------------------+
| house_no | sum | time |
+----------+------+---------------------+
| 1 | 18 | 2014-10-20 10:00:00 |
| 2 | 27 | 2014-10-20 10:00:00 |
+----------+------+---------------------+
but the actual answer should be:
+----------+------+---------------------+
| house_no | sum | time |
+----------+------+---------------------+
| 1 | 15 | 2014-10-20 10:00:00 |
| 2 | 7 | 2014-10-20 10:00:00 |
+----------+------+---------------------+
You have to group the time also based on the hours
SELECT house_no, sum( energy ) AS sum, time
FROM main
GROUP BY house_no,DATE_FORMAT(time,'%d %b %Y %H')
HAVING (
TIMESTAMPDIFF(
MINUTE , time, '2014-10-20 11:00:00' ) >0)
DEMO
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This a simple my table
+-----------+----------------+-----------+
| id | date | meter |
------------+----------------+-----------+
| 1 | 2103-11-01 | 5 |
| 2 | 2103-11-10 | 8 |
| 4 | 2103-11-14 | 10 |
| 6 | 2103-11-20 | 18 |
| 7 | 2103-11-25 | 25 |
| 10 | 2103-11-29 | 30 |
+-----------+----------------+-----------+
how do I get the results to the use of meters between two ranges of the results of recording time,
like bellow
+----------------+----------------+-------+-----+--------+
| date1 | date2 | start | end | amount |
+----------------+----------------+-------+-----+--------+
| 2013-11-01 | 2013-11-10 | 5 | 8 | 3 |
| 2013-11-10 | 2013-11-14 | 8 | 10 | 2 |
| 2013-11-14 | 2013-11-20 | 10 | 18 | 8 |
| 2013-11-20 | 2013-11-25 | 18 | 25 | 7 |
| 2013-11-25 | 2013-11-29 | 25 | 30 | 5 |
+----------------+----------------+-------+-----+--------+
Edit:
I got it:
select meters1.date as date1, min(meters2.date) as date2, meters1.meter as start,
meters2.meter as end, (meters2.meter - meters1.meter) as amount
from meters meters1, meters meters2 where meters1.date < meters2.date
group by date1;
Outputs:
+------------+------------+-------+-----+--------+
| date1 | date2 | start | end | amount |
+------------+------------+-------+-----+--------+
| 2013-11-01 | 2013-11-10 | 5 | 8 | 3 |
| 2013-11-10 | 2013-11-14 | 8 | 10 | 2 |
| 2013-11-14 | 2013-11-20 | 10 | 18 | 8 |
| 2013-11-20 | 2013-11-25 | 18 | 25 | 7 |
| 2013-11-25 | 2013-11-29 | 25 | 30 | 5 |
+------------+------------+-------+-----+--------+
Original Post:
This is most of the way there:
select meters1.date as date1, meters2.date as date2, meters1.meter as start,
meters2.meter as end, (meters2.meter - meters1.meter) as amount
from meters meters1, meters meters2 having date1 < date2 order by date1;
It outputs:
+------------+------------+-------+-----+--------+
| date1 | date2 | start | end | amount |
+------------+------------+-------+-----+--------+
| 2013-11-01 | 2013-11-10 | 5 | 8 | 3 |
| 2013-11-01 | 2013-11-20 | 5 | 18 | 13 |
| 2013-11-01 | 2013-11-29 | 5 | 30 | 25 |
| 2013-11-01 | 2013-11-14 | 5 | 10 | 5 |
| 2013-11-01 | 2013-11-25 | 5 | 25 | 20 |
| 2013-11-10 | 2013-11-20 | 8 | 18 | 10 |
| 2013-11-10 | 2013-11-29 | 8 | 30 | 22 |
| 2013-11-10 | 2013-11-14 | 8 | 10 | 2 |
| 2013-11-10 | 2013-11-25 | 8 | 25 | 17 |
| 2013-11-14 | 2013-11-25 | 10 | 25 | 15 |
| 2013-11-14 | 2013-11-20 | 10 | 18 | 8 |
| 2013-11-14 | 2013-11-29 | 10 | 30 | 20 |
| 2013-11-20 | 2013-11-25 | 18 | 25 | 7 |
| 2013-11-20 | 2013-11-29 | 18 | 30 | 12 |
| 2013-11-25 | 2013-11-29 | 25 | 30 | 5 |
+------------+------------+-------+-----+--------+
If it's SQL server try it this way
WITH cte AS
(
SELECT *, ROW_NUMBER() OVER (ORDER BY date) rnum
FROM table1
)
SELECT c.date date1, p.date date2, c.meter [start], p.meter [end], p.meter - c.meter amount
FROM cte c JOIN cte p
ON c.rnum = p.rnum - 1
Here is SQLFiddle demo
If it's MySQL then you can do
SELECT date1, date2, meter1, meter2, meter2 - meter1 amount
FROM
(
SELECT #d date2, date date1, #m meter2, meter meter1, #d := date, #m := meter
FROM table1 CROSS JOIN (SELECT #d := NULL, #m := NULL) i
ORDER BY date DESC
) q
WHERE date2 IS NOT NULL
ORDER BY date1
Here is SQLFiddle demo
Output in both cases:
| DATE1 | DATE2 | START | END | AMOUNT |
|------------|------------|-------|-----|--------|
| 2103-11-01 | 2103-11-10 | 5 | 8 | 3 |
| 2103-11-10 | 2103-11-14 | 8 | 10 | 2 |
| 2103-11-14 | 2103-11-20 | 10 | 18 | 8 |
| 2103-11-20 | 2103-11-25 | 18 | 25 | 7 |
| 2103-11-25 | 2103-11-29 | 25 | 30 | 5 |
MySql
SELECT DATES.date1,
DATES.date2,
m1.meter as start,
m2.meter as end,
m2.meter - m1.meter as amount
FROM
(SELECT date as date1,
(SELECT min(date)
FROM tableName t2
WHERE t2.date > t1.date) as date2
FROM tableName t1
)DATES,
tableName m1,
tableName m2
WHERE DATES.date2 IS NOT NULL
AND m1.date = DATES.date1
AND m2.date = DATES.date2
ORDER BY DATES.date1
sqlFiddle here
in MS-SQL SERVER 2002 change the word end to "end" as it complains about syntax near end
You haven't made it clear whether you're really using mySQL or SQL Server but I'm posting a solution that works for SQL 2008 and above. Might work for 2005 but I can't test that.
-- Set up a temp table with sample data
DECLARE #testData AS TABLE(
id int,
dt date,
meter int)
INSERT #testData(id, dt, meter) VALUES
(1, '2013-11-01', 5)
,(2, '2013-11-10', 8)
,(4, '2013-11-14', 10)
,(6, '2013-11-20', 18)
,(7, '2013-11-25', 25)
,(10, '2013-11-29',30)
---------------------------------------------
-- Begin SQL Server solution
;WITH cte AS (
SELECT
ROW_NUMBER() OVER (ORDER BY id) AS rownum
,id
,dt
,meter
FROM
#testData AS [date2]
)
SELECT
t1.id
,t1.dt AS [date1]
,t2.dt AS [date2]
,t1.meter AS [start]
,t2.meter AS [end]
,t2.meter - t1.meter AS [amount]
FROM
cte t1
LEFT OUTER JOIN cte t2 ON (t2.rownum = t1.rownum + 1)
WHERE
t2.dt IS NOT NULL
If you're using MySQL, then a self-join will work well here. Join the table to itself, using an ON clause to make sure you don't join the same record to itself. This will give you ((N * N) - N) permutations of your data, where N is the number of original rows.
SELECT
...
FROM
tableName first
JOIN
tableName second
ON first.id != second.id
Then, it's all about SELECTing the right stuff (including the calculation of the difference between the two meter values). To get the columns in the result set you posted, you'd probably want to SELECT:
first.date AS date1,
second.date AS date2,
first.meter AS start,
second.meter AS end,
ABS(first.meter - second.meter) AS amount
Edit
Ah, I see. I'd envisioned something like a inter-city mileage chart that you used to see on road maps (where you'd have the same cities in the rows and columns, and the cell in the intersection would indicate the number of miles between those two cities.
But it looks like you just want to compare values from one date to the next. If that's the case, you can take advantage of the way MySQL handles GROUPing and ORDERing... but be careful, because I'm not sure this is guaranteed:
mysql> SELECT
table1.date AS date1,
table2.date AS date2,
table1.meter AS start,
table2.meter AS end,
ABS(table1.meter - table2.meter) AS amount
FROM tableName table1
JOIN tableName table2
WHERE table2.date > table1.date
GROUP BY table1.date
ORDER BY table2.date - table1.date;
+---------------------+---------------------+-------+------+--------+
| date1 | date2 | start | end | amount |
+---------------------+---------------------+-------+------+--------+
| 2103-11-25 00:00:00 | 2103-11-29 00:00:00 | 25 | 30 | 5 |
| 2103-11-10 00:00:00 | 2103-11-14 00:00:00 | 8 | 10 | 2 |
| 2103-11-20 00:00:00 | 2103-11-25 00:00:00 | 18 | 25 | 7 |
| 2103-11-14 00:00:00 | 2103-11-20 00:00:00 | 10 | 18 | 8 |
| 2103-11-01 00:00:00 | 2103-11-10 00:00:00 | 5 | 8 | 3 |
+---------------------+---------------------+-------+------+--------+
5 rows in set (0.00 sec)