To save list in CSV file python? - csv

Question

I want to transpose row into column and then save words in CSV file. The problem is only last value of column after transpose is save in file, and if i append string with list, it save in file but characters not words.
Anyone help me to sort it. Thanks in advance
import re
import csv
app =[]
with open('afterstem.csv') as f:
words = [x.split() for x in f]
for x in zip(*words):
for y in x:
res=y
newstr = re.sub('"', r'', res)
app = app + list(res)
#print("AFTER" ,newstr)
with open(r"removequotes.csv", "w") as output:
writer = csv.writer(output, lineterminator='\n', delimiter='\t')
for val in app:
writer.writerow(val)
output.close()
The output save in file look like this:
But i want "Bank" in one cell.

Answer 1

Simply use
for column in zip(*words):
newrows = [[word.replace('"', '')] for word in column]
app.extend(newrows)
to put all columns one after another into the first column.
newrow = [[word.replace('"', '')] for word in column] creates a new list for each column with double quotes stripped and wrapped into a list and app.extend(newrow) appends all of these lists to your result variable app.
You got your result because of your inner loop and in particular its last line:
for y in x:
...
app = app + list(res)
The for-loop takes each word in each column and list(res) converts the string with the word into a list of characters. So "Bank" becomes ['B', 'a', 'n', 'k'], etc. Then app = app + list(res) creates a new list that contains every item from app and the characters from the word and assigns that to app.
In the end you got a array containing every letter from the file instead of a array with all words in the file in the right order. The call to writer.writerow(val) then wrote each letter as it's own row.
BTW: If your input also uses tabs to delimit columns, it might be easier to use list(csv.reader(f, lineterminator='\n', delimiter='\t')) instead of your simple read with split() and stripping of quotes.