I want to rewrite this query so it would be working with table and column alias, but I can't get it working. After some research I found that we cannot use table alias in WHERE clause, I tried to change WHERE to HAVING, but still not working ...
Does anyone have a better idea?
This is the query:
SELECT pos.pat_id+1000 as Barcode
,pat_sex as Sex
,pat_dob as DoB
,Test
,Required_diagnosis
,Sample_date
,Location
,DQ_list
FROM (SELECT icv_pat_id as pat_id
,icv_test_name as Test
,'Trichomonas' as Required_diagnosis
,lrr_request_date as Sample_date
,d.Location
,d.DQ_List
FROM investigation_component_values
INNER JOIN lab_result_records l on l.lrr_rrc_id = icv_rrc_id
LEFT JOIN lookups.dq_lists d ON d.lrr_ordering_location_name = l.lrr_ordering_location_name
WHERE lrr_request_date BETWEEN '2015-08-01' AND '2015-08-31'
AND icv_pat_id NOT IN (SELECT pat_id FROM cnwlreports.test_patients)
AND icv_ist_id = 83882
AND icv_non_quantifiable_result = 'Trichomonas vaginalis ISOLATED') as pos
LEFT JOIN trungnguyen.patients pat on pos.pat_id = pat.pat_id
WHERE pos.pat_id NOT IN (SELECT DISTINCT p.pat_id
FROM pos p
LEFT JOIN (SELECT rrc_pat_id as pat_id
,rrc_clinic_date as diag_date
FROM referral_records
WHERE rrc_status = 'approved'
AND rrc_answered_id = 17380
AND rrc_clinic_date BETWEEN DATE_SUB('2015-08-01',INTERVAL 7 DAY)
AND DATE_ADD('2015-08-31',INTERVAL 7 DAY)
AND rrc_pat_id IN (SELECT pat_id FROM pos)
GROUP BY rrc_pat_id
,rrc_clinic_Date) d ON p.pat_id = d.pat_id
WHERE ABS(datediff(sample_date,diag_date)) < 7
)
;
You are confusing table aliases and column aliases. A column alias is defined in a SELECT and cannot be used in the WHERE clause for that SELECT.
A table alias is defined in the FROM clause. It can -- and should -- be used whenever columns from that table are used. Such a column name, with a table alias, is called a qualified column.
For example, from your subquery:
SELECT icv.icv_pat_id as pat_id,
icv.icv_test_name as Test,
'Trichomonas' as Required_diagnosis,
lrr.lrr_request_date as Sample_date
. . .
FROM investigation_component_values icv INNER JOIN
lab_result_records lrr
on lrr.lrr_rrc_id = icv.icv_rrc_id
WHERE lrr.lrr_request_date BETWEEN '2015-08-01' AND '2015-08-31' . . .
pat_id, test, Required_diagnosis and Sample_date are all column alias. icv and lrr are table aliases. In the WHERE clause, you can have:
WHERE lrr.lrr_request_date BETWEEN '2015-08-01' AND '2015-08-31' . . .
But you cannot have:
WHERE Sample_Date BETWEEN '2015-08-01' AND '2015-08-31' . . .
You can use the real column name, so in the 'WHERE pos.pat_id' for example, You should use: 'WHERE pos.icv_pat_id'.
generally you can use alias for table in where clause;
Normally , I do:
Select * from Table T, Table2 T2 WHERE T.key = T2.key;
For example, try to explicit inner join with this syntax.
Related
I want to use mysql's "JOIN"
I want to group rows by "date_text" where "tokenIdx" is "1001" and "datetime_unix" is the highest value.
Is my code wrong?
SELECT `A.idx`
FROM `data_candle_h1` 'A'
JOIN
(
SELECT `date_text`, MAX(`datetime_unix`) AS 'datetime_unix'
FROM `data_candle_h1`
WHERE `tokenIdx` = '1002'
GROUP BY `date_text`
) 'B'
ON `A.datetime_unix` = `B.datetime_unix`
WHERE `A.tokenIdx` = '1002'
Your query is syntactically perfect. Just remove single quotes('') around table aliases (A and B). I have corrected it. Please check this out.
SELECT `A.idx`
FROM `data_candle_h1` A
JOIN
(
SELECT `date_text`, MAX(`datetime_unix`) AS 'datetime_unix'
FROM `data_candle_h1`
WHERE `tokenIdx` = '1002'
GROUP BY `date_text`
) B
ON `A.datetime_unix` = `B.datetime_unix`
WHERE `A.tokenIdx` = '1002'
I've searched a lot but I still don't get it.
Here's my sample code
SELECT sp.testno, sp.companyid, st.*
FROM sponsor AS sp
LEFT JOIN
(
SELECT a.sponsorempno, (CASE WHEN t.companyid IS NULL OR t.companyid = '' THEN'aa' ELSE t.companyid END) agncy, a.controlno, a.tnpl, t.*
FROM applicant AS a
LEFT JOIN
test AS t
ON a.controlno = t.controlno
) AS st
ON sp.testno = st.testno
I still returns an error:
#1060 - Duplicate column name 'controlno'
Can somebody tell me what's wrong with the code?
In the subselect of your join, you are selecting a.controlno and by t.* t.controlno.
You should provide an alias for one of the selected columns. In your case a.controlno. This is necessary, because the table aliases of the inner select are lost, when accessing it from the outer one.
The statement below should work, if there aren't any other duplicate column names in test and the set of used columns from applicant.
SELECT sp.testno, sp.companyid, st.*
FROM sponsor AS sp
LEFT JOIN
(
SELECT a.sponsorempno, (CASE WHENt.companyid IS NULL OR t.companyid = '' THEN'aa' ELSE t.companyid END) agncy, a.controlno as a_controlno, a.tnpl, t.*
FROM applicant AS a
LEFT JOIN
test AS t
ON a.controlno = t.controlno
) AS st
ON sp.testno = st.testno
I have a problem with this query in MariaDB language. I want to do an intersect with the same field but with two values. The problem is that i can't use the INTERSECT query.
How can I do it?? I have tried with exists and inner join but it still doesn't work.
SELECT nombre
FROM actores
WHERE codactor IN ( SELECT actor
FROM participacion
WHERE (titulo,año) IN (SELECT titulo, año
FROM peliculas
WHERE director IN (
SELECT coddirector
FROM directores d
WHERE d.nombre='Alejandro'
AND d.apellido='Amenabar')))
INTERSECT
SELECT nombre
FROM actores
WHERE codactor IN ( SELECT actor
FROM participacion
WHERE (titulo,año) IN (SELECT titulo,año
FROM peliculas
WHERE director in (
SELECT coddirector
from directores p
WHERE p.nombre='Pedro'
AND p.apellido='Almodobar')));
INTERSECT was introduced in MariaDB 10.3.0.
INTERSECT
The result of an intersect is the intersection of right and left SELECT results, i.e. only records that are present in both result sets will be included in the result of the operation.
(SELECT e_name AS name, email FROM employees)
INTERSECT
(SELECT c_name AS name, email FROM customers);
As for your query you could leave it as is.
First try it like this, to check you have all the actors. I have to add codactor in case you have actors with same name.
SELECT a.codactor, a.nombre -- add ', *' to see all columns and test query is ok.
FROM actores a
JOIN participacion p
ON a.codactor = p.actor
JOIN peliculas m
ON p.titulo = m.titulo
AND p.ano = m.ano
JOIN directores d
ON p.director = d.coddirector
WHERE (d.nombre = 'Alejandro' and d.apellido = 'Amenabar')
OR (d.nombre = 'Pedro' and d.apellido = 'Almodobar')
Then add GROUP BY to see which actor are in movies from both directors.
GROUP BY a.codactor, a.nombre
HAVING COUNT(DISTINCT coddirector) = 2
I have two tables:
customer with schema_id
Schema table has: schema_id, period, amt, updated_date
I need to take join of customer and schema but only retrieve the latest record joined and not the others.
customer table
cust_id name schema_id
1 ABC 1
Schema table
schema_id period amt updated_date
1 1 100 2010-4-1
1 2 150 2011-4-1
If you need the max(updated_date) for each schema_id, then you can use an subquery:
select c.cust_id, c.name, c.schema_id, s.period, s.amt, s.updated_date
from customer c
inner join
(
select s1.schema_id, s1.period, s1.amt, s1.updated_date
from `schemas` s1
inner join
(
select schema_id, max(updated_date) MaxDate
from `schemas`
group by schema_id
) s2
on s1.schema_id = s2.schema_id
and s1.updated_date = s2.maxdate
) s
on c.schema_id = s.schema_id
See SQL Fiddle with Demo
The subquery is then used in a join back to your table to return the rows that have the matching date and schema_id.
If I understood your problem, you need to take lastest register of the "schema".
I think you need to use max() function. So, try the query below:
select *
from customer c,
schema s
where c.schema_id = s.schema_id
and s.updated_date = ( select max(s2.updated_date)
from schema s2
where s2.schema_id = s.schema_id
)
Regards!
Edmilton
I need to update multiple records in a table based upon the sum of some values in another table. Here is my query:
UPDATE aallinnot2 c SET c.Energ_Kcal = ( SELECT d.id1, SUM( c.Energ_Kcal)
FROM aaingred a
LEFT JOIN aaweight b ON a.unit = b.uni
LEFT JOIN aallinnot2 c ON a.mfdfsds = c.NDB_No
LEFT JOIN aalinfsds d ON a.fsdsnum = d.id1
WHERE d.own_id =42
GROUP BY id1 )
WHERE c.NDB_No
IN ( SELECT DISTINCT `fsdsnum`
FROM `aaingred`
WHERE `usernum` LIKE '42'
)
MySQL said:
#1093 - You can't specify target table 'c' for update in FROM clause
Unfortunately, I don't know how to get my values without referencing target table 'c'! Is there a workaround for this?
With the crazy table/column names and indecipherable logic, this might be the ugliest query I have ever seen. Congrats. :)
I think the following should work (or this approach). The main problem was untangling the group-by expression-- you need to give the database engine a dataset where each row in the target table is joined to a set that contains the updated value for that row. So here, select the new values in a sub-query, then join that sub-query to the original table.
EDIT Fixed some syntax
UPDATE
(
SELECT d.id1, SUM (c.Energ_Kcal) AS Sum_Energ_Kcal
FROM aaingred a
LEFT JOIN aaweight b ON a.unit = b.uni
LEFT JOIN aallinnot2 c ON a.mfdfsds = c.NDB_No
LEFT JOIN aalinfsds d ON a.fsdsnum = d.id1
WHERE d.own_id =42
GROUP BY id1
) d
,aaingred a, aallinnot2 d
SET Energ_Kcal = d.Sum_Energ_Kcal
WHERE d.id1 = a.fsdsnum
AND a.mfdfsds = aallinnot2.NDB_No
AND c.NDB_No IN (
SELECT DISTINCT `fsdsnum`
FROM `aaingred`
WHERE `usernum` LIKE '42'
);
I'm not sure about mysql, but with SQL Server the statement would be something like this:
UPDATE aallinnot2
SET Energ_Kcal = (
SELECT SUM( c.Energ_Kcal)
FROM aaingred a
LEFT JOIN aaweight b ON a.unit = b.uni
LEFT JOIN aallinnot2 c ON a.mfdfsds = c.NDB_No
LEFT JOIN aalinfsds d ON a.fsdsnum = d.id1
WHERE d.own_id =42)
WHERE c.NDB_No
IN ( SELECT DISTINCT `fsdsnum`
FROM `aaingred`
WHERE `usernum` LIKE '42')
You can't alias the table to be updated in the UPDATE clause, but you can in the FROM clause.