I need a list of user IDs (course_user_ids) that is currently stored in a single field of a larger table.
I have a table called courses that contains course information with course_id and course_students as such:
-----------------------------------------------------------
| course_id | course_students |
----------------------------------------------------------
| 1 | a:3:{i:0;i:12345;i:1;i:22345;i:2;i:323456;} |
-----------------------------------------------------------
| 2 | a:32:{ … } |
-----------------------------------------------------------
The course_students part contains 3 chunks of information:
the number of students (a:3:{…) -- not needed
the order/key for the array of each student ({i:0;… i:1;… i:2; …}) -- also not needed
the course_user_id (i:12345; … i:22345;… i:32345;)
I only need the course_user_id and the original course_id, resulting in a new table that i can use for joins/subqueries like this:
------------------------------
| course_id | course_user_id |
------------------------------
| 1 | 12345 |
------------------------------
| 1 | 22345 |
------------------------------
| 1 | 323456 |
------------------------------
(ideally able to continue to break out values for other course_ids and course_user_ids, but not a priority:)
| … | … |
------------------------------
| 2 | … |
------------------------------
| 2 | … |
------------------------------
| 97 | … |
------------------------------
| 97 | … |
------------------------------
| … | … |
------------------------------
Note: the course_user_id can vary in length (some are 5 digits, some are 6)
Any ideas would be much appreciated!
Update
My user table does have user_id which can be mapped to course_students or course_user_id, so that is a very helpful observation from below.
I also think I need to use a LEFT JOIN because some students are registered in multiple courses, and I'd like to see each instance/combo.
Let us assume that you have a table name users which contains all users data along with user_id.
Now you can join table courses and table users in following manner:
select c.course_id,u.user_id
from
courses c
join users u
on u.user_id=if(instr(c.course_students,concat(":",u.user_id,";"))>0,u.user_id,c.course_students)
You get the result as per your requirement.
Verify at http://sqlfiddle.com/#!9/3667d/2
Note: The above query works fine if no overlapping between user_id and array index. In case of overlapping, kindly filter data using where-clause
If I got your goal correctly you have users table. And {i:0;i:12345;i:1;i:22345;i:2;i:323456; equal users.id=12345,users.id=22345 etc.
If my guess is correct you can try this solution:
http://sqlfiddle.com/#!9/cfef27/5
SELECT * FROM courses
LEFT JOIN users u
ON courses.course_students LIKE CONCAT('%i:',u.id,';%')
Related
I have a question and don't know how to approach the problem exactly.
I have two tables as following:
Clients
| c_id | name | reference |
| ---- | ------- | --------- |
| 1 | ClientA | 1 |
| 2 | ClientB | 1 |
| 3 | ClientC | 2 |
| 4 | ClientD | 2 |
| 5 | ClientE | 1 |
| 1 | ClientF | 3 |
Tour
| t_id | name | count |
| ---- | ------- | ----- |
| 1 | TourA | 3 |
| 2 | TourB | 2 |
| 3 | TourC | 1 |
"Reference" in the "Client" table is defined as foreign key.
Is it possible to fill the column "count" in the table "Tour" with an automated formula where it counts how many times the t_id appears in the "Client" table?
Something like: COUNT(c_id) FROM clients WHERE reference = t_id
I have read about to create a view but not sure how to fetch the data correctly.
Thanks for your help,
Raphael
UPDATE #1:
The workflow as described with the view works perfectly. I'm trying now to fill the column via a trigger but I'm getting an SQL error with the following code:
CREATE TRIGGER client_count
AFTER UPDATE
ON clients FOR EACH ROW
SELECT t.*,
(
SELECT COUNT(*) FROM clients c where c.tour_id = t.tour_id
) AS tours.tour_bookedspace
FROM tours t
The view you have referred to is indeed the way to go here. The view you need to create needs to join the two tables and perform a count aggregation as follows:
CREATE VIEW vwTour
AS
SELECT t.t_id,
t.name,
COUNT(t.name) AS Cnt
FROM tour t
JOIN Clients c
ON t.t_id = c.reference
GROUP BY t_id,
t.name
No you can't. Generated columns can only use data from the same table.
The options you have are:
1. Use a view
You can select from a view that computes the extra value(s) you want. For example:
create view tour_data as
select t.*,
(
select count(*) from clients c where c.reference = t.t_id
) as number_of_clients
from your t
2. Use a trigger
Alternatively, you can add the extra column number_of_clients and populate it using a trigger every time a row is added, modified, or deleted from the table clients.
I have a table with a column for agent names and a column for each of the skills those agents could possibly have. Each skill the agent is assigned shows a 1 in the field under that skill.
Columns look like this:
+---------+----------+----------+----------+
| Name | 'Skill1' | 'Skill2' | 'Skill3' |
+---------+----------+----------+----------+
| John | 1 | | 1 |
| Sam | 1 | 1 | |
| Roberta | 1 | | 1 |
+---------+----------+----------+----------+
I would like to make a query that returns a list of all agent names that have a 1 for each particular skill. The query would return something like this:
+-----------+
| Skill 1 |
+-----------+
| John |
| Sam |
| Roberta |
+-----------+
Additionally I would like to be able to query a single name and retrieve all skills that agent has (all rows the Name column has a 1 in) like this:
+-----------+
| John |
+-----------+
| Skill 1 |
| Skill 3 |
+-----------+
I've done this in Excel using an index but I'm new to Access and not sure how to complete this task.
Thanks in advance.
One of the reasons that you are finding this task difficult is because your database is not normalised and so due to the way that your database is structured, you are working against MS Access, not with it.
Consequently, whilst a solution is still possible with the current data, the resulting queries will be painful to construct and will either be full of multiple messy iif statements, or several union queries performing the same operations over & over again, one for each 'skill'.
Then, if you every wish to add another Skill to the database, all of your queries have to be rewritten!
Whereas, if your database was normalised (as Gustav has suggested in the comments), the task would be a simple one-liner; and what's more, if you add a new skill later on, your queries will automatically output the results as if the skill had always been there.
Your data has a many-to-many relationship: an agent may have many skills, and a skill may be known by many agents.
As such, the most appropriate way to represent this relationship is using a junction table.
Hence, you would have a table of Agents such as:
tblAgents
+-----+-----------+----------+------------+
| ID | FirstName | LastName | DOB |
+-----+-----------+----------+------------+
| 1 | John | Smith | 1970-01-01 |
| ... | ... | ... | ... |
+-----+-----------+----------+------------+
This would only contain information unique to each agent, i.e. minimising the repeated information between records in the table.
You would then have a table of possible Skills, such as:
tblSkills
+-----+---------+---------------------+
| ID | Name | Description |
+-----+---------+---------------------+
| 1 | Skill 1 | Skill 1 Description |
| 2 | Skill 2 | Skill 2 Description |
| ... | ... | ... |
+-----+---------+---------------------+
Finally, you would have a junction table linking Agents to Skills, e.g.:
tblAgentSkills
+----+----------+----------+
| ID | Agent_ID | Skill_ID |
+----+----------+----------+
| 1 | 1 | 1 |
| 2 | 1 | 2 |
| 3 | 2 | 1 |
| 4 | 3 | 2 |
+----+----------+----------+
Now, say you want to find out which agents have Skill 1, the query is simple:
select Agent_ID from tblAgentSkills where Skill_ID = 1
What if you want to find out the skills known by an agent? Equally as simple:
select Skill_ID from tblAgentSkills where Agent_ID = 1
Of course, these queries will merely return the ID fields as present in the junction table - but since the ID uniquely identifies a record in the tblAgents or tblSkills tables, such ID is all you need to retrieve any other required information:
select
tblAgents.FirstName,
tblAgents.LastName
from
tblAgentSkills inner join tblAgents on
tblAgentSkills.AgentID = tblAgents.ID
where
tblAgentSkills.Skill_ID = 1
To get all agents with skill1, open the query designer and create the following query:
this will generate the following sql
SELECT Skills.AgentName
FROM Skills
WHERE (((Skills.Skill1)=1));
If you adjust the names you can also paste this query into the sql pane of the designer to get the query you want.
To get all the skills an agent has I chose a parameterized query. Open the query designer and create a new query:
When you run this query it will ask you for the name of the agent. Make sure to type the agent name exactly. Here is the resulting sql:
SELECT Skills.AgentName, Skills.Skill1, Skills.Skill2, Skills.Skill3
FROM Skills
WHERE (((Skills.AgentName)=[Agent]));
If you continue working with this query I would improve the table design by breaking your table into a skills table, agents table, skills&agents table. Then link the skills and agents tables to the skills&agents table in a many to many relationship. The query to get all an agents skills would then look like this in the designer:
I have two tables "contacts" and "users". Users table storing data with "," separated. Need to distinct data in "Contacts" column from "Contacts" table. And need to join with "Users" table, and get the records.
Contacts Table
--------------------------
id | user_Id | contats
--------------------------
1 | 2147483647 | 90123456789,90123456789,90123456789,90123456789
2 | 2147483647 | 90123456789,90123456789,90123456789,90123456789
3 | 919444894154 | 90123456789,90123456789,90123456789,90123456789
Users Table
-----------------------------
id | username | email | phone
-----------------------------
1 | bhavan | bhavanram93#gmail.com | 90123456789
2 | bhavan | bhavanram93#gmail.com | 90123456789
3 | prince | prince#gmail.com | 1234567980
4 | bhavan | bhavanram93#gmail.com | 90123456789
5 | hello | hello#gmail.com | 1234567890
6 | bhavan | bhavanram93#gmail.com | 90123456789
Your table Contacts shouldn't be constructed this way.
Since you want 1 Users table containing all the data about a user, and 1 Contacts table containing links between different users, you'd rather do this kind of table structure :
Contacts table
id | user_id | contact_id
-------------------------
1 | 1 | 2
2 | 1 | 3
3 | 2 | 3
That'll allow you to do something like :
SELECT *
FROM Users
JOIN Contacts ON (Users.id = Contacts.contact_id)
WHERE Contacts.user_id = 1
Which will return all the data of the contacts of the user 1.
Your current structure is a huge ongoing mess, it's the opposite of being flexible.
You should restructure your db to a normalized format as Steve suggest.
But if you cant:
SELECT *
FROM Users
JOIN Contacts
ON CONCAT(',', Contacts.contacts, ',') like
CONCAT('%,', Users.phone, ',%')
WHERE Contacts.user_id = 1
the idea is you convert your contacts to
, <numbers> ,
,90123456789,90123456789,90123456789,90123456789,
and try to match with
%,90123456789,%
Note this approach cant use any index so will have bad performance with many
rows. if you are in the order of 1k-10k rows may be ok. More than that you need consider restructure your db.
I am trying to write a mySQL statement that selects data from one table but counts up entries from another table with a matching ID in a specific field.
The two tables are jobs and job_cards. A job will always be a single entry which will have multiple job cards, so I need to write a singular statement that selects data from the job table but adds another field in the result which is a count of all related job cards.
Example:
jobs table:
| ID | customer | status | date_added |
|----------------------------------------|
| 1 | 3 | active | 2017-10-10 |
------------------------------------------
job_cards table is a bit more complex but includes a column called job_id which will be 1 in this case. But lets say there are 3 cards assigned to the job above. I wrote the following statement:
SELECT j.*, COUNT(jc.id) AS card_count FROM jobs j LEFT JOIN job_cards jc ON j.id = jc.job_id
But the count column only returns the TOTAL number of cards in the job_cards table, regardless of which job they are assigned to. Not only that, but it only ever returns a single result even though at the moment there are 4 entries in the jobs table.
Is there any way to do what I need to do with a single statement?
EDIT:
Sample data from the job_cards table:
| ID | job_id | customer | description | materials | notes |
|--------------------------------------------------------------|
| 1 | 1 | 3 | blah blah | none | test |
| 2 | 1 | 3 | something | pipes | n/a |
----------------------------------------------------------------
The result I would like to get is:
| ID | customer | date_added | card_count |
|-------------------------------------------|
| 1 | 3 | 2017-10-10 | 2 |
---------------------------------------------
Where the ID here is the ID of the job.
You can try this:
SELECT *, (select count(*)
from job_cards jc
where jc.job_id=j.id) as card_count
FROM jobs j
I have table like:
user :
uid | course_id | subjects
---------------------------
1 | 1 | html,php
2 | 1 | java,html,sql
3 | 1 | java
4 | 1 | fashion,html,php,sql,java
I want to run a query which can return most liked subjects in query and then second most and so on...
For Example :
select * from user where subjects like '%java%' or '%php%' or '%html%';
this query will return data like this:
uid | course_id | subjects
---------------------------
2 | 1 | java,html,sql
3 | 1 | java
4 | 1 | fashion,html,php,sql,java
but i want output like this :
uid | course_id | subjects
---------------------------
4 | 1 | fashion,html,php,sql,java
2 | 1 | java,html,sql
1 | 1 | html,php
3 | 1 | java
so the most matched subjects 1st then 2nd most matched subjects and so on....
Is there any modification in my query so that i can get this type of sorted output.
Never, never, never store multiple values in one column!
Like you see now this will only give you headaches. Normalize your user table. Then you can select normally.
It should look like this
uid | course_id | subjects
---------------------------
1 | 1 | html
1 | 1 | php
2 | 1 | java
2 | 1 | html
2 | 1 | sql
3 | 1 | java
...
or better introduce an new table subjects and then make a mapping table called course_subjects
subject
id | name
------------
1 | html
2 | sql
3 | java
...
course_subjects
uid | course_id | subject_id
---------------------------
1 | 1 | 1
1 | 1 | 2
...
Based on the way you want your results, it looks like you want to order by the number of subjects (or tags) within subject. This can be accomplished by counting the number of , (commas).
The way to count the number of occurances of a character is to subtract the original length by the length when the character is removed.
Example:
SELECT *
FROM USER
WHERE subjects LIKE '%java%'
OR '%php%'
OR '%html%'
ORDER BY ( Length(subjects) - Length(Replace(subjects, ',', '')) ) DESC;
SQLFiddle: http://sqlfiddle.com/#!2/cc793/4
Result:
UID COURSE_ID SUBJECTS
4 1 fashion,html,php,sql,java
2 1 java,html,sql
3 1 java
Note:
As juergen says it is a bad idea to store multiple values in one column.
With MyISAM storage engine you can do match against.
The simplest example:
SELECT *,
MATCH (subjects) AGAINST ('java php html') AS relevance
FROM `user`
WHERE MATCH (subjects) AGAINST ('java php html')
ORDER BY relevance DESC
In MySQL 5.6 full-text search is available with InnoDB too but needs a bit extra to make it work. For more info checkout the following post: http://www.mysqlperformanceblog.com/2013/03/04/innodb-full-text-search-in-mysql-5-6-part-2-the-queries/