I have one table named viewlist as follows
Id article_id viewdate
--------------------------------------------------
1 1 2015-07-01
2 1 2015-07-01
3 1 2015-07-01
4 2 2015-07-01
5 2 2015-07-01
6 1 2015-07-02
7 2 2015-07-02
8 1 2015-07-03
9 2 2015-07-03
10 1 2015-07-05
11 1 2015-07-05
----------------------------------------------------
i need to write a MySQL query to get count and article_id by grouping adjacent viewdate field
wanted result as follows
article_id count date_period
-----------------------------------------------------------------
1 4 2015-07-01 - 2015-07-02
2 3 2015-07-01 - 2015-07-02
1 1 2015-07-03 - 2015-07-04
2 1 2015-07-03 - 2015-07-04
1 2 2015-07-05 - 2015-07-06
Is there any simple query to get this type of result?
you may use something on these lines
SELECT v.article_id, COUNT(*), CONCAT(b.dt, ' - ', b.dt2) as 'date_period'
FROM viewlist v INNER JOIN
(SELECT a.dt, DATE_ADD(a.dt, INTERVAL 1 DAY) AS dt2 FROM (SELECT DISTINCT(viewdate) AS dt FROM viewlist WHERE (DAY(viewdate) MOD 2) = 1) a) b ON v.viewdate BETWEEN b.dt AND b.dt2
GROUP BY 1, 3
ORDER BY b.dt
Related
hi guys i really newbie in sql, i need help to generate percentage of attendance, here is the table:
Table Schedule
Schedule_ID Course_ID Lecture_ID Start_Date End_Date Course_Days
1 1 11 2019-09-09 2019-12-08 2,4,6
2 3 4 2019-09-09 2019-12-08 3,4
3 4 13 2019-09-09 2019-12-08 2,5
4 5 28 2019-09-09 2019-12-08 3
5 2 56 2020-01-27 2020-04-26 2,4
6 7 1 2020-01-27 2020-04-26 4,5
7 1 11 2020-01-27 2020-04-26 2,4,6
8 7 22 2020-01-27 2020-04-26 2,3
9 8 56 2020-01-27 2020-04-26 5
10 3 37 2020-01-27 2020-04-26 5,6
Reference of days of week used in this data.
1: Sunday, 2:Monday, 3:Tuesday, 4:Wednesday, 5:Thursday, 6:Friday, 7:Saturday
Table course_attendance
ID STUDENT_ID SCHEDULE_ID ATTEND_DT
1 1 2 2019-09-10
2 1 2 2019-09-11
3 1 2 2019-09-17
4 1 2 2019-09-18
......
46 2 1 2019-12-02
47 2 1 2019-09-11
48 2 1 2019-09-18
49 2 1 2019-09-25
50 2 1 2019-10-09
51 2 1 2019-10-16
....
111 6 1 2019-09-23
112 6 1 2019-09-30
113 6 1 2019-10-07
114 6 1 2019-10-14
table student
ID NAME
1 Jonny
2 Cecilia
3 Frank
4 Jones
5 Don
6 Harry
i need to show up like this :
STUDENT_ID NAME Course_ID Attendance rate
1 Jonny 1 82%
2 Cecilia 1 30%
3 Frank 3 100%
4 Jones 2 100%
5 Don 2 25%
6 Harry 4 40%
EDIT this my last step to get percentage:
result:
with main as (
select ca.STUDENT_ID,
ca.SCHEDULE_ID,
s.COURSE_ID,
co.NAME as course_name,
st.NAME,
count(ca.ID) as total_attendance,
((CHAR_LENGTH(s.COURSE_DAYS) - CHAR_LENGTH(REPLACE(s.COURSE_DAYS , ',', '')) + 1) * 13) as attendance_needed
from univ.course_attendance ca
left join univ.schedule s on ca.SCHEDULE_ID = s.ID
left join univ.student st on ca.SCHEDULE_ID = st.ID
left join univ.course co on ca.SCHEDULE_ID = co.ID
group by ca.STUDENT_ID, ca.SCHEDULE_ID
)
select *,total_attendance/attendance_needed as attendance_percentage
from main
order by 1,2;
This can be done following three steps.
Step 1: Calculate the total number of days a particular course of a schedule has. It's a good thing the start_date is always on Monday and the end_date is always on Sunday, which makes the week complete and saves some trouble. By calculating the total number of weeks a course go through and the number of days a week has for that course, we can get the total number of days a particular course of a schedule has.
Step 2:Calculate the total number of days a student for a schedule. This is done fairly easily. Note: As the majority part of the table has been skipped and the OP has yet to provide the complete data set, I could only have 14 existing rows provided.
Step 3: Calculate the percentage for the attendance using the result from the above two steps and get other required columns.
Here is the complete statement I wrote and tested in workbench:
select t2.student_id as student_id,`name`,course_id, (t2.total_attendance/t1.total_course_days)*100 as attendance_rate
from (select schedule_id,course_id,
length(replace(course_days,',',''))*(week(end_date)-week(start_date)) as total_course_days
from Schedule) t1
JOIN
(select count(attend_dt) as total_attendance,student_id,schedule_id
from course_attendance group by student_id, schedule_id) t2
ON t1.schedule_id=t2.schedule_id
JOIN
student s
ON t2.student_id=s.id;
Here is the result set ( the attendance_rate is not nice due to the abridged course_attendance table):
student_id, name, course_id, attendance_rate
2, Cecilia, 1, 15.3846
6, Harry, 1, 10.2564
1, Jonny, 3, 15.3846
I have 1 table called itemmovement : It has Item Id , Quantity In , Quantity Out , Invoice Id, Date. I need to make in one query to show how many pieces are sold and beside the sold column there will be the current on hand quantity .
itemmovement
Id itemid qtyin qtyout invid purchasereturnid date
1 1 10 2019-01-04
2 2 8 2019-01-06
3 2 2 1 2019-01-08
4 1 3 2 2019-01-12
5 2 1 2019-02-04
6 3 4 2019-03-04
7 1 1 3 2019-04-04
8 1 1 1 2019-04-14
9 3 1 2 2019-04-24
I need the query to show this result
Id itemid Sold Quantity OnHandQty
1 1 4 5
2 2 2 7
3 3 0 3
I'm Trying to use this query but not working
SELECT *
FROM
(SELECT itmv.itemid,
sum(itmv.qtyout)-sum(itmv.qtyin)
FROM itemmovement itmv
WHERE (itmv.systemdate BETWEEN '2019-01-01' AND '2019-06-01')
AND invid>0
GROUP BY itmv.itemid) AS result1,
(SELECT sum(itmv2.qtyin)-sum(itmv2.qtyout)
FROM itemmovement itmv2
WHERE itmv.itemid=itmv2.itemid
GROUP BY itmv2.itemid) AS result2
ORDER BY sum(itmv.qtyin)-sum(itmv.qtyout)
I'm getting :
Unknown column 'itmv.itemid' in 'where clause it for this syntax :
where itmv.itemid = itmv2.itemid
Here's your query.
select itemid
, sum(case when COALESCE(invid,0) > 0 then qtyout else 0 end) as Sold_Qantity
, sum(qtyin)-sum(qtyout) as OnHandQty
from itemmovement
group by itemid
This question already has answers here:
MySQL : isn't in GROUP BY
(5 answers)
Closed 4 years ago.
I have the following table and i want to generate a view. See the result.
How can i achieve that?
I tried with group_cat but that doesnt work :(
id product_id cat_id date
1 1 1 2018-05-01
2 1 1 2018-05-02
3 1 1 2018-05-04
4 1 1 2018-05-05
5 1 1 2018-05-06
6 1 1 2018-05-07
4 1 1 2018-05-08
5 1 1 2018-05-09
6 1 1 2018-05-10
7 1 2 2018-05-01
8 1 2 2018-05-02
9 1 2 2018-05-04
10 1 2 2018-05-05
11 1 2 2018-05-06
12 1 2 2018-05-07
13 1 2 2018-05-08
14 1 2 2018-05-09
15 1 2 2018-05-10
Result:
product_id cat_id dates
1 1 2018-05-01,2018-05-02,2018-05-03,2018-05-04,etc comma seperated
1 2 2018-05-01,2018-05-02,2018-05-03,2018-05-04,etc comma seperated
Query:
select
tmp.product_id, tmp.cat_id, group_concat(tmp.date separator ',') as dates
from xxxx as tmp
group by tmp.cat_id;
Your group by should be tmp.product_id, tmp.cat_id
select
tmp.product_id, tmp.cat_id, group_concat(tmp.date separator ',') as dates
from demo as tmp
group by tmp.product_id, tmp.cat_id
Demo
Try this:
SELECT product_id, cat_id, GROUP_CONCAT(date SEPARATOR ',') dates FROM `table_name` GROUP BY product_id, cat_id
I have below customer table with max qty.
I need a unique user who has max qty order by its group id.
Input:
id, customer_id, customer_group_id qty
1 1 3 1
2 1 3 10
3 1 3 5
4 2 2 10
5 2 2 1
6 2 2 2
7 3 1 5
8 3 1 10
9 4 4 1
10 4 4 2
11 4 4 2
Output should be:
id, customer_id, customer_group_id, qty
11 4 4 2
10 4 4 2 - This should be not selected
2 1 3 10
4 2 2 10
8 3 1 10
Query:
SELECT * FROM customer
WHERE qty IN ( SELECT MAX(qty) FROM customer GROUP BY customer_id)
ORDER BY customer_group_id DESC;
I tried above query but seems not working.
I can't figure out the mysql query to extract the data I want from this table "timeEntry":
hours creationDate userId clientId projectId taskId
20 2012-02-18 1 1 1 1
40 2012-02-18 1 1 1 1
30 2012-02-21 2 1 1 1
20 2012-02-22 2 1 1 2
30 2012-02-22 2 1 1 2
80 2012-02-23 1 2 2 2
10 2012-02-23 3 2 2 2
15 2012-02-23 1 2 2 3
40 2012-02-23 1 2 4 1
And I would like to have this kind of result as another table, or csv/excel file or php array (where totalHours is the sum of the hours for a userId) for a given period of time, let say (between 2012-02-01 and 2012-02-25):
clientId projectId taskId userId totalHours
1 1 1 1 60
2 30
2 2 50
2 2 2 1 80
3 10
3 1 15
4 1 1 40
I guess I have to use multiple group by, I tried something like:
SELECT clientId, projectId, taskId, userId, sum(hours)
FROM `timeEntry`
WHERE date_creation >= "2012-02-01"
AND date_creation <= "2012-02-25"
GROUP BY clientId, projectId, taskId, userId;
But didn't work...
Thanks in advance.
Where needs to go before Group by.
If you want to filter by date before grouping, use the where clause you have but moved before the group by.
If you'd instead like to filter entire groups in or out, use a having:
...
Group by ...
Having max(date) <= someValue and min(date) >= someValue
SELECT clientId, projectId, taskId, userId sum(Hours) total_hours
FROM timeEntry
GROUP BY clientID, ProjectID, TaskID, userID;
You can use [with Rollup][1] to generate sub-aggregrates. if you want
Here is a simple solution. You need to group by all necessary fields
SELECT
t.clientId,
t.projectId,
t.taskId,
t.userId,
SUM(t.hours) AS Total
FROM test AS t
GROUP BY t.creationDate , t.userId , t.clientId , t.projectId , t.taskId
Fiddle Demo
OUTPUT:
clientId projectId taskId userId Total
____________________________________________________________
1 1 1 1 60
1 1 1 2 30
1 1 2 2 50
2 2 2 1 80
2 2 3 1 15
2 4 1 1 40
2 2 2 3 10