I have a table as follows.
+------------+-------------+---------+
| productid | attributeid | valueid |
+------------+-------------+---------+
| 1011052312 | 331100 | 1543697 |
| 1011052312 | 33113319 | 1534108 |
| 1011098009 | 33129 | 2655849 |
| 1011052380 | 331100 | 1543697 |
| 1011052380 | 33113319 | 1233908 |
+------------+-------------+---------+
Now I need to fetch only those productid who has very selected set of attribute value pair. Say for example I need to fetch a product who's attribute 331100 has value 1543697 and attribute 33113319 has value 1534108. Product 1011052312 satisfy this condition.
One thing to note is that I should avoid multiple joins because there can be a long list of attributes that I need to match. And for each attribute there can be any number of possible value.
It's a common problem, select all the products matching at least one attribute, group them, count how many attributes each product has and then use a HAVING clause to select only the products which have all the attributes. Something like this:
SELECT productid
FROM table
WHERE (attributeid=331100 and valueid=1543697)
OR (attributeid=33113319 and valueid=1534108)
GROUP BY productid
HAVING COUNT(*) = 2
Another way of saying the same thing - I can't remember if the EXPLAIN is the same or not, so this might be slower...
SELECT productid
FROM my_table
WHERE (attributeid,valueid) IN ((331100,1543697)
,(33113319,1534108)
)
GROUP
BY productid
HAVING COUNT(*) = 2;
Related
I have a table products and a table locations which are linked together in a many-to-many relationship with a table products_locations. Now a client can select a set of products, and I want to run a query that selects only the locations, where ALL of the selected products are available.
This seemed pretty straight forward at first, but I see myself being quite baffled by how to achieve this. I initially thought I could get all the correct location-ids with something like
SELECT location_id
FROM products_locations
WHERE product_id = ALL [the user selected product ids]
But on second thought that does not appear to make sense either (the structure of products_locations is quite simply [product_id, location_id].
Any suggestion on how to structure such a query would be appreciated. I feel like I am overlooking something basic..
EDIT: I am using mysql syntax/dialect
Quick sample: Given the following tables
| products | | locations | | products_locations |
| id | name | | id | name | | product_id | location_id |
|------------| |-----------| |--------------------------|
| 1 | prod1 | | 1 | locA | | 1 | 2 |
| 2 | prod2 | | 2 | locB | | 2 | 1 |
| 3 | prod3 | |-----------| | 2 | 2 |
|------------| | 3 | 1 |
|--------------------------|
If a user selects products 1 and 2, the query should return only location 2. If the user selects products 2 and 3, the query should return location 1. For 1, 2, and 3, no location would be valid, and for product 2, both locations would be valid.
I figured out a query that achieves what I need. Though it is not as clean as I had hoped, it seems to be a robust approach to what I'm trying to query:
SELECT t.location_id
FROM (SELECT location_id, COUNT(*) as n_hits
FROM products_locations
WHERE product_id IN [the user selected products]
GROUP BY location_id) t
WHERE n_hits = [the number of user selected products];
Explanation:
I create a temporary table t which contains every location_id that has at least one matching product in the user's selection, together with the number of times that location matches a product in the user's selection. This is achieved by grouping the query by location_id.
I select the location_id(s) from that temporary table t, where the number of hits is equal to the number of products the user had selected. If that number is lower, I know that at least one product did not match that location.
I have two tables with the following structures (unnecessary columns trimmed out)
----------------- ---------------------
| mod_personnel | | mod_skills |
| | | |
| - prs_id | | - prs_id |
| - name | | - skl_id |
----------------- | |
---------------------
There may be 0 to many rows in the skills table for each prs_id
What I want is all the personnel records which do NOT have an associated skill record with skill_id 1.
In plain English "I want all the people who do not have the skill x".
Currently, I have only been able to do it with the following nested select. But I am hoping to find a faster way.
SELECT * FROM `mod_personnel` WHERE `prs_id` NOT IN (
SELECT `prs_id` FROM `mod_skills` WHERE `skl_id` = 1 )
This may be faster:
SELECT `mod_personnel`.*
FROM `mod_personnel`
left outer join `mod_skills`
on `mod_skills`.`prs_id` = `mod_personnel`.`prs_id`
and `mod_skills`.`skl_id` = 1
WHERE `mod_skills`.`prs_id` is null;
Using a NOT EXISTS might be faster.
SELECT *
FROM `mod_personnel` p
WHERE NOT EXISTS (SELECT *
FROM `mod_skills` s
WHERE s.`prs_id` = p.`prs_id`
AND s.`skl_id` = 1 );
This is an excerpt from one table:
| id | type | other_id | def_id | ref_def_id|
| 1 | int | NULL | 5 | NULL |
| 2 | string | NULL | 5 | NULL |
| 3 | int | NULL | 5 | NULL |
| 20 | ref | 3 | NULL | 5 |
| 21 | ref | 4 | NULL | 5 |
| 22 | ref | 5 | NULL | 5 |
What I want is to find entries with type ref. Then I would for example have this one entry in my result:
| 22 | ref | 5 | NULL | 5 |
The problem I am facing is that I now want to combine this entry with other entries of the same table where def_id = 5.
So I would get all entries with def_id = 5 for this specific ref type as result. I somehow need the output from my first query, check what the ref_def_id is and then make another query for this id.
I really have problems to understand how to proceed. Any input is much appreciated.
If I understand correctly you need to find rows with a type of 'ref' and then use the values in their ref_def_id columns to get the rows with the same values in def_id. In that case you need to use a subquery for getting the rows with 'ref' type and combine it using either IN or EXISTS:
select *
from YourTable
where def_id in (select ref_def_id from YourTable where type='ref');
select *
from YourTable
where exists (select * from YourTable yt
where yt.ref_def_id=YourTable.def_id and yt.type='ref')
Both queries are equivalent, IN is easier to understand at first sight but EXISTS allow more complex conditions (for example you can use more than one column for combining with the subquery).
Edit: since you comment that you need also the id from the 'ref' rows then you need to use a subquery:
select source_id, YourTable.*
from YourTable
join (select id as source_id, ref_def_id
from YourTable
where type='ref')
as refs on refs.ref_def_id=YourTable.def_id
order by source_id, id;
With this for each 'ref' row you would get all the rows with the associated ref_id.
use below query to get column from sub query.
select a.ref_def_id
from (select ref_def_id from YourTable where type='ref') as a;
What you are looking for is a subquery or even better a join operation.
Have a look here: http://www.mysqltutorial.org/mysql-left-join.aspx
Joins / the left join allows you to combine rows of tables within one query on a given condition. The condition could be id = 5 for your purpose.
You would seem to want aggregation:
select max(id) as id, type, max(other_id) as other_id,
max(def_id) as def_id, ref_def_id
from t
where type = 'ref'
group by type, ref_def_id
I want to count all entries in one table grouped by the user id.
This is the query I used which works fine.
select uuid_mapping_id, count(*) from t_message group by uuid_mapping_id;
and these are the results:
+-----------------+----------+
| uuid_mapping_id | count(*) |
+-----------------+----------+
| 1 | 65 |
| 4 | 277 |
Now I would like to display the actual user name, instead of the ID.
To achieve this I would need the help of two different tables.
The table t_uuid_mapping which has two columns:
uid_mapping_id, which equals uuid_mapping_id in the other table.
And f_uuid which is also unique but completely different.
f_uuid can also be found in another table t_abook which also contains the names in the column f_name.
The result I am looking for should be:
+-----------------+----------+
| f_name | count(*) |
+-----------------+----------+
| admin | 65 |
| user1 | 277 |
I am new to the database topic and understand that this could be achieved by using JOIN in the query, but to be honest I did not completely understand this yet.
if I understand you correctly:
SELECT tm.f_name, COUNT(*) as count
FROM t_message tm
LEFT JOIN t_abook ta ON (tm.uuid_mapping_id = ta.uid_mapping_id)
GROUP BY tm.f_name
How do I display all the contents of a table without duplicates?
Example:
Table 1
______________________
| ID | VALUE |
| 0 | A |
| 1 | A |
| 2 | B |
| 3 | C |
Expected output:
A
B
C
What about
SELECT DISTINCT VALUE FROM table
or use GROUP BY statement with VALUE column
there is not any duplicate rows. you can use distinct keyword only with values like
SELECT DISTINCT VALUE FROM XYZ;
you can do the same using group by
SELECT VALUE FROM XYZ GROUP BY VALUE;
but this is bullshit. a good developer will not use it.